Dirac Notation Basics

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Name__________________________
Dirac Notation Basics
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For all questions involving a generic operator 𝑄̂ corresponding to a physical observable 𝑄, assume that it only
depends on position π‘₯Μ‚ and momentum 𝑝̂ .
For a hermitian operator 𝑄̂ , the notation ⟨Ψ|𝑄̂|Ψ⟩ with 𝑄̂ between two vertical lines is the same as ⟨Ψ|𝑄̂ Ψ⟩, i.e.,
⟨Ψ|𝑄̂|Ψ⟩ = ⟨Ψ|𝑄̂ Ψ⟩ since a hermitian operator can act forward or backwards on the state, i.e., ⟨Ψ|𝑄̂|Ψ⟩ =
βŸ¨π‘„Μ‚ † Ψ|Ψ⟩ = βŸ¨π‘„Μ‚ Ψ|Ψ⟩. If an operator is not hermitian (does not correspond to a physical observable), one should
assume that the operator acts on the state after it (to the right of the operator), even if ⟨Ψ|𝑄̂ |Ψ⟩ notation is used.
The goals of this tutorial are to help you learn that:
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The state of a quantum system |𝚿⟩ is a vector
o that lies in an 𝑁 dimensional Hilbert space.
o that has all possible information about the quantum system.
Scalar products (or inner products) βŸ¨π“|𝝍⟩
o are defined as the component of one state |πœ“⟩ along another state |πœ™⟩.
o Are, in general, complex numbers (the number could have dimensions).
Hilbert Space
o A quantum state |Ψ⟩ is a vector in the Hilbert space.
o The dimensionality of the Hilbert space is given by the number of linearly independent vectors that span the
Hilbert space.
o The eigenstates of a non-degenerate hermitian operator can be chosen as the basis vectors for the Hilbert
space because they span the space.
Expansion of a state using a complete set of eigenstates
o A state |Ψ⟩ can be written in terms of a linear superposition of a complete set of eigenstates {|π‘žπ‘› ⟩, 𝑛 =
1, 2, 3 … 𝑁} of any hermitian operator 𝑄̂ .
o The coefficients in the expansion, βŸ¨π‘žπ‘› |Ψ⟩, are the components of the state |Ψ⟩ along the direction of the
eigenstates |π‘žπ‘› ⟩ of a hermitian operator 𝑄̂ .
Μ‚ in a generic state |Ψ⟩
Probability of measuring an eigenvalue of a hermitian operator 𝑸
o
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is the probability
of measuring π‘žπ‘› for an observable 𝑄
For orthonormal eigenstates |π‘ž⟩ with continuous eigenvalues π‘ž, |βŸ¨π‘ž|Ψ⟩|2 π‘‘π‘ž is the probability of measuring
the observable 𝑄 in a narrow range between π‘ž and π‘ž + π‘‘π‘ž.
Μ‚ in a generic state |Ψ⟩ in terms of eigenstates and eigenvalues of 𝑸
Μ‚
Expectation value of an operator 𝑸
o The expectation value of a hermitian operator 𝑄̂ with eigenstates {|π‘žπ‘› ⟩, 𝑛 = 1,2, … 𝑁} and discrete
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eigenvalues π‘žπ‘› in a generic state |Ψ⟩ is ⟨Ψ|𝑄̂ |Ψ⟩ = ∑𝑁
𝑛=1 π‘žπ‘› |βŸ¨π‘žπ‘› |Ψ⟩| .
o The expectation value of a hermitian operator 𝑄̂ with eigenstates |π‘ž⟩ and continuous eigenvalues π‘ž in a
∞
generic state |Ψ⟩ is ⟨Ψ|𝑄̂ |Ψ⟩ = ∫−∞ π‘ž|βŸ¨π‘ž|Ψ⟩|2 π‘‘π‘ž
Completeness relation
Μ‚
o The completeness relation can be written as ∑𝑁
𝑛=1|π‘žπ‘› ⟩⟨π‘žπ‘› | = 𝐼 , where {|π‘žπ‘› ⟩, 𝑛 = 1, 2, 3 … 𝑁} form an
Μ‚
orthonormal basis for an N dimensional vector space. 𝐼 is the identity operator.
∞
o The completeness relation can be written as ∫−∞|π‘ž⟩⟨π‘ž|π‘‘π‘ž = 𝐼̂, where |π‘ž⟩ form an orthonormal basis for an
infinite dimensional vector space.
o The completeness relation is useful for decomposing a state vector into its components along each of the basis
vectors.
Projection operator
o The projection operator |π‘žπ‘› ⟩⟨π‘žπ‘› | acting on a state |Ψ⟩ returns a vector in the direction of |π‘žπ‘› ⟩ together with a
number βŸ¨π‘žπ‘› |Ψ⟩, which is the component of a state vector along the direction of the orthonormal basis vector
|π‘žπ‘› ⟩.
o The projection operator |π‘ž⟩⟨π‘ž| acting on a state |Ψ⟩ returns a vector in the direction of |π‘ž⟩ together with a
number βŸ¨π‘ž|Ψ⟩, which is the component of a state vector along the direction of the orthonormal basis vector
|π‘ž⟩.
o
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For orthonormal eigenstates {|π‘žπ‘› ⟩, 𝑛 = 1, 2, 3 … 𝑁} with discrete eigenvalues π‘žπ‘› , qn 
State of the quantum mechanical system
1. Choose all of the following statements that are correct.
(I)
In Dirac notation, eigenstates of a physical observable are generally labeled by the corresponding
eigenvalue. For example, position eigenstates |π‘₯⟩ are labeled by eigenvalues π‘₯, and momentum
eigenstates |𝑝⟩ are labeled by eigenvalues 𝑝.
(II)
The quantum state written in Dirac notation, |Ψ⟩, lies in an abstract Hilbert space.
(III)
The state |Ψ⟩ contains all information one can obtain about the system at a given time.
(a)
(I) and (II) only
(b)
(II) and (III) only
(c)
(I) and (III) only
(d)
All of the above
2. Choose all of the following statements that are correct.
(I)
The state vector in Dirac notation, |Ψ⟩, is an abstract vector without reference to a coordinate
system.
(II)
The infinite dimensional column vector ⟨π‘₯|Ψ⟩ = Ψ(π‘₯) when considered as a function of x is the
wavefunction of the system at a given time. Ψ(π‘₯) = ⟨π‘₯|Ψ⟩ is obtained when the position
eigenstates |π‘₯⟩ are chosen as the basis vectors to write state |Ψ⟩.
(III)
The state vector |Ψ⟩ and wavefunction  (x) have the same information, but  (x) is a vector
with position eigenstates as the coordinate axes and  (x) for each x denotes the component of
|Ψ⟩ along the direction of |π‘₯⟩.
(a) (I) and (II) only
(b) (I) and (III) only
(c) (II) and (III) only
(d) All of the above.
Summary of state vectors:
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The state of a quantum system is given by a vector |Ψ⟩ in an abstract Hilbert space.
The state |Ψ⟩ contains all possible information about the quantum system at a given time.
The state |Ψ⟩ makes no reference to a coordinate system until the basis vectors are chosen.
The infinite dimensional column vector ⟨π‘₯|Ψ⟩ = Ψ(π‘₯) when considered as a function of π‘₯ is the wavefunction of
the system at a given time. Ψ(π‘₯) = ⟨π‘₯|Ψ⟩ is obtained when the position eigenstates |π‘₯⟩ are chosen as the basis
vectors to write state |Ψ⟩.
The State vector |Ψ⟩ and wavefunction  (x) have the same information, but  (x) is a vector with position
eigenstates as the coordinate axes and  (x) for each x denotes the component of |Ψ⟩ along the direction of |π‘₯⟩.
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Scalar product (Inner product)
3. The scalar product, or inner product, gives the component of a state, e.g., |Ψ2 ⟩, along another state, e.g., |Ψ1 ⟩. Choose
all of the following notations that are correct for the scalar product that gives the component of state |Ψ2 ⟩ along state
|Ψ1 ⟩?
⟨Ψ1 |Ψ2⟩
(I)
|Ψ1 ⟩⟨Ψ2 |
(II)
|Ψ1 ⟩|Ψ2 ⟩
(III)
(a) (I) only
(b) (II) only
(c) (III) only
(d) (I) and (II) only
4. Which one of the following equations is correct in general?
|Ψ1 ⟩⟨Ψ2 | = ⟨Ψ1|Ψ2 ⟩
(a)
⟨Ψ2 |Ψ1⟩ = ⟨Ψ1|Ψ2 ⟩
(b)
⟨Ψ1 |Ψ2⟩ = ⟨Ψ2|Ψ1 ⟩∗ , where * denotes complex conjugate.
(c)
|Ψ1 ⟩⟨Ψ2 | = ⟨Ψ2|Ψ1 ⟩∗ , where * denotes complex conjugate.
(d)
5. Since the wave function is normalizable, the scalar product of a normalized state vector |Ψ⟩ with itself gives
(a) ⟨Ψ|Ψ⟩ = 1
(b) ⟨Ψ|Ψ⟩ = 0
(c) ⟨Ψ|Ψ⟩ can be any finite number depending on the state.
(d) ⟨Ψ|Ψ⟩ = 𝑒 π‘–πœ‘ , where οͺ is a phase factor that depends on the state.
Summary of scalar products (inner products):
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A scalar product of state |Ψ2 ⟩ with |Ψ1 ⟩, ⟨Ψ1|Ψ2 ⟩ , is defined as the component of state |Ψ2 ⟩ along state |Ψ1 ⟩.
A scalar product is not a vector. In general, the scalar product is a complex number.
Interchanging the “bra” and “ket” states in a scalar product produces its complex conjugate: ⟨Ψ2 |Ψ1 ⟩ = ⟨Ψ1 |Ψ2⟩∗ .
The scalar product of a normalized state |Ψ⟩ with itself gives 1, i.e., ⟨Ψ|Ψ⟩ = 1.
Hilbert Space
6. Which one of the following statements is true about the Hilbert space corresponding to a spin ½ system?
(a) The Hilbert space is two dimensional and the spin operator corresponding to each of the spin components has two
eigenstates that form a complete set of basis vectors.
(b) The Hilbert space is three dimensional because the physical laboratory space is three dimensional and Hilbert space is
a mathematical representation of the real world.
(c) The Hilbert space is infinite dimensional, because a finite dimensional space cannot be the Hilbert space for any
quantum mechanical system.
(d) None of the above.
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7. Choose all of the following statements that are correct about the eigenstates of an operator in a Hilbert space.
(I)
An operator in a finite dimensional Hilbert space can have a finite number of discrete
eigenvalues.
(II)
An operator in an infinite dimensional Hilbert space can have infinitely many discrete
eigenvalues.
(III)
An operator in an infinite dimensional Hilbert space can have infinitely many continuous
eigenvalues.
(a) (I) and (II) only
(b) (I) and (III) only
(c) (II) and (III) only
(d) All of the above.
8. Suppose 𝑄 is an observable for a given quantum system and its corresponding operator in the Hilbert space is 𝑄̂ .
Choose all of the following statements that are correct.
(I)
𝑄̂ must be a hermitian operator.
(II)
𝑄̂ = 𝑄̂ †
(III)
βŸ¨πœ™|𝑄̂ πœ“βŸ© = βŸ¨π‘„Μ‚ πœ™|πœ“βŸ© for all states |πœ™⟩ and |πœ“⟩ in the Hilbert space.
A. 1 only B. 2 only C. 3 only D. 1 and 2 only E. all of the above
9. “Any state vector in a Hilbert space can be expanded as a linear combination of a complete set of eigenstates of a
hermitian operator.” Which one of the following does this statement imply? Note: Answer choices below may be
correct statements but may not be implied by the statement in this question.
(a) All hermitian operators commute with each other and have simultaneous eigenstates.
(b) Eigenstates of a Hermitian operator can be chosen to be the coordinates (basis vectors) in the Hilbert space.
(c) All hermitian operators have real eigenvalues that correspond to results of measurements in physical space.
(d) The given statement is incorrect. The correct statement should read “Any vector in Hilbert space can only be
expanded as a linear superposition of a complete set of energy eigenstates (eigenstates of the Hamiltonian operator).”
10. “Any state vector in the Hilbert space can be expanded as a linear superposition of a complete set of eigenstates of a
hermitian operator” is a correct statement. Choose all of the following that can be examples of the mathematical
representation of this statement.
|Ψ⟩ = ∑𝑛 𝐢𝑛 |πœ“π‘› ⟩, where |πœ“π‘› ⟩ are energy eigenstates for a given quantum system and 𝐢𝑛 =
(I)
⟨ψ𝑛 |Ψ⟩ are appropriate expansion coefficients.
∞
|Ψ⟩ = ∫−∞ 𝐢π‘₯ |π‘₯⟩𝑑π‘₯, where |π‘₯⟩ are position eigenstates and 𝐢π‘₯ = ⟨π‘₯|Ψ⟩ = Ψ(π‘₯) are appropriate
(II)
expansion coefficients.
|Ψ⟩ = ∑𝑛 𝐢𝑛 ⟨Ψ|πœ“π‘› ⟩, where |πœ“π‘› ⟩ are energy eigenstates and 𝐢𝑛 = ⟨ψ𝑛 |Ψ⟩ are appropriate
(III)
expansion coefficients.
(a) (I) only
(b) (I) and (II) only
(c) (II) and (III) only
(d) All of the above.
Summary of Hilbert Space:
ο‚· Quantum state vectors are vectors in the Hilbert space.
ο‚· State vectors can be expanded as a linear superposition of a complete set of eigenstates of a hermitian operator.
ο‚· The dimensionality of the Hilbert space is given by the number of linearly independent vectors in the space. The
eigenstates of a hermitian operator span the space which means that they form a complete set of basis vectors for
the Hilbert space.
ο‚· When the measurement of an observable is performed in physical space, the values one measures are the
eigenvalues of the corresponding hermitian operator.
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Checkpoint 1
Consider the following conversation between student A and student B:
ο‚· Student A: The Hilbert space for a particle interacting with a one dimensional infinite square well is
infinite dimensional. Also, the position eigenstates form a complete set of basis vectors for the space
and the position of the particle has infinitely many values within the width of the square well.
ο‚· Student B: I disagree. The Hilbert space for a particle interacting with a one dimensional infinite
square well is one dimensional, because the well is one dimensional and the particle is confined in one
dimension.
Which student, if either, do you agree with and why?
Expansion of a state vector in terms of a complete set of eigenstates
11. Earlier you learned that any vector in the Hilbert space can be expanded as a linear superposition of a complete set of
eigenstates of a hermitian operator 𝑄̂ . For an operator 𝑄̂ with eigenstates {|π‘žπ‘› ⟩, 𝑛 = 1,2,3 … 𝑁} (which form an
orthonormal basis for an 𝑁 dimensional vector space) and discrete eigenvalues π‘žπ‘› , choose all of the following
statements that are correct about the coefficients 𝐢𝑛 in the expansion
|Ψ⟩ = ∑𝑛 𝐢𝑛 |π‘žπ‘› ⟩.
(I)
To find 𝐢𝑛 , we take the scalar product with an eigenstate |π‘žπ‘› ⟩. Then,
βŸ¨π‘žπ‘› |Ψ⟩ = ∑π‘š πΆπ‘š βŸ¨π‘žπ‘› |π‘žπ‘š ⟩ = ∑π‘š πΆπ‘š π›Ώπ‘›π‘š = 𝐢𝑛 .
(II)
To find 𝐢𝑛 , we take the scalar product with an eigenstate |π‘žπ‘› ⟩. Then,
βŸ¨π‘žπ‘› |Ψ⟩ = ∑𝑛 𝐢𝑛 βŸ¨π‘žπ‘› |π‘žπ‘› ⟩ = ∑𝑛 𝐢𝑛 .
(III)
The coefficient 𝐢𝑛 for a particular eigenstate |π‘žπ‘› ⟩ in the expansion |Ψ⟩ = ∑𝑛 𝐢𝑛 |π‘žπ‘› ⟩ is related to
the probability of measuring the corresponding eigenvalue π‘žπ‘› when a measurement of observable
𝑄 is made in the state |Ψ⟩.
(a) (I) and (II) only
(b) (I) and (III) only
(c) (II) and (III) only
(d) All of the above.
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12. Consider the following conversation between Student A and Student B.
ο‚· Student A: In the preceding question, statement (II) seems to make more sense than statement (I), because we are
using the expansion |Ψ⟩ = ∑𝑛 𝐢𝑛 |π‘žπ‘› ⟩ as opposed to |Ψ⟩ = ∑π‘š πΆπ‘š |π‘žπ‘š ⟩.
ο‚· Student B: But m and n are just “dummy” indices. They both can range from 1 to N, where N is the dimension of
the Hilbert space.
ο‚· Student A: What is the point of changing the label from 𝑛 to π‘š in the expansion of |Ψ⟩ (|Ψ⟩ = ∑𝑛 𝐢𝑛 |π‘žπ‘› ⟩ →
|Ψ⟩ = ∑π‘š πΆπ‘š |π‘žπ‘š ⟩) in statement (I)?
ο‚· Student B: If you take the scalar product of |Ψ⟩ = ∑𝑛 𝐢𝑛 |π‘žπ‘› ⟩ with an eigenstate βŸ¨π‘žπ‘› | with the same index 𝑛, like
in statement (II), you obtain βŸ¨π‘žπ‘› |Ψ⟩ = ∑𝑛 𝐢𝑛 βŸ¨π‘žπ‘› |π‘žπ‘› ⟩ = ∑𝑛 𝐢𝑛 . You end up with a sum over all 𝐢𝑛 ’s. This is
incorrect. You must take the inner product with a different “dummy” indexed state |Ψ⟩ = ∑π‘š πΆπ‘š |π‘žπ‘š ⟩, so that you
get βŸ¨π‘žπ‘› |Ψ⟩ = ∑π‘š πΆπ‘š βŸ¨π‘žπ‘› |π‘žπ‘š ⟩ = ∑π‘š πΆπ‘š π›Ώπ‘›π‘š = 𝐢𝑛 . Instead of βŸ¨π‘žπ‘› |π‘žπ‘› ⟩ = 1, you obtain βŸ¨π‘žπ‘› |π‘žπ‘š ⟩ = π›Ώπ‘›π‘š which gets
rid of the summation. This is the correct answer, which is just a single coefficient 𝐢𝑛 , not a sum ∑𝑛 𝐢𝑛 .
ο‚· Student A: I see. If we choose a different dummy index for state |Ψ⟩ = ∑π‘š πΆπ‘š |π‘žπ‘š ⟩ when taking the inner
product, we get βŸ¨π‘žπ‘› |π‘žπ‘š ⟩ = π›Ώπ‘›π‘š , which gets rid of the sum over 𝑛.
Do you agree with Student B’s explanation? Explain why or why not.
13. Consider the following conversation between Student A and Student B.
ο‚· Student A: For an operator with a discrete eigenvalue spectrum, such as energy, we can talk about measuring each
of the eigenvalues. We can calculate the probabilities for measuring each of them individually.
ο‚· Student B: I agree. But for an operator that has a continuous eigenvalue spectrum, like position or momentum, we
should talk about measuring a value in a narrow range. For example, the probability of measuring position
between x and x  dx is |Ψ(π‘₯)|2 𝑑π‘₯.
Do you agree with Student A and/or Student B? Explain your reasoning.
14. For an arbitrary physical observable 𝑄 with discrete eigenvalues π‘žπ‘› and eigenstates |π‘žπ‘› ⟩, where
𝑛 = 1,2, … 𝑁, write the probability of measuring eigenvalue π‘žπ‘› as a result of a measurement of 𝑄 performed when
the system is in the state |Ψ⟩.
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15. Earlier you learned that any vector in the Hilbert space can be expanded as a linear superposition of a complete set of
eigenstates of a hermitian operator 𝑄̂ . In the case of an operator 𝑄̂ with continuous eigenvalues π‘ž and eigenstates |π‘žβŸ©
(which form an orthonormal basis for an infinite dimensional vector space), choose all of the following statements
that are correct about the coefficients πΆπ‘ž in the expansion
∞
|Ψ⟩ = ∫−∞ πΆπ‘ž |π‘ž⟩π‘‘π‘ž? (Hint: This is similar to question 11, except the eigenvalues are continuous).
(I)
To find πΆπ‘ž , we take the scalar product with an eigenstate |π‘ž⟩. Then,
∞
∞
βŸ¨π‘ž|Ψ⟩ = ∫−∞ πΆπ‘ž′ βŸ¨π‘ž|π‘ž ′ βŸ©π‘‘π‘ž ′ = ∫−∞ πΆπ‘ž′ 𝛿(π‘ž − π‘ž ′ )π‘‘π‘ž ′ = πΆπ‘ž .
(II)
Physically, the coefficient πΆπ‘ž is the component of the state |Ψ⟩ along the direction of the
eigenvector |π‘ž⟩ (with eigenvalue π‘ž).
∞
(III)
The coefficient πΆπ‘ž = βŸ¨π‘ž|Ψ⟩ in the expansion |Ψ⟩ = ∫−∞ πΆπ‘ž |π‘ž⟩π‘‘π‘ž is related to the probability of
measuring the eigenvalue π‘ž when observable 𝑄 is measured in the state |Ψ⟩.
(a) (I) and (II) only
(b) (I) and (III) only.
(c) (II) and (III) only
(d) All of the above.
16. Earlier, you learned that for an operator 𝑄̂ corresponding to a physical observable 𝑄 with eigenstates {|π‘žπ‘› ⟩, 𝑛 =
1,2, … 𝑁} with discrete eigenvalues π‘žπ‘›
βŸ¨π‘žπ‘› |Ψ⟩ is the probability amplitude for measuring π‘žπ‘› if we measure observable 𝑄
(I)
|βŸ¨π‘žπ‘› |Ψ⟩|2 is the probability for measuring π‘žπ‘› if we measure observable 𝑄.
(II)
Before Dirac notation was introduced, physicist Max Born interpreted the probabilistic nature of quantum mechanics and
proposed the following statements for the continuous case for observable π‘₯ which has a continuous eigenvalue spectrum:
(I)
(II)
(III)
Ψ(π‘₯) is the probability density amplitude for measuring position.
|Ψ(π‘₯)|2 is the probability density for measuring position.
|Ψ(π‘₯)|2 𝑑π‘₯ is the probability of finding the particle in the narrow range between x and x  dx when
position of the particle is measured.
Write each of these expressions (probability density amplitude, probability density, and probability of measuring position
in a narrow range between π‘₯ and π‘₯ + 𝑑π‘₯) in Dirac notation.
(a)
Ψ(π‘₯) =
(b)
|Ψ(π‘₯)|2 =
(c)
|Ψ(π‘₯)|2 𝑑π‘₯ =
17. Dirac extended Born’s interpretation to apply to measurements of not only position but any physical observable.
Keeping in mind your answers to the two preceding questions, for an arbitrary physical observable 𝑄 with eigenstates
|π‘ž⟩ with continuous eigenvalues π‘ž, write the probability of measuring observable 𝑄 between π‘ž and π‘ž + π‘‘π‘ž as a
result of a measurement performed when the system is in the state |Ψ⟩.
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18. The expectation value of an operator is the average value of the observable measured over many identical
experiments performed on identically prepared systems in state |Ψ⟩. For a general quantum mechanical hermitian
operator 𝑄̂ , the expectation value is represented by ⟨Ψ|𝑄̂ |Ψ⟩. If 𝑄̂ has discrete eigenvalues π‘žπ‘› and eigenstates |π‘žπ‘› ⟩
where 𝑛 = 1,2, … 𝑁, let’s write ⟨Ψ|𝑄̂ |Ψ⟩ in terms of the eigenstates |π‘žπ‘› ⟩ and eigenvalues π‘žπ‘› .
(a)
Write |Ψ⟩ as a linear superposition of the eigenstates of 𝑄̂ .
(b)
Consider the following conversation between two students:
ο‚· Student A: If we write |Ψ⟩ as a linear superposition of the eigenstates of 𝑄̂ , we obtain
|Ψ⟩ = ∑𝑁
𝑛=1 π‘Žπ‘› |π‘žπ‘› ⟩, where π‘Žπ‘› is the expansion coefficient.
ο‚· Student B: I agree with you. But we know that the expansion coefficients, π‘Žπ‘› , are the eigenvalues π‘žπ‘›
of the operator 𝑄̂ . So we can write |Ψ⟩ as a linear superposition of the eigenstates of 𝑄̂ like this:
|Ψ⟩ = ∑𝑁
𝑛=1 π‘žπ‘› |π‘žπ‘› ⟩.
With whom do you agree? Explain your reasoning.
(c)
The linear superposition of |Ψ⟩ in terms of the eigenstates of 𝑄̂ can be written as
|Ψ⟩ = ∑𝑁
𝑛=1 π‘Žπ‘› |π‘žπ‘› ⟩, where π‘Žπ‘› is the expansion coefficient and gives the component of the state |Ψ⟩ along the
direction of the nth eigenstate |π‘žπ‘› ⟩. Write π‘Žπ‘› explicitly in terms of |Ψ⟩ and |π‘žπ‘› ⟩.
(d)
What is the probability of measuring π‘žπ‘› when you measure observable 𝑄 in the state |Ψ⟩?
(e)
Consider the following conversation between Student A and Student B:
ο‚· Student A: |βŸ¨π‘žπ‘› |Ψ⟩|2 is the probability of measuring π‘žπ‘› when you measure observable 𝑄 in the state
 . The expectation value is the average value of a large number of measurements performed on
identically prepared systems. Since we know the probability of measuring each eigenvalue π‘žπ‘› of the
2
operator 𝑄̂ , the expectation value is ⟨Ψ|𝑄̂ |Ψ⟩ = ∑𝑁
𝑛=1 π‘žπ‘› |βŸ¨π‘žπ‘› |Ψ⟩| .
ο‚· Student B: No. You cannot think about expectation value physically as an average of a large number
of measurements on identically prepared systems. We must use our expansion |Ψ⟩ = ∑𝑁
𝑛=1 π‘Žπ‘› |π‘žπ‘› ⟩, to
calculate the expectation value ⟨Ψ|𝑄̂ |Ψ⟩.
With whom, if either, do you agree? Explain your reasoning.
8
(f)
Student A is correct. The expectation value is the average value of a large number of measurements on
identically prepared systems, which can be represented mathematically by the equation ⟨Ψ|𝑄̂ |Ψ⟩ =
𝑁
2
∑𝑁
𝑛=1 π‘žπ‘› |βŸ¨π‘žπ‘› |Ψ⟩| . But let’s follow Student B’s method using the expansion |Ψ⟩ = ∑𝑛=1 π‘Žπ‘› |π‘žπ‘› ⟩ to prove that
2
Μ‚
the equation ⟨Ψ|𝑄̂ |Ψ⟩ = ∑𝑁
𝑛=1 π‘žπ‘› |βŸ¨π‘žπ‘› |Ψ⟩| , suggested by Student A, is correct. Act with 𝑄 on the state
𝑁
|Ψ⟩ = ∑𝑛=1 π‘Žπ‘› |π‘žπ‘› ⟩. What do you obtain?
(g)
So far, we have 𝑄̂ |Ψ⟩ = ∑𝑁
𝑛=1 π‘Žπ‘› π‘žπ‘› |π‘žπ‘› ⟩. Using your answer from part (c), insert what you obtained for π‘Žπ‘›
|π‘ž
⟩
into 𝑄̂ |Ψ⟩ = ∑𝑁
π‘Ž
π‘ž
𝑛=1 𝑛 𝑛 𝑛 .
(h)
𝑁
Μ‚
We now have 𝑄̂ |Ψ⟩ = ∑𝑁
𝑛=1 π‘žπ‘› |π‘žπ‘› ⟩ βŸ¨π‘žπ‘› |Ψ⟩. Now take the inner product of 𝑄 |Ψ⟩ = ∑𝑛=1 π‘žπ‘› |π‘žπ‘› ⟩ βŸ¨π‘žπ‘› |Ψ⟩ with
a “bra” state ⟨Ψ| to find the expectation value ⟨Ψ|𝑄̂|Ψ⟩. Does your answer agree with Student A’s statement
from part (e)? If not, go back and check your work with a partner to obtain the equation for the expectation
value of observable 𝑄̂ in terms of its complete set of eigenstates {|π‘žπ‘› ⟩, 𝑛 = 1,2, … 𝑁} and eigenvalues π‘žπ‘› , i.e.,
2
⟨Ψ|𝑄̂|Ψ⟩ = ∑𝑁
𝑛=1 π‘žπ‘› |βŸ¨π‘žπ‘› |Ψ⟩| .
(i)
Repeat the calculation for the expectation value ⟨Ψ|𝑄̂ |Ψ⟩ of an operator 𝑄̂ with eigenstates |π‘ž⟩ (which form
a basis in an infinite dimensional vector space) with continuous eigenvalues π‘ž.
19. Suppose an operator 𝑄̂ corresponding to a physical observable 𝑄 has eigenstates {|π‘žπ‘› ⟩, 𝑛 = 1,2, … 𝑁} with discrete
2
eigenvalues π‘žπ‘› . Which of the following are correct about the expression ∑𝑁
𝑛=1|βŸ¨π‘žπ‘› |Ψ⟩| ?
𝑁
2
∑𝑛=1|βŸ¨π‘žπ‘› |Ψ⟩| = 1
(I)
2
∑𝑁
(II)
𝑛=1|βŸ¨π‘žπ‘› |Ψ⟩| is equal to a real number.
𝑁
∑𝑛=1|βŸ¨π‘žπ‘› |Ψ⟩|2 is equal to a complex number that does have an imaginary part.
(III)
(a)
(II) only
(b)
(III) only
(c)
(I) and (II) only
(d)
None of the above.
9
20. Consider the following conversation between two students about the preceding question:
2
ο‚· Student A: I don’t see how ∑𝑁
𝑛=1|βŸ¨π‘žπ‘› |Ψ⟩| = 1.
ο‚· Student B: Let me show you.
1. We can start with ⟨Ψ|Ψ⟩ = 1, since any state vector can be normalized to 1.
2. Insert the identity operator, written in terms of the eigenstates {|π‘žπ‘› ⟩, 𝑛 = 1,2, … 𝑁} of the operator 𝑄̂ , like
this: 1 = ⟨Ψ|Ψ⟩ = ∑𝑁
𝑛=1⟨Ψ|π‘žπ‘› βŸ©βŸ¨π‘žπ‘› |Ψ⟩.
3. Using the fact that ⟨Ψ|π‘žπ‘› ⟩∗ = βŸ¨π‘žπ‘› |Ψ⟩, we can write
𝑁
2
1 = ⟨Ψ|Ψ⟩ = ∑𝑁
𝑛=1⟨Ψ|π‘žπ‘› βŸ©βŸ¨π‘žπ‘› |Ψ⟩ = ∑𝑛=1|βŸ¨π‘žπ‘› |Ψ⟩| .
ο‚· Student A: I see. Is there any physical significance to βŸ¨π‘žπ‘› |Ψ⟩?
ο‚· Student B: Yes. βŸ¨π‘žπ‘› |Ψ⟩ is the probability amplitude and |βŸ¨π‘žπ‘› |Ψ⟩|2 is the probability for measuring π‘žπ‘› if we
measure observable 𝑄.
2
ο‚· Student A: So based on the mathematical expression ∑𝑁
𝑛=1|βŸ¨π‘žπ‘› |Ψ⟩| = 1, the probabilities of measuring
different eigenvalues π‘žπ‘› when we measure the observable 𝑄 must add up to 1.
Do you agree with Student A and Student B? Explain your reasoning.
Summary of the expansion of a state vector in terms of a complete set of eigenstates:
ο‚·
We can write the state vector in terms of a linear superposition of the energy eigenstates, position eigenstates, or
eigenstates of any other hermitian operator since each of them spans the space.
o If 𝑄̂ has eigenstates |π‘žπ‘› ⟩ ( 𝑛 = 1,2, … 𝑁 ) with discrete eigenvalues π‘žπ‘› , then
|Ψ⟩ = ∑𝑁
𝑛=1 π‘Žπ‘› |π‘žπ‘› ⟩, in which π‘Žπ‘› is the component of the state |Ψ⟩ along |π‘žπ‘› ⟩, i.e., π‘Žπ‘› = βŸ¨π‘žπ‘› |Ψ⟩.
∞
Μ‚
o If 𝑄 has eigenstates |π‘ž⟩ with continuous eigenvalues π‘ž, then |Ψ⟩ = ∫ π‘Žπ‘ž |π‘ž⟩ π‘‘π‘ž, in which π‘Žπ‘ž is the
−∞
o
component of the state |Ψ⟩ along the eigenstate |π‘ž⟩, i.e., π‘Žπ‘ž = βŸ¨π‘ž|Ψ⟩.
If a hermitian operator 𝑄̂ has a discrete eigenvalue spectrum, the expansion of a state vector |Ψ⟩ in terms
of the eigenstates |π‘žπ‘› ⟩ of the hermitian operator is a sum. If a hermitian operator 𝑄̂ has a continuous
eigenvalue spectrum, the expansion of a state vector vector |Ψ⟩ in terms of the eigenstates |π‘ž⟩ of the
hermitian operator is an integral.
o
For discrete eigenvalues π‘žπ‘› , qn 
2
is the probability of measuring π‘žπ‘› for an observable 𝑄 when the
system is in the state  .
For continuous eigenvalues π‘ž, |βŸ¨π‘ž|Ψ⟩|2 π‘‘π‘ž is the probability of measuring an observable 𝑄 in a narrow
range between π‘ž and π‘ž + π‘‘π‘ž when the system is in the state |Ψ⟩.
The expectation value of a hermitian operator 𝑄̂ in a generic state |Ψ⟩ is the average value of the observable 𝑄
measured over many identical experiments performed on identically prepared systems in state |Ψ⟩.
o In a generic state |Ψ⟩, the expectation value for an operator 𝑄̂ with eigenstates |π‘žπ‘› ⟩ (𝑛 = 1, 2, … 𝑁) with
2
discrete eigenvalues π‘žπ‘› is ⟨Ψ|𝑄̂ |Ψ⟩ = ∑𝑁
𝑛=1 π‘žπ‘› |βŸ¨π‘žπ‘› |Ψ⟩|
o In a generic state |Ψ⟩, the expectation value for an operator 𝑄̂ with eigenstates |π‘ž⟩ with continuous
∞
eigenvalues π‘ž is ⟨Ψ|𝑄̂ |Ψ⟩ = ∫ π‘ž|βŸ¨π‘ž|Ψ⟩|2 π‘‘π‘ž
o
ο‚·
−∞
10
Completeness Relation
The completeness relation can be written in terms of orthonormal eigenstates |π‘žπ‘› ⟩ of an operator 𝑄̂ with discrete
Μ‚
eigenvalues π‘žπ‘› . Mathematically, the completeness relation is ∑𝑁
𝑛=1|π‘žπ‘› ⟩⟨π‘žπ‘› | = 𝐼 , where {|π‘žπ‘› ⟩, 𝑛 = 1, 2, 3 … 𝑁} is an
ˆ
orthonormal basis for an N dimensional Hilbert space and I is the identity operator which can be represented by an 𝑁 ×
𝑁 identity matrix. Completeness (of a set of basis vectors, e.g., eigenstates of an operator corresponding to a physical
observable) means that an arbitrary state vector |Ψ⟩ can be written in terms of the complete set of basis vectors.
21. a) Act with the identity operator 𝐼̂, written in terms of orthonormal eigenstates |π‘žπ‘› ⟩ of an operator 𝑄̂ with discrete
eigenvalues π‘žπ‘› , on an arbitrary state vector |Ψ⟩. What do you obtain?
b) Explain your results from part (a) in a sentence.
𝑁
22. So far we have 𝐼̂|Ψ⟩ = ∑𝑁
𝑛=1|π‘žπ‘› ⟩⟨π‘žπ‘› |Ψ⟩. If |Ψ⟩ = ∑𝑛=1 π‘Žπ‘› |π‘žπ‘› ⟩, which one of the following is the correct expression
for the coefficients π‘Žπ‘› along the state |π‘žπ‘› ⟩ in the expansion of |Ψ⟩?
(a)
π‘Žπ‘› = βŸ¨π‘žπ‘› |Ψ⟩
(b)
π‘Žπ‘› = βŸ¨π‘žπ‘› |π‘žπ‘› ⟩
(c)
π‘Žπ‘› = |βŸ¨π‘žπ‘› |Ψ⟩|2
(d)
π‘Žπ‘› = ⟨Ψ|Ψ⟩
𝑁
The identity operator acting on an arbitrary state |Ψ⟩ is 𝐼̂|Ψ⟩ = ∑𝑁
𝑛=1|π‘žπ‘› ⟩⟨π‘žπ‘› |Ψ⟩ = ∑𝑛=1 π‘Žπ‘› |π‘žπ‘› ⟩. This shows that a
generic state |Ψ⟩ can be written in terms of a complete set of eigenstates which span the Hilbert space. We often use the
completeness relation to decompose a generic state |Ψ⟩ into its components along each of the basis vectors (eigenstates of
a hermitian operator can be chosen to be the basis vectors in the Hilbert space).
Μ‚
23. Re-calculate expectation value of 𝑄̂ in state |Ψ⟩, ⟨Ψ|𝑄̂ |Ψ⟩, by using the completeness relation ∑𝑁
𝑛=1|π‘žπ‘› ⟩⟨π‘žπ‘› | = 𝐼
inserted into the expression ⟨Ψ|𝑄̂ |Ψ⟩ and compare to your answer for question 18 part (h).
11
24. The completeness relation can also be written in terms of the eigenstates of an operator 𝑄̂ with a continuous
eigenvalue spectrum. The completeness relation corresponding to a hermitian operator 𝑄̂ with eigenstates |π‘ž⟩ with
∞
continuous eigenvalues π‘ž is ∫−∞|π‘žβŸ©βŸ¨π‘ž|π‘‘π‘ž = 𝐼̂, where 𝐼̂ is an infinite dimensional identity matrix.
(a)
What is the result of 𝐼̂ (completeness relation written in terms of a complete set of eigenstates |π‘ž⟩) acting
on |Ψ⟩?
(b)
∞
So far have |Ψ⟩ = 𝐼̂|Ψ⟩ = ∫−∞|π‘žβŸ©βŸ¨π‘ž|ΨβŸ©π‘‘π‘ž. Explain whether βŸ¨π‘ž|Ψ⟩ is a number, operator, or vector.
(c)
Consider the following conversation between Student A and Student B:
ο‚· Student A: The component of |Ψ⟩ along the basis vector |π‘ž⟩ is π‘Žπ‘ž = βŸ¨π‘ž|Ψ⟩, which is a number.
∞
∞
So we are free to move βŸ¨π‘ž|Ψ⟩ in the integral |Ψ⟩ = 𝐼̂|Ψ⟩ = ∫−∞|π‘žβŸ©βŸ¨π‘ž|ΨβŸ©π‘‘π‘ž = ∫−∞βŸ¨π‘ž|Ψ⟩|π‘ž⟩π‘‘π‘ž.
∞
So |Ψ⟩ = ∫−∞ π‘Žπ‘ž |π‘žβŸ©π‘‘π‘ž.
ο‚· Student B: I disagree with you. We cannot simply move βŸ¨π‘ž|Ψ⟩ around inside the integral, like
∞
∞
this ∫−∞|π‘žβŸ©βŸ¨π‘ž|ΨβŸ©π‘‘π‘ž ≠ ∫−∞βŸ¨π‘ž|Ψ⟩|π‘ž⟩π‘‘π‘ž.
With whom, if either, do you agree? Explain your reasoning.
(d)
Using your answers to the preceding parts (a-c), what is the expression for an arbitrary state |Ψ⟩ written in
terms of continuous eigenstates |π‘ž⟩ of a hermitian operator 𝑄̂ and numbers π‘Žπ‘ž = βŸ¨π‘ž|Ψ⟩?
(e)
Use your answers to the preceding parts (a-d) to calculate the expectation value ⟨Ψ|𝑄̂ |Ψ⟩ in terms of
eigenstates |π‘ž⟩ with continuous eigenvalues π‘ž of a hermitian operator 𝑄̂ .
12
25. Which one of the following relations is correct about an operator 𝑄̂ with eigenstates {|π‘žπ‘› ⟩, 𝑛 = 1,2,3 … 𝑁} (which
form an orthonormal basis for an 𝑁 dimensional vector space) and discrete eigenvalues π‘žπ‘› ?
(a)
𝑄̂ = ∑𝑁
𝑛=1 π‘žπ‘› |π‘žπ‘› ⟩
(b)
𝑄̂ = ∑𝑁
𝑛=1 π‘žπ‘› ⟨π‘žπ‘› |π‘žπ‘› ⟩
(c)
𝑄̂ = ∑𝑁
𝑛=1 π‘žπ‘› |π‘žπ‘› ⟩⟨π‘žπ‘› |
Μ‚
(d)
𝑄 = π‘žπ‘› |π‘žπ‘› ⟩
26. To check your answer to the preceding question, you must show that the operator 𝑄̂ acting on any generic state gives
the same result as the right hand side of the expression in the preceding question.
(a)
Act with the operator 𝑄̂ on a generic state |Ψ⟩, like this: 𝑄̂ |Ψ⟩. Now insert the identity operator, written in
terms of the orthonormal eigenstates {|π‘žπ‘› ⟩, 𝑛 = 1,2,3 … 𝑁} of the operator 𝑄̂ , between the operator 𝑄̂ and
generic state |Ψ⟩.
(b)
𝑁
Μ‚
Μ‚
So far, you should have 𝑄̂ |Ψ⟩ = ∑𝑁
𝑛=1 𝑄 |π‘žπ‘› ⟩⟨π‘žπ‘› |Ψ⟩ = ∑𝑛=1 π‘žπ‘› |π‘žπ‘› ⟩⟨π‘žπ‘› |Ψ⟩ . We can think of 𝑄 |Ψ⟩ like this:
𝑁
𝑁
{𝑄̂ }|Ψ⟩ = {∑𝑛=1 𝑄̂ |π‘žπ‘› ⟩⟨π‘žπ‘› |}|Ψ⟩ = {∑𝑛=1 π‘žπ‘› |π‘žπ‘› ⟩⟨π‘žπ‘› |}|Ψ⟩ , such that the terms in the curly brackets must be
equal. So the operator 𝑄̂ = ∑𝑁
𝑛=1 π‘žπ‘› |π‘žπ‘› ⟩⟨π‘žπ‘› |.
(d)
Using your answers to the preceding parts (a)-(c), determine the expression for a hermitian operator 𝑄̂ with
eigenstates |π‘ž⟩ with continuous eigenvalues π‘ž in terms of the eigenstates |π‘ž⟩ and eigenvalues π‘ž.
Summary of the completeness relation:
ο‚· A complete set of orthonormal eigenstates of a hermitian operator 𝑄̂ with discrete or continuous eigenvalues can
be used to write the completeness relation.
ο‚· The completeness relation is useful for decomposing a state vector into its components along each of the basis
vectors.
Μ‚
o The completeness relation for basis vectors with a discrete eigenvalue spectrum is ∑𝑁
𝑛=1|π‘žπ‘› ⟩⟨π‘žπ‘› | = 𝐼 ,
where {|π‘žπ‘› ⟩, 𝑛 = 1, 2, 3 … 𝑁} is an orthonormal basis for an N dimensional vector space (e.g., formed
with a complete set of eigenstates |π‘žπ‘› ⟩ with eigenvalues π‘žπ‘› of an operator 𝑄̂ corresponding to an
observable 𝑄).
o The completeness relation for basis vectors with a continuous eigenvalue spectrum is
∞
∫−∞|π‘žβŸ©βŸ¨π‘ž|π‘‘π‘ž = 𝐼̂, where |π‘ž⟩ is an orthonormal basis for an infinite dimensional vector space (e.g.,
formed with a complete set of eigenstates |π‘ž⟩ with eigenvalues π‘ž of an operator 𝑄̂ corresponding to an
observable 𝑄).
ο‚· The identity operator doesn’t change the vector it acts on.
ο‚· An operator 𝑄̂ with a complete set of orthonormal eigenstates {|π‘žπ‘› ⟩, 𝑛 = 1,2,3 … 𝑁} with discrete eigenvalues
π‘žπ‘› can be written as 𝑄̂ = ∑𝑁
𝑛=1 π‘žπ‘› |π‘žπ‘› ⟩⟨π‘žπ‘› |.
ο‚· An operator 𝑄̂ with a complete set of orthonormal eigenstates |π‘ž⟩ with continuous eigenvalues π‘ž can be written
∞
as 𝑄̂ = ∫−∞ π‘ž|π‘ž⟩⟨π‘ž|π‘‘π‘ž.
13
Checkpoint 2
Choose all of the following statements which are correct for a given quantum system about an operator 𝑄̂ that
corresponds to a physical observable 𝑄 with discrete eigenvalues π‘žπ‘› and eigenstates |π‘žπ‘› ⟩:
|Ψ⟩ = ∑𝑛 𝐢𝑛 |π‘žπ‘› ⟩, where 𝐢𝑛 = βŸ¨π‘žπ‘› |Ψ⟩ are expansion coefficients.
(I)
βŸ¨π‘žπ‘› |Ψ⟩ is the probability of measuring π‘žπ‘› in a generic state |Ψ⟩.
(II)
|𝐢𝑛 |2 = |βŸ¨π‘žπ‘› |Ψ⟩|2 is the probability of measuring π‘žπ‘› in a generic state |Ψ⟩.
(III)
(a)
(b)
(c)
(d)
(e)
(I) only
(II) only
(I) and (II) only
(I) and (III) only
None of the above.
Projection Operator
27. Which one of the following statements is correct about the expression |π‘žπ‘› ⟩⟨π‘žπ‘› |, where {|π‘žπ‘› ⟩, 𝑛 = 1,2,3, … 𝑁} form an
orthonormal basis for an N dimensional vector space?
(a) |π‘žπ‘› ⟩⟨π‘žπ‘› | is equal to the number 1.
(b) |π‘žπ‘› ⟩⟨π‘žπ‘› | is a scalar, but one cannot determine what number it is equal to without knowing what |π‘žπ‘› ⟩ is explicitly.
(c) |π‘žπ‘› ⟩⟨π‘žπ‘› | is an outer product, so it is an operator.
(d) |π‘žπ‘› ⟩⟨π‘žπ‘› | is a vector.
28. Act on a generic state |Ψ⟩ with the operator |π‘žπ‘› ⟩⟨π‘žπ‘› |. That is, |π‘žπ‘› ⟩⟨π‘žπ‘› |Ψ⟩. Which one of the following statements
correctly describes what you obtain?
(a) You get back the same state |Ψ⟩, because |π‘žπ‘› ⟩⟨π‘žπ‘› | is the identity operator.
(b) You get the projection of |Ψ⟩ along the direction of |π‘žπ‘› ⟩. ⟨π‘žπ‘› |Ψ⟩ is the component of |Ψ⟩ along the direction of |π‘žπ‘› ⟩.
The vector |π‘žπ‘› ⟩, which multiplies the coefficient ⟨π‘žπ‘› |Ψ⟩, gives the direction of the projected vector.
(c) You get the same state |Ψ⟩ back, with the corresponding eigenvalue.
(d) It cannot be determined from the given information. The state |Ψ⟩ has to be given explicitly in position representation
for a given quantum system to be able to calculate the answer.
29. Consider the following conversation between Student A and Student B.
ο‚· Student A: I thought that |π‘žπ‘› ⟩⟨π‘žπ‘› | was equal to the identity operator. Wasn’t that what we had learned earlier in
this tutorial? How is it that the same expression is the identity operator and the projection operator at the same
time?
ο‚· Student B: The expression that was equal to the identity operator was ∑𝑁
𝑛=1|π‘žπ‘› ⟩⟨π‘žπ‘› |, where there is a sum over a
complete set of basis vectors. Applying that on a state |Ψ⟩ would give the same state back. An example of a
projection operator is |π‘žπ‘› ⟩⟨π‘žπ‘› |. Acting with |π‘žπ‘› ⟩⟨π‘žπ‘› | on a state |Ψ⟩ gives the projection of that state along the
direction of |π‘žπ‘› ⟩ as follows:
|π‘žπ‘› ⟩
The vector
multiplying
the inner
product
⟨π‘žπ‘› |Ψ⟩
Inner product of |Ψ⟩ with
|π‘žπ‘› ⟩ equals the component
of |Ψ⟩ along the direction
of |π‘žπ‘› ⟩
Do you agree with Student B’s explanation? Explain why or why not.
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Summary of the projection operator:
ο‚·
ο‚·
ο‚·
The projection operator |π‘žπ‘› ⟩⟨π‘žπ‘› | returns the component of a state vector along the direction of a vector |π‘žπ‘› ⟩.
Unlike the identity operator, the projection operator acting on a state vector need not return the same state vector
back.
The projection operator formed with orthonormal eigenstates of a hermitian operator 𝑄̂ with discrete or
continuous eigenvalues has a similar affect on a generic state |Ψ⟩ as follows:
o |π‘žπ‘› ⟩⟨π‘žπ‘› | is a projection operator, e.g., written in terms of orthonormal eigenstates |π‘žπ‘› ⟩ with discrete
eigenvalues π‘žπ‘› of an operator 𝑄̂ . The projection operator |π‘žπ‘› ⟩⟨π‘žπ‘› | projects a generic state |Ψ⟩ along the
direction of vector |π‘žπ‘› ⟩.
o |π‘ž⟩⟨π‘ž| is a projection operator, e.g., written in terms of orthonormal eigenstates |π‘ž⟩ with continuous
eigenvalues π‘ž of an operator 𝑄̂ . The projection operator |π‘ž⟩⟨π‘ž| projects a generic state |Ψ⟩ along the
direction of vector |π‘ž⟩.
Checkpoint 3
Assume we have a generic vector |𝐺⟩ = π‘Ž|𝑖⟩ + 𝑏|𝑗⟩ + 𝑐|π‘˜⟩ in a three dimensional Hilbert space where
π‘Ž, 𝑏, and 𝑐 are complex numbers and |𝑖⟩, |𝑗⟩ and |π‘˜⟩ form an orthonormal basis.
a. Write the projection operator that projects |𝐺⟩ along the basis vector |π‘–βŸ©.
b. Use the projection operator you constructed to find the components of state |𝐺⟩ along the direction
|π‘–βŸ©.
c. Act with the identity operator, written in terms of the basis vectors |𝑖⟩, |𝑗⟩, and |π‘˜⟩ on the vector
|𝐺⟩.
d. Write down, in your own words, the difference between a projection operator and the identity
operator based upon your answers to the preceding parts.
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Answers to Checkpoints
Checkpoint 1:
Student A. There are an infinite number of values of position in a one dimensional infinite square well.
Checkpoint 2:
(d)
Checkpoint 3:
a. |𝑖⟩⟨𝑖|
b. |𝑖⟩⟨𝑖|𝐺⟩ = π‘Ž|𝑖⟩
c. |𝑖⟩⟨𝑖|𝐺⟩ + |𝑗⟩⟨𝑗|𝐺⟩ + |π‘˜⟩⟨π‘˜|𝐺⟩ = π‘Ž|𝑖⟩ + 𝑏|𝑗⟩ + 𝑐|π‘˜⟩ = |𝐺⟩
d. The identity operator acting on a state gives the same state back. A projection operator acting on a state gives
a component of the state along a basis vector times a basis vector.
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