BC Calculus Chapter 9 Review I. Convergence/Divergence Tests

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BC Calculus

Chapter 9 Review

I. Convergence/Divergence Tests

Special Series o P-series, Geometric, Alternating, Telescoping

Ratio, Root, nth term, Integral, Basic/Direct Comparison, Limit Comparison

Absolute/Conditional Convergence

II. Sums of Series

Partial Sums

Geometric Sum

Telescoping Sum

III. Interval and Radius of Convergence

Note: usually use Geometric, Ratio, or Root test

IV. Taylor/Maclaurin Series

Special Maclaurin series

Taylor series centered at x = a

 Taylor’s Theorem/Lagrange Error Bound

Problems:

1. Find the radius of convergence, the interval of convergence, and the values of x for which the series converges absolutely and conditionally. a.) n

0

(

 x ) n n !

b.) n

0

2

3 n

( x

1 ) n

2. Find the Maclaurin series for the functions below. c.) n

1 x n n n d.) n

1 n !

2 n x

2 n a.) f ( x )

1

1

6 x b.) f ( x )

  x

 sin x c.) f ( x )

  xe

 x

2

3. Find the first four nonzero terms and the general term of the Taylor series. d.) a.) f ( x )

1

3

 x

around a = 2 b.) f ( x )

 x

3 

2 x

2 f ( x )

 ln( 1

2 x )

5 around a = –1 c.) f ( x )

1

around a = 3 d.) f ( x )

 sin x around a =

 x

4. Determine if the series converges absolutely, converges conditionally, or diverges. Give reasons for your answers. a.) n

1

(

1 ) n n b.) n

1 ln n n

3 c.) n

2 n (ln

1 n )

2 d.) n

1

(

1 ) n

( n

2

2 n

2 

1 ) n

1 e.) n

1

2 n

3 n n n f.) n

1

1 n ( n

1 )( n

2 )

7.

5. Find the sum of the series. a.) n

3

4 n

2 

1

8 n

3 b.) n

1

4

5

7

 n

1

6. Let P

4

( x )

7

3 ( x

4 )

5 ( x

4 )

2 

2 ( x

4 )

3 

6 ( x

4 )

4 be the Taylor polynomial of order 4 for the function f at x = 4 . Assume f has derivatives for all orders for all real numbers. a.) Find f(4) and f’’’(4)

. b.) Write the second order Taylor polynomial for f’

at x = 4 and use it to approximate f’(4.3)

. c.) Write the fourth order Taylor polynomial for g ( x )

 x

4 f ( t ) dt at x = 4 . d.) Can the exact value of f(3) be determined from the information given? Justify your answer.

Answers to problems

1. a.) ROC = ∞

IOC = all real #

Converges absolutely for all real #

Converges conditionally none (since converges absolutely for all real #) c.) ROC = ∞

IOC = all real #

Converges absolutely for all real #

Converges conditionally none (since converges absolutely for all real #) b.) ROC = 3

IOC = [–7, –1]

Conv. abs. (–7, –1)

 notice not at endpts.

Conv. cond. At x = –7 d.) ROC = 0

IOC = x = 0 only

Conv. abs. x = 0

Conv. cond. None

2. a.) n

0

( 6 n x ) b.) n

1

(

1 ) n

( 2 x

2 n

1 n

1 )!

c.) n

0

(

1 ) n x

2 n

1 n !

3. a.) 1

1

c.)

3

d.)

( x

( x

1

9

( x

 

2 )

3 )

)

( x

1

3 !

( x

1

27

2 )

2

( x

 

)

3

...

3 )

2

( x

1

5 !

( x

1

81

( x

2 ) n

)

5

3 )

3

...

1

7 !

( x

 b.)

(

1 ) n

2

7 ( x

 x

3

 n

3 n

1

1 )

)

7 

...

(

1 ) n

1

5 ( x

1 )

2

( x

( 2 n

)

2 n

1

1 )!

d.)

( x

1 )

3 n

1

(

1 )

( 2 x ) n

...

0 n

4. a.) Conditionally convergent (Alternating series test…does not converge absolutely because of p-series test)

b.) Absolutely convergent (Direct Comparison Test with 1/n 2 )

c.) Absolutely convergent (Integral Test)

d.) Divergent (n th term test)

e.) Absolutely convergent (Root Test or Ratio Test)

f.) Absolutely convergent (Direct comparison test with 1/n 3/2 )

5. a.) S = 1/6 b.) S = 14 f ' ' ' ( 4 )

6. a.) Since the constant term is f(4) , f(4) = 7 . Since

 

2 , f’’’(4) = –12 .

3 !

b.) (Take the derivative of the polynomial given) f ' ( x )

 

3

10 ( x

4 )

6 ( x

4 )

2 

24 ( x

4 )

3

. f'(4.3) = –0.54

c.) (Integrate term by term) g ( x )

7 ( x

4 )

3

2

( x

4 )

2

7.

5

3

( x

4 )

3 

1

2

( x

4 )

4

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