instroduction_c_final

advertisement
File:P:\How_NMR_Works
How NMR Works----- Section III
by Shaoxiong Wu 03-5-2010
Let’s start a simplest case, ONE single spin (I=1/2). We have calculated the Energy level ->
EigenValues, with its Hamiltonian Δ€one spin=-γB0Îz with the EigenFunctions: Ψ+1/2=Ψα and Ψ1/2=Ψβ . In previous discussion, we don’t have to know the Eigenfunction in detail. From the
calculation, we are able to find its transitions and Larmor frequency when the spin in the magnet
Bo.
The new idea is: we can construct a new WaveFunction by a linear combination of the
EigenFunctions (we call the pure states such as Ψα Ψβ ). This WaveFunction is still an
EigenFunction the Hamiltonian.
For Example:
Ψ
= 𝐢𝛼 πœ“π›Ό + 𝐢𝛽 πœ“π›½ ----- a new function that is combination of the two EigenFunction.
Δ€one spin Ψ= -γB0Îz (𝐢𝛼 πœ“π›Ό + 𝐢𝛽 πœ“π›½ )
=>-γB0(𝐢𝛼 Îzπœ“π›Ό +𝐢𝛽 Îzπœ“π›½ )
1
1
=>-γB0(2 𝐢𝛼 πœ“π›Ό - (-2 𝐢𝛽 πœ“π›½ ))
1
=> (-γB0) (𝐢𝛼 πœ“π›Ό + 𝐢𝛽 πœ“π›½ )
2
1
1
=>- γB0 Ψ -------- The EigenValue is still - γB0 and the EigenFunction is Ψ. The 𝐢𝛼 π‘Žπ‘›π‘‘ 𝐢𝛽
2
2
are just numbers, but importance of them are able to related to the time late on we
will discuss it. The value (𝐢𝛼 π‘Žπ‘›π‘‘ 𝐢𝛽 ) can be changed with time, or called time
dependent coefficients. The WaveFunction (EigenFunction of the Hamitonian) is
called superposition of states. Or a mixed state of a spin.
If this is understandable, then we have following concept:
According to the principle of quantum mechanics, a spin system consisting of N nuclei, each of spin
(if I = ½) there are 2N spin state functions i.e. φ1, φ2 for N=1, and φ1, φ2, φ3, and φ4 for N=2, etc.
As well as there are 2N wavefunctions that describing the state of all nuclear spins, i.e. ψ1, ψ2 for
N=1 and ψ1, ψ2, ψ3 and ψ4 for N = 2, etc. These wavefunctions can always be described as a
linear combination of these spin state functions φ1, φ2 etc. That become a complete set of basis
functions and it is specified by:
1
File:P:\How_NMR_Works
If I = ½ and only one spin, N=1, there will be two functions --- Eigenfunctions as a complete set:
 2 ο€½ C12οͺ1  C22οͺ 2
1 ο€½ C11οͺ1  C21οͺ2
If I = ½ and two spins, N=2, there will be four functions --- Eigenfunctions as a complete set:
1 ο€½ C11οͺ1  C21οͺ2  C31οͺ3  C41οͺ4
 2 ο€½ C12οͺ1  C22οͺ2  C32οͺ3  C42οͺ4
 3 ο€½ C13οͺ1  C23οͺ2  C33οͺ3  C43οͺ4
 4 ο€½ C14οͺ1  C24οͺ2  C34οͺ3  C44οͺ4
Or we can write a simple way:
2N
 ο€½ οƒ₯ Ckοͺ k
i
k ο€½1
--------i =2N k=1,2,3,4 ….. 2N
Note: In previous section; we write them as Ψ1 π‘œπ‘Ÿ Ψ−1 , Now we changed them a little. But they are same.
2
2
1 ο€½ C11οͺ1 ο€½ 
; οƒŸ Ψ+1/2=Ψα if C 21 = 0 and C11 ο€½ 1
 2 ο€½ C22οͺ2 ο€½ 
; οƒŸ Ψ-1/2=Ψβ if C12 = 0 and C 22 ο€½ 1
where φk are spin EigenFunctions or the EigenStates of the Zeeman Hamiltonian. Since one spin and I= ½,
there are only two possible energy levels, in convention, we write them as α and β state. We now could
write them as:
1
1
𝐼̂𝑧 πœ“π›Ό = + 2 πœ“π›Ό οƒ  𝐼̂𝑧 |𝛼⟩ = + 2 |𝛼⟩
1
1
𝐼̂𝑧 πœ“π›½ = − 2 πœ“π›½ οƒ  𝐼̂𝑧 |𝛽⟩ = − 2 |𝛽⟩
Μ‚π‘œπ‘›π‘’ 𝑠𝑝𝑖𝑛 πœ“ 1 = −𝛾𝐡0 𝐼̂𝑧 πœ“ 1 οƒ  = −𝛾𝐡0
That is the same as we wrote before: 𝐻
+
+
2
2
1
2
Δ§πœ“+1 then
2
1
1
𝐼̂𝑧 πœ“+1 = Δ§πœ“+1 or 𝐼̂𝑧 πœ“π›Ό = Δ§πœ“π›Ό remove the Δ§, π‘“π‘œπ‘Ÿ π‘ π‘–π‘šπ‘π‘™π‘’π‘Ÿ π‘€π‘Ÿπ‘–π‘‘π‘–π‘›π‘”.
2
2
2
2
From now on, we use |𝛼⟩ π‘Žπ‘›π‘‘ |𝛽⟩ for I=1/2 spin. Before we continue, I would like to bring up two
properties of these WaveFunctions: Just remember them, do not have to know why now.
2
File:P:\How_NMR_Works
Normalization: βŸ¨π›Ό|π›ΌβŸ© =1 or βŸ¨π›½|π›½βŸ©=1
in Math, we may write this way: ∫ πœ“π›Ό ∗ πœ“π›Ό =1
Orthogonality: βŸ¨π›Ό|π›½βŸ© =0 or βŸ¨π›½|π›ΌβŸ©=0
Now let’s use above sample to calculate it is normalized or not:
Ψ = 𝐢𝛼 πœ“π›Ό + 𝐢𝛽 πœ“π›½
can be rewritten as |Ψ⟩ = 𝐢𝛼 |𝛼⟩ + 𝐢𝛽 |𝛽⟩ its complex
conjugated function of |Ψ⟩ 𝑖𝑠 ⟨Ψ| = 𝐢𝛼∗ |𝛼⟩ + 𝐢𝛽∗ |𝛽⟩, note the bra-ket has different
direction. If we could approve ⟨Ψ|Ψ⟩ = 1 then they are normalized.
⟨Ψ|Ψ⟩ =[𝐢𝛼∗ |𝛼⟩ + 𝐢𝛽∗ |𝛽⟩][ 𝐢𝛼 |𝛼⟩ + 𝐢𝛽 |𝛽⟩]
=>𝐢𝛼∗ 𝐢𝛼 βŸ¨π›Ό|π›ΌβŸ© + 𝐢𝛼∗ 𝐢𝛽 βŸ¨π›Ό|π›½βŸ©+𝐢𝛽∗ 𝐢𝛼 βŸ¨π›½|π›ΌβŸ©+𝐢𝛽∗ 𝐢𝛽 βŸ¨π›½|π›½βŸ©
=>𝐢𝛼∗ 𝐢𝛼 + 𝐢𝛽∗ 𝐢𝛽 --- since the other two terms are zero [βŸ¨π›Ό|π›½βŸ© =0 or βŸ¨π›½|π›ΌβŸ©=0].
The result is not zero!!! So the WaveFunction is not normalized. To normalize this
function we have to dividing the function by:
∗
∗
√𝐢𝛼 𝐢𝛼 + 𝐢𝛽 𝐢𝛽 That is:
|Ψ⟩ =
𝐢𝛼 |𝛼⟩ + 𝐢𝛽 |𝛽⟩
∗
√𝐢𝛼∗ 𝐢𝛼 +𝐢𝛽 𝐢𝛽
This will be a normalized WaveFunction if we do the calculation
again as above.
⟨Ψ|Ψ⟩ =[𝐢𝛼∗ |𝛼⟩ + 𝐢𝛽∗ |𝛽⟩][ 𝐢𝛼 |𝛼⟩ + 𝐢𝛽 |𝛽⟩]/ [𝐢𝛼∗ 𝐢𝛼 + 𝐢𝛽∗ 𝐢𝛽 ]=1
So these new WaveFunctions that are linear combined by original WaveFunctions
can be normalized by multiple a constant.
####################################################################
3
File:P:\How_NMR_Works
Fact: In NMR calculation, the value of 𝐢𝛼 π‘Žπ‘›π‘‘ 𝐢𝛽 are change with time (such as after RF
pulse or during the RF pulse). But the value of [𝐢𝛼∗ 𝐢𝛼 + 𝐢𝛽∗ 𝐢𝛽 ] remains constant, no matter at
what kind of pulses and directions. The value of 𝐢𝛼 π‘Žπ‘›π‘‘ 𝐢𝛽 only affect our scale of the result.
So we just concede they were chosen to be equal ONE----- normalized.
4
Download