inverse coefficient

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Finite Math B
Chapter 2 MATRICES
1
Chapter 2 – Part 2
MATRICES
A: Augmented Matrices and Row Operations
(Lessons 2.2 pg 68 - 70)
Augmented Matrices
Suppose you are given a system of
equations such as:
The system can be written as a matrix:
2
1

 1
2x  y  z  2
x  3y  2z  1
x yz 2
1
3
1
1
2
1
2
1 
2 
To separate the coefficients of the variables from the constants after the equals signs, we draw in a vertical line
in the matrix. This is called an augmented matrix.
Example 1: Write an augmented matrix for each system of equations. Do not solve.
a)
3 x  4 y  2
8x  y  4
c)
2 x  3 y  5 z  12
3x  4 z  15
x yz 5
b)
5 x  25
x  4 y  10
Example 2: Write the system of equations associated with each augmented matrix.
a)
1
2

3 6 
3 10 
b)
3
 2

 0
1
1
4
0 5
9 10 
1 8 
Finite Math B
Chapter 2 MATRICES
2
(example 2 continued…. Write the system of equations associated with each augmented matrix)
1

c)  0
 0
0
1
0
0
0
1
3
5 
4 
1
d) 
0
0
1
4 
5 
In algebra, our goal when faced with a system of equations is to find a solution for x, y, and z that makes the
system of equations true.
Note that when you see this pattern:
1
0

 0
0
1
0
0
0
1
#1 
#2 
#3 
x  #1
You end up with y  #2
z  #3
(1’s on main diagonal, 0’s elsewhere, constants last column)
Row Operations
We will be using “Row Operations” to manipulate matrices to help us solve systems of equations.
What you are allowed to do:
1. INTERCHANGE TWO ROWS
2. MULTIPLY THE ELEMENTS OF A ROW BY A NONZERO REAL NUMBER
3. ADD A NONZERO MULTIPLE OF THE ELEMENTS OF ONE ROW TO THE CORRESPONDING ELEMENTS OF A
NONZERO MULTIPLE OF SOME OTHER ROW.
Example 3: Use the indicated row operations to change each matrix.
a) Interchange R1 with R2.
0 4 2 1 


1 1 1 2 
6 6 0 9 
Finite Math B
Chapter 2 MATRICES
(Example 3 continued: Use the indicated row operation to change each matrix)
b) Replace R3 by
1
3
R3 .
1 3 2 1 


0 1 1 2 
6 6 3 9 
c) Replace R2 with (-2)R1 +R2
3
6

 1
1
5
3
4 1 
0 2 
4 5 
d) Replace R3 with (-3)R2 + 5R3
3
0

 0
1
5
3
4 1 
0 2 
4 5 
e) Replace R1 with (-2)R3 + 3R1
1
0

 0
0
5
0
4
7
6
7
2 
24 
f) Replace R2 with (-7)R3 + 6R2
1
0

 0
0
5
0
4
7
6
7
2 
24 
g) Replace R2 with (-1)R1 +4R2
4
1

 6
3 3 7 
1 7 2 
4 6 2 
3
Finite Math B
Chapter 2 MATRICES
4
B: Gauss-Jordan Method for Solving Systems of Equations
(Lesson 2.2 , textbook pg 70 – 80)
x  y  5 z  6
3 x  3 y  z  10
x  3y  2z  5
Problem: Find the solution to a system of equations like
Strategy:
1. Write the system of equations as an augmented matrix
2. Use Row Operations to transform the matrix into a matrix with whole numbers on the main diagonal, but 0’s
elsewhere.
3. Use Row Operations to transform the matrix into an “identity” matrix.
(1’s on diagonal, 0’s elsewhere)
4. Final solution = numbers in the “answer” column of the matrix.
Example:
1 0 3

1
0 1 5 
Example:
Meaning:
1 0 0 4 


0 1 0 2 
0 0 1 3 
Meaning:
Make it happen: GAUSS-JORDAN
Your Goal:
1 0 0 # 
1 0 # 


 0 1 #  or  0 1 0 # 


 0 0 1 # 
Using legal row operations:
2x2 System
Clear Col 1
Clear Col 2
# # #
0 # #


3x3 System
Clear Col 1
# # # #
0 # # #


 0 # # # 
# 0 #
0 # #


Create 1’s Main Diag.
1 0 # 
0 1 #


Clear Col 2
Clear Col 3
Create 1’s Main Diag.
# 0 # #
0 # # #


 0 0 # # 
# 0 0 #
0 # 0 #


 0 0 # # 
1 0 0 # 
0 1 0 #


 0 0 1 # 
Finite Math B
Chapter 2 MATRICES
Example 1 : Use the Gauss-Jordan Method to solve each system of equations
a)
2 x  4 y  2

3 x  5 y  0
b)
3x  4 y  1

5 x  2 y  19
c)
x  2 y  2

3 x  6 y  5
5
Finite Math B
Chapter 2 MATRICES
(Example 1 continued): Use the Gauss-Jordan Method to solve each system of equations
d)
x yz 3
2x  3y  7z  0
x  3 y  2 z  17
6
Finite Math B
Chapter 2 MATRICES
(Example 1 Continued): Use the Gauss-Jordan Method to solve each system of equations
2x  5 y  4z  8
e)
2x  2z  4
x  2 y  z  2
7
Finite Math B
Chapter 2 MATRICES
(Example 1 Continued): Use the Gauss-Jordan Method to solve each system of equations
f)
x  y  5 z  6
3 x  3 y  z  10
x  3y  2z  5
8
Finite Math B
Chapter 2 MATRICES
9
C: Matrix Inverses
(Lessons 2.5 pg 107-111)
Additive Inverse Vs Multiplicative Inverse
For numbers, algebraic expressions, and matrices “zero” or the “zero matrix” plays the role of the
Additive Identity. The sum of a value and the additive identity is the original value, unchanged.
144  0 
 3 5 0 0 
 6 2   0 0  

 

3 x  0 
If A and B are additive inverses then their sum gives you the additive inverse value, then A + B = 0
Examples of Additive Inverses:
144 +
=0
-3x +
=0
 3 5 
 6 2  +


0 0 
= 

0 0 
For numbers and algebraic expressions, 1 plays the role of the Multiplicative Identity. For matrices, the
“Identity Matrix” is the Multiplicative Identity. The product of the a value and the multiplicative identity is the
original value, unchanged.
 3 5 1 0 
 6 2   0 1 

 

3 x  1 =
144 x 1 =
If A and B are Multiplicative Inverses then their product gives you the multiplicative inverse value,
then A x B = 1
Examples of Multiplicative Inverses:
144 x
=1
3x 
=1
 3 5
 6 2   ????


1 0 
= 

0 1 
Finding a multiplicative inverse for a matrix is more challenging than just reciprocating each value in the matrix
due to the unique ROWS x COLUMNS requirement of multiplying matrices.
Finite Math B
Chapter 2 MATRICES
10
Terminology/Facts






Only a square matrix can have a multiplicative inverse.
If A is your given matrix, then A1 is the multiplicative matrix.
I is the identity matrix.
The identity matrix I is a square matrix with 1’s on the main diagonal and 0’s elsewhere
A  A1  I
A I  A
Example 1: Decide whether the given matrices are inverses of each other. (Check to see if their product is the
identity matrix I )
 2 1
 3 1
and 
a) 


 5 3
 5 2 
2 6
 1 2 
and 
b) 


2 4
 2 4 
1 3 3 
 7 3 3 
1 4 3  and  1 1 0 
c) 



1 3 4 
 1 0 1 
Finding the Multiplicative Inverse of a Matrix
 A I 
Step 2: Perform row operations to get the matrix in the form  I B  if possible.
Step 3: Matrix B is A1
Step 1: Form an augmented matrix that looks like
Finite Math B
Chapter 2 MATRICES
Example 2: Find the multiplicative inverse of each matrix
a)
1 1
2 0 


b)
 3 1
 5 2 


 1 3 
c) 

 2 6 
11
Finite Math B
Chapter 2 MATRICES
(Example 2 continued) : Find the multiplicative inverse of each matrix
d)
 1 1 1
4 5 0


 0 1 3
1 2 3


e)  3 2 1
 1 0 1 
12
Finite Math B
Chapter 2 MATRICES
D: Using Matrix Inverses to Solve Systems of Equations
(Lessons 2.5 pg 111-115)
Any system of equations can be written as AX  B
where A  the square coefficient matrix
X  the column matrix of the variables
B  the matrix of constants
Example:
2 x  5 y  15
x  4y  9
Solving A System of Equations Using the Inverse Method
1. Find the A1 , the inverse of the coefficient matrix
2. Multiply A1  B
3. Check your answers
Example 1: Solve each system of equations by using the inverse of the coefficient matrix.
a)
2 x  5 y  15
x  4y  9
13
Finite Math B
Chapter 2 MATRICES
14
(Example 1 Continued): Solve each system of equations by using the inverse of the coefficient matrix.
b)
2 x  7 y  14
3x  4 y  8
x  y  z  1
c) 4 x  5 y  2
y  3z  3
We already found the inverse of this matrix in exercise 2d on page 12. Go back and copy that answer here:
Finite Math B
Chapter 2 MATRICES
15
(Example 1 continued): Solve each system of equations by using the inverse of the coefficient matrix.
x  2 z  1
d) y  z  5
 x  y  8
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