ME 362
Conservation Laws
Page 1 of 2
Conservation of Mass:
dm
min mout
dt CV
Rate of change of mass in C.V. = Mass flow rate into C.V. – Mass flow rate out of C.V.
n̂
m V nˆ dA AVn
Mass flow rate:
A
dA
V
Vn V nˆ
where A is the surface area of C.V. that flow passing through
Vn is the component of flow velocity ( V ) normal to area A
Conservation of Momentum:
d mV
mV
mV
dt
in
out
F
CV
where
F F
applied
Fpressure Fshear Fgravity
Rate of change of momentum in C.V. = Momentum flow rate into C.V. – Momentum
flow rate out of C.V. + Forces applied to C.V. (e.g., gravity force, friction force etc.)
Momentum flow rate:
mV
Note: m is a scalar (magnitude) and V is a vector (magnitude and direction)
x-momentum flow rate = m u
y-momentum flow rate = m v
+ or – depends on the flow direction
and the coordinate system
For example,
V
Mass flow rate: m AV
x-mom flow rate = mVx m V cos
Vx
Vy
y-mom flow rate = mVy m V sin
y
x
Note: the velocity is in the negative
y-direction
ME 362
Conservation Laws
Page 2 of 2
Assumptions:
Incompressible
applies to liquid flows or low speed gas flows
and are constant
Steady flow
d
0 (properties inside the C.V. do not change in time)
dt
Neglect gravity
Fgravity 0
Neglect viscous
Fshear 0
Neglect pressure
Fpressure 0
(applicable when entire C.V. is exposed to
atmospheric pressure only)
Apply above assumptions to the governing equations of mass and momentum yields,
Conservation of mass:
m in m out
V ) out (m
V ) in
Conservation of momentum: F (m