SPH4U1: ENERGY & MOMENTUM LESSON 7 – Conservation of Momentum Law of Conservation of Linear Momentum If the net force acting on a system of interacting objects is zero, then the linear momentum of the system before the interaction equals the linear momentum of the system after the interaction. NOTE: A system represents all of the objects involved in a collision. If the net external force on all objects as a group is zero, we say the system is isolated or closed. Let’s use Newton’s third law to come up with an equation for this: Therefore, for 2 solid objects colliding, the conservation of momentum can be written as m1v1i m2 v2i m1v1 f m2 v2 f This can easily be split into components so that just the horizontal and/or vertical aspects can be analyzed. m1v1ix m2 v 2ix m1v1 fx m2 v 2 fx and m1v1iy m2 v 2iy m1v1 fy m2 v 2 fy EX 1: A shell of mass 7.0kg leaves the muzzle of a cannon with a horizontal velocity of 490m/s [right]. Find the recoil velocity of the cannon if it’s mass if 700kg. SPH4U1: ENERGY & MOMENTUM LESSON 7 – Conservation of Momentum ELASTIC and INELASTIC COLLISIONS Conservation of momentum can be applied to many collisions but there are two basic types of two-particle collisions that always conserve momentum. The typical situation in momentum conservation involves two particles in the initial system with one or both having a velocity. These two particles collide where again only internal forces act and the particles separate with certain final velocities. Conservation of momentum enables us to relate the final velocities to the initial velocities. The two basic types of collisions are: 1) Elastic Collisions 2) Inelastic Collisions 1) Elastic Collisions An elastic collision is one in which the total kinetic energy of the two particles is the same after the collision as it was before the collision. Examples of elastic collisions are those between billiard balls, between masses and springs, and those involving rubber or tennis balls. For elastic collisions one can write not only the momentum conservation equation, but also a kinetic energy conservation equation: m1v1i m2 v2i m1v1 f m2 v2 f (Momentum conserved) 1 2 1 2 1 2 1 2 m1v1i m2 v2i m1v1 f m2 v2 f (Kinetic Energy conserved) 2 2 2 2 By combining these two equations one can achieve the general result that v1i v 2i v1 f v 2 f The relative velocity of approach is the negative of the relative velocity of separation. SPH4U1: ENERGY & MOMENTUM LESSON 7 – Conservation of Momentum 2) Inelastic and Perfectly Inelastic Collisions If there are very strong frictional and deformation forces, then kinetic energy will no longer be conserved and instead we will have an inelastic collision. The limiting case of an inelastic collision is one in which the two particles fuse during the collision, and travel together afterwards with the same final velocity. v1 f v 2 f v f (Perfectly Inelastic Collision) m1v1i m2v2i m1v f m2v f m1 v1i m2 v 2i vf m1 m2 (Particles with same final velocity) (Perfectly Inelastic Collision) EX 2: Two billiard balls have velocities of 2.0m/s and -0.5 m/s before they meet in a head on collision. What are their final velocities? NOTE: In equal mass elastic collisions in one dimension, the masses simply exchange velocities. In equal mass, one dimensional elastic collisions with the first particle at rest, the second particle stops and the first particle goes forward with the original velocity of the second particle. SPH4U1: ENERGY & MOMENTUM LESSON 7 – Conservation of Momentum EX 3: A Cadillac with a mass of 1800 kg, while stopped at a traffic light, is rear ended by a Volkswagen with a mass of 900 kg traveling at 20 m/s. After the collision both cars are completely entangled, and slide into the intersection. What is their velocity after the collision? HMWK: Pg. 243 #4-8 Pg. 245 #6-10, Pg. 253 #4-7