Level 1 Geometry Review 7: Angles and Polygons Polygon angle formulas - Let n = the number of sides in a polygon. The sum of the interior angles in any n-gon: (n – 2) 180 ( n 2)180 One interior angle in a regular n-gon: n The sum of the exterior angles in any n-gon: 360 360 The measure of an exterior angle in a regular n-gon: n _______________________________________________________________________ 1. Define a regular polygon. 2. What is the sum of the interior angles of a 40 sided polygon? 3. Given the angles shown in this polygon, find the value of x. 119 105 2x 3x 2x 90 4. Given a regular 90-gon how large is each exterior angle? 5. What is the size of each interior angle of a regular dodecagon (12 sided polygon)? 6. Suppose a regular polygon has exterior angles of size 0.5º. How many sides are there? 7. Suppose a regular polygon has each interior angle of size 170º. How many sides are there? 8. Suppose a polygon’s interior angles add to 7200º. How many sides are there? 9. True or false? A polygon’s interior angles can add up to 1970º. 10. In a regular polygon each interior angle is 170º larger than each exterior angle. How many sides are there? 11. The supplement of an angle is 6.5 times as large as the angle. Find the angle. 12. The angles of a triangle are in the ratio of 5:5:6. Find the angles. 13. The complement of an angle is 22º more than the angle. Find the angle. 14. Twice the supplement of an angle is 230º. Find the angle. 15. Half the complement of an angle when added to one quarter of the angle makes 32.5º. Find the angle and its complement. 16. Two sides of a triangle are of lengths 5 and 14. What are all the possible lengths for the third side? Level 1 Geometry Review 8: Congruent Triangles 1. 2. 3. 4. 5. 6. 7. 8. 9. Vertical angles are congruent. Base Angles Theorem – If 2 sides of a triangle are congruent, then the opposite angles are congruent. And its converse – If 2 angles of a triangle are congruent then the opposite sides are congruent. Proving triangles congruent: ASA, SAS, SSS, AAS, and HL Properties of parallelograms Opposite sides are parallel Opposite sides are congruent Opposite angles are congruent Diagonal bisect each other Properties of rectangles All properties of a parallelogram All angles are right. Diagonals are congruent. Properties of a rhombus All properties of a parallelogram All sides are congruent. Diagonals are perpendicular. Diagonals bisect opposite angles. Properties of a square All properties of a rectangle All properties of a rhombus Properties of an isosceles trapezoid One pair of opposite sides parallel Legs are congruent. Base angles are congruent. Diagonals are congruent. Besides the properties, you can prove that a quadrilateral is a parallelogram by proving that one pair of opposite sides are both congruent and parallel. Problems. 1. Given: ACDF is a parallelogram. AFB = ECD E F D Prove: FBCE is a parallelogram. A AC AR C A 2. Given: AC BK C K Prove: BARK is a parallelogram. B C B R K 3. Given: NRTW is a parallelogram. NX TS W WV PR V T X Prove: XPSV is a parallelogram. S N 4. Given: RSOT is a parallelogram. MS TP P R P R T Prove: MOPR is a parallelogram. S M O 5. Given: AB AC Prove: 1 2 A 2 1 B 6. Given: KRM PRO C R KR PR Prove: RM RO K 7. M SX TY P O R Given: WX YZ SW TZ Prove: RW RZ T S W X Y Z 8. PR ST N V Given: NP VT P T Prove: W ∆WRS is isosceles. P 9. Given: FG JH FGH JHG S R F T J K Prove: ∆FKJ is isosceles. G H Level 1 Geometry Review 9 1. A coordinate proof. X (0, b) Given: any isosceles triangle, positioned cleverly as shown. Show that the medians of XYZ from Y and Z are congruent. Reminders: A median is a line segment from a vertex of a triangle to the midpoint of the other side. Midpoint formula: x x y y 1 2 2 , 1 2 2 Distance formula: (x1 x2 )2 (y1 y2 )2 Z (-a, 0) Y (0, 0) (a, 0) 2. Given: BED BDE C A BEA BDC B AE CD Prove: A C D E 3. Given: AB AC A AD AE E D Prove ∆FBC is isosceles F B C Level 1 Geometry Review 4 The following are valid reasons for proving that two triangles are congruent: ASA, AAS, SAS, SSS, HL. Other reasons are not enough: AAA, SSA 1. In each diagram state why the triangles are congruent or write “NN” (not necessarily congruent). Pay no attention to the appearance of the triangles, only the facts given. a. b. d. g. 2. Given: AB = CD. AX BD. CY BD. BX = DY. c. e. f. h. i. A B X Prove: ABCD is a parallelogram. Y D C 3. Find the value of x. a. 20º xº 48º b. 19º xº 4. Given: AO OB D A O AC || BD Prove: ∆AOC ∆BOD B C 5. Find x. a. b. xº 64º 48º xº c. d. 2xº 5xº xº 78º 4xº e. f. 80º xº 58º 39º xº Level 1 Geometry Review 5 a o t h a opposite sin( x) hypotenuse s Hypotenuse Opposite X Adjacent o h c cos(x) adjacent hypotenuse tan( x) opposite adjacent Examples: 140 x x cos(18º ) 140 140 x cos(18º ) x 147.2 130 tan( x) 275 130 x tan 1 ( ) 275 x 25.3º cos(18º ) x 18 140 130 xº 275 Problems: 1. How high is the tree? 2. Find the height of this parallelogram and then its area. 22 81º 15 height = area = 40 244 ft. 3. Find all missing sides and angles. Note that the third side can be found by the Pythagorean Theorem or trig. x= y= z= y x 12 z 77 4. While watching a spaceship take off you hear on the radio that it is 14 miles in the air. You have to look up at an angle of 86º to see it. How far from the blastoff position are you? rocket 14 mi. 86 x 5. Given P, find the area of the shaded segment. 6. Find the perimeter of the triangle. 16 25º 70 Area of sector = Area of triangle = Area of segment = 7. Find the area of this regular pentagon by dividing it into triangles from the center. P 20 8. Without a calculator, tan(45º) = you should be able to find these values by cos(60º) = drawing and labeling familiar triangles. sin(45º) = 83 25º Level 1 Geometry Review 6 Area, Surface Area, Volume 1. Find the shaded area. 17 10 10 2. Find the shaded triangular area. 8 5 6 3. This figure is a parallelogram. Find length x. 12 135 10 Area = 195 sq. units x 4. In each figure congruent circles just fit in congruent squares with sides of length 20. For each one find the percentage of the square’s area occupied by the circles. 20 Explain your result. 5. Find the sector area. 12 80º 6. This is a semicircle. Its perimeter is 65. What is its radius? 20 20 7. A cylinder has a base area of 25π square inches and a volume of 375π cubic inches. Base radius = Altitude = Lateral area = 8. A cone has a volume of 1500 cubic inches. The altitude is equal to the diameter of the base. Altitude = 9. A right prism has a right triangular base. The legs of the base are 21 and 28 and the altitude of the prism is 25. Volume = Total surface area = 21 25 28 10. x= 116º y= 2x+10 29y 11. x= 3x+4y 50 y= 5x 12. x= x y= 2y 4x+y Level 1 Geometry Review 1 Conditional or If-Then statements. Suppose a certain statement “If P then Q” is true. Original statement: If p then q. (pq) Suppose this is true. Converse: If q then p. (qp) This is not necessarily true. Inverse: If not p then not q. (~p~q) This is not necessarily true. Contrapositive: If not q then not p. (~q~p) Always true if the original statement is true. _______________________________________________________________________ 1. Assume this statement is always true: If you bang your head against the wall you will get a headache. a. Make a Venn diagram for this situation. b. Write the converse and state whether it is necessarily true. c. Write the inverse and state whether it is necessarily true. d. Write the contrapositive and state whether it is necessarily true. e. Joe Max banged his head against the wall. Put Joe Max in the diagram (possibly in more than one place) and draw any conclusion you can about him. f. Ozzie has never had a headache. Put Ozzie in the picture, wherever possible, and draw any conclusion you can. g. Latrice has a headache. Place her and draw a conclusion if you can. h Charmaine has never banged her head against the wall. Place her and conclude what you can. 2. Assume the following to be always true statements: A watched pot of water never boils. To be able to cook spaghetti you must boil a pot of water. Determine whether the following are always true, always false or neither. a. If you are cooking spaghetti you did not watch the pot. b. If you don't watch a pot of water, it will boil. c. If you boil water you can cook some spaghetti. d. If you are boiling water you did not watch the pot. Circle theorems: C A 2X D X B x r 76º Area of a sector of angle x in a circle of radius r: x A= š r2 360 95ª 85º 104º 3. Find the radius of the circle. 4. Find the radius. 16 7 A C 2 5 5 D B 5. Two concentric circles have radii of 17 and 7. The chord is tangent to the small circle. What is its length? 6. C is the center of this circle and the triangle is inscribed in it. Find the size of angle X. 7. Find the missing angles and arcs. 50º X C 8. Find angle X. X 42º 28º 172º Level 1 Geometry Review 2 128º 1. An architect is designing a house and builds a scale model. The model is 2 feet high and the house will be 24 feet high. How do the heights of the front doors compare, the floor areas of the master bedrooms compare, and the volume of the attics compare in the model to the actual house? 2. Three regular polygons surround a point. How many sides has the largest polygon? 3. Find x. 150º xº 4. A sphere just fits in a cube whose sides are of length 10. What percentage of the cube’s volume is occupied by the sphere? 10 Level 1 Geometry Review 3 1. Coordinate transformations. Be prepared to recognize TRANSLATIONS, ROTATIONS, REFLECTIONS and combinations like GLIDE REFLECTIONS. For each problem: i. Transform each figure according to the transformations given by applying them to the vertices of the figure and then connecting the new vertices. Draw the new figure on the same graph. Here’s the notation: x1 is the starting x –coordinate of a point. x2 is the x-coordinate of the point after the transformation. y1 is the starting y –coordinate of a point. y2 is the y-coordinate of the point after the transformation. ii. Describe the transformation in words using the terminology above, if it applies. FOR TRANSLATIONS SPECIFY HOW FAR AND IN WHAT DIRECTION. FOR ROTATIONS SPECIFY THE CENTER AND ANGLE TURNED. FOR REFLECTIONS SPECIFY THE LINE OF REFLECTION. 6 a. x2 x1 5 y2 y1 3 4 Describe the transformation. 2 -10 -5 5 10 -2 -4 -6 6 b. x2 x1 y2 2 y1 4 Describe the transformation. 2 -10 -5 5 -2 -4 -6 10 6 c. 1 x1 2 y2 4y1 x2 4 2 Describe the transformation. -10 -5 5 10 -2 -4 -6 d. x2 y1 y2 x1 6 B 4 A C D Describe the transformation. 2 E -5 5 -2 -4 -6 e. x2 x1 y2 6 y1 6 B 4 Describe the transformation. A C D 2 E -5 5 -2 -4 -6 Tools of analytic geometry. Given two points (x1, y1 ) , (x2 ,y 2) : Distance formula: Midpoint formula: Slope formula: D (x1 x2 )2 (y1 y2 )2 x x 2 y1 y 2 M 1 , 2 2 y y m 2 1 Parallel lines have equal slopes. x 2 x1 Perpendicular lines have opposite reciprocal slopes. 1. Here are the vertices of a triangle: A(2, -6), B(12, 18), C(-10, -1). Calculate the slopes of the three sides. mBC m AC m AB Why is the triangle a right triangle? Which is the right angle? Find the area of the triangle by any method you choose. Show your work. 2. Show that triangle PDQ is isosceles but not equilateral: P(1, 6), D(7, -1), Q(-1, -3). 3. A circle has a diameter AB with A( -1, 2) and B( 23, 9). a. Find the center of the circle. Center: ( b. Find the radius of the circle: Radius: , ) Level 1 Geometry Review Answers Review 7: 1. A regular polygon is a polygon with all sides congruent and all angles congruent. 2. 6840 3. 58 4. 4 5. 150 6. 720 sides 7. 36 sides 8. 42 sides 9. False 10. 72 sides 11. 24 12. 56.25, 56.25, 67.5 13. 34 14. 65 15. 50, 40 16. 9<x<19 Review 8: 1. 1. Givens 2. AF CD opp. sides 3. AD opp s 4. AFBDCE ASA 5. AB ED CPCTC 6. FD AC opp sides 7. FE BC Subtraction 8. FB EC CPCTC 9. FBCE is a p-gram two pr of opp sides 2. 3. 1. Givens 2. AR BK Transitive 2. CARC Base Angles 3. ARCK transitive 4. AR || BK Corr. Angles Thm 5. BARK is a p-gram one pr of opp sides and || 1. Givens 2. NW RT WT NR opp sides of p-gram 3. XW RS VT NP subtraction 4. WR NT opp s 5. XNPSTV WXVRSP SAS 6. XV PS XP VS CPCTC 7. XPSV is a p-gram opp sides of a p-gram 4. 1. Givens 2. SO RT RS TO opp sides 3. RS || TO RT || SO opp sides || 4. RSTSTO RTSTSO alt. int. s 5. RSMOTP MSOPTR Supp are 6. RSMOTP MSOPTR SAS 7. RM PO RP MO CPCTC 8. MOPR is a p-gram opp sides of a p-gram are 5. 6. 7. 8. 1. 1. 1. 1. 5. 9. 1. Givens 2. GH GH Reflexive 3. FGHJHG SAS 4. FH GJ JGH FHG CPCTC 5. GK KH CITT 6. FK KJ Subtraction 7. FKJ is isosceles Def. of isosceles Givens 2. ABCACB Base Angles 3. 12 supp. of are Givens 2. KP Base Angles 3. RKMRPO ASA 4. RM RO CPCTC Givens 2. SWXTZY SSS 3. WZ CPCTC 4. RW RZ CITT Givens 2. RS RS Reflexive 3. PS RT Addition 4. NPSVTR SAS WRSWSR CPCTC 6. WR WS CITT 7. WRS is isosceles Def of isosceles Review 9: 1. See me for solution 2. 1. Givens 2. BE BD CITT 3. AEBCDB SAS 4. AC CPCTC 3. 1. Givens 2. DB EC Subtraction 3. ABCACB ITT 4. BC BC Reflexive 5. DBCECB SAS 6. DCBEBC CPCTC 7. FB FC CITT 8. FBC is isosceles Def of isosceles. Level 1 Geometry Review Answers Review 4: 1. a. SSS b. AAS c. AAS d. NN e. ASA or AAS f. AAS g. SAS h. NN i. HL 2. 1. Givens 2. CDYABX HL 3. YDC XBA CPCTC 4. AB||DC If alt. int. s , lines are || 5. ABCD is a p-gram One pr of opp sides are and || 3. a. 68 b. 57 4. 1. Givens 2. CAODBO If || lines, alt. int. 3. AOCDOB vertical s 4. AOCBOD ASA 5. a. 48 b. 64 c. 26 d. 20 e. 58 f. 80 Review 5: 1. 204.74 feet 2. height = 14.82 area = 325.94 3. x = 13, y = 51.98, z = 53.34 4. 0.979 miles 5. Area of sector = 49.8, Area of triangle = 120.28, Area of segment = 49.8-120.8 6. 174.58 7. 688.19 2 1 8. a. 1 b. c. 2 2 Review 6: 1. 85 5. 32 8. 17.89 in 10. x = 27, y = 4 2. 6. 9. 11. 33 3. 27.58 4. They are all 78.5% 12.64 7. base radius = 5, altitude = 15, lateral area = 150 volume = 7350, total surface area = 2688 x = 10, y = 5 12. x = 27, y = 45 Level 1 Geometry Review Answers Review 1: 1. a. b. c. d. Venn Diagram If you get a headache, then you banged your head against the wall. Not necessarily true. If you do not bang your head against the wall, you will not get a headache. Not necessarily true. If you do not get a headache, you did not bang your head against the wall. True Joe Max got a headache. Ozzie has never banged his head against the wall. No conclusion possible. No conclusion possible. Always true neither neither Always true e. f. g. h. 2. a. b. c. d. 3. 113 4. 7.25 8 15 5. 65 6. 7. angles - 86, 66 arcs - 56, 132 8. 43 Review 2: 1. front doors: 1:12; floor areas: 1:44; attic volumes: 1:1728 2. 18 sides 3. 120 4. 52.3% Review 3: Transformations: 1a. translation 3 up and 5 to the left 1b. reflection over the line y=-1 1c. ? 1d. reflection over the line y= x 1e. rotation about (0 , 3) Coordinates: 12 19 5 m AB ; m BC ; m AC 1. 5 22 12 The triangle is a right triangle because the slopes of 2 of the sides are opposite reciprocals. A is the right angle. Area of the triangle is 169 square units. 2. PD = 49 36 85 DQ = 4 64 68 PQ = 4 81 85 Therefore, it is isosceles because PD = PQ. 3. Center = (11 , 5.5) Radius = 12.5