3/PH/SB Quantum Theory - Dr. P.A. Mulheran - Week 4 THE POSTULATES OF QUANTUM MECHANICS - PART II 4.1 The Measurement Postulate It is clear that if the wave function of a system is an eigenfunction u n of a Hermitian operator Q , then a measurement of the dynamical quantity represented by Q will yield the corresponding eigenvalue q n with probability one. Conversely it is reasonable to expect that if the measurement has resulted in one particular eigenvalue q n , then the wave function of the system following the measurement must be the corresponding eigenfunction u n . This expectation is confirmed in experiments, some of which will be discussed later in this course. However this means that in general measurements are not passive and profoundly disturb the state of a system. If the initial wave function of a system is described as a linear superposition of the eigenfunctions before the measurement, after the measurement it has been “reduced” or “collapsed” to one eigenfunction (assuming that we have performed a perfect ‘noise-free’ experiment and found a definite value for the measured quantity). measure result q n u n This collapse of the wave function is the source of most of the interpretational problems associated with quantum theory, as will be discussed later in the course. However most physicists are pragmatists and accept the fact that this rule works perfectly well in describing the behaviour seen in experiments and they do not worry too much about what it means! P4 The probability of finding the result q n when measuring the dynamical quantity represented by the Hermitian operator Q is | a n | function can be expressed as 2 where the initial wave a n u n , which is a linear superposition of n the eigenfunctions u n of Q . Upon finding the result q n the wave function is reduced to the corresponding eigenfunction u n . 1 3/PH/SB Quantum Theory - Dr. P.A. Mulheran - Week 4 4.2 Links with classical mechanics The development over time of a linear superposition of bound states in a well often helps us see the link to the classical description. For example, consider a particle in a simple harmonic oscillator with the wave function x, t 1 1 3 u 0 x exp i c t u1 x exp i c t 2 2 2 2 1 The probability x, t of finding the particle at position x in the well swings 2 from side to side; in fact <x> oscillates back and forth with the classical frequency of the harmonic oscillator, as you will be asked to show in the workshops. A similar consideration of a linear superposition of states for a Hydrogen atom shows how an oscillating dipole can arise in this system. This helps to explain how light of the correct frequency can excite an atom from its ground state to certain excited states. This form of a linear superposition that includes the time-dependence, generally written as E r, t a n u n r exp i n t , n where Hˆ u n r E n un r , is justified since this wave function satisfies the Time Dependent Schrodinger Equation. Amplitudes can be found at any arbitrary time and interpreted in the usual way as measurement probabilities for the eigenvalues of the Hamiltonian (i.e. the energy levels of the system). These probabilities do not change over time E because the time dependent factors exp i n t have modulus one. This shows that energy is conserved in these systems. Another link with classical Newtonian mechanics can be found by considering the rate of change of the expectation value of momentum in quantum mechanics: Pˆx t V x (This result is an example of the application of the Ehrenfest Theorem). In particular it shows how F=ma is recovered from the quantum mechanical equations when the spatial extent of a wave function is much less than the scale on which the potential energy varies. Thus it appears that quantum mechanics encompasses classical mechanics, so that people believe the quantum theory is the true theory that applies to everything from electrons to footballs and beyond! 2 3/PH/SB Quantum Theory - Dr. P.A. Mulheran - Week 4 WORKSHOP QUESTIONS Hand your solutions to the following questions to Dr. Mulheran at the start of the next-but-one workshop. Some of your solutions will be marked as part of the continuous assessment of this course which contributes 20% of the overall module grade. Your solutions must be well presented; untidy work will be penalised. 4.1 A particle is confined to the region [0 < x < L] by walls of infinite potential. It is in the ground state of this well when the wall at x = L is instantaneously moved to a new position at x = 2L. By assuming that the wave function remains unchanged by the movement of the wall, show that the probability of measuring the particle’s energy to be that of the ground state of the wider well is approximately 0.36. [5 marks] Hint: Express the particle’s wave function as a linear superposition of states of the wider well. 4.2 Consider a harmonic oscillator with the time-dependent wave function 1 1 1 3 x, t u 0 x exp i c t u1 x exp i c t , 2 2 2 2 where u0(x) and u1(x) are the n=0 and n=1 eigenfunctions of the Hamiltonian and c is the classical oscillator frequency. (a) Show that the expectation value of the oscillator’s position varies with time as x cos( c t ) . 2 c [3 marks] (b) Compare this to the classical motion of the oscillator when it has total energy given by <E> for the above wave function. [2 marks] Hint: the normalised eigenfunctions are c u 0 x 1 4 c 2 exp x 2 and 1 4 4 c u1 x 3 3 4 c 2 x exp x . 2 3/PH/SB Quantum Theory - Dr. P.A. Mulheran - Week 4 WORKSHOP SOLUTIONS 4.1 The wave function is 2 x , 0 x L sin ( x ) L L 0 otherwise. The ground state wave function of the new well is 1 x , 0 x 2 L sin u1 ( x ) L 2 L 0 otherwise. Expressing (x) as a linear superposition of the energy eigenfunctions of the new well, the amplitude for the first state is given by L 2 x x . sin .dx a1 u1 * ( x ). ( x ).dx sin L L 2L allspace 0 L x 2 3 x dx cos cos 2 L 0 2 L 2 L L 1 2 L 3 x 2 L x sin sin L 2 3 2L 2 L 0 4 2 . 3 Thus probability of measuring the ground state energy is 32 | a1 |2 0.36 . 9 2 4.2a x, t 2 1 2 u 0 x u12 x 2u 0 x u1 x cos c t 2 x x 2 dx 0 0 cos c t xu0 x u1 x dx cos c t 2 c u12 x dx which is the answer given since u1(x) is normalised. 4.2b 1 1 3 c c c . 2 2 2 Classical amplitude A when total energy is all potential, 1 E c2 A 2 2 2 Thus A which is twice the amplitude of <x>. E c 4