1 Phase Transitions Introduction Phase – substance in a form of matter which is homogeneous throughout both in chemical composition and physical state. Transition – a change from one state to another at a characteristic temperature and a given pressure According to the 2nd law, free energy decreases for a spontaneous process. Thus for an arbitrary phase transition , or 0 Consider the chemical potentials of the different forms of water. Below 0 C, the chemical potential of the solid must be lower than the chemical potential of the liquid s l . At 0 C, the chemical potential of the solid is equal to the chemical potential of the liquid s l . Above 0 C, the chemical potential of the solid must be higher than the chemical potential of the liquid s l . Temperature Dependence of Free Energy Recall the Gibbsian relationship for Gibbs free energy (which is true molar quantities also) dG SdT V dp dG d SdT V dp Considering only the temperature change yields d S dT That is, the slope of a vs. T is the negative of the molar entropy. solid liquid Tm T Note the transition temperature occurs when s l . 2 Pressure Dependence of Free Energy A change in the pressure will cause a change in the free energy of a material. dG d SdT V dp d V dp Since the molar volume (inverse of the molar density) is always positive, as pressure increases, the free energy increases. The chemical potential change with pressure is greater with liquids than solids since the molar volume of a solid is usually smaller than the molar volume of a liquid. The greatest change in chemical potential with pressure would be for a gas. Since the changes in chemical potential for each phase are different, the temperatures where the chemical potential for different phases are equal will be different when the pressure changes. Thus melting point and boiling points of substances have a dependence on the external pressure. solid(P2 ) solid(P1 ) liquid (P2) liquid (P 1) Tm (P1) Tm (P2) T 3 Clapeyron Equation Phase diagrams are give the state of a substance at a given temperature and pressure. Since the phase diagram is a plot of pressure and temperature, the boundaries between the phases are specific pressure-temperature relationships for a particular substance. The boundaries between phases are described with the Clapeyron equation. S dT V dp S dT V dp S S dT S dT V dp V dp S dT V V dp S dT V dp dp S dT V Above is the most fundamental version of the Clapeyron equation. We can the Clapeyron equation into another form by remembering that during the phase transition, the free energy is unchanged; therefore, G 0 From the Gibbs-Helmholtz equation we have, H TS S H T Thus the boundaries between the phases (i.e. the pressure dependence of the phase transition temperatures) depend on the molar enthalpy of the phase transition. dp H dT TV We can follow-through by integrating the equation (assuming that enthalpy of the phase transition and the volume are temperature independent). [A reasonable assumption for pressure change of a few bars. dp H 1 dT V T p2 dp p1 H 2 1 dT V T1 T T p2 p1 H T2 ln V T1 Now we will use a clever algebra trick and the Maclaurin series expansion for 1 ln 1 x x x 2 x . 2 H T2 T1 p 2 p1 V T1 This equation is a useful relationship for the description of a solid – solid or the solid – liquid boundary. 4 Clausius-Clapeyron Equation The boundary between the liquid and gaseous phases deserves special attention primarily because of the large difference between the molar volume of a gas and the molar volume of a liquid. We will start with the second version of the Clapeyron equation that we derived. Hg Hl H vap dp H dT TV T Vg Vg T Vg Vg The molar volume of a liquid is very small compared to the molar volume of a gas; therefore, we will assume that the change in the molar volume is the molar volume of the gas. H vap H vap dp dT T Vg Vl T Vg Substituting the ideal gas equation yields, H vap p H vap dp H vap dT T Vg T RT p RT 2 Now the equation will be integrated, assuming that the enthalpy of vaporization is temperature independent. dp H vap p R p1 p2 p 2 H vap 1 1 1 dT ln T2 R T2 T1 p1 T1 H vap 1 1 p ln 2 p R 1 T2 T1 T2 The differential form of the Clausius – Clapeyron can be put into an alternative form with small amount of clever manipulation. First consider the following equalities: 1 d ln p dp p 1 1 d 2 dT T T Now we can use these manipulations to put the Clausius – Clapeyron equation in an alternative (and sometimes more useful) equation. dp p H vap dT RT 2 H vap 1 dp H vap 1 dT d ln p d p R T2 R T H vap d ln p R 1 d T Note that the result allows the plot of logarithm pressure versus inverse temperature to yield a straight line whose slope yields the enthalpy of vaporization. 5 Classification of Phase Transitions 1st Order Transitions 1. Heat capacity at transition temperature is infinite. - 2 T 2 is discontinuous. 2. Derivative of chemical potential w.r.t. temperature at transition temperature is discontinuous. 3. Molar volume, entropy and enthalpy are discontinuous at transition temperature. 4. Phase transition has a specific transition enthalpy. 5. Melting, evaporation and sublimations are first-order transitions. V Ttrans T H Ttrans T Cp Ttrans T Ttrans T 2nd Order Transitions 1. Heat capacity at transition temperature is discontinuous. 2. Derivative of chemical potential w.r.t. temperature at transition temperature is continuous. 3. Molar volume , entropy and enthalpy are continuous at transition temperature. 4. Temperature derivatives of volume and enthalpy are discontinuous at transition temperature. 5. Second-order transitions include glass transitions in polymers, onset of ferroelectricity is perovskite crystals, onset of superconductivity. V Ttrans Ttrans T Cp H Ttrans T Ttrans T T Lambda Transitions 1. Heat capacity at transition temperature is discontinuous. 2. Theoretically, the transition has a specific transition enthalpy, though in practice the transition enthalpy exists only as a limit in infinite time. 3. Molar volume , entropy and enthalpy are continuous at transition temperature. 4. Lambda transitions include transitions between phases of liquid crystals or the onset of ferromagnetism. 5. A lambda transition is a like a second-order transition except that it has an infinite heat capacity at the transition temperature (theoretically!). V Ttrans T H Ttrans T Cp T trans T Ttrans T 6 Thermodynamic versus Kinetic Control Graphite and diamond Some substances exist in a thermodynamically unstable state. To illustrate, let us compare two allotropes of carbon, graphite and diamond. Gf 0 (C(graphite)) = 0 kJ/mol, because graphite is the most thermodynamically stable allotrope of carbon. The Gibbs free energy of formation Gf 0 (C(diamond)) = 2.900 kJ/mol. Diamond should spontaneous lose free energy to change into graphite. However, because the carbon-carbon bonding in diamond is so strong, the activation energy to allow the transformation is extremely high. Thus diamond can exist for eons even though graphite is thermodynamically favored because the carbons atoms don’t have enough energy to rearrange themselves to make graphite. As a side note, the third allotrope of carbon, “buckyballs”, has a Gibbs free energy of formation of approximately 13.9 kJ/mol. Thus finding buckyballs in nature are extremely rare. White tin and grey tin At 25 C, the allotrope of tin known as white tin (-tin) is thermodynamically favored over the allotrope, grey tin (-tin) with Gf 0 (C(-tin)) = 0.1 kJ/mol. The solid-solid phase transition temperature between the two phases is 13.2 C, though impurities can cause the transition temperature to lowered considerably (> 0 C). Extremely cold weather in 18th century Europe caused many organ pipes to turn to dust over several years. The dust has been named tin blight, tin disease, tin pest or tin leprosy. The dust is grey tin which lacks the malleability of its brother white tin. The cold temperature conversion of tin from its white form to its grey form reflects a change in the thermodynamic favorable alloptrope with temperature. Kinetically, the reaction is autocatalytic. Formation of the tin blight lowers the activation for the formation of more tin blight. Thus a piece of tin may survive a long time in cold weather; however, it may fail catastrophically in a single season without warning. 7 Summary Clapeyron equation dp S dT V or dp H dT TV Clausius-Clapeyron Equation H vap 1 1 p ln 2 R T2 T1 p1 H vap d ln p R 1 d T