mathematical system I am having a problem drawing the table for the following system: Define a universal set U as the set of counting numbers. Form a new set that contains all possible subsets of U. This new set of subsets together with the operation of set intersection forms a mathematical system. Then I have to tell which properties that we did in class are satisfied by the system, which I would not have a problem with if I could just get the table drawn. Analysis: Since a universal set U is the set of counting numbers, namely, a set of all positive integers, denoted by N={1,2,3,…,}. a new set that contains all possible subsets of U can be described as follows. (1) The size of a subset equals zero There is only one such set: empty set (2) The size of a subset equals to 1 There are infinitely many such sets, namely, {1}, {2},{3},….,{n},…. (3) The size of a subset equals to 2 There are infinitely many such sets, namely, {1,2}, {1,3},{1,4},….,{1,n},…. {2,3},{2,4},….,{2,n},…. {3,4},….,{1,n},…. …….. …… (n+1) The size of a subset equals to n Again, there are infinitely many such sets, namely, {1,2,…,n-1,n}, {1,2,…,n-1,n+1},{1,2,…,n-1,n+2},…., …… ……………….. So, if we use to denote the above new set containing all possible subsets of U, then we can show that has the following properties: (I) and ; It is obvious, since and U are subsets of U. (II) If A , then A c where Ac is the complement of A. Since A c U A and we know that U A is a subset of U, so A c U A (III) If A1 , A2 ,..., An ,... , then A k k 1 Once again, since contains all possible subsets of U, we know that A k k 1 also a subset of U. Hence, A k . k 1 (IV) If A1 , A2 ,..., An ,... , then A k k 1 Same reason as that in (III) I hope I answered your question. Good luck! Changping is