Calc 2 Lecture Notes Section 8.3 Page 1 of 5 Which test do I use for a sequence or series? Are you evaluating a sequence or a series (infinite sum)? If a series, go to page 3. Otherwise… For a Sequence Calculate a few terms Graph some terms Definition 1.1: Convergence of a sequence and divergence of a sequence. The set an n n converges to L if and only if given any number > 0 there is an integer N for 0 which an L for every n > N. If there is no such number L, then we say the sequence diverges. Theorem 1.1: Combinations of limits of sequences. If an n n and bn n n both converge, then 0 0 (i). lim an bn lim an lim bn (ii). lim an bn lim an lim bn (iii). lim anbn lim an (iv). a lim an lim n n (assuming lim bn 0 ). n n b bn n lim n n n n n n n n n lim b n n Theorem 1.2: The limit of a sequence is the limit of its function. If x and lim f x L , then lim f n L for n . x n Note that the converse is not true. Counterexample: lim cos 2 n n Theorem 1.3: Squeeze Theorem Suppose that an n n and bn n n both converge to the limit L. If there is an integer n1 n0 such 0 0 that all n n1 guarantees that an cn bn, then cn n n converges to L as well. 0 Corollary 1.1: If lim an 0 , then lim an 0 as well. n n Calc 2 Lecture Notes Section 8.3 Page 2 of 5 Definition 1.3: Increasing and Decreasing sequences. The sequence an n 1 is increasing if a1 a2 a3 an an1 The sequence an n 1 is decreasing if a1 a2 a3 an an1 If a sequence is either increasing or decreasing it is called monotonic. Key trick: To determine whether a series is monotonic, look at the ratio of successive terms. Definition 1.4: Bounded sequences. The sequence an n 1 is bounded if there is a number M > 0 (called a bound) for which |an| < M for all n. Theorem 1.4: Convergence of bounded monotonic sequences. Every bounded, monotonic sequence converges. Calc 2 Lecture Notes Section 8.3 Page 3 of 5 For a Series Get a “feel” for the series: 1. Evaluate a few partial sums. 2. Graph the first few partial sums. 3. Evaluate some large-n partial sums. If the terms are always positive: 1. Quick check for convergence: can you work out the answer to the sum? 1 10 k a. Geometric series: example: 0.1 (Section 8.2) 1 0.1 9 k 0 a ar k converges to if r 1 and diverges if r 1 1 r k 0 b. Telescoping series: 1 1 1 1 1 1 1 1 1 1 (Section 8.2) k 1 1 2 2 3 3 4 k 1 k k 1 k 1 k 2. Quick check for convergence: is the series a p-Series? 1 a. The p-Series p converges if p > 1 and diverges if p 1. (Section 8.3) i 1 k 3. Quick check for divergence: do the terms grow instead of tending to zero? a. divergence by the kth term test. Example: k because lim a k k 1 k 0. (Section 8.2) b. The harmonic series diverges: 1 k . (Section 8.2) k 1 4. Develop an intuition for whether it will converge or diverge, then compare the sequence to a known converging or diverging integral or series: a. Theorem 3.1: The Integral Test for Convergence of a Series If f(k) = ak for all k = 1, 2, 3, …, and f is both continuous and decreasing, and f(x) 0 for x 1, then f x dx and 1 a i 1 k either both converge or both diverge. b. Theorem 3.3: The Comparison Test for Convergence of a Series Suppose that 0 ak bk for all k . If bk converges, then k 1 ak diverges, then k 1 a k 1 k converges, too. If b k 1 k diverges, too. c. Theorem 3.4: The Limit Comparison Test for Convergence of a Series a Suppose that ak, bk > 0, and that for some finite number L, lim k L 0 . Then, k b k either a k 1 k and b k 1 k both converge or both diverge. Calc 2 Lecture Notes Section 8.3 Page 4 of 5 If the terms of the series are not always positive, including if they alternate sign: 1. If the terms do go to zero, and they alternate sign, then the series converges. (Section 8.4) 2. If some of the terms are negative, but a k 1 k converges (which you would test using techniques from the previous page), then the series converges absolutely (Section 8.5) 3. Theorem 5.2: The Ratio Test Given a k 1 k , with ak 0 for all k, suppose that ak 1 L . Then: k a k a. if L < 1, the series converges absolutely. b. if L > 1 (or L = ), the series diverges. c. if L =1, no conclusion can be made. lim 4. Theorem 5.3: The Root Test Given a k 1 k , with ak 0 for all k, suppose that lim k ak L . Then: k a. if L < 1, the series converges absolutely. b. if L > 1 (or L = ), the series diverges. c. if L =1, no conclusion can be made. Calc 2 Lecture Notes Section 8.3 Test Geometric Series When to Use Kth-Term Test All series. Integral Test ar Comparison Test Conclusions a Converges to if r 1 and 1 r diverges if r 1 . k k 0 If lim ak 0 , the series diverges. k k 1 1 ak , where ak f k , f ak and is continuous and decreasing, and f(x) 0 1 p k 1 k 0 ak bk for all k . converge or both diverge. k 1 p-Series Page 5 of 5 b k 1 8.3 8.3 converges, then k 8.2 8.3 f x dx both Converges if p > 1 and diverges if p 1. If Section 8.2 a k 1 converges. k If a k 1 k diverges, then b k 1 Limit Comparison Test ak, bk > 0, and a lim k L 0 k b k Alternating Series Test 1 Absolute Convergence Ratio Test Root Test k 1 k 1 ak , where ak 0 Series with some positive and some negative terms (including alternating series) Any series (especially those with exponentials or factorials) Any series (especially those with exponentials) k diverges. ak and k 1 b k 1 k both converge or 8.3 both diverge. If lim ak 0 and ak 1 ak , then the 8.4 k series converges. If a k 1 k converges, then a k 1 8.5 k converges absolutely. ak 1 L and if L < 1, the k a k series converges absolutely. 8.5 If lim k ak L and if L < 1, the 8.5 If lim k series converges absolutely.