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Solving quadratic equations: which method to use? Once we have been introduced to the quadratic formula, it is tempting to use it to solve any quadratic equation we come across. While it is true that the quadratic formula will solve ANY quadratic equation, it is not necessarily the easiest or most efficient method. Refer to page 673 in the text book, and consider the following: 1) Solve 36 x 2 84 x 49 0 This could certainly be solved with the quadratic formula, but the leading coefficient and the constant should give us a clue that the left side of the equation is, in fact, a trinomial square. If we see this, we can solve quickly and efficiently without the quadratic formula: 36 x 2 84 x 49 0 (6 x 7 ) 2 0 6x 7 0 6 x 7 7 x 6 2) Solve x 2 4 x 4 12 Again, the key to doing this problem quickly is to recognize the perfect square trinomial on the left side. If we recognize it, we can solve the problem more efficiently than putting it in standard form and using the quadratic equation. x 2 4 x 4 12 ( x 2) 2 12 x 2 12 x 2 12 x 22 3 3) Solve 7 x( x 2) 5 3x( x 1) With this problem, we don’t know the best approach until we can simplify both sides. 7 x 2 14 x 5 3x 2 3x 4 x 2 11x 5 0 Since neither side results in a “nice” perfect square after the first or second step, this is a problem best served by using the quadratic formula, with a 4, b 11, c 5 : 11 112 4(4)(5) 11 121 80 11 41 x 2(4) 8 8 (OVER) 4) Solve 11( x 2) (5 x) ( x 2)( x 4) Notice, this is another one that needs to be simplified on each side first. 11x 22 x 5 x 2 6 x 2 x 12 12 x 27 x 2 4 x 12 0 x 2 16 x 15 At this point we want to see what we have before throwing it into the quadratic formula. Notice that the right side of the equation will factor very nicely: there is no need to use the quadratic formula here. 0 ( x 15)( x 1) 0 x 15 or 0 x 1 x 15 or x 1 To summarize, the quadratic formula can make our lives easier, but it can also make it unduly tedious. Use the quadratic formula: If there are no nice perfect square trinomials, or If, when set in standard form (= 0), the quadratic will not factor easily