C4 – Vectors Summary A vector has magnitude and direction, a scalar has magnitude only. In typed text vectors are printed in bold p or written as OP , in OP . Vectors may be written in component form as a a1 i a 2 j a3 k or handwriting vectors are underlined p or written as a1 as a column vector a a 2 . a 3 PF is perpendicular to the line, i.e. PF b 0 . Also PF OF OP (a b) OP . Use these to find a a1 a2 a3 . 2 2 2 A position vector starts at the origin. A unit vector has magnitude 1, e.g. i and j. Vector scalar: same direction, magnitude changes (multiply each component by the scalar) Negative vector: opposite direction, same magnitude (change signs) Adding vectors: draw “nose to tail” to find the resultant (add each component) AB OB OA . The midpoint M of a line AB is OM 12 (OA OB ) . Points are collinear if they lie on a straight line. If points A, B and C are collinear then AB and BC are parallel and share a common point B. The scalar/dot product of a and b is a b a1b1 a2 b2 a3b3 . The angle between 2 vectors is given by cos ab (Vectors ab should start from the same point.) 2 vectors are perpendicular if a b 0 . Vector equation of a line: a point on the line and equations for each component and solve simultaneously). iii) skew if not i) or ii) (in 3D only). The angle between lines is given by the angle between their directions. To find the distance between a point P and a line r a b , let F be a point on the line such that The magnitude (size/length) of a vector is Vector joining 2 points: r a b and r c d are i) parallel if b md , where m is a scalar (i.e. same direction). ii) intersect if and exist for which a b c d (write out 2 lines given by r a b where a is the position vector of b is the direction of the line Equation of a line through A and B: r OA AB . then PF . (F is sometimes called the foot of the perpendicular from the point to the line.)