Examples for discussion 13 a. Let S = {1, 2, 3, 4) and let relation R on A be defined by R = {(1, 2), (1, 4), (2, 3), (3, 1), (4, 2)}. Find 1) R-1 2) R′ 3) R2 = RR 4) reflexive closure of R 5) symmetric closure of R 6) transitive closure of R b. Find the properties of the following relation: R = {(a, b)N N | a + b is even} Reflexive: Since a + a = 2a for all natural numbers a, R is reflexive. Symmetric: If (a, b) R, then a + b = 2k for some integer k. Then, b + a = 2k also, so (b, a) R. Thus, R is symmetric. Clearly, R is not irreflexive, antisymmetric or asymmetric, so the only thing we have left to consider is the transitive property. Suppose (a, b) R and (b, c) R. Then, there are integers j and k such that a + b = 2k and b + c = 2j Thus, a + c + 2b = 2k + 2j a + c = 2(k + j - b) Since a + c is even, (a, c) R and R is transitive. c. Start with A = {1, 2, 3, 4}. Find nonempty relations on A with the following characteristics: 1) irreflexive and antisymmetric 2) symmetric and transitive but not reflexive d. Prove the complement of a symmetric relation is symmetric. Proof: Let R be a symmetric relation on a set A and let (a, b) be an element of R′. (a, b) R Definition of complement (b, a) R Definition of symmetric (b, a) R′ Definition of complement Therefore R′ is symmetric Definition of symmetric e. Prove the inverse of a transitive relation is transitive. Proof: Let R be a transitive relation on S. Suppose (a, b) R-1 and (b, c) R-1 Then, (b, a) R and (c, b) R Thus, (c, a) R Therefore, (a, c) R-1 Therefore R-1 is transitive Definition of inverse Given that R is transitive Definition of inverse Definition of transitive f. One of the properties of composition is R1(R2R3) (R1R2) (R1R3). Find an example for which the containment is proper. g. Prove that a relation R on a set S is symmetric if and only if R = R-1 Part 1: If R is symmetric, then R = R-1. In this case we must show that if R is symmetric, then R R-1 and R-1 R. Let (a, b) R. Then, (b, a) R. Then, (a, b) R-1 Therefore, R R-1. Given that R is symmetric Definition of inverse Definition of subset Let (x, y) R-1 Then, (y, x) R Then, (x, y) R. Therefore R-1 R Therefore R = R-1 Definition of inverse Given that R is symmetric Definition of subset Definition of set equality Part 2: If R = R-1 then R is symmetric (Specifically, what we need to show is that if (a, b) R, then (b, a) R.) Let (a, b) R. Then, (a, b) R-1 Then, (b, a) R. Therefore, R is symmetric. Given that R = R-1 Definition of inverse Definition of symmetric