Advanced Algebra 2: CH variation and other common functions
DIRECT and INVERSE VARIATION FUNCTION INTRODUCTION
Direct Variation
: ( k is the constant of proportionality) y varies directly with x . y
kx y
Note that this is a linear function through the origin.
varies directly with the square of x . y
kx
2
Note that this is a quadratic function through the origin. y varies directly with the cube of x . y
kx
3 y
Note that this is a cubic function through the origin.
varies directly with x the nth power. y
kx n
Note that this is a nth degree polynomial through the origin.
Example 1 : Suppose y varies directly with x and y = 25 when x = 10. Write the function of this relationship and determine the value of y when x
16 .
Solution : y
kx and with substitution: 25
k which implies k
25
10
5
2
So the function is y
5
2 x and y
5
2
20 when x
16 .
Example 2 : Suppose y varies directly with the cube of x and y = 100 when x = 4. Write the function of this relationship and determine the value of y when x
10 .
Solution : y
kx 3 and with substitution: 100
k
3
100
k which implies k
100
64
25
.
16
So the function is y
25 x
3
16 and y
25
3
16
25
1000
16
3125 when x
10 .
2
Complete problems 1 and 5 from section 7.11
Advanced Algebra 2: CH variation and other common functions
DIRECT and INVERSE VARIATION FUNCTION INTRODUCTION
Inverse Variation:
( k is the constant of proportionality) y varies inversely with x . y
k x
Note that this is a rational function with a vertical asymptote at x
0 . y varies inversely with the square of x . y
x k
2
Note that this is a rational function with a vertical asymptote at x
0 . y varies inversely with the cube of x . y
x k
3
Note that this is a rational function with a vertical asymptote at x
0 . y varies inversely with x the nth power. y
x k n
Note that this is a rational function with a vertical asymptote at x
0 .
Example 3 : Suppose y varies inversely with the square of x and y = 4 when x = 5. Write the function of this relationship and determine the value of y when x
9 .
Solution : y
k x
2 and with substitution: 4
k
2
which implies k
100 .
So the function is y
100 x
2 and y
100
9
2
100
81 when x
9 .
Complete problems 7abcd, and 9 from section 7.11
Advanced Algebra 2: CH variation and other common functions
DIRECT and INVERSE VARIATION FUNCTION INTRODUCTION
Lets investigate the response to doubling, tripling or halving x in direct and inverse variation functions.
Illustration 1
: Consider y varies directly with x : y
1 kx
Question :
What happens to y when we double x , that is, what happens when we replace ( x ) with (2 x )?
Solution :
Let y be a result of doubling x , that is
2 twice that of y
1
. In short, doubling x y
2
k
doubles y .
( 2 ) kx
2 y
1
. We see from this that y is
2
Illustration 2
: Consider y varies inversely with the cubed of x : y
1
3 x k
Question :
What happens to y when we double x , that is, what happens when we replace ( x ) with (2 x )?
Solution :
Let y be a result of doubling x , that is
2 y
2
k
3
2
3 k
k
2
3 x
3
1
2
3
k x
3
1
2
3 y
1
. We see from this that
1 y is
2
2
3
(or one-eighth) that of y
1
.
Complete the chart on the following page.
Advanced Algebra 2: CH variation and other common functions
DIRECT and INVERSE VARIATION FUNCTION INTRODUCTION
For each type of variation, indicate the effect doubling, tripling, or halving x has on y . If done correctly a patterns should arise.
1. y varies directly with x . y
kx
Doubling x : Tripling x :
2. y varies directly with the square of x . y
kx
2
Halving x :
Doubling x : Tripling x :
3. y varies directly with the cube of x . y
kx
3
Halving x :
Doubling x : Tripling x :
4. y varies directly with x the nth power. y
kx n
Doubling x : Tripling x :
5. y varies inversely with x . y
k x
Doubling x : Tripling x :
6. y varies inversely with the square of x . y
x k
2
Doubling x : Tripling x :
7. y varies inversely with the cube of x . y
x k
3
Doubling x : Tripling x :
8. y varies inversely with x the nth power. y
x k n
Doubling x : Tripling x :
Halving
Halving
Halving
Halving
Halving
Halving x x x x x x
:
:
:
:
:
: