Revision Exercise Sheet - Solutions 1. Solve for x in the following equations: (i) 2x=1 x = 1/2 (ii) 2x+6=12 2x = 12-6 2x = 6 x = 6/2 x=3 (iii) 3-x=7 -x = 7-3 -x = 4 x = -4 (iv) 5(2x-4)=30 10x-20 = 30 10x = 30+20 10x = 50 x = 50/10 x=5 (v) x 2 3 x = 2*3 x=6 (vi) x x 2 3 2 2 x 3x 2 6 2x-3x = 2*6 -x = 12 x = -12 2. Express x in terms of y in each of the following cases: (i) y=6x+12 -6x = 12-y 6x = y-12 x = y/6-2 (ii) 6x-12y = 18 6x = 18+12y x = 3+2y (iii) 2x+8y=12 2x = 12-8y x = 6-4y 1 (iv) 1 y 2x 4 5 y = 10x+20 -10x = 20-y 10x = y-20 x = y/10-2 (v) x 2 3 3 x2 y 3 y 3y = x+2 -x = 2-3y x = 3y-2 (vi) 2 1 y x2 3 6 2 y x 12 3 6 3 x 36 2y 6 12 y 3 x 36 -3x = 36-12y 3x = 12y-36 x = 4y-12 3. Solve the following systems of simultaneous equations: (i) y=3-2x y=x STEP 1: Express in terms of same value of one variable (y) (Given in question) STEP 2: Substitute value of eq1 for eq2 3-2x = x STEP 3: Collect the terms 3 = x+2x 3 = 3x 1=x STEP 4: Compute y Sub into equation 1 or equation 2: y = 3-2(1) y=1 (ii) 5x-2y = 11 3x+3y = 15 STEP 1: Express in terms of same value of one variable (15x) (5x-2y = 11) multiplied by 3 (3x+3y = 15) multiplied by 5 15x-6y = 33 15x = 33+6y 15x+15y = 75 2 15x = 75-15y STEP 2: Substitute value of eq1 for eq2 33+6y = 75-15y STEP 3: Collect the terms 6y+15y = 75-33 21y = 42 y=2 STEP 4: Compute x Sub into equation 1 or equation 2: 5x-2y = 11 5x = 11+2y 5x = 11+2(2) 5x = 11+4 5x = 15 x=3 (iii) 2x-5y=20 2=3x-2.5y STEP 1: Express in terms of same value of one variable (5y) 2x-5y = 20 -5y = 20-2x 5y = 2x-20 (2 = 3x-2.5y) multiplied by 2 4 = 6x-5y 5y = 6x-4 STEP 2: Substitute value of eq1 for eq2 2x-20 = 6x-4 STEP 3: Collect the terms 2x-6x = -4+20 -4x = 16 4x = -16 x = -4 STEP 4: Compute y Sub into equation 1 or equation 2: 5y = 2x-12 5y = 2(-4)-7 5y = -8-7 5y = -15 y = -3 (iv) 4P-3Q = 5 2Q+2P = 20 STEP 1: Express in terms of same value of one variable (4P) 4P = 5+3Q (2Q+2P = 20) multiplied by 2 4Q+4P = 40 4P = 40-4Q STEP 2: Substitute value of eq1 for eq2 5+3Q = 40-4Q STEP 3: Collect the terms 3Q+4Q = 40-5 7Q = 35 Q=5 STEP 4: Compute P Sub into equation 1 or equation 2: 4P-3Q = 5 3 4P = 5+3Q 4P = 5+3(5) 4P = 20 P=5 (v) x-y+z = 0 2y-2z = 2 -x+2y+2z = 29 STEP 1: Express in terms of same value of one variable (y) Equation 1: x-y+z = 0 -y = -x-z y = x+z Equation 2: (2y-2z = 2) divided by 2 y-z = 1 y = 1+z STEP 2: Substitute value of eq1 for eq2 x+z = 1+z STEP 3: Collect the terms x = 1+z-z x=1 STEP 4: Compute 2 equations for y and z Sub into equation 3: -x+2y+2z = 29 -1+2y+2z = 29 2y+2z = 29+1 2y+2z = 30 Eq2 and Eq3 are now 2 equations in 2 unknowns begin procedure again 2y-2z = 2 2y+2z = 30 STEP 1: Express in terms of same value of one variable (2y) Equation 1: 2y = 2+2z Equation 2: 2y = 30-2z STEP 2: Substitute value of eq1 for eq2 2+2z = 30-2z STEP 3: Collect the terms 2z+2z = 30-2 4z = 28 z=7 STEP 4: Compute y Sub into equation 1: 2y = 2+2z 2y = 2+2(7) 2y = 2+14 2y = 16 y=8 (vi) 2x+2y-5z = -5 x-y+z = 3 -3x+y+2z = -2 STEP 1: Express in terms of same value of one variable (2x) Equation 1: 2x+2y-5z = -5 2x = -5-2y+5z Equation 2: (x-y+z = 3) multiplied by 2 2x-2y+2z = 6 2x = 6+2y-2z STEP 2: Substitute value of eq1 for eq2 4 -5-2y+5z = 6+2y-2z STEP 3: Collect the terms -2y+5z-2y+2z = 6+5 -4y+7z = 11 1 equation in 2 unknowns. Repeat procedure for 2 other equations STEP 1: Express in terms of same value of one variable (-3x) Equation 2: (x-y+z = 3) multiplied by –3 -3x+3y-3z = -9 -3x = -9-3y+3z Equation 3: -3x+y+2z = -2 -3x = -2-y-2z STEP 2: Substitute value of eq1 for eq2 -9-3y+3z = -2-y-2z STEP 3: Collect the terms -3y+3z+y+2z = -2+9 -2y+5z = 7 2 equations in 2 unknowns begin procedure again using 2 new equations -4y+7z = 11 -2y+5z = 7 STEP 1: Express in terms of same value of one variable (-4y) Equation 1: -4y+7z = 11 -4y = 11-7z Equation 2: (-2y+5z = 7) multiplied by 2 -4y+10z = 14 -4y = 14-10z STEP 2: Substitute value of eq1 for eq2 11-7z = 14-10z STEP 3: Collect the terms -7z+10z = 14-11 3z = 3 z=1 STEP 4: Compute y -4y = 11-7z -4y = 11-7(3) -4y = 11-21 -4y = -10 4y = 10 y = 10/4 = 2½ Compute x from original equations: 2x+2y-5z = -5 2x+2(2.5)-5(3) = -5 2x +5-15 = -5 2x-10 = -5 2x = -5+10 2x = 5 x = 5/2 = 21/5 5 4. Given the equations of the lines: (a) y = 2+x (b) y = 3-4x (c) y = 0.5x-2 Plot each line over the interval x = -2 to x = 6 (a) y = 2+x y 0 1 2 3 4 5 6 7 8 = a 2 2 2 2 2 2 2 2 2 + b 1 1 1 1 1 1 1 1 1 * x -2 -1 0 1 2 3 4 5 6 9 8 7 6 5 4 3 2 1 0 -2 -1 (b) y = 3-4x y 11 7 3 -1 -5 -9 -13 -17 -21 0 = a 3 3 3 3 3 3 3 3 3 1 2 + 3 b -4 -4 -4 -4 -4 -4 -4 -4 -4 4 5 * 6 x -2 -1 0 1 2 3 4 5 6 6 15 10 5 0 -2 -1 -5 0 1 2 3 4 5 6 -10 -15 -20 -25 (c) y = 0.5x-2 y = -3 -2.5 -2 -1.5 -0 -0.5 0 0.5 1 a -2 -2 -2 -2 -2 -2 -2 -2 -2 + b 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 * x -2 -1 0 1 2 3 4 5 6 1.5 1 0.5 0 -2 -1 -0.5 0 1 2 3 4 5 6 -1 -1.5 -2 -2.5 -3 -3.5 7 5. Given the equations of the following lines: (a) 2y-5x+10 = 0 (b) x = 10-2y (c) y+5x=15 (i) Write each of the equations in the form y = f(x) (ii) Write down the slope and the intercept of each line (iii) Write down the inverse of each function (i.e. x = g(y)) (iv) Sketch the graph of each line (a) 2y-5x+10 = 0 (i) 2y = 5x-10 y = 5x/2-5 (ii) slope = 5/2 intercept = -5 (iii) y = 5x/2-5 y+5 = 5x/2 2y+10 = 5x 2y/5+2 = x x = 2y/5+2 (iv) y = 5x/2-5 Let x = 0 y = -5 x = 2y/5+2 Let y = 0 x=2 0 -1 0 2 -2 -3 -4 -5 -6 (b) x = 10-2y (i) 2y = 10-x y = 5-x/2 (ii) slope = -1/2 intercept = 5 (iii) inverse function: x = 10-2y (iv) y = 5-x/2 Let x = 0 y=5 x = 10-2y Let y = 0 x = 10 8 6 5 4 3 2 1 0 0 (c) 10 y+5x=15 (i) y = 15-5x (ii) Slope = -5 Intercept = 15 (iii) inverse function: 5x = 15-y x = 3-y/5 (iv) y = 15-5x Let x = 0 y = 15 x = 3-y/5 Let y = 0 x=3 20 15 10 5 0 0 3 9