1 Evolutionary Stability in the Asymmetric Volunteer’s Dilemma 2 Supporting Information 3 Jun-Zhou He, Rui-Wu Wang and Yao-Tang Li 4 Appendix S1: The equilibrium points and Local stability analysis 5 From the definition of equilibrium point of nonlinear systems, we know that the 6 equilibrium points of the equation (2.3) in text are the solutions of the following 7 equations S ( 1 S )K( S U S N 1W ) 0 . N 2 ( 1 ) K ( U ) 0 W W W W S W 8 9 (1) Now, we solve the equation (1). Solving S (1 S )( K S U S W N 1 ) 0 , we get S 0, S 1, W K S U S 1 ( N 1) 10 . 11 Solving W (1 W )( KW UW S W N 2 ) 0 , we get W 0, W 1 and 12 KW UW S W N 2 0 . (2) 13 Obviously, points ( S , W ) (0,1), (0, 0), (1, 0), (1,1) are the solutions of the 14 equations (1). We denote them as A(0,1) , B (0, 0) , C (1, 0) , D (1,1) , respectively, 15 where S and W are respectively the frequencies of defectors of “strong” and 16 “weak” players. 17 Substituting S 1 in Equation (2) yields: W KW UW 1 ( N 2) 18 , 1, K UW 1 ( N 2) 19 that is, 20 denote it as E (1, W* ) ,here W* KW UW 21 S W W , is also a solution of the equations (1), and we 1 ( N 2) Substituting W K S U S 1 ( N 1) . in Equation (2), we obtain 1 S KW UW K S U S KW UW K S U S 22 ( N 2) ( N 1) ( N 11) ( N 1) KW UW K S U S K S U S 1 ( N 1) U S KW K SUW K S U S 1 ( N 1) , W U S KW K SUW K S U S . , KS denote it 1 ( N 1) US 1 ( N 1) 23 So 24 the 25 S** U S KW K SUW K S U S 26 From above discussion, we obtain six equilibrium points of the nonlinear system (2.3): 27 A(0,1) , B (0, 0) , C (1, 0) , D (1,1) , E (1, W* ) , F ( S** , W** ) , 28 S equations (1), we and 1 ( N 1) where W* KW UW 1 ( N 2) F ( S** , W** ) as and W** K S U S 1 ( N 1) , S** U S KW K SUW K S U S 1 ( N 1) is also a solution of , here . , W** K S U S 1 ( N 1) . 29 30 The following is the local stability analysis of the system of volunteer dilemma 31 game. In text, the linearization of the replicator dynamics (2.3) at an equilibrium point 32 ( S , W ) is f ( S , W ) g ( S , W ) 33 34 S f ( S , g ( S , ) W (S W) S . W , W ) ( S , W (3) ) For convenience, let f ( S , W ) S J ( S , W ) g ( S , W ) S 35 36 S f ( S , W ) W , g ( S , W ) S ( , ) ( , ) S W S W (4) where 37 f ( S , W ) S (1 2 S )( K S U S W N 1 ) , 38 f ( S , W ) W ( N 1)U S W N 2 S (1 S ) , 39 g ( S , W ) S UW W N 1 (1 W ) , 40 g ( S , W ) S (1 2W ) KW [ N W ( N 1)]UW S W N 2 , 2 ( S , W ) represents the equilibrium points of the nonlinear system (2.3), S and 41 and 42 W are respectively the frequencies of defection of “strong” and “weak” players. 43 44 From (4), we obtain the Jacobi matrices of the linear system (3) of the nonlinear system (2.3) at these six equilibrium points: 0 , KW K US J ( 0 , 1) S 0 0 , KW K J ( 1 , 0) S 0 45 K J (0, 0) S 0 46 [ K S U S ( W* ) N 1 ] 0 0 U S K S * J (1,1) , J (1, W ) * UW KW 0 ( N 2) KW (1 W ) 0 47 0 ( N 1)U S S** (1 S** )( W** ) N 2 J ( S** , W** ) . ** ** N 1 ( N 2)UW S** (1 W** )( W** ) N 2 UW (1 W )( W ) 0 , KW 48 The local stability of the nonlinear system (2.3) at equilibrium points is 49 determined by the eigenvalues of the Jacobi matrices. Now, we analyze character of 50 the eigenvalues of above six matrices. 51 Since 0 K S KW UW U S and J (0, 0) , J (1,1) , J (0,1) and J (1, 0) are 52 diagonal matrices, we can easily get that the eigenvalues of J (0, 0) and J (1,1) are 53 all positive, and the eigenvalues of J (0,1) are negative. On thus condition, one of 54 the eigenvalues of J (1, 0) is positive and another is negative. 55 For J (1, W* ) , we obtain easily that its eigenvalues are ( N 2) KW (1 W* ) and 56 [ K S U S ( W* ) N 1 ] . Obviously, 57 0 K S U S KW UW 1 , we know that yield 58 W* KW UW 59 negative if and only if K S U S KW UW 60 J (1, W* ) are all negative under the special condition 1 N 2 ( N 2) KW (1 W* ) 0 . ) demand K S U S KW UW [ K S U S ( W* ) N 1 ] 0 N 1 N 2 N 1 N 2 In addition, from (here . So another eigenvalue is , that is, the eigenvalues of KS US N 2 KW UW N 1 . 3 61 As to J ( S** , W** ) , its characteristic equation is 2 a22 a12 a21 0 . 62 63 Solving Equation (8), we get 64 65 2 a22 a22 4a12 a21 , 2 where 66 a12 ( N 1)U S S** (1 S** )( W** ) N 2 , 67 a21 UW (1 W** )( W** ) N 1 , 68 a22 ( N 2)UW S** (1 W** )( W** ) N 2 . 69 70 71 (8) Obviously, a12 0, a21 0 and a22 0 , then it is easy to obtain 2 a22 a22 4a12 a21 . Hence, one of the eigenvalues of J ( S** , W** ) is a positive real number and another is a negative. 72 From above analysis of the eigenvalues and the stability theory of differential 73 equations (Hofbauer and Sigmund 1998; Hirsch et al. 2004), we obtain that A(0,1) 74 and E (1, W* ) are sinks (stable); and that B (0, 0) and D (1,1) are sources (unstable); 75 C (1, 0) and F ( S** , W** ) are saddles (unstable). 76 77 References 78 Hirsch, M. W., Smale, S., Devaney, R. L., 2004. Differential Equations, Dynamical 79 80 81 Systems, and an Introduction to Chaos. Calif. Acad. Press. Hofbauer, J., Sigmund, K., 1998. Evolutionary Games and Population Dynamics. Cambridge Uni. Press. 4