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Sql url : http://rfhs8012.fh-regensburg.de/~oracle/sqlplus/index.html
Note: Learn from this URL, U will be Master in SQL
IBM Any Document – Reference :- http://publib.boulder.ibm.com/infocenter/db2help/index.jsp?topic=/com.ibm.db2.udb.do
c/wareh/c0008688.htm
Gentle Introduction to SQL : http://sqlzoo.net/ http://expertanswercenter.techtarget.com/eac/knowledgebaseCategory/0,295197,sid63_tax29681
4_idx0_off50,00.html
http://w2.syronex.com/jmr/edu/db/
Oracle PL/SQL Tutorial : http://www-db.stanford.edu/~ullman/fcdb/oracle/or-plsql.html
Oracle SQL*Plus Tutorial : http://oldweb.uwp.edu/academic/mis/baldwin/sqlplus.htm
Oracle/SQL Tutorial : http://www.db.cs.ucdavis.edu/teaching/sqltutorial/
SQL Tutorial : http://www.1keydata.com/sql/sql.html
SQL - A Practical Introduction. (Free Download) : http://www.managedtime.com/freesqlbook.php3
: http://scarlet.ucc.nau.edu/oracle9.0.1/index.htm
http://scarlet.ucc.nau.edu/oracle9.0.1/nav/docindex.htm
Administrator Guide – DOC - http://scarlet.ucc.nau.edu/oracle9.0.1/server.901/a90117/toc.htm
PL/SQL REFERENCE Guide : http://scarlet.ucc.nau.edu/oracle9.0.1/appdev.901/a89856/toc.htm
SQL REFERENCE Guide : http://scarlet.ucc.nau.edu/oracle9.0.1/server.901/a90125/toc.htm
http://scarlet.ucc.nau.edu/oracle9.0.1/server.901/a88827/toc.htm

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CONSTRAINTS
PRIMARY CONSTRAINTS : PRIMARY,UNIQUE,CHECK,REFERENCES)
SECONDARY CONSTRAINTS : NOT NULL,DEFAULT)
CONSTRAINTS BASED ON 2 LEVELS COLUMN LEVEL and TABLE LEVEL
Except Not null all others can be defined as Both table and column level.
But Not null as only column level .
Eg. For SECONDARY CONSTRAINTS
~~~~~~~~~~~~~~~~~~~~~~~
1.
NOT NULL CONSTRAINT
CREATE TABLE EMP9( ENO NUMBER(3) NOT NULL,
ENAME VARCHAR2(10));
2. DEFAULT CONSTRAINT
CREATE TABLE EMP9(ENO NUMBER(3) NOT NULL,
ENAME VARCHAR2(10),DOJ DATE DEFAULT SYSDATE);
3. PRIMARY CONSTRAINT(COLUMN LEVEL)
UNIQUE
CREATE TABLE EMP9(
ENO NUMBER(3) NOT NULL CONSTRAINT UNIEMP UNIQUE,
ENAME VARCHAR2(10));
PRIMARY KEY
CREATE TABLE EMP9(
ENO NUMBER(3) CONSTRAINT PKEMP9 PRIMARY KEY,
ENAME VARCHAR2(10));
4. CHECK CONSTRAINT
CREATE TABLE BANK(
ACNO NUMBER(2) CONSTRAINT PKBANK PRIMARY KEY,
ACTYPE VARCHAR2(2) CONSTRAINT CKBANK CHECK ( ACTYPE IN
('SB','CA','RD')),
ACNAME VARCHAR2(10),
AMOUNT NUMBER(4));
5. REFERENCES
CREATE TABLE EMP9(
ENO NUMBER(3) CONSTRAINT PKE9 PRIMARY KEY,
JOB VARCHAR2(10),

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ENAME VARCHAR2(10),
MGR NUMBER(4) REFERENCES EMP9(ENO));
6. REFERENCES(REFERING TO DIFFERENT TABLE)
CREATE TABLE DEPT9(DEPTNO NUMBER(2) CONSTRAINT PKDNO PRIMARY
KEY, DNAME VARCHAR2(10), LOC VARCHAR2(10));
CREATE TABLE EMP9( EMPNO NUMBER(4),ENAME VARCHAR2(10),
SAL NUMBER(7,2),DEPTNO NUMBER(2) CONSTRAINT FKDNO REFERENCES
DEPT9(DEPTNO));
7. TABLE LEVEL CONSTRAINTS
UNIQUE TABLE LEVEL
CREATE TABLE BANK( ACNO NUMBER(3),ACTYPE VARCHAR2(10),
BAL NUMBER(7,2),PLACE VARCHAR2(10),CONSTRAINT UNIBANK
UNIQUE(ACNO,ACTYPE));
PRIMARY KEY(TABLE LEVEL)
CREATE TABLE BANK( ACNO NUMBER(2), ACTYPE VARCHAR2(2)
CONSTRAINT CKBANK CHECK (ACTYPE IN ('SB','CA','RD')),AMOUNT
NUMBER)
1. Display the Details of all employees working in the same Department
as 'FORD'
SELECT * FROM EMPLOYEES EMP, DEPARTMENT DEPT
WHERE EMP.DEPTNO = DEPT.DEPTNO AND EMP.DEPTNAME = ‘FORD’
2. Display the details of all employees who are joined before 'FORD'
SELECT * FROM EMPLOYEES EMP, DEPARTMENT DEPT
WHERE EMP.DEPTNO = DEPT.DEPTNO AND EMP.JOINED_DATE<(
SELECT JOINED_DATE FROM EMPLOYEES EMP
WHERE EMP.DEPTNAME=’FORD’)
3. Display the Names of all the employees who are all getting the
salary Greater than the salary of 'SMITH' along with the
difference in salary select ename,sal-(select sal from TEMP_EMP where ename='SMITH')
"DIFF SAL" from TEMP_EMP where sal>(select sal from TEMP_EMP where ename='SMITH')
4. Display all the employees working in chicago
5. find the two minimum salaries among table
SELECT SAL FROM (SELECT * FROM TEMP_EMP ORDER BY SAL )
WHERE ROWNUM< 3

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6. Nth Highest Salary
-- select min ( sal ) "nth highest sal" from TEMP_EMP where sal in ( select sal from (select DISTINCT( sal ) from TEMP_EMP order by sal desc) where rownum<=& n )
-- SELECT DISTINCT ( a .
sal ) FROM TEMP_EMP A
WHERE & N = (SELECT COUNT (DISTINCT ( b .
sal )) FROM TEMP_EMP B WHERE a .
sal <= b .
sal )
-- SELECT sal FROM (SELECT ROWNUM rn , sal FROM (SELECT DISTINCT
( sal ) FROM temp_emp ORDER BY sal desc)) x WHERE x .
rn = : n ;
7. How do i get Greatest salaray of dept group from employee ( we have to tables
EMP and DEPT. for exp: dept 10 have 10000,dept 20 have 5000 and dept 30 have 15000 salaries , i need dept 30 group salary(means sum of that group is 15000).
)
-- select deptno , sal1 from (select deptno , sum ( sal ) sal1 from temp_emp group by deptno order by sal1 desc) where rownum<= 1
Differentiate between TRUNCATE and DELETE
TRUNCATE deletes much faster than DELETE
TRUNCATE
It is a DDL statement
It is a one way trip,cannot ROLLBACK
Doesn't have selective features (where clause)
DELETE
It is a DML statement
One can Rollback
Has
Doesn't fire database triggers Does
It requires disabling of referential constraints. Does not require
SUBQUERIES
SINGLE ROW SUBQUERY
MULTIPLE ROW SUBQUERY
SINGLE ROW SUBQUERY
1.
DISPLAY THE EMPLOYEES WHOSE JOB IS SAME AS THAT OF JONES
Select * from emp where job = (select job from emp
Where ename = ‘jones’);
2.
DISPLAY THE EMPLOYEES BELONGING TO MILLER'S DEPARTMENT
Select * from emp where dname = (select dname from emp
Where ename = ‘milers’);
3.
DISPLAY ALL THE EMPLOYEES REPORTING TO KING
Select * from emp where rname = (select rname from emp
Where ename = ‘king’);
4.
DISPLAY ALL THE EMPLOYEES WHO ARE GETTING MAX SALARY
Select * from emp where basal = (select max(basal) from emp);
5.
DISPLAY ALL THE DETAILS WHERE SAL IS GREATER THAN MILLER'S SALARY

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AND WHO ARE IN SALES DEPARTMENT.
Select * from emp where dname = ‘sales’ and basal > (select basal from emp where ename = ‘milers’);
6.
DISPLAY ALL THE DETAILS WHO HAVE JOINED IN SAME DATE AS THAT OF
JAMES.
Select * from emp where doj = (select doj from emp where ename
= ‘james’);
MULTIPLE ROW SUBQUERIES
7.
DISPLAY ALL THE DETAILS WHERE DEPT IS EITHER SALES OR RESEARCH
Select * from emp where dname = any(select dname from emp where dname = ‘sales’ or dname = ‘research’);
Select * from emp where dname = any(select dname from emp where
Dname like(‘sales’,’research’));
SUBQUERY RETURNING MULTIPLE COLUMNS
SELECT ENAME,JOB,MGR FROM EMP WHERE (JOB,MGR) IN(SELECT JOB,MGR
FROM EMP WHERE EMPNO=7788);
EXPRESSIONS WITH SUBQUERIES
SELECT * FROM EMP WHERE SAL=(SELECT SAL+50 FROM EMP WHERE
ENAME='JONES');
 ROWID
For each row in the database, the ROWID pseudocolumn returns a row's address.ROWID values contain information necessary to locate a row:
* which data block in the data file
* which row in the data block (first row is 0)
* which data file (first file is 1)
 ROWNUM
For each row returned by a query, the ROWNUM pseudocolumn returns a number indicating the order in which Oracle selects the row from a table or set of joined rows. The first row selected has a
ROWNUM
Of 1, the second has 2, and so on.
CORRELATED SUBQUERY

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FIRST TRY USING MAX
 5TH HIGHEST SALARY
SELECT * FROM EMP A WHERE 5=(SELECT COUNT(DISTINCT SAL)FROM
EMP B WHERE A.SAL<=B.SAL);
 DELETE DUPLICATE DEPARTMENT NUMBERS
DELETE FROM DEPT A WHERE ROWID NOT IN (SELECT MIN(ROWID) FROM
DEPT B WHERE A.DEPTNO=B.DEPTNO);
 DISPLAY ALTERNATE ROWS
SELECT * FROM EMP WHERE ROWID IN
(SELECT DECODE(MOD(ROWNUM,2),0,ROWID) FROM EMP);
 TO DISPLAY NTH HIGHEST SALARY
SELECT MAX(SAL) FROM EMP A WHERE &N=(SELECT COUNT(DISTINCT
SAL) FROM EMP B WHERE A.SAL<=B.SAL);
SELECT * FROM EMP A WHERE &N=(SELECT COUNT(DISTINCT SAL)
FROM EMP B WHERE A.SAL<=B.SAL);
 DELETE DUPLICATE OCCURENCES
DELETE FROM DEPT WHERE DEPTNO IN(SELECT DEPTNO FROM DEPT
GROUP BY DEPTNO HAVING COUNT(DEPTNO)>1);
DELETE FROM emp A WHERE ROWID NOT IN(SELECT MIN(ROWID) FROM emp WHERE A.DEPTNO=B.DEPTNO);
 DISPLAY ALTERNATE ROWS
SELECT * FROM GDEPT WHERE ROWID IN(SELECT
DECODE(MOD(ROWNUM,2),0,ROWID) FROM GDEPT);
 DISPLAY from NTH ROW
SELECT * FROM DEPT WHERE ROWID NOT IN(SELECT ROWID FROM DEPT
WHERE ROWNUM<=(SELECT COUNT(*)-&N FROM DEPT));
 DISPLAY DETAILS OF ALL EMPLOYEES WHOSE SAL IS GREATER THAN
AVG(SAL) OF EMPLOYEES IN RESPECTIVE DEPTS
SELECT A.ENAME,A.DEPTNO,A.SAL FROM EMP A,EMP B

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WHERE B.SAL>(SELECT AVG(SAL) FROM EMP B GROUP BY DEPTNO)
 DISPLAY ALL THE DETAILS WHERE SAL> LOWEST SAL OF EMPLOYEES IN
DEPTNO 20
SELECT * FROM EMP WHERE SAL> ANY(SELECT SAL FROM EMP WHERE
DEPTNO=20);
SELECT * FROM EMP WHERE SAL> ANY (SELECT SAL FROM EMP WHERE
DEPTNO=20);
 DISPLAY ALL THE DETAILS WHERE SAL> HIGHEST SAL OF EMPLOYEES IN
DEPTNO 20
DECLARE
NAME EMP.ENAME%TYPE;
SALARY EMP.SAL%TYPE;
DESIG EMP.JOB%TYPE:='&JOB';
BEGIN
SELECT ENAME,SAL,JOB INTO NAME,SALARY ,DESIG FROM EMP WHERE
JOB=DESIG;
DBMS_OUTPUT.PUT_LINE(NAME||' '||SALARY||' '||DESIG);
END;
1.display name,hiredate of all employees using cursors
2.DISPLAY DETAILS OF ALL EMPLOYEES WHO ARE CLERKS
3.DISPLAY DETAILS OF ALL EMPLOYEES WHEN DEPTNO IS 10.
4. EXAMPLES FOR %FOUND A B C
5.*ASSIGNMENT CLERK 200/-INCREMENT MANAGER INSERT TO TEMP ANALYST
DELETE SALESMAN AND ANNSAL>15000 300/- DECREMENT
6. EXAMPLE FOR %ISOPEN
7.EXAMPLE FOR C1%ROWCOUNT (7 A, 7 B)* display first 5 records
8. display details of first 5 highly paid employees
9.EVEN ROWS
10.NTH ROW
11.CURSOR USING FOR LOOP
12.IF ANNSAL>10000 AND JOB=CLERK INCOME TAX IS 10%,IF ANNSAL>15000 AND
JOB=SALESMAN TAX IS 20%,IF ANNSAL>10000 AND JOB=MANAGAER INCOME TAX IS
30%,ELSE A MESSAGE <10000.
13 CURSOR PARAMETERS TO PASS EMPLOYEE NUMBER AND GET THE DETAILS
14 PASS JOB & GET THE DETAILS
15 PASS DEPTNO AND JOB AND GET THE DETIALS
16 CURSOR LOCKS
17 EXAMPLE FOR IMPLICIT CURSORS
18 INSERT WITH IMPLICIT CURSORS
19 UPDATE AND SELECT WITH IMPLICIT CURSORS
20 DELETE WITH IMPLICIT CURSORS
21.DISPLAY NAMES OF EMPLOYEES WITH SAL IN DESCENDING ORDER

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WITHOUT USING ORDER BY
22.DISPLAY JOB CATEGORIES ,COUNT(JOB) AND SUM(SAL) FROM EMP
Answers:
1. display name,hiredate of all employees using cursors
DECLARE cursor c1 is select ename,hiredate from emp; name varchar(20); hdate date; begin open c1; loop fetch c1 into name,hdate; exit when c1%NOTFOUND; dbms_output.put_line(name||' '||hdate); end loop; close c1; end;
(VERY IMPORTANT POINT TO BE NOTED IS THAT EXIT WHEN CONDITION IS
SATISFIED WHEN THE FETCH RETURNS FALSE AND WE WILL COME OUT OF LOOP
WHEN EXIT CONDITION IS TRUE.)
4. EXAMPLES FOR %FOUND
DECLARE cursor c1 is select ename,sal,DEPTNO from emp
WHERE DEPTNO=10; name varchar(20); sl number; dno number; begin open c1; loop fetch c1 into name,sl,dno ;
IF c1%notFOUND THEN
DBMS_OUTPUT.PUT_LINE('CURSOR IS NOT FOUND'); exit; elsif c1%found then
DBMS_OUTPUT.PUT_LINE('FOUND'||' '||C1%ROWCOUNT);
--INSERT INTO TEMP VALUES(NAME,SL,DNO);
END IF; end loop; close c1; end;
4 B
DECLARE cursor c1 is select * from emp
WHERE DEPTNO=&deptno; a emp%rowtype; begin open c1;
LOOP

9 fetch c1 into a;
IF c1%FOUND THEN
DBMS_OUTPUT.PUT_LINE(A.ENAME||' '||A.SAL||' '||A.DEPTNO); else
EXIT;
END IF;
END LOOP; close c1; end;
4 C
DECLARE cursor c1 is select * from emp
WHERE DEPTNO=&deptno; a emp%rowtype; begin open c1; loop fetch c1 into a;
IF not c1%FOUND THEN exit; else
DBMS_OUTPUT.PUT_LINE(a.ename||' '||a.sal);
END IF; end loop; close c1; end;
5.CLERK 200/-INCREMENT MANAGER INSERT NAME,SAL TO TEMP ANALYST DELETE
SALESMAN AND ANNSAL>15000 300/- INCREMENT
DECLARE
CURSOR C1 IS SELECT * FROM EMP;
A C1%ROWTYPE;
BEGIN
OPEN C1;
LOOP
FETCH C1 INTO A;
EXIT WHEN C1%NOTFOUND;
IF A.JOB='CLERK' THEN
UPDATE EMP SET SAL=A.SAL+200 WHERE EMPNO=A.EMPNO;
COMMIT;
ELSIF A.JOB='MANAGER' THEN
DBMS_OUTPUT.PUT_LINE('ROW INSERTED');
INSERT INTO TEMP VALUES(A.ENAME,A.JOB,A.SAL);
COMMIT;
ELSIF A.JOB='ANALYST' THEN
DBMS_OUTPUT.PUT_LINE('ROW DELETED');
DELETE FROM EMP WHERE EMPNO=A.EMPNO;
COMMIT;
ELSIF A.JOB='SALESMAN' AND A.SAL*12>5000 THEN
DBMS_OUTPUT.PUT_LINE('ROW SALESMAN UPDATED');
UPDATE EMP SET SAL=SAL+300 WHERE EMPNO=A.EMPNO;
COMMIT;
ELSE

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DBMS_OUTPUT.PUT_LINE('NO CHANGES');
END IF;
END LOOP;
CLOSE C1;
END;
CREATE TABLE TEMP( A VARCHAR2(10),B VARCHAR2(10),C NUMBER(7,2));
6. EXAMPLE FOR %ISOPEN
DECLARE
CURSOR C1 IS SELECT * FROM EMP;
A C1%ROWTYPE;
BEGIN
IF C1%ISOPEN THEN
DBMS_OUTPUT.PUT_LINE('CURSOR ALREADY OPEN');
ELSE
DBMS_OUTPUT.PUT_LINE('CURSOR IS YET TO BE OPENED');
OPEN C1;
END IF;
LOOP
FETCH C1 INTO A;
EXIT WHEN C1%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(A.SAL||' '||A.ENAME||' '||A.JOB);
END LOOP;
CLOSE C1;
END;
6. B
IF NOT C1%ISOPEN
OPEN C1;
ELSE
DBMS_OUTPUT.PUT_LINE('CURSOR IS NOT OPEN');
END IF;
7.EXAMPLE FOR C1%ROWCOUNT display first 5 records
DECLARE cursor c1 is select * from emp; a c1%rowtype; begin open c1; loop fetch c1 into a; exit when c1%rowcount>6; dbms_output.put_line(a.ename||' '||a.sal||' '||a.job||'

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'||C1%ROWCOUNT); end loop; close c1; end;
7 B other method for above pgm
DECLARE cursor c1 is select * from emp; a c1%rowtype; begin open c1; loop fetch c1 into a; exit when c1%notfound; if c1%rowcount<=6 then dbms_output.put_line(a.ename||' '||a.sal||' '||a.job); end if; end loop; close c1; end;
8 display details of first 5 highly paid employees
DECLARE cursor c1 is select * from emp order by sal desc; a c1%rowtype; begin open c1; loop fetch c1 into a; exit when c1%rowcount>6; dbms_output.put_line(a.ename||' '||a.sal||' '||a.job||'
'||C1%ROWCOUNT); end loop; close c1;
end;
9. display only even rows
DECLARE cursor c1 is select * from emp ; a c1%rowtype; begin open c1; loop fetch c1 into a; exit when c1%notfound; if mod(c1%rowcount,2)=0 then dbms_output.put_line(a.ename||' '||a.sal||' '||a.job); end if; end loop; close c1; end;
(for odd rows change 0 to 1);

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10 display nth row
DECLARE cursor c1 is select * from emp ; a c1%rowtype; n number; begin
n:=&n;
open c1;
loop fetch c1 into a; exit when c1%notfound;
if c1%rowcount=n then
dbms_output.put_line(a.ename||' '||a.sal||' '||a.job); end if;
end loop;
close c1; end;
11 cursor using for loop declare
cursor c2 is select * from emp; begin
for a in c2 loop
dbms_output.put_line(a.ename||' '||a.sal||' '||a.job);
end loop; end;
12. IF ANNSAL>10000 AND JOB=CLERK INCOME TAX IS 10%,IF ANNSAL>15000 AND
JOB=SALESMAN TAX IS 20%,IF ANNSAL>10000 AND JOB=MANAGAER INCOME TAX IS
30%,ELSE A MESSAGE <10000 alter table emp add(it number(3)); declare
cursor c1 is select * from EMP;
a c1%rowtype; begin
open c1;
loop
fetch c1 into a;
exit when c1%notfound;
if a.sal*12>10000 and a.job='CLERK' THEN
UPDATE EMP SET IT=A.SAL*12*0.1 WHERE EMPNO=A.EMPNO;
ELSIF A.SAL*12>15000 AND A.JOB ='SALESMAN' THEN
UPDATE EMP SET IT=A.SAL*12*0.2 WHERE EMPNO=A.EMPNO;
ELSIF A.SAL*12>10000 AND A.JOB='MANAGER' THEN
UPDATE EMP SET IT=A.SAL*12*0.3 WHERE EMPNO=A.EMPNO;
ELSIF A.SAL*12<10000 THEN
DBMS_OUTPUT.PUT_LINE(A.ENAME||' '||'SAL< 10000');
END IF;
END LOOP;
COMMIT;
CLOSE C1;
END;

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13 CURSOR PARAMETERS TO PASS EMPLOYEE NUMBER AND GET THE DETAILS
DECLARE
CURSOR C1( z NUMBER) IS SELECT * FROM EMP WHERE DEPTNO=z;
A C1%ROWTYPE;
BEGIN
OPEN C1(&DEPTNO);
LOOP
FETCH C1 INTO A;
EXIT WHEN C1%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(A.ENAME||' '||A.DEPTNO||' '||A.SAL);
END LOOP;
CLOSE C1;
END;
14 TO PASS JOB AND GET THE DETAILS
DECLARE
CURSOR C1( A VARCHAR) IS SELECT * FROM EMP WHERE JOB=A;
A C1%ROWTYPE;
BEGIN
OPEN C1('&AJOB');
LOOP
FETCH C1 INTO A;
EXIT WHEN C1%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(A.JOB||' '||A.ENAME||' '||A.EMPNO||'
||A.SAL);
END LOOP;
CLOSE C1;
END;
NOTE :it will not take job in uppercase so upper(job)=upper(a)
15. TO PASS DESIGNATION AND DEPTNO AND GET THE DETAILS
DECLARE
CURSOR C1(A NUMBER,B VARCHAR) IS SELECT * FROM EMP
WHERE DEPTNO=A AND JOB=B;
A C1%ROWTYPE;
BEGIN
OPEN C1(&ADETNO,'&BJOB');
LOOP
FETCH C1 INTO A;
EXIT WHEN C1%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(A.ENAME||' '||A.JOB||' '||A.SAL||'
||A.DEPTNO);
END LOOP;
CLOSE C1;
END;

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16 CURSOR LOCKING
DECLARE
CURSOR C1 IS SELECT * FROM EMP FOR UPDATE OF SAL;
A C1%ROWTYPE;
BEGIN
OPEN C1;
LOOP
FETCH C1 INTO A;
EXIT WHEN C1%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(A.JOB||' '||A.ENAME||' '||A.SAL||'
'||A.DEPTNO);
IF A.JOB='CLERK' THEN
UPDATE EMP SET JOB='FDC' WHERE empno=a.empno;
end if;
end loop;
close c1; end;
17 EXAMPLE FOR IMPLICIT CURSORS
DECLARE
CURSOR C1 IS SELECT * FROM EMP;
A C1%ROWTYPE;
BEGIN
OPEN C1;
LOOP
FETCH C1 INTO A;
EXIT WHEN C1%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(C1%ROWCOUNT||' '||SQL%ROWCOUNT||'
'||A.ENAME);
END LOOP;
CLOSE C1;
END;
(YOU WILL NOT GET THE OUTPUT BECAUSE SQL%ROWCOUNT WILL RETURN A VALUE
ONLY WHEN THE PREVIOUS DML OPERATION IS SUCCESSFULLY COMPLETLE)
18. IMPLICIT CURSOR WITH INSERT
CREATE TABLE TEMP(A VARCHAR2(10),B NUMBER(7,2), C VARCHAR2(10));
DECLARE
CURSOR C2 IS SELECT * FROM EMP;
A C2%ROWTYPE;
BEGIN
OPEN C2;
LOOP
FETCH C2 INTO A;
EXIT WHEN C2%NOTFOUND;
INSERT INTO TEMP VALUES(A.ENAME,A.SAL,A.JOB);
IF SQL%FOUND THEN
DBMS_OUTPUT.PUT_LINE(SQL%ROWCOUNT||' '||C2%ROWCOUNT||' '||
A.SAL||' '||A.ENAME);
ELSE
EXIT;
END IF ;

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END LOOP;
CLOSE C2;
END;
19 DELETE WITH IMPLICIT CURSORS
DECLARE
BEGIN
DELETE FROM EMP WHERE DEPTNO=10;
DBMS_OUTPUT.PUT_LINE(SQL%ROWCOUNT);
END;
20. UPDATE AND SELECT WITH IMPLICIT CURSORS
DECLARE
A EMP%ROWTYPE;
BEGIN
SELECT * INTO A FROM EMP WHERE EMPNO=7788;
DBMS_OUTPUT.PUT_lINE('AFTER SELECT SQLCOUNT'|| ' '||SQL%ROWCOUNT);
UPDATE EMP SET DEPTNO=99 WHERE DEPTNO=10;
DBMS_OUTPUT.PUT_lINE('AFTER UPDATE SQLCOUNT'|| ' '||SQL%ROWCOUNT);
END;
OUTPUT IS
AFTER SELECT SQLCOUNT 1
AFTER UPDATE SQLCOUNT 3
21.DISPLAY NAMES OF EMPLOYEES WITH SAL IN DESCENDING ORDER WITHOUT
USING ORDER BY
DECLARE
CURSOR C1 IS SELECT * FROM EMP;
A C1%ROWTYPE;
N NUMBER;
BEGIN
OPEN C1;
SELECT MAX(SAL) INTO N FROM EMP;
LOOP
FETCH C1 INTO A;
EXIT WHEN C1%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(N);
SELECT MAX(SAL) INTO N FROM EMP WHERE SAL<N;
END LOOP;
CLOSE C1;
END;
22.DISPLAY JOB CATEGORIES ,COUNT(JOB) AND SUM(SAL) FROM EMP
DECLARE
CURSOR C1 IS SELECT JOB,COUNT(JOB) XY ,SUM(SAL) AB FROM EMP
GROUP BY JOB;
A C1%ROWTYPE;
BEGIN
OPEN C1;
LOOP
FETCH C1 INTO A;
EXIT WHEN C1%NOTFOUND;

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DBMS_OUTPUT.PUT_LINE('________________________________________________'
);
DBMS_OUTPUT.PUT_LINE(' JOB '||' NUMBER '||' SUM OF SAL
');
DBMS_OUTPUT.PUT_LINE(A.JOB||' '|| A.XY ||' '||
A.AB);
END LOOP;
CLOSE C1;
END;
DECLARE
CURSOR T1 IS SELECT * FROM TEST1;
TEST_REC T1%ROWTYPE;
BEGIN
FOR TEST IN T1
LOOP
UPDATE TEST1 SET AREA=400 WHERE RADIUS=50;
IF SQL%ROWCOUNT >0 THEN
DBMS_OUTPUT.PUT_LINE('RECORD IS ALREADY EXISTS');
ELSE
DBMS_OUTPUT.PUT_LINE('THERE IS NO RECORD');
END IF;
END LOOP;
END;
DECLARE
RDA AREAS.RADIUS%TYPE;
BEGIN
SELECT RADIUS INTO RDA FROM AREAS WHERE RADIUS =345;
EXCEPTION WHEN NO_DATA_FOUND THEN DBMS_OUTPUT.PUT_LINE('RECORD NOT
FOUND');
END;
Database objects
TABLES,VIEWS,SYNONYM,INDEX,CLUSTER,SEQUENCE,PROCEDURE,FUNCTION
PACKAGE,TRIGGER
 VIEWS
Virtual table changes reflected in table & viceversa no data of its own, no redundancy and security. A logical table based on one or more tables or views.
1.CREATE VIEW EV AS SELECT * FROM EMP;
2.CREATE VIEW EV1 AS SELECT ENAME,EMPNO,DEPTNO FROM EMP;
3.CREATE VIEW EV2(EMPNO,SALARY) AS SELECT EMPNO,SAL FROM EMP;
4.CREATE VIEW EM1 AS SELECT ENAME,SAL,DEPTNO,EMPNO,JOB
FROM EMP WHERE DEPTNO=20;
 READ ONLY VIEW
VIEWS WITH GROUP BY,ORDER BY ,AGG , PRIMARY KEY AND CHECK
CONSTRAINTS. THE VIEW BECOMES A READ ONLY VIEW.

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1.
CREATE VIEW EV AS SELECT DEPTNO,COUNT(*) COUNT FROM EMP GROUP BY
DEPTNO;
2.
CREATE VIEW EM1 AS SELECT ENAME,SAL,DEPTNO,EMPNO,JOB
FROM EMP WHERE DEPTNO=20 WITH CHECK OPTION CONSTRAINT CK1;
FORCED VIEWS
CREATE FORCE VIEW ABC AS SELECT EMPNO,ENAME,SAL FROM EMPOP;
SEE THE VIEWS
SELECT * FROM <view name>;
DROP VIEW ABC;
SELECT * FROM USER_VIEW;
CREATE VIEW MAG AS SELECT M.MNO,M.NAME,MA.GP,MA.NP FROM MAGI M,MAG MA ;
SYNONYMS
A synonym is an alternative name for a table,view, sequence, procedure, stored function.
1).Public synonym
2).Private synonym
CREATE SYNONYM Z FOR EMP;
CREATE PUBLIC SYNONYM VV FOR EMP;
DROP SYNONYM Z;
SELECT * FROM USER_SYNONYMS WHERE TABLE_NAME='EMP';
INDEXES
An index is a database object that contains an entry for each value that appears in the indexed column(s) of the table or cluster and provides direct, fast access to rows.
PRIMARY KEY AUTOMATICALLY INDEXED HAS ITS EFFECT ON LARGER TABLES
CREATE INDEX AB ON EMP(EMPNO);
SELECT * FROM USER_INDEXES WHERE TABLE_NAME='EMP';
IF YOU WANT TO INDEX A PRIMARY KEY COLUMN FIRST JUST DISABLE IT
DROP INDEX AB;
SEQUENCES
A sequence is a database object from which multiple users may generate unique integers.You can use sequences to automatically generate primary key values.

18
1.CREATE SEQUENCE S1 INCREMENT BY 10 START WITH 10 MAXVALUE 50
2.CREATE SEQUENCE S5 INCREMENT BY 10 START WITH 10 MAXVALUE 50
MINVALUE 5 CYCLE CACHE 2;
3.CREATE SEQUENCE S5 INCREMENT BY –2 START WITH 10 MAXVALUE 20
MINVALUE –5 CYCLE CACHE 2;
4.CREATE SEQUENCE S6 INCREMENT BY –2 START WITH 6 MAXVALUE 20
MINVALUE –4 CYCLE CACHE 2;
SELECT * FROM USER_SEQUENCES WHERE TABLE_NAME='EMP';
DROP SEQUENCE S6;
CLUSTERS
A cluster is a schema object that contains one or more tables that all have one or more columns in common.
1. create cluster c44(deptno number);
2. create table EMPC44(Eno number(9),deptno number,
SAL NUMBER(7,2),HIREDATE DATE)cluster c44(deptno);
3. create table DMPC44(deptno number,DNAME VARCHAR2(10),
LOC VARCHAR2(10))cluster c44(deptno);
4. create index c1i on cluster c4; tcl commands
grant, revoke grant privilege on tablename to username
(PRIVILEGES THAT CAN BE GRANTED ARE SELECT , UPDATE, DELETE, INSERT
ALTER,REFERENCE,INDEX)
1. GRANT SELECT ON EMP TO SAVITHA
2. GRANT SELECT ON EMP TO SAVITHA WITH GRANT OPTION
REVOKE ALL ON EMP FROM GEETHA;
COMMIT, ROLLBACK , SAVEPOINT
SQL> SELECT * FROM DEPT;
DEPTNO DNAME LOC
--------- -------------- -------------
10 ACCOUNTING NEW YORK
20 RESEARCH DALLAS
30 SALES CHICAGO
40 OPERATIONS BOSTON
50 CS MYSORE
SQL> SAVEPOINT A

19
2 ;
Savepoint created.
SQL> INSERT INTO DEPT VALUES(60,'IP','BANGALORE');
1 row created.
SQL> SAVEPOINT B;
Savepoint created.
SQL> INSERT INTO DEPT VALUES(70,'IT','GOA');
1 row created.
SQL> SELECT * FROM DEPT;
DEPTNO DNAME LOC
--------- -------------- -------------
10 ACCOUNTING NEW YORK
20 RESEARCH DALLAS
30 SALES CHICAGO
40 OPERATIONS BOSTON
50 CS MYSORE
60 IP BANGALORE
70 IT GOA
7 rows selected.
SQL> ROLLBACK TO SAVEPOINT B;
Rollback complete.
SQL> SELECT * FROM DEPT;
DEPTNO DNAME LOC
--------- -------------- -------------
10 ACCOUNTING NEW YORK
20 RESEARCH DALLAS
30 SALES CHICAGO
40 OPERATIONS BOSTON
50 CS MYSORE
60 IP BANGALORE
6 rows selected.

20
A database trigger is a stored PL/SQL program unit associated with a specific database table. Oracle executes (fires) the database trigger automatically whenever a given SQL operation affects the table.
So,unlike subprograms, which must be invoked explicitly, database triggers are invoked implicitly. Among other things, you can use database triggers to
 audit data modifications
 log events transparently
 enforce complex business rules
 derive column values automatically
 implement complex security authorizations
 maintain replicate tables .
CREATE TRIGGER <triggername> AFTER UPDATE/INSERT/DELETE OF
<COLUMN NAME> ON <TABLENAME> FOR EACH ROW
BEGIN
-----
END;
----- executable statements;
-----
-----
DATABASE TRIGGERS
1. WRITE A DATABASE TRIGGER WHICH WILLN'T ALLOW THE USER TO
INSERT,UPDATE OR DELETE BETWEEN NIGHT 7 AND MORNING 6
2. WRITE A DATABASE TRIGGER WHICH FIRES IF YOU TRY TO INSERT ,
UPDATE OR DELETE AFTER 7'O' CLOCK.
3. WRITE A DATABASE TRIGGER BEFORE INSERTING VALUES ON TO
EMP TABLE IF DEPTNO DOES NOT EXIST IN DEPT THEN RAISE THE ERROR.
4. WRITE A DATABASE TRIGGER TO ILLUSTRATE TABLE LEVEL AND
ROW LEVEL TRIGGERS.
5. WRITE A DATABASE TRIGGER WHICH ACTS JUST LIKE PRIMARY KEY
AND DOES NOT ALLOW DUPLICATE VALUE.
6. CREATE A DATABASE TRIGGER WHICH PERFORMS THE ACTION OF THE
ON DELETE CASCADE;
7. WRITE A DATABASE TRIGGER TO INSERT DISTINCT EMPLOYEE NUMBER TO
EMP TABLE (BEFORE INSERT)

21
8.
WRITE A DATABASE TRIGGER TO UPDATE THE SAL FIELD.IF SAL IS MORE
THAN 5000 OR LESS THAN 1000 THEN RAISE THE ERROR.(BEFORE UPDATE).
9.
WRITE A DATABASE TRIGGER WHERE WHEN CONDITION IS SPECIFIED. WHEN
JOB IS MANAGER THEN CHECK FOR SALARY. IF SAL IS <1000 THEN
RAISE THE ERROR.
10. WRITE A DATABASE TRIGGER WHICH SHOULD NOT DELETE FROM EMP TABLE
IF THE DAY IS SUNDAY.
11. WRITE A DATABASE TRIGGER WHICH SHOULD NOT ALLOW US TO UPDATE IF WE
ARE DOING TRANSACTIONS IN LAST DAY OF THE MONTH
12. WRITE A DATABASE TRIGGERS WHICH INSERTS THE EMPNO AND DEPTNO
INTO TEMP TABLE(AFTER INSERT)
13. WRITE A DATABASE TRIGGER USING INSERTING AND UPDATING WE SHOULD NOT
INSERT ON SUNDAY AND WE SHOULD NOT UPDATE ON LAST DAY OF THE MONTH.
14. UPDATE EMP TABLE AND CHANGE OLD DEPTNO TO NEW DEPTNO. IF OLD DEPTNO
IS 20 THEN DELETE FROM DEPT WHERE DEPTNO IS EQUAL TO NEW DEPTNO
15. WRITE A DATABASE TRIGGER TO DELETE FROM DEPT TABLE .AFTER DELETING
INSERT THE OLD VALUES TO A TABLE.
16. WRITE A DATABASE TRIGGER WHICH SHOULD NOT DELETE THE ROW IF THE
MONTH IS APRIL.
17. WRITE A DATABASE TRIGGER WHICH FIRES BEFORE PERFORMING INSERT
OR UPDATE OPERATIONS. IF THE JOB IS MANAGER THEN HIS SALARY
SHOULD BE IN THE GRADE 5.ELSE RAISE THE APPLICATION ERROR.
1. WRITE A DATABASE TRIGGER WHICH WILLN'T ALLOW THE USER TO
INSERT,UPDATE OR DELETE BETWEEN NIGHT 7 AND MORNING 6
CREATE OR REPLACE TRIGGER GEETIME BEFORE INSERT OR UPDATE
OR DELETE ON EMP for each row
DECLARE
A VARCHAR2(10);
BEGIN
--select to_char(sysdate,'hh24') into a from dual;
A:=TO_CHAR(SYSDATE,'HH24');
IF TO_NUMBER(A) > 19 OR TO_NUMBER(A) < 7 then
RAISE_APPLICATION_ERROR(-20500,'YOU CANT DO THIS OPERATION NOW');
END IF;
END;
2.WRITE A DATABASE TRIGGER WHICH FIRES IF YOU TRY TO INSERT ,UPDATE OR
DELETE AFTER 7'O' CLOCK
CREATE OR REPLACE TRIGGER GEETIME BEFORE INSERT OR UPDATE OR
DELETE ON EMP for each row
DECLARE
A VARCHAR2(10);

22
BEGIN
SELECT TO_CHAR(SYSDATE,'HH:MI') INTO A FROM DUAL;
IF A > '06:00' then
RAISE_APPLICATION_ERROR(-20500,'YOU CANT DO THIS
OPERATION
NOW');
END IF;
END;
2.WRITE A DATABASE TRIGGER BEFORE INSERTING VALUES ON TO
EMP TABLE IF DEPTNO DOES NOT EXIST IN DEPT THEN RAISE THE ERROR.
CREATE OR REPLACE TRIGGER IEMP BEFORE INSERT ON EMP
FOR EACH ROW
DECLARE
A NUMBER;
BEGIN
END;
SELECT COUNT(*) INTO A FROM DEPT WHERE
DEPTNO=:NEW.DEPTNO;
IF A=0 THEN
RAISE_APPLICATION_ERROR(-20300,'PARENT KEY IS NOT
EXISTING');
ELSE
PRINT('RECORD IS ALREADY INSERTED');
END IF;
OUTPUT OF THE QUERY IS AS BELOW
SQL> INSERT INTO EMP(EMPNO,DEPTNO) VALUES(23,44);
INSERT INTO EMP(EMPNO,DEPTNO) VALUES(23,44)
*
ERROR at line 1:
ORA-20300: PARENT KEY IS NOT EXISTING
ORA-06512: at "GEETHA.IEMP", line 6
ORA-04088: error during execution of trigger 'GEETHA.IEMP'
3.WRITE A DATABASE TRIGGER TO ILLUSTRATE TABLE LEVEL AND
ROW LEVEL TRIGGERS.
CREATE OR REPLACE TRIGGER UPTABLE BEFORE update ON EMP
BEGIN
DBMS_OUTPUT.PUT_LINE('UPDATE ON TABLE IS FIRED');
END;
CREATE OR REPLACE TRIGGER UPROW BEFORE UPDATE ON EMP
FOR EACH ROW
BEGIN
DBMS_OUTPUT.PUT_LINE('UPDATE ON ROW IS FIRED');
END;
4.WRITE A DATABASE TRIGGER WHICH ACTS JUST LIKE PRIMARY KEY AND DOES
NOT

23
ALLOW DUPLICATE VALUES
CREATE OR REPLACE TRIGGER PRIKEY BEFORE INSERT ON EMP
FOR EACH ROW
DECLARE
A NUMBER;
BEGIN
SELECT COUNT(*) INTO A FROM EMP WHERE EMPNO=:NEW.EMPNO;
IF A >=1 THEN
RAISE_APPLICATION_eRROR(-20500,'THE PRI KEY RULE IS
VOILATED');
ELSIF A=0 THEN
END IF;
END;
PRINT('RECORD IS INSERTED');
SQL> INSERT INTO EMP(EMPNO,DEPTNO) VALUES(7788,20);
INSERT INTO EMP(EMPNO,DEPTNO) VALUES(7788,20)
*
ERROR at line 1:
ORA-20500: THE PRI KEY RULE IS VOILATED
ORA-06512: at "GEETHA.PRIKEY", line 6
ORA-04088: error during execution of trigger 'GEETHA.PRIKEY'
SQL> INSERT INTO EMP(EMPNO,DEPTNO) VALUES(77,20);
1 row created.
5. CREATE A DATABASE TRIGGER WHICH PERFORMS THE ACTION OF THE
ON DELETE CASCADE;
CREATE OR REPLACE TRIGGER DELDEPT
AFTER DELETE ON DEPT FOR EACH ROW
BEGIN
DELETE FROM EMP WHERE DEPTNO=:OLD.DEPTNO;
PRINT('RECORDS IN EMP ARE ALSO DELETED');
END;
6.WRITE A DATABASE TRIGGER TO INSERT DISTINCT EMPLOYEE NUMBER TO
EMP TABLE (BEFORE INSERT)
CREATE OR REPLACE TRIGGER PRIM_UNIQUE
BEFORE INSERT ON emp FOR EACH ROW
DECLARE
NO NUMBER;
BEGIN
SELECT NVL(MAX(EMPNO),0)+1 INTO NO FROM EMP;
:NEW.EMPNO:=NO;
END;
7.WRITE A DATABASE TRIGGER TO UPDATE THE SAL FIELD.IF SAL IS MORE THAN
5000 OR LESS THAN 1000 THEN RAISE THE ERROR.(BEFORE UPDATE).
CREATE OR REPLACE TRIGGER CHECK_SAL BEFORE update ON emp

24
FOR EACH ROW
BEGIN
if :new.sal <1000 or :new.sal>5000 then
raise_application_error(-20001,'check sal ');
end if;
END;
8.WRITE A DATABASE TRIGGER WHERE WHEN CONDITION IS SPECIFIED.
WHEN JOB IS MANAGER THEN CHECK FOR SALARY. IF SAL IS <1000 THEN
RAISE THE ERROR.
CREATE OR REPLACE TRIGGER EMPNO_CHECK BEFORE INSERT ON emp
FOR EACH ROW when (NEW.job='MANAGER')
BEGIN
if :new.SAL<1000 THEN
raise_application_error(-20001,'PLEASE INCREASE THE SALARY
');
END; end if;
9.WRITE A DATABASE TRIGGER WHICH SHOULD NOT DELETE FROM EMP TABLE IF
THE DAY IS SUNDAY.
CREATE OR REPLACE TRIGGER EMPNO_CHECK
BEFORE DELETE ON emp
BEGIN
if to_char(sysdate,'dAy')='SUNDAY' then raise_application_error(-20001,'TO DAY IS SUNDAY '); end if;
END;
10.WRITE A DATABASE TRIGGER WHICH SHOULD NOT ALLOW US TO UPDATE IF WE
ARE DOING TRANSACTIONS IN LAST DAY OF THE MONTH
CREATE OR REPLACE TRIGGER EMPNO_CHECK
BEFORE UPDATE ON emp
BEGIN
if to_char(sysdate)=LAST_DAY(SYSDATE) then raise_application_error(-20001,'TO DAY IS LAST DAY OF MONTH'); end if;
END;
11.WRITE A DATABASE TRIGGERS WHICH INSERTS THE EMPNO AND DEPTNO
INTO TEMP TABLE(AFTER INSERT)
CREATE OR REPLACE TRIGGER AFTER_INS
AFTER INSERT ON emp
FOR EACH ROW
BEGIN
END;
INSERT INTO TEMP(EMPNO,DEPTNO)VALUES(:NEW.EMPNO,:NEW.DEPTNO);
12.WRITE A DATABASE TRIGGER USING INSERTING AND UPDATING WE SHOULD NOT
INSERT ON SUNDAY AND WE SHOULD NOT UPDATE ON LAST DAY OF THE MONTH.

25
CREATE OR REPLACE TRIGGER EMPNO_CHECK
BEFORE INSERT OR UPDATE ON emp
FOR EACH ROW
BEGIN
IF INSERTING THEN if to_char(sysdate,'dy')='mon' then raise_application_error(-20001,'TO DAY IS SUNDAY '); end if; end if;
IF UPDATING THEN if to_char(sysdate)=LAST_DAY(SYSDATE) then raise_application_error(-20001,'TO DAY IS MONTHY
LAST DAY so no updating '); end if;
END IF;
END;
13.UPDATE EMP TABLE AND CHANGE OLD DEPTNO TO NEW DEPTNO. IF OLD DEPTNO
IS 20 THEN DELETE FROM DEPT WHERE DEPTNO IS EQUAL TO NEW DEPTNO
CREATE OR REPLACE TRIGGER AFTER_UPDATE
AFTER UPDATE ON EMP
FOR EACH ROW
BEGIN
IF :OLD.DEPTNO=20 THEN
DELETE FROM DEPT WHERE DEPTNO=:NEW.DEPTNO;
END IF;
END;
14.WRITE A DATABASE TRIGGER TO DELETE FROM DEPT TABLE .AFTER DELETING
INSERT THE OLD VALUES TO A TABLE.
CREATE OR REPLACE TRIGGER AFTER_delete
AFTER delete ON DEPT
FOR EACH ROW
BEGIN insert into dept1 values(:old.deptno,:old.dname,:old.loc);
END;
15.WRITE A DATABASE TRIGGER WHICH SHOULD NOT DELETE THE ROW
IF THE MONTH IS APRIL.
CREATE OR REPLACE TRIGGER month_CHECK
BEFORE DELETE ON emp
BEGIN
if to_char(sysdate,'month')='july' then raise_application_error(-20001,'this month is holiday '); end if;
END;
16.WRITE A DATABASE TRIGGER WHICH FIRES BEFORE PERFORMING INSERT OR
UPDATE OPERATIONS. IF THE JOB IS MANAGER THEN HIS SALARY SHOULD BE

26
IN THE GRADE 5.ELSE RAISE THE APPLICATION ERROR. create or replace trigger jobgrade before insert or update of JOB,SAL on emp for each row when (new.job='MANAGER') declare lo number; hi number; begin select losal,hisal into lo,hi from salgrade where grade=5; if :new.sal>lo and :new.sal<hi then print('insert success'); else raise_application_error(-20500,'INsert operation not allowed'); end if; end;
EXTRA INFORMATION FOR MISS.MG create or replace trigger days before delete on emp declare a number:=to_number(to_char(sysdate,'d')) ; dummy varchar(20); begin if NOT a in(1,6) then raise_application_error(-20002,'today no transaction'); else begin end if; end; end; declare dummy varchar(20); select user into dummy from dual; if dummy <>'geetha' then raise_application_error(-20004,'NOT A PROPER USER'); else db('a proper user '); end if; begin select user into dummy from dual; if dummy <>'GEETHA' then raise_application_error(-20002,'today no transaction'); else db('a proper user '); end if; exception when no_data_found then

27 end; db('no data found');
CREATE OR REPLACE TRIGGER T2 BEFORE INSERT ON EMP FOR EACH ROW
DECLARE
A NUMBER;
BEGIN
SELECT COUNT(*) INTO A FROM EMP WHERE DEPTNO=:NEW.DEPTNO;
IF A>=1 THEN
RAISE_APPLICATION_ERROR(-20101,'PRIMARY KEY VIOLATION');
ELSE
DBMS_OUTPUT.PUT_LINE('VALUE INSERTED');
END IF;
END;
CREATE OR REPLACE TRIGGER DELDEPT
AFTER DELETE ON DEPT
FOR EACH ROW
BEGIN
DELETE EMP WHERE DEPTNO=:OLD.DEPTNO;
DBMS_OUTPUT.PUT_LINE('SDFSDF');
END;
CREATE OR REPLACE TRIGGER CHECK_SAL
BEFORE update ON emp
FOR EACH ROW
BEGIN
if :new.sal <1000 or :new.sal>5000 then
raise_application_error(-20001,'check sal ');
end if;
END;
EXCEPTION
---------
PRE-DEFINED :
-----------
NO_DATA_FOUND
TOO_MANY_ROWS
VALUE_ERROR A NUMBER(3) A:=1000;
INVALID_NUMBER A NUMBER A:='XXX'
CURSOR_ALREADY_OPEN
INVALID_CURSOR
ZERO_ERROR 100/0
STORAGE_ERROR
PROGRAM_ERROR
LOGIN_DENIED

28
DUP_VAL_INDEX VIOLATING UNIQUE
USER-DEFINED EXCEPTION
----------------------
---------------------------------------------------------------------
VALUE_ERROR:
-----------
DECLARE
S1 NUMBER;
BEGIN
A:=1000;
SELECT SAL INTO S1 FROM EMP WHERE EMPNO=700;
DBMS_OUTPUT.PUT_LINE(S1);
EXCEPTION
WHEN NO_DATA_FOUND THEN
DBMS_OUTPUT.PUT_LINE('NO SUCH EMPLOYEE');
WHEN VALUE_ERROR THEN
A:=100;
UPDATE EMP SET SAL=SAL+A;
END;
---------------------------------------------------------------------
USER-DEFINED EXCEPTION
----------------------
DECLARE
A1 EXCEPTION;
S1 EMP.SAL%TYPE;
BEGIN
SELECT SAL INTO S1 FROM EMP WHERE EMPNO=7900;
RAISE A1;
EXCEPTION
WHEN A1 THEN
UPDATE EMP SET SAL=S1+2000 WHERE EMPNO=7900;
END;
--------------------------------------------------------------------
DECLARE
RAD NUMBER;
AREA2 NUMBER;
BEGIN
SELECT RADIUS,AREA INTO RAD,AREA2 FROM TEST1 WHERE RADIUS IN(10,20);
DBMS_OUTPUT.PUT_LINE(RAD||AREA2);
EXCEPTION
WHEN TOO_MANY_ROWS THEN
DBMS_OUTPUT.PUT_LINE('TOO MANY ROWS');

29
END;
8.
9.
5.
6.
7.
PASSED
10.
3.
4.
1.
WRITE A FUCTION TO DISPLAY THE SYSTEM TIME AND THE
CORRESPONDING
PL/SQL BLOCK.
2.
(STORED FUNCTION)
WRITE A FUNCTION TO DISPLAY THE JOB WHEN THE NUMBER IS PASSED
WRITE A FUNCTION TO ACCEPT NAME AND PRINT JOB
WRITE A FUCTION TO ADD 2 NUMBERS.
(STORED FUNCTION)
WRITE A FUNCTION TO CHECK WHETHER NUMBER IS EVEN OR ODD
(LOCAL FUNCTION)
WRITE A FUNCTION TO GET SALARY WHEN NUMBER IS PASSED.
WRITE A FUNCTION TO ILLUSTRATE IN OUT PARAMETERS.
EXAMPLE FOR IN PARAMETER
WRITE A FUNCTION TO ILLUSTRATE OUT PARAMETER.
WRITE A FUNCTION TO DISPLAY NAME,JOB AND SALARY WHEN NUMBER IS
IF ANNSAL>10000 TAX IS 10%
IF ANNSAL>15000 TAX IS 20%
IF ANNSAL>20000 INCOME TAX IS 30%
ELSE
INCOME TAX IS ZERO.
WRITE A FUNCTION TO FIND THE FACTORIAL OF A NUMBER
WRITE A BLOCK TO CALCULATE GROSS SALARY WHEN NUMBER IS PASSED.
GROSS=BASIC+HRA(30%)+DA(50%)-PF(10%)

30
11.
WRITE A FUNCTION TO RETURN THE AVERAGE SALARY OF THE
EMPLOYEES.IF THE
NUMBER OF EMPLOYEES ARE MORE THAN 2 THEN ONLY CALCULATE THE
AVERAGE.
12. is write a pl/sql block to delete a record. If delete operation
13. successful return 1 else return 0. write a pl/sql block to pass the employee number and the increment amount.FUNCTION SHOULD RETURN THE NET SALARY.
14. write a pl/sql block to illustrate default as in parameter.
***********************************************************************
************
FUNCTIONS
~~~~~~~~~
1.
WRITE A FUCTION TO DISPLAY THE SYSTEM TIME AND THE CORRESPONDING
PL/SQL BLOCK.
CREATE OR REPLACE FUNCTION TIME1
RETURN VARCHAR IS
TIM VARCHAR(10);
BEGIN
SELECT TO_CHAR(SYSDATE,'HH:MI:SS') INTO TIM FROM DUAL;
RETURN TIM;
END;
DECLARE
AB VARCHAR(30);
BEGIN
AB:=TIME1;
DBMS_OUTPUT.PUT_lINE(AB);
END;
_______________________________________________________________________
__
2.(STORED FUNCTION)
WRITE A FUNCTION TO DISPLAY THE JOB WHEN THE NUMBER IS PASSED
CREATE OR REPLACE FUNCTION SAL (N NUMBER)
RETURN VARCHAR IS
DESIG EMP.JOB%TYPE;
BEGIN
SELECT JOB INTO DESIG FROM EMP WHERE EMPNO=N;
RETURN DESIG;

31
END;
SELECT SAL(&N) FROM DUAL;
IF YOU GIVE THE VALUE FOR N IMMEDIATELY VALUE WILL BE DISPLAYED.
DECLARE
A VARCHAR(10);
BEGIN
A:=SAL(&EMPNO);
DBMS_OUTPUT.PUT_LINE(A);
END;
_____________________
WRITE A FUNCTION TO ACCEPT NAME AND PRINT JOB
S
CREATE OR REPLACE FUNCTION FUN(N VARCHAR2)
RETURN VARCHAR2 IS
J VARCHAR2(10);
BEGIN
SELECT JOB INTO J FROM EMP WHERE ENAME=N;
RETURN J;
END;
Declare
A varchar2(25);
B varchar2(25);
Begin
A:= fun(&b);
Dbms_output.put_line(a);
End;
_______________________________________________________________________
__
3.(STORED FUNCTION)
WRITE A FUNCTION TO CHECK WHETHER NUMBER IS EVEN OR ODD
CREATE OR REPLACE FUNCTION EV_ODD(N NUMBER)
RETURN VARCHAR IS
BEGIN
IF MOD(N,2)=0 THEN
RETURN('NUMBER IS EVEN');
ELSE
RETURN('NUMBER IS ODD');
END IF;
END;
DECLARE
NO_TEST NUMBER:=&NO_TEST;
MES VARCHAR(25);
BEGIN
MES:=EV_ODD(NO_tEST);

32
DBMS_OUTPUT.PUT_LINE(MES);
END;
______________________
CREATE OR REPLACE FUNCTION ADD1(N1 NUMBER,N2 NUMBER)
RETURN NUMBER IS
RES NUMBER;
BEGIN
RES:=N1+N2;
RETURN RES;
END;
SELECT ADD1(2,3) FROM DUAL;
OR
YOU CAN ALSO HAVE A PL/SQL BLOCK TO EXECUTE THE FUNCTION.
_______________________________________________________________________
__
4.(LOCAL FUNCTION)
WRITE A FUNCTION TO GET SALARY WHEN NUMBER IS PASSED.
DECLARE
A NUMBER;
FUNCTION F1(N NUMBER) RETURN NUMBER
IS
SALARY EMP.SAL%TYPE;
BEGIN
SELECT SAL INTO SALARY FROM EMP WHERE EMPNO=N;
RETURN SALARY;
END;
BEGIN
A:=F1(&N);
DBMS_OUTPUT.PUT_LINE(A);
END;
_______________________________________________________________________
__
5.
WRITE A FUNCTION TO ILLUSTRATE IN OUT PARAMETERS. create or replace function FUN(n IN OUT number) return number IS
BEGIN
N:=N+10;
RETURN N;
END; declare n1 number :=10; n2 number;

33 begin
n2 :=fun(n1); dbms_output.put_line(n2); end;
_______________________________________________________________________
__
6.
EXAMPLE FOR IN PARAMETER
CREATE OR REPLACE FUNCTION FUN1(N IN NUMBER)
RETURN NUMBER IS
SALARY NUMBER;
BEGIN
SELECT SAL INTO SALARY FROM EMP WHERE EMPNO=N;
RETURN SALARY;
END;
DECLARE
SALARY NUMBER(7,2);
BEGIN
SALARY:=FUN1(7788);
DBMS_OUTPUT.PUT_lINE(SALARY);
END;
_______________________________________________________________________
__
7.
--WRITE A FUNCTION TO ILLUSTRATE OUT PARAMETER.
--WRITE A FUNCTION TO DISPLAY NAME,JOB AND SALARY WHEN NUMBER IS
PASSED
CREATE OR REPLACE FUNCTION FUN5(DESIG EMP.EMPNO%TYPE,SALARY OUT
EMP.SAL%TYPE,
S OUT EMP.JOB%TYPE)
RETURN VARCHAR2 IS
NAME VARCHAR(30);
BEGIN
SELECT ENAME,JOB,SAL INTO NAME,S,SALARY FROM EMP WHERE EMPNO=DESIG;
RETURN NAME;
EXCEPTION
WHEN OTHERS THEN
RETURN ('ERROR');
END;
DECLARE
A EMP.EMPNO%TYPE:=&EMPNO;
B VARCHAR(30);
C VARCHAR(30);
D NUMBER(8,2);
BEGIN

34
B:=FUN5(A,D,C);
DBMS_OUTPUT.PUT_LINE(A||' '||B||' '||C||' '||d);
END;
OUTPUT OF THE QUERY IS
Enter value for empno: 7900 old 2: A EMP.EMPNO%TYPE:=&EMPNO; new 2: A EMP.EMPNO%TYPE:=7900;
Commit complete.
7900 JAMES CLERK 950
_______________________________________________________________________
__
8.
IF ANNSAL>10000 TAX IS 10%
IF ANNSAL>15000 TAX IS 20%
IF ANNSAL>20000 INCOME TAX IS 30%
ELSE
INCOME TAX IS ZERO.
CREATE OR REPLACE FUNCTION INCOMETAX(N NUMBER)
RETURN NUMBER IS
SC NUMBER;
ANN NUMBER;
IT NUMBER;
BEGIN
SELECT SAL+NVL(COMM,0) INTO SC FROM EMP WHERE EMPNO=N;
ANN:=SC*12;
IF ANN>10000 AND ANN<15000 THEN
IT:=ANN*0.1;
ELSIF ANN>15000 AND ANN<20000 THEN
IT:=ANN*0.2;
ELSIF ANN>20000 THEN
IT:=ANN*0.3;
ELSE
IT:=0;
END IF;
RETURN IT;
END;
DECLARE
IT NUMBER;
BEGIN
IT:=INCOMETAX(&EMPNO);
DBMS_OUTPUT.PUT_LINE('INCOME TAX OF THE EMPLOYEE IS');
DBMS_OUTPUT.PUT_LINE(IT);
END;
_______________________________________________________________________
__
9.

35
--WRITE A FUNCTION TO FIND THE FACTORIAL OF A NUMBER
CREATE OR REPLACE FUNCTION FACT( N NUMBER) RETURN NUMBER IS
F NUMBER:=1;
BEGIN
FOR I IN 1..N LOOP
F:=F*I;
END LOOP;
RETURN F;
END;
DECLARE
RESULT NUMBER;
N NUMBER:=&N;
BEGIN
RESULT:= FACT(N);
DBMS_OUTPUT.PUT_LINE('FACTORIAL OF'|| N || 'IS'||RESULT);
END;
OR
SELECT FACT(4) FROM DUAL;
_______________________________________________________________________
__
10.
WRITE A BLOCK TO CALCULATE GROSS SALARY WHEN NUMBER IS PASSED.
GROSS=BASIC+HRA(30%)+DA(50%)-PF(10%)
CREATE OR REPLACE FUNCTION GROSS(N NUMBER) RETURN NUMBER IS
S NUMBER;
HRA NUMBER;
DA NUMBER;
PF NUMBER; gross NUMBER;
BEGIN
SELECT SAL INTO S FROM EMP WHERE EMPNO=N;
HRA:=S*0.3;
DA:=S*0.5;
PF:=S*0.1; gross:=S+HRA+DA-PF;
RETURN gross;
END;
DECLARE
GROSS1 NUMBER;
ENO NUMBER:=&EMPNO;
SALARY NUMBER;
BEGIN
SELECT SAL INTO SALARY FROM EMP WHERE EMPNO=ENO;
DBMS_OUTPUT.PUT_LINE('BEFORE FUNCTION CALL SALARY IS'||' '||SALARY);
GROSS1:=GROSS(ENO);
DBMS_OUTPUT.PUT_LINE('AFTER FUNCTION CALL SALARY IS'||' '||GROSS1);
END;

36
OR
SQL> SELECT GROSS(7934) FROM DUAL;
GROSS(7934)
-----------
2210
_______________________________________________________________________
__
11.
WRITE A FUNCTION TO RETURN THE AVERAGE SALARY OF THE
EMPLOYEES.IF THE
NUMBER OF EMPLOYEES ARE MORE THAN 2 THEN ONLY CALCULATE THE
AVERAGE.
CREATE OR REPLACE FUNCTION AVSAL(N NUMBER) RETURN NUMBER IS
CO1 NUMBER;
AG NUMBER;
BEGIN
SELECT COUNT(*) INTO CO1 FROM EMP WHERE DEPTNO=N;
IF N>2 THEN
SELECT AVG(SAL) INTO AG FROM EMP WHERE DEPTNO=N;
END IF;
RETURN AG;
END;
DECLARE
N NUMBER:=&DEPTNO;
ASAL NUMBER;
BEGIN
ASAL:=AVSAL(N);
DBMS_OUTPUT.PUT_lINE('AVERAGE SALARY OF DEPTNO'||' '||N||' IS
'||ASAL);
END;
_______________________________________________________________________
__
12.
--write a pl/sql block to delete a record. If delete operation --ISsuccessful return 1 else return 0. create or replace function fun3(n emp.empno%type) return number is a number; begin delete from emp where empno=n; if sql%found then return 1; else return 0; end if;
--exception

37
--when no_data_found then
--return 100; end; declare n number; begin n:=fun3(&empno); dbms_output.put_Line(n); if n=0 then dbms_output.put_line('deletion unsuccessfull'); elsif n=1 then dbms_output.put_line('deletion successfull'); end if; end;
_______________________________________________________________________
__
13. write a pl/sql block to pass the employee number and the increment amount . FUNCTION SHOULD RETURN THE NET SALARY create or replace function raise_sal(eno number,incre number) return number is a number; begin select count(*) into a from emp where empno=eno; if a=0 then raise_application_error(-20300,'employee does not exist'); else update emp set sal=sal+incre where empno=eno; select sal into a from emp where empno=eno; end if; return a; end; declare netsal number; begin netsal:=raise_sal(&empno,&salary); dbms_output.put_line('Net salary is'||' '||netsal); end;
_______________________________________________________________________
__
14. write a pl/sql block to illustrate default as in parameter. create or replace function def(n number default 7369) return number

38 is salary emp.sal%type; begin select sal into salary from emp where empno=n; return salary; end; select def from dual;
_______________________________________________________________________
__ functions : 1) single row functions
2) multiple row functions(group)(aggregate)
Single row functions

~~~~~~~~~~~~~~~~~~~~
1) ARITHMETIC
2) CHARACTER
3) GENERAL
4) DATE
5) CONVERSION
1 ARITHMETIC FUNCTIONS
~~~~~~~~~~~~~~~~~~~~
ABs ceil(>n) floor(<n) mod power sign sqrt trunc round
(SIN,COS,TAN,SINH,LOG,LN)
2 CHARACTER FUNCTIONS
~~~~~~~~~~~~~~~~~~~~~~~~~~~
INITCAP
LOWER
UPPER
LPAD
RPAD
SOUNDEX
LTRIM
RTRIM
SUBSTR
LENGTH
INSTR
3
CONCAT
GENERAL FUNCTIONS
~~~~~~~~~~~~~~~~~~~~~~~~~
NVL
DECODE
TRANSLATE
REPLACE
GREATEST
LEAST
4 DATE FUNCTIONS
~~~~~~~~~~~~~~~~~~~~~~~~~
SYSDATE
ADD_MONTHS
MONTHS_BETWEEN
LAST_DAY
NEXT_DAY
39

40
5 CONVERSION FUNCTIONS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
TO_DATE
TO_CHAR
TO_NUMBER
GROUP FUNCTIONS
~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~~~~
COUNT
SUM
MAX
MIN
AVG
SYMBOL DEFINITION
~~~~~~ ~~~~~~~~~~
D NUMBER OF DAY IN WEEK(1-7 STARTS WITH SUNDAY)
DD
DDD
DAY IN NUMBERS
NUMBER OF DAYS SINCE JAN1
DAY
DY
DAY FULLY SPELT OUT
FIRST 3 CHARACTERS OF THE DAY
MM MONTH IN NUMBERS
MONTH MONTH FULLY SPELT OUT
MON
WW
W
Y
YY
YYY
YYYY
YEAR
MONTH IN 3 LETTERS
NUMBER OF WEEKS OVER SINCE JAN 1
NUMBER OF WEEKS OVER IN THAT MONTH
1 DIGIT YEAR
2 DIGIT YEAR
3 DIGIT YEAR
4 DIGIT YEAR
YEAR FULLY SPELT OUT
HH
MI
SS
SSSS
HOUR
MINUTES
SECONDS
MILLISECONDS
HH24
HH12
FMDDSPTH
24 HOUR FORMAT
12 HOUR FORMAT
FMDDTH 1ST,2ND,3RD ----(ORDINAL FORMAT)
RM ROMAN NUMERAL MONTH
SPELLED FORMAT (FIRST, SECOND, THIRD)
4).
5).
GROUP BY AND HAVING CLAUSE
~~~~~~~~~~~~~~~~~~~~~~~~~~~
1). NUMBER OF EMPLOYEES DEPTNOWISE
2).
3).
SUM OF SALARIES DEPTNOWISE
NUMBER OF EMPLOYEES JOBWISE
SUM,MAX,MIN AND AVG OF SAL JOBWISE
AVG(SAL) DEPTNOWISE WITH SAL>4000

41 query to select nth record
~~~~~~~~~~~~~~~~~~~~~~~~~~~
Query to delete nth record
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
delete from emp where rowid in
( select rowid from emp where rownum<=&n minus select rowid from emp where rownum<=&n-1);
HBN select * from emp where rowid in
( select rowid from emp where rownum<=&n minus select rowid from emp where rownum<=&n-1);
display n records in between
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
CORRECT QUERY
~~~~~~~~~~~~~~
SELECT ROWNUM,ROWID,ENAME FROM EMP WHERE ROWNUM<=&N
MINUS
SELECT ROWNUM,ROWID,ENAME FROM EMP WHERE ROWNUM<=&N
(TRIALS)
~~~~~~~~~ select rownum,rowid,empno,ename,job FROM EMP A WHERE ROWID IN
(
(SELECT ROWID FROM EMP WHERE ROWNUM <=
(SELECT COUNT(*)-&N FROM EMP)) minus
(select rowid from emp where rownum<=
(select count(*) -&n from emp))
);
(SECOND TRIAL)
~~~~~~~~~~~~~~ select rownum,rowid,empno,ename,job FROM EMP A WHERE ROWID IN
(
(SELECT ROWID FROM EMP WHERE ROWNUM <

42
(SELECT COUNT(*)-&N FROM EMP)) minus
(select rowid from emp where rownum<=
(select count(*) -&n from emp))
);
(THIRD TRIAL)
~~~~~~~~~~~~~~~
DELETE FROM EMP A WHERE ROWID IN
(
( SELECT ROWID FROM EMP WHERE ROWNUM<=&N)
MINUS
(SELECT ROWID FROM EMP WHERE ROWNUM<=&N)
);
DISPLAY ALL THE DETAILS OF EMPLOYEES WHOSE JOB IS
SAME AS THAT OF JONES.
1. Display the Details of all Employees along with their
Department Information. select e.* ,d.dname,d.deptno,d.loc from emp e,dept d where e.deptno=d.deptno;
2. Display the Details of all Employees who are Getting Salary
Greater than the Salary of ADAMS select a.ename,a.sal,b.ename,b.sal from emp a,emp b where a.ename='FORD' AND B.SAL>A.SAL;
SELECT ENAME,SAL,JOB
FROM EMP
WHERE SAL>(SELECT SAL FROM EMP WHERE ENAME='ADAMS');
3. Display the details of all employees who are joined before 'FORD'
SELECT A.ENAME,A.SAL,A.HIREDATE,B.ENAME,B.SAL,B.HIREDATE
FROM EMP A,EMP B
WHERE A.ENAME='FORD' AND B.HIREDATE<A.HIREDATE;
SELECT * FROM EMP WHERE HIREDATE <(SELECT HIREDATE
FROM EMP WHERE ENAME='FORD');
4. Display the details of all the employees who are joined After SMITH
2 But Before Miller.
SELECT A.ENAME,A.HIREDATE ,B.HIREDATE,C.HIREDATE
FROM EMP A,EMP B,EMP C
WHERE B.ENAME='SMITH' AND C.ENAME='MILLER' AND

43
A.HIREDATE> B.HIREDATE AND A.HIREDATE<C.HIREDATE;
SELECT * FROM EMP WHERE HIREDATE
>(SELECT HIREDATE FROM EMP WHERE ENAME='SMITH') AND
HIREDATE <(SELECT HIREDATE FROM EMP WHERE ENAME='MILLER');
5. Display the Details of all employees along with their managers Name
AND
Employee Number.
SELECT A.EMPNO,A.ENAME,A.JOB,B.JOB"REPORT",B.ENAME "REPNAME"
FROM EMP A ,EMP B
WHERE A.MGR=B.EMPNO;
6. Display the Details of all employees working in the same Department
as 'FORD' select * from emp where deptno=(select deptno from emp where ename='FORD'); select a.ename,a.sal,a.job,a.deptno from emp a,emp b where a.deptno=b.deptno and b.ename='FORD';
7. Display the details of all the employees who are Getting the Less
commision than 'FORD.'. Consider NULL commision as '0'
SQL> SELECT A.ENAME,A.COMM,B.COMM,B.ENAME
2 FROM EMP A,EMP B
3 WHERE NVL(A.COMM,0) >NVL(B.COMM,0) AND B.ENAME='FORD';
ENAME COMM COMM ENAME
---------- --------- --------- ----------
ALLEN 300 FORD
WARD 500 FORD
MARTIN 1400 FORD
SELECT a.ename oriname,a.comm oricomm, b.ename,b.comm from emp a,emp b
WHERE A.COMM < B.COMM AND B.ENAME='MARTIN';
SELECT a.ename oriname,a.comm oricomm, b.ename,b.comm from emp a,emp b where NVL(a.comm,0)<NVL(b.comm,0) and b.ename='MARTIN';
8. Display the details of all the employees for whom the Ford is
the Manager.
SELECT A.ENAME ACTUALNAME,A.SAL,A.JOB,B.ENAME REPORTSTO ,B.SAL,
B.JOB
FROM EMP A,EMP B WHERE B.ENAME='FORD' AND A.MGR=B.EMPNO;

44
11.
9. Display the Details of all the employees who are joined in the
same month of FORD
SELECT A.ENAME,A.HIREDATE,B.ENAME,B.HIREDATE
FROM EMP A,EMP B
WHERE B.ENAME='FORD' AND TO_CHAR(A.HIREDATE,'MONTH')=
TO_CHAR(B.HIREDATE,'MONTH');
10. Display the details of all the employees who are in the
SALES Department
SELECT * FROM EMP WHERE DEPTNO=(SELECT DEPTNO
FROM DEPT WHERE DNAME='SALES');
SELECT A.ENAME,A.DEPTNO,A.JOB,B.DEPTNO,B.DNAME
FROM EMP A,DEPT B WHERE B.DNAME='SALES' AND
A.DEPTNO=B.DEPTNO;
Display the details of all the employees who are not ANALYSTS and Getting Salary Greeater than 'CLARK';
SELECT A.ENAME,A.JOB,A.SAL,B.ENAME,B.SAL,B.JOB
FROM EMP A,EMP B
WHERE A.JOB!='ANALYST' AND A.SAL >B.SAL AND
B.ENAME='CLARK';
SELECT * FROM EMP WHERE JOB NOT IN 'ANALYST' AND
SAL > (SELECT SAL FROM EMP WHERE ENAME='CLARK');
12. Display All the employee Names along with their Manager.
SELECT A.EMPNO,A.ENAME,A.JOB,B.ENAME MANAGER,B.JOB REPORTING
FROM EMP A,EMP B
WHERE A.MGR=B.EMPNO;
13. Display the Names of all the employees who are all getting the salary Greater than the salary of 'SMITH'
SELECT * FROM EMP WHERE SAL >(SELECT SAL FROM EMP
WHERE ENAME='SMITH');
SELECT A.ENAME,A.JOB,A.SAL,B.ENAME,B.SAL
FROM EMP A,EMP B
WHERE B.ENAME='SMITH' AND A.SAL > B.SAL;
14. Display the Names of all the employees who are all getting the
salary Greater than the salary of 'SMITH' along with the
difference in salary

45
SELECT A.ENAME,A.JOB,A.SAL,B.ENAME,B.SAL,A.SAL-B.SAL
FROM EMP A,EMP B
WHERE B.ENAME='SMITH' AND A.SAL>B.SAL ;
15. Display the details of all the employees whose sal is greater
than the average salary of the employees in their
respective deparments.
SELECT * FROM EMP A
WHERE SAL > ( SELECT AVG(SAL) FROM EMP B
WHERE A.DEPTNO=B.DEPTNO );
16. WRITE A QUERY TO PRINT THE MULTIPLICATION TABLE
SELECT &R || '*'||' ' ||LPAD(ROWNUM,4,' ')||' = '|| &R * ROWNUM
FROM EMP WHERE ROWNUM <= 10;
17. LIST FOLLOWING DETAILS FOR EMPLOYEES WHO EARN 36000/- A YEAR
OR ARE CLERKS
SELECT A.ENAME,A.JOB,A.SAL*12,B.DNAME
FROM EMP A,DEPT B
WHERE A.DEPTNO=B.DEPTNO AND A.SAL*12>30000
OR A.DEPTNO=B.DEPTNO AND A.JOB='CLERK';
18.
select ename,sal,
decode(sal,least(sal,1000),'<1000',
greatest(least(sal,2000)),'>1000 and <2000',
greatest(least(sal,3000)),'>2000 and <3000') from emp;
ENAME SAL DECODE(SAL,LEAS
---------- --------- ---------------
SMITH 800 <1000
ALLEN 1600 >1000 and <2000
WARD 1250 >1000 and <2000
JONES 2975 >2000 and <3000
MARTIN 1250 >1000 and <2000
BLAKE 2850 >2000 and <3000
CLARK 2450 >2000 and <3000
SCOTT 3000 >2000 and <3000
KING 5000
TURNER 1500 >1000 and <2000
ADAMS 1100 >1000 and <2000
JAMES 950 <1000
FORD 3000 >2000 and <3000
MILLER 1300 >1000 and <2000
/*SILLY*/
select sal,count(*) aa,
decode(sal,least(sal,1000),'<1000',
greatest(least(sal,2000)),'>1000 and <2000',
greatest(least(sal,3000)),'>2000 and <3000') from emp group by
decode(sal,least(sal,1000),'<1000',
greatest(least(sal,2000)),'>1000 and <2000',

46
greatest(least(sal,3000)),'>2000 and <3000'),sal;
OR
SELECT SAL,DECODE(FLOOR(SAL/1000),0,'<1000',1,'> 1000 AND < 2000',
3,'>2000 AND < 3000','> 3000') FROM EMP;
OR
(SANJAYA)
SELECT SAL,DECODE(GREATEST(SAL,1000),1000,'< 1000',
LEAST(SAL,2000), ' > 1000 AND < 2000',
LEAST(SAL,3000), '> 2000 AND < 3000',
LEAST(SAL,4000),' = 3000',' > 3000 ') FROM EMP;
19. display the details of all the employees whose salary is equal to
range as specified in grade 5.
select sal from emp where sal >
(select losal from salgrade where grade=5) and
sal< (select hisal from salgrade where grade=5);
20. CREATE A SEQUENCE AND GENERATE SOME NUMBERS .INSERT THESE NUMBERS
INTO THE TABLE BY CONCATENATING IT WITH E. create sequence s1 start with 1 increment by 1 maxvalue 10 insert into EM3(A) values
(concat('e',s12.nextval));
21.
select lpad(' ',level-1)||ename from emp
START WITH job = 'PRESIDENT'
CONNECT BY PRIOR EMPNO = MGR;
_______________________________________________________________________
END OF REPORT
_______________________________________________________________________ select a.sal,a.ename,a.deptno from emp a group by a.deptno having a.sal>all(select avg(sal) from emp b
from emp b
group by deptno); select distinct a.sal, a.ename, a.deptno from emp a,emp b

47 where a.deptno=b.deptno and a.sal >all(select avg(sal) from emp b group by deptno);
------------------------------------------------------------------- declare a number:=&a; b number:=&b; c number; begin c:=a*b; b:=a+b; a:=mod(c,b); dbms_output.put_line(' '||a); dbms_output.put_line(' '||b); dbms_output.put_line(' '||c); end; declare a number:=&a; n number; begin for i in 1..10 loop n:=a*i; dbms_output.put_line(a||'*'||i||'='||n); end loop; end; declare a number:=&a; b number; c number:=2; begin for i in 1..10 loop if a:=1 then b:=c+2; else b:=2+i; dbms_output.put_line(b); end if; end loop; end; declare

48 begin for i in 1..3 loop dbms_output.put_line('?'); dbms_output.new_line; dbms_output.put(?); end loop; end; declare a number(10); begin a:=1; dbms_output.put_line(a); a:=12; dbms_output.put_line(a); a:=123; dbms_output.put_line(a); a:=1234; dbms_output.put_line(a); a:=12345; dbms_output.put_line(a); a:=123456; dbms_output.put_line(a); a:=1234567; dbms_output.put_line(a); a:=12345678; dbms_output.put_line(a); a:=123456789; dbms_output.put_line(a); a:=1234567890; dbms_output.put_line(a); end; declare e1 number; e2 number; e3 number; val number; begin val:=&e3; select deptno into e2 from emp where empno=val; if e2=10 then update emp set comm=1000 where empno=val; elsif e2 = 20 then update emp set comm=2000 where empno=val; elsif e3=30 then update emp set comm=3000 where empno=val; end if; end; declare type type1 is record(eno number(4) not null:=7788,ena emp.ename%type); erec type1; begin select empno,ename into erec from emp where empno=7788; dbms_output.put_line(erec.eno||erec.ena); end; declare

49 salary emp.sal%type; mgr_num emp.mgr%type; emno emp.empno%type; enam emp.ename%type; begin select ename,empno,sal, mgr into enam,emno,salary,
mgr_num from emp where empno=7788; while salary<4000 loop update emp set sal=1000 where empno=mgr_num; end loop; insert into emp1 values(null,salary,enam); commit; end; declare no number; name varchar2(20); salary number(7,2); begin select ename,sal into name,salary from emp where empno=&no; insert into emp1 values(name,salary); end; declare str varchar2(20); rev varchar2(20); begin str:='&input'; if length(str)=0 then dbms_output.put_line('null'); else for i in 1..length(str) loop rev:=substr(str,i,1); end loop; end if; dbms_output.put_line('rev string' ||rev); end; declare a number; b number:=1; begin a:=&no; for i in 1..a loop b:=b*i; end loop; dbms_output.put_line(b); end;

50
I.
ORACLE WORKSHEET QUESTIONS
QUESTIONS BASED ON DATA DEFINITION LANGUAGE COMMANDS :
1: CREATE A TABLE EMP AND DEPT USING THE FOLLOWING INFORMATION:- a. DEPT :
COLUMN NAME DATATYPE(SIZE)
------------------------------- -------- -------------
DEPTNO NUMBER(2)
DNAME VARCHAR2(14)
LOC VARCHAR2(13)
-------------------------------------------------------- b.EMP:
2:
3:
COLUMN NAME DATATYPE(SIZE)
------------------------------- -------- ------------
EMPNO NUMBER(4)
ENAME VARCHAR2(10)
JOB VARCHAR2(9)
MGR NUMBER(4)
HIREDATE DATE
SAL NUMBER(7,2)
COMM NUMBER(7,2)
DEPTNO NUMBER(2)
CHECK THE DEFAULT SIZE OF A NUMBER,CHAR AND DATE DATATYPES
DESCRIBE THE STRUCTURE OF THE DEPT TABLE AND EMP TABLE
4: ADD TWO COLUMNS TO THE TABLE EMP WITH THE FOLLOWING
INFORMATION IN ONE SINGLE ALTER COMMAND :-
COLUMN NAME DATATYPE(SIZE)
--------------------------------------------------------------
SEX CHAR(1)
PLACE CHAR(15)
5: MODIFY THE COLUMN JOB PRESENT IN THE EMP TABLE
WITH THE FOLLOWING INFORMATION GIVEN BELOW :-
COLUMN NAME DATATYPE(SIZE)
-------------------------------------------------------
JOB VARCHAR2(15)
6: MODIFY THE COLUMN ENAME PRESENT IN THE EMP TABLE
WITH THE FOLLOWING INFORMATION GIVEN BELOW :-
COLUMN NAME DATATYPE(SIZE)
------------------------------------------------------
ENAME CHAR(15)
7: DECREASE THE SIZE FOR THE COLUMN EMPNO WITH THE FOLLOWING
INFORMATION :-
COLUMN NAME DATATYPE(SIZE)
--------------------------------------------------------
EMPNO NUMBER(2)

51
8: MODIFY THE COLUMN NAME OF EMPNO TO EMPLOYEE_NUMBER PRESENT
IN THE EMP TABLE VERIFY THE RESULT
9: ADD A NEW COLUMN NATIONALITY PLACED BETWEEN JOB AND MGR
COLUMNS
AND VERIFY THE RESULT
10:
11:
12:
DROP THE TABLE DEPT AND EMP
WHAT IS THE DATA TYPE OF THE COLUMN HIREDATE AND HOW MANY BYTES
IT OCCUPIES
QUESTIONS BASED ON CONSTRAINTS :
CREATE A TABLE EMP AND DEPT USING THE FOLLOWING INFORMATIOM a. DEPT :
COLUMN NAME DATATYPE(SIZE)
------------------------------- -------- -------------
DEPTNO NUMBER(2)CONSTRAINT PK_DEPTNO
PRIMARY
KEY,
DNAME VARCHAR2(14)
LOC VARCHAR2(13)
EMP :
COLUMN NAME DATATYPE(SIZE)
------------------------------- -------- ------------
EMPNO NUMBER(4)CONSTRAINT PK_EMPNO
PRIMARY
KEY,
UNIQUE,
ENAME VARCHAR2(10)CONSTRAINT UQ_ENAME
JOB VARCHAR2(9),
MGR NUMBER(4),
HIREDATE DATE DEFAULT SYSDATE,
SAL NUMBER(7,2)CONSTRAINT CK_SAL
CHECK(SAL>0) NN_SAL NOT NULL,
COMM NUMBER(7,2),
DEPTNO NUMBER(2)CONSTRAINT FK_DEPTNO
REFERENCES DEPT(DEPTNO)
13: SELECT ALL THE CONSTRAINTS IN EMP TABLE
SOL: SELECT * FROM USER_CONSTRAINTS WHERE TABLE_NAME='EMP';
14: SELECT THE OWNER,CONSTRAINT NAME,CONSTRAINT TYPE,TABLE
NAME,STATUS
FOR DEPT TABLE
SOL:
15:
SELECT OWNER,CONSTRAINT_NAME,CONSTRAINT_TYPE,TABLE_NAME,STATUS
FROM USER_CONSTRAINTS WHERE TABLE_NAME='DEPT';
DROP THE CONSTRAINT UQ_ENAME FROM EMP TABLE

52
SOL:
21:
SOL:
22:
SOL:
16:
SOL:
17:
SOL:
18:
SOL:
ALTER TABLE EMP DROP CONSTRAINT UQ_ENAME;
ADD A NEW COLUMN PINCODE WITH NOT NULL CONSTRAINT
TO THE EXISTING TABLE DEPT
ALTER TABLE DEPT ADD(PINCODE NUMBER(6) NOT NULL);
DISABLE THE CONSTRAINT PK_DEPTNO PRESENT IN DEPT TABLE
ALTER TABLE DEPT DISABLE CONSTRAINT PK_DEPTNO;
ENABLE THE CONSTRAINT PK_DEPTNO WHICH IS DEFINED IN THE
DEPTNO COLUMN OF DEPT TABLE
ALTER TABLE DEPT ENABLE CONSTRAINT PK_DEPTNO;
20:
II. QUESTIONS BASED ON DATA MANIPULATION LANGUAGE COMMANDS :-
PROBLEMS BASED ON INSERT COMMAND:-
INSERT THE GIVEN VALUES INTO THE TABLES: 19:
EMP:
(i)7369,SMITH,CLERK,7902,17-DEC-80,800,NULL,20
(ii)7499,ALLEN,SALESMAN,7698,20-FEB-81,1600,300,30
(iii)7521,WARD,SALESMAN,7698,22-FEB-81,1250,500,30
(iv)7566,JONES,MANAGER,7839,02-APR-81,2975,NULL,20
(v)7654,MARTIN,SALESMAN,7698,28-SEP-81,1250,1400,30
(vi)7698,BLAKE,MANAGER,7839,01-MAY-81,2850,NULL,30
(vii)7782,CLARK,MANAGER,7839,09-JUN-81,2450,NULL,10
(viii)7788,SCOTT,ANALYST,7566,19-NOV-96,3000,NULL,20
(ix)7839,KING,PRESIDENT,NULL,17-NOV-81,5000,NULL,10
(x)7844,TURNER,SALESMAN,7698,08-SEP-81,1500,0,30
(xi)7876,ADAMS,CLERK,7788,23-DEC-96,1100,NULL,20
(xii)7900,JAMES,CLERK,7698,03-DEC-81,950,NULL,30
(xiii)7902,FORD,ANALYST,7566,03-DEC-81,3000,NULL,20
(xiv)7934,MILLER,CLERK,7782,23-JAN-82,1300,NULL,10
(xv)7943,JOHN,CLERK,7943,10-DEC-83,2000,NULL,50
DEPT:
(i)10,ACCOUNTING,NEW YORK
(ii)20,RESEARCH,DALLAS
(iii)30,SALES,CHICAGO
(iv)40,OPERATIONS,BOSTON
(v)50,COMPUTER,AMERICA
INSERT ONLY THE RECORDS OF EMPLOYEE NUMBER,NAME,SALARY
INTO EMP TABLE
INSERT INTO EMP(EMPNO,ENAME,SAL) VALUES('7955','PAUL',1200);
INSERT TWO ROWS INTO EMP TABLE USING PARAMETER SUBSTITUTION
INSERT INTO EMP VALUES(&EMPNO,'&ENAME','&JOB',&MGR,'&HIREDATE',
&SAL,&COMM,&DEPTNO);
INSERT THE CURRENT TRANSACTION DATE TEMPORARY TABLE

53
SOL:
26:
SOL:
27:
SOL:
28:
NAMES
SOL:
23:
SOL:
24:
SOL:
25:
INSERT INTO TEMP VALUES(SYSDATE);
PROBLEMS ON SELECT COMMAND:-
LIST THE INFORMATION OF ALL EMPLOYEES
SELECT * FROM EMP;
LIST THE INFORMATION OF ALL THE DEPARTMENTS
SELECT * FROM DEPT;
LIST THE DEPARTMENT NUMBERS,EMPLOYEE NUMBERS AND THEIR MANAGERS
NUMBERS
SELECT DEPT.DEPTNO,EMP.EMPNO,EMP.MGR FROM EMP,DEPT;
LIST DEPARTMENT NAME AND LOCATIONS FROM DEPT TABLE
SELECT DNAME,LOC FROM DEPT;
LIST THE INFORMATION OF EMPLOYEES AND THEIR DEPARTMENTS
IN A SINGLE DML COMMAND
SELECT * FROM EMP;
COPY ALL THE RECORDS OF THREE COLUMNS EMPNO,ENAME,JOB FROM EMP
TABLE AND INSERT THE RECORDS INTO A TEMP TABLE WITH COLUMN
SAME AS EMPNO,ENAME,JOB
SOL:
29:
SOL:
SOL:
33:
INSERT INTO TEMP(EMPNO,ENAME,JOB)
SELECT EMPNO,ENAME,JOB
LIST THE DETAILS OF BOTH THE TABLES
SELECT * FROM EMP,DEPT;
30:
SOL:
LIST THE INFORMATION OF ALL THE EMPLOYEES PRESENT IN THE USER
NAMED SCOTT
SELECT * FROM SCOTT.EMP;
31: LIST THE INFORMATION OF ALL THE DEPARTMENTS FROM YOUR
BATCHMATES
DEPT TABLE
SOL:
32:
SELECT * FROM ORA252P.DEPT;
LIST OUT ALL THE TABLE NAMES IN YOUR SCHEMA
SELECT * FROM TAB;
LIST ALL THE SYSTEM TABLES

54
SOL:
34:
A
SOL:
35:
36:
SOL:
37:
SELECT * FROM SYS.DICTIONARY;
GET THE INFORMATION OF THE MAXIMUM AVAILABLE BLOCKS ALLOTED TO
PARTICULAR USER FOR CREATING TABLES FROM THE SYSTEM TABLES
SELECT * FROM USER_TS_QUOTAS;
LIST OUT ALL THE PRIVILAGES GIVEN TO A PARTICULAR USER
LIST OUT ALL THE TABLES WHICH START WITH 'S'
SELECT TABLE_NAME FROM USER_TABLES WHERE TABLE_NAME LIKE 'S%';
COPY THE STRUCTURE OF DEPT TABLE ALONE TO A TEMPORARY TABLE
CALLED TEMP1
SOL:
38:
CREATE TABLE TEMP1 AS SELECT * FROM DEPT WHERE 1=2;
PROBLEMS ON UPDATE COMMAND:-
UPDATE THE SALARY BY 10% HIKE TO ANALYSTS WORKING IN DEPARTMENT
NUMBER 20 AND 30
SOL:
39:
SOL: UPDATE EMP SET SAL=SAL+(SAL*0.5) WHERE JOB='SALESMAN';
40: PROMOTE ALL THE EMPLOYEES DESCRIBED AS SALESMAN TO SALES
OFFICER
IF THEIR GROSS SALARY PER MONTH IS GREATER THAN 3000
SOL:
41:
UPDATE EMP SET SAL=SAL+(SAL*0.1) WHERE DEPTNO IN (10,20)
AND JOB='ANALYST';
GIVE 5% RAISE IN SALARY TO ALL THE SALESMAN
UPDATE EMP SET JOB='SALES OFFICER' WHERE JOB='SALESMAN'
AND SAL>3000;
GIVE ALL THE EMPLOYEES A COMMISSION OF RS.500
44:
SOL:
45:
SOL:
SOL:
42:
UPDATE EMP SET COMM=500;
CHANGE THE DEPARTMENT OF JAMES TO 20
SOL: UPDATE EMP SET DEPTNO=20 WHERE ENAME='JAMES';
43. CALCULATE ALL THE EMPLOYEES TOTAL SALARY WITH COMMISION
SOL: SELECT SAL+NVL(COMM) "TOTAL" FROM EMP;
PROBLEMS ON DELETE COMMAND:-
DELETE ALL THE RECORDS OF EMPLOYEES
DELETE FROM EMP;
GET BACK THE ORIGINAL RECORDS OF EMPLOYEES BACK
ROLLBACK;

55
46:
SOL:
47:
SOL:
48:
SOL:
49:
DELETE ALLEN'S RECORD ONLY
DELETE FROM EMP WHERE ENAME='ALLEN';
DELETE RECORDS OF ENAME COLUMN ONLY AND VERIFY IT
NOT POSSIBLE
DELETE THE RECORDS OF EMPLOYEE NUMBER 7782
DELETE FROM EMP WHERE EMPNO=7782;
DELETE THE EMPLOYEE'S RECORDS WHO DOES'NT HAVE COMMISION
SOL:
50:
SOL:
51:
DELETE FROM EMP WHERE COMM IS NULL;
GET BACK THE ORIGINAL RECORDS
ROLLBACK;
DELETE THE DUPLICATE RECORDS OF THE EMPLOYEE TABLE
SOl:
52:
SOL:
DELETE FROM EMP A
WHERE ROWID<>(SELECT MIN(ROWID) FROM EMP B
WHERE A.EMPNO=B.EMPNO);
DELETE THE FIRST FIVE RECORDS OF EMPLOYEE TABLE
53:
SOL:
DELETE FROM EMP X
WHERE 5>(SELECT COUNT(ROWID) FROM EMP Y WHERE Y.ROWID<X.ROWID);
( OR )
DELETE FROM EMP WHERE ROWNUM <6;
DELETE THE ROWS OF THE TEMP TABLE PERMANENTLY
TRUNCATE TABLE TEMP;
III.
54:
PROBLEMS ON TRANSACTIONAL COMMANDS :-
SOL:
55:
SOL:
UPDATE A RECORD OF EMP TABLE AND SAVE THE CHANGES PERMANENTLY
IN THE DATABASE
UPDATE EMP SET SAL=SAL+100 WHERE EMPNO=100;
COMMIT;
SQL*PLUS HAS THE FACILITY TO AUTOMATICALLY SAVE ALL THE
RECORDS, WITHOUT ISSUING THE TCL COMMAND WHICH IS THAT
SET AUTOCOMMIT ON
56: GIVE ALL THE PRIVILAGES YOU HAVE OF A DATABASE OBJECT TO
ANOTHER
USER

56
63:
SOL:
64:
SOL:
65:
SOL:
66:
SOL:
67:
SOL:
57:
SOL:
58:
SOL:
59:
SOL:
IV.
GRANT ALL ON EMP TO ORA253A;
GIVE ONLY SELECT,INSERT PRIVILAGES TO ANOTHER USER
GRANT SELECT,INSERT ON EMP TO ORA267A;
LIST THE USER'S ID AND WHICH DATABASE OBJECT YOU HAVE GRANTED
SELECT * FROM USER_TAB_PRIVS;
GET BACK THE PRIVILAGES BACK FROM THE USER
REVOKE ALL ON EMP FROM ORA267A;
PROBLEMS BASED ON OPERATORS :-
60:
SOL:
PROBLEMS BASED ON ARITHMETIC,RELATIONAL,LOGICAL AND
CHARACTER OPERATORS:-
LIST ALL THE EMPLOYEES SALARY WITH COMMISSION PROVIDE A NEW
HEADING AS TOTAL SALARY
SELECT SAL+NVL(COMM,0) "TOTAL SALARY" FROM EMP ;
61:
NUMBER
GIVE THE SALARY WITH A REDUCTION OF 10% FROM THEIR SALARY TO
PERSONS WHOSE JOB IS CLERK AND AND BELONGING TO DEPARTMENT
30
SOL: UPDATE EMP SET SAL=SAL-(0.1*SAL) WHERE JOB='CLERK' AND
DEPTNO=30;
62:
SOL:
LIST THE EMPLOYEES BELONGING TO DEPARTMENT 20
SELECT * FROM EMP WHERE DEPTNO=20;
LIST THE NAME AND SALARY OF THE EMPLOYEES WHOSE SALARY IS
LESS THAN 3000
SELECT ENAME,SAL FROM EMP WHERE SAL<3000;
LIST THE NAME AND SALARY OF THE EMPLOYEES WHOSE SALARY IS
GREATER THAN 3000
SELECT ENAME,SAL FROM EMP WHERE SAL>3000;
LIST THE EMPLOYEE NUMBER AND NAME OF MANAGERS
SELECT EMPNO,ENAME FROM EMP WHERE JOB='MANAGER';
LIST THE EMPLOYEES WHOSE SALARY IS NOT EQUAL TO 3000
SELECT * FROM EMP WHERE SAL!=3000;
LIST THE EMPLOYEE NAME AND SALARY WHOSE SALARY IS BETWEEN
2000 AND 3000

57
SOL:
75:
SOL:
76:
SOL:
77:
DOES
SOL:
78:
SOL:
79:
SOL:
80:
SOL:
72:
3000
SOL:
73:
SOL:
AND
74:
SOL:
68:
1981
SOL:
69:
SOL:
70:
SOL:
71:
SELECT ENAME,SAL FROM EMP WHERE SAL>=2000 AND SAL<=3000;
LIST ALL THE EMPLOYEES WHO HAVE JOINED BEFORE 30TH SEPTEMBER
SELECT * FROM EMP WHERE HIREDATE<='30-SEP-81';
LIST THE NAMES OF EMPLOYEES WHO ARE NOT MANAGERS
SELECT ENAME FROM EMP WHERE JOB<>'MANAGER';
LIST ALL THE EMPLOYEES BELONGING TO THE DEPARTMENT 10,30
SELECT * FROM EMP WHERE DEPTNO IN(10,30);
LIST ALL EMPLOYEES NOT BELONGING TO MANAGER,PRESIDENT
SELECT * FROM EMP WHERE JOB NOT IN ('MANAGER','PRESIDENT');
LIST EMPLOYEES NAME AND JOB WHOSE SALARY IS BETWEEN 2000 AND
SELECT ENAME,JOB FROM EMP WHERE SAL BETWEEN 2000 AND 3000;
LIST THE EMPLOYEE NAMES AND THEIR DESIGNATION WHO HAVE JOINED
BEFORE 30TH JUNE '81 AND AFTER DECEMBER '81
SELECT ENAME FROM EMP WHERE HIREDATE NOT BETWEEN '30-JUN-81'
'31-DEC-81';
LIST THE EMPLOYEE NAMES WHO ARE NOT ELIGIBLE FOR COMMISSION
SELECT ENAME FROM EMP WHERE COMM IS NULL;
LIST THE EMPLOYEE NAMES WHO ARE ELIGIBLE FOR COMMISSION
SELECT ENAME FROM EMP WHERE COMM IS NOT NULL;
LIST ALL THE EMPLOYEE NAMES BETWEEN THE LETTER 'M' AND 'O'
SELECT * FROM EMP WHERE ENAME BETWEEN 'M' AND 'O';
LIST THE NAME OF THE EMPLOYEE AND JOB OF THE EMPLOYEE , WHO
NOT BELONGS TO ANY BODY
SELECT ENAME,JOB FROM EMP WHERE MGR IS NULL;
LIST THE EMPLOYEES WHOSE NAMES START WITH AN "S"
SELECT ENAME FROM EMP WHERE ENAME LIKE 'S%';
LIST THE EMPLOYEE NAMES ENDING WITH "S"
SELECT ENAME FROM EMP WHERE ENAME LIKE '%S';
LIST THE EMPLOYEES WHOSE NAMES HAVE EXACTLY 5 CHARACTERS

58
88:
SOL:
89:
SOL:
90:
SOL:
91:
SOL:
DUAL;
92:
SOL:
93:
SOL:
3000
SOL:
85:
SOL:
86:
30
SOL:
87:
SOL:
SOL:
81:
SOL:
82:
SOL:
83:
SOL:
84:
SELECT ENAME FROM EMP WHERE ENAME LIKE '_ _ _ _ _';
LIST THE EMPLOYEE NAMES HAVING 'I' AS THE SECOND CHARACTER
SELECT ENAME FROM EMP WHERE ENAME LIKE '_I%';
LIST THE DIFFERENT JOBS AVAILABLE IN THE EMP TABLE
SELECT DISTINCT JOB FROM EMP;
LIST THE DISTINCT JOB FROM EMP IN DEPARTMENT 30
SELECT DISTINCT JOB FROM EMP WHERE DEPTNO=30;
LIST THE EMPLOYEE NAME,SALARY, WHOSE SALARY IS BETWEEN 2000 AND
SELECT ENAME,SAL FROM EMP WHERE SAL>=2000 AND SAL<=3000;
LIST THE NAMES OF ANALYSTS AND SALESMAN
SELECT ENAME FROM EMP WHERE JOB='SALESMAN' OR JOB='ANALYST';
LIST THE EMPLOYEE NAMES WHOSE JOB IS CLERK AND DEPTARTMENT IS
SELECT ENAME FROM EMP WHERE JOB='CLERK' AND DEPARTMENT=30;
DISPLAY ALL THE EMPLOYEE NAMES IN THE FORMAT AS "NAME IS ALLEN"
SELECT 'NAME IS '||ENAME FROM EMP;
DISPLAY THE ABSOLUTE VALUE OF -25
SELECT ABS(-25) "ABSOLUTE" FROM DUAL;
DISPLAY THE SMALLEST INTEGER GREATER THAN OR EQUAL TO 16.7
SELECT CEIL(16.7) "CEILING" FROM DUAL;
DISPLAY THE GREATEST INTEGER LESSER THAN OR EQUAL TO 15.34
SELECT FLOOR(15.34) "FLOOR" FROM DUAL;
DISPLAY THE COSINE OF THE ANGLE IN DEGREES
SELECT COS(180*3.14159265359/180)"COSINE OF 180 DEGREES" FROM
DISPLAY THE HYPERBOLIC COSINE OF 0
SELECT COSH(0) "HYPERBOLIC COSINE OF 0 " FROM DUAL;
DISPLAY THE EXPONENTIAL POWER OF THE VALUE 7
SELECT EXP(7) "e TO THE 7TH POWER " FROM DUAL;

59
103:
SOL:
104:
SOL:
105:
SOL:
DUAL;
106:
94:
SOL:
95:
SOL:
96:
NUMBER
SOL:
97:
DISPLAY THE NATURAL LOGARITHM OF 75
SELECT LN(75) "NATURAL LOG OF 75" FROM DUAL;
DISPLAY THE LOGARITHM, BASE 10, OF 100
SELECT LOG(10,100) "LOG BASE 10 OF 100" FROM DUAL;
DISPLAY REMAINDER ZERO WHEN A NUMBER IS DIVIDED BY AN EVEN
SELECT MOD(10,2) "MODULUS" FROM DUAL;
CHECK THE O/P WHEN A VALUE M>N IN A MOD FUNCTION AND NOTE DOWN
THE REASON FOR THAT KIND OF O/P
SOL:
98:
SELECT MOD(2,10) "MODULUS" FROM DUAL;
DISPLAY THE VALUE WHEN 9 RAISED TO 2
SOL: SELECT POWER(9,2) "RAISED AS " FROM DUAL;
99:
FORWARD
DISPLAY THE VALUE FOR 15.193 ROUNDED TO FIRST DECIMAL PLACE
SOL: SELECT ROUND(15.193,1) "ROUND" FROM DUAL;
100: DISPLAY THE VALUE FOR 15.193 ROUNDED TO FIRST DECIMAL PLACE
BACKWARDS
SOL: SELECT ROUND(15.193,-1) "ROUND" FROM DUAL;
101: DISPLAY THE SIGN OF -15
SOL:
102:
SOL:
DUAL;
SELECT SIGN(-15) FROM DUAL;
DISPLAY THE SINE OF ANGLE 30 DEGREES
SELECT SIN(30*3.14159265359/180) "SINE OF 30 DEGREES" FROM
DISPLAY THE HYPERBOLIC SINE OF 1
SELECT SINH(1) "HYPERBOLIC SINE OF 1 " FROM DUAL;
DISPLAY THE SQUARE ROOT OF THE VALUE 25
SELECT SQRT(25) "SQUARE ROOT " FROM DUAL;
DISPLAY THE TANGENT OF THE VALUE 135 IN DEGREES
SELECT TAN(135*3.14159265359/180)"TANGENT OF 135 DEGREES" FROM
TRUNCATE THE VALUE 15.79 TO FIRST DECIMAL PLACES

60
115:
SOL:
116:
SOL:
117:
SOL:
118:
SOL:
SOL:
107:
SOL:
108:
SQL:
111:
SELECT TRUNC(15.79,1)" TRUNCATE " FROM DUAL;
TRUNCATE THE VALUE 15.79 TO FIRST DECIMAL PLACE N DIGITS
LEFT TO THE DECIMAL POINT
SELECT TRUNC(15.79,-1)"TRUNCATE" FROM DUAL;
DISPLAY THE CHARACTER VALUE FOR THE NUMBER 75
SOL:
109:
SELECT CHR(75) "CHARACTER " FROM DUAL;
110:
DISPLAY THE ENAME AND JOB OF EMPNO=7900 IN THE FORMAT eg:- ALLEN IS A SALESMAN
SQL: SELECT ENAME || ' IS A ' || JOB FROM EMP;
CAPITALISE THE FIRST LETTER OF "the soap "
SELECT INITCAP(' brainware infotech(p) ltd') from dual;
DISPLAY THE WORDS IN LOWER CASE LETTERS
SELECT LOWER('BRAINWARE INFOTECH(P) LTD') FROM DUAL; SQL:
112:
SQL:
113:
DISPLAY THE LEFT PADDED CHAR'S TO THE STRING BRAINWARE WHEN
THE RETURN VALUE IS 15 AND PADDED CHARACTER IS '*'
SELECT LPAD('BRAINWARE',15,'*') FROM DUAL;
DISPLAY THE RIGHT PADDED CHAR'S TO THE STRING BRAINWARE WHEN
THE RETURN VALUE IS 15 AND PADDED CHARACTER IS '*'
SQL:
114:
SQL:
SELECT RPAD('BRAINWARE',15,'*') FROM DUAL;
REMOVE CHARAECTER 'RE' TOWARDS RIGHT OF THE STRING
FROM THE LETTER 'BRAINWARE'
SELECT RTRIM('BRAINWARE','RE') FROM DUAL;
REMOVE CHARAECTER 'IN' TOWARDS LEFT OF THE STRING
FROM THE LETTER 'BRAINWARE'
SELECT LTRIM('INFOTECH','IN') FROM DUAL;
REPLACE THE CHARACTER 'J' WITH 'BL' FROM THE WORD
JACK AND JUE
SELECT REPLACE('JACK AND JUE','J','BL') FROM DUAL;
DISPLAY THE ENAME WITH THE PHONETIC REPRESENTATION OF
'SMYTHE' FROM TABLE EMP
SELECT ENAME FROM EMP WHERE SOUNDEX(ENAME)=SOUNDEX('SMYTHE');
DISPLAY THE FIRST THREE LETTERS OF THE EMPLOYEE NAMES
SELECT SUBSTR(ENAME,1,3) FROM emp;

61
119:
SOL:
120:
DISPLAY THE CHARACTERS 'AR' FROM THE WORD 'BRAINWARE'
SELECT SUBSTR('BRAINWARE',-3,2) FROM DUAL;
CONVERT ALL THE CHARACTERS WHICH IS 'ABC..Z' TO LETTER 'T'
AND ALL DIGITS '012..9' TO DIGIT '9' FROM THE GIVEN CHARACTER
'0123KASL'
SOL: SELECT
TRANSLATE('0123KASL','0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ',
'9999999999TTTTTTTTTTTTTTTTTTTTTTTTTT') from dual;
121:
SOL:
122:
SOL:
DISPLAY THE ASCII VALUE OF THE CHARACTER 'A'
SELECT ASCII('A') FROM DUAL;
DISPlay THE ASCII VALUE OF CHARACTER'S 'AB' FROM DUAL
SELECT ASCII('AB') FROM DUAL
HINT:ASCII WILL DISPLAY ONLY THE FIRST LETTER 'A' ONLY
123:
SOL:
124:
DISPLAY THE 3RD OCCURRENCE OF CD AT THE THIRD OCCURRENCE OF
WORD "ABCDABCDABCDJJ"
SELECT INSTR('ABCDABCDABCDJJ','CD',3,3) FROM DUAL;
DISPLAY THE LENGTH OF THE WORD 'ALLEN'
SOL:
125:
SOL:
126:
128:
1992"
SOL:
SELECT LENGTH('ALLEN') FROM DUAL;
DISPLAY THE DATE OF THE NEXT TUESDAY AFTER MARCH 15,1992.
SELECT NEXT_DAY('15-MAR-92','TUESDAY') "NEXT DAY" FROM DUAL;
DISPLAY THE LAST DAY OF THIS MONTH
SOL:
127:
SELECT LAST_DAY(SYSDATE) FROM DUAL;
DISPLAY THE DIFFERENCE DATE BETWEEN CURRENT DATE AND LAST DAY
OF THE SYSDATE
SOL:
SYSDATE
SELECT SYSDATE,LAST_DAY(SYSDATE) "LAST",LAST_DAY(SYSDATE)-
"DAYS LEFT" FROM DUAL;
DISPLAY THE DIFFERENCE OF TWO DATES "02-02-1992" AND "01-01-
SELECT MONTHS_BETWEEN(TO_DATE('02-02-1992','DD-MON-YYYY'),
TO_DATE('01-01-1992','DD-MON-YYYY')) FROM DUAL;
129: DISPLAY THE CURRENT DATE AND TIME
SOL:
130:
SELECT TO_CHAR(SYSDATE,'DD-MON-YY HH24:MI:SS') FROM DUAL;
ADD TWO MONTHS TO SYSDATE

62
SOL:
135:
SOL:
136:
SOL:
137:
SOL:
SOL:
131:
SOL:
132:
SOL:
133:
SOL:
134:
SELECT TO_CHAR(SYSDATE,2) FROM DUAL;
ADD 10 DAYS TO SYSDATE
SELECT TO_CHAR(TO_DATE(SYSDATE,'DD-MON-YY'),'DD')+10 FROM DUAL;
DISPLAY THE NUMBER FORMAT OF THE NUMBER 1234
SELECT TO_NUMBER('1234') FROM DUAL;
CONVERT ROWID OF EMPLOYEE NAME SMITH TO EMPLOYEE NAME
SELECT ENAME FROM EMP WHERE ROWID='00000707.0000.000D';
DISPLAY THE SYSTEM DATE AS "MON DD YYYY"
SELECT TO_CHAR(SYSDATE,'MON DD YYYY') FROM DUAL;
DISPLAY THE CURRENT DATE IN THE FORMAT DDTH MONTH YYYY
SELECT TO_CHAR(SYSDATE,'FMDDTH MONTH YYYY') FROM DUAL;
CONVERT THE FOLLOWING STRING TO ORACLE DATE FORMAT.
"12-AUGUST-97"
SELECT TO_DATE('12-AUGUST-97','DD-MONTH-YY') FROM DUAL;
DISPLAY THE USERNAME IN WHICH YOU ARE WORKING
SELECT USER FROM DUAL;
138:
SOL:
DISPLAY TH USERID NUMBER IN WHICH YOU ARE WORKING
SELECT UID FROM DUAL;
139: DISPLAY THE GREATEST OF THE LIST OF EXPRESSIONS "HARRY"
"HARRIOT"
"HAROLD"
SELECT GREATEST('HARRY','HARRIOT','HAROLD') FROM DUAL; SOL:
140: DISPLAY THE LEAST OF THE LIST OF EXPRESSIONS "HARRY" "HARRIOT"
"HAROLD"
SOL: SELECT LEAST('HARRY','HARRIOT','HAROLD') FROM DUAL;
141: DISPLAY ALL THE ENAMES WHERE COMMISSION IS NULL AND PLACE
THE EXPRESSION " NOT POSSIBLE " IN DEPTARTMENT 30 WHERE
COMMISSION
IS NULL ELSE DISPALY THEIR COMMISSION
SOL:
142:
SELECT ENAME,NVL(TO_CHAR(COMM),'NOT POSSIBLE') "COMMISSION"
FROM EMP WHERE DEPTNO=30;
DISPLAY THE GREENWICH TIME OF 05:15 A.M

63
146:
SOL:
147:
SOL:
148:
SOL:
149:
SOL:
SOL: SELECT
TO_CHAR(NEW_TIME(TO_DATE('05:15','HH24:MI'),'PST','GMT'),
'HH24:MI') FROM DUAL;
143:
SESSION
DISPLAY THE LANGUAGE AND TERRITORY CURRENTLY USED BY YOUR
SOL: SELECT USERENV('LANGUAGE') FROM DUAL;
144:
SOL:
145:
SOL:
DISPLAY THE NUMBER OF BYTES EACH EMPLOYEE OCCUPIES INTERNALLY
SELECT VSIZE(ENAME) "BYTES" FROM EMP;
DISPLAY THE AVERAGE SALARY DEPARTMENTWISE
SELECT AVG(SAL),DEPTNO FROM EMP GROUP BY DEPTNO;
DISPLAY THE SUMMATION OF SALARIES DEPARTMENTWISE
SELECT SUM(SAL),DEPTNO FROM EMP GROUP BY DEPTNO;
DISPLAY THE SUMMATION OF SALARIES OF FIRST FIVE RECORDS
SELECT SUM(SAL) FROM EMP WHERE ROWNUM<=5;
DISPLAY THE MINIMUM SALARY IN THE TABLE EMP
SELECT MIN(SAL) FROM EMP;
DISPLAY THE MAXIMUM SALARY FROM THE TABLE EMP
SELECT MAX(SAL) FROM EMP;
150:
SOL:
151:
SOL:
DISPLAY ALL THE SALARIES SUPRESSING THE DUPLICATES
SELECT DISTINCT SAL FROM EMP;
DISPLAY ALL THE JOB SUPRESSING THE DUPLICATES
SELECT DISTINCT JOB FROM EMP;
152:
SOL:
DISPLAY NUMBER OF RECORDS PRESENT IN EMP TABLE
SELECT COUNT(*) FROM EMP;
153:
SOL:
DISPLAY THE NUMBER OF JOBS IN EMP TABLE
SELECT COUNT(JOB) FROM EMP;
154: DISPLAY NUMBER OF RECORDS FOR DESIGNATION SUPRESSING THE
DUPLICATES
SOL:
155:
SOL:
SELECT COUNT(DISTINCT JOB) FROM EMP;
DISPLAY THE MINIMUM HIREDATE HIRED FOR EMPLOYEES
SELECT MIN(HIREDATE) FROM EMP;

64
SOL:
163:
SOL:
164:
SOL:
165:
SOL:
166:
SOL:
160:
SOL:
161:
SOL:
162:
156:
SOL:
157:
SOL:
158:
SOL:
DUAL;
159:
CALCULATE THE STANDARD DEVIATION OF SALARIES FROM EMP TABLE
SELECT STDDEV(SAL) FROM EMP;
CALCULATE THE VARIANCE OF ALL THE SALARIES FROM EMP TABLE
SELECT VARIANCE(SAL) FROM EMP;
DISPLAY THE YEAR 2017
SELECT TO_CHAR(TO_DATE('27-NOV-25','DD-MON-RR'),'YYYY') FROM
IF DEPARTMENT NUMBER IS 10 DISPLAY GOODCHOICE ELSE
DISPLAY BADCHOICE IN ALL OTHER DEPARTMENT FIELDS
SELECT DECODE(DEPTNO,10,'GOODCHOICE','BADCHOICE') FROM EMP;
PROBLEMS ON JOINS:-
LIST THE DEPARTMENT NAME,EMPLOYEES NAME,EMPLOYEE NUMBER
SELECT EMP.EMPNO,EMP.ENAME,DEPT.DNAME FROM EMP,DEPT;
WHERE EMP.DEPTNO=DEPT.DEPTNO;
LIST THE TOTAL SALARIES OF EACH DEPARTMENT
SELECT EMP.DEPTNO,SUM(SAL) FROM EMP,DEPT
WHERE EMP.DEPTNO=DEPT.DEPTNO GROUP BY EMP.DEPTNO;
LIST THE TOTAL EMPLOYEES SALARIES WHO DOES NOT BELONG
TO ANY DEPARTMENT
SELECT DEPTNO,SUM(SAL) FROM EMP,DEPT
WHERE EMP.DEPTNO=DEPT.DEPTNO(+);
LIST THE MANAGER'S NAME AND EMPLOYEES NAME WHO BELONGS TO
THEIR MANAGER'S
SELECT M.ENAME||' '||'IS THE MANAGER FOR'||' '|| E.ENAME
FROM EMP E,EMP M WHERE E.MGR=M.EMPNO;
LIST THE EMPLOYEES WHOSE SALARIES
BETWEEN 2000 AND 3000
SELECT * FROM EMP WHERE EMPNO IN (SELECT EMPNO
FROM EMP WHERE SAL BETWEEN 2000 AND 3000);
LIST THE DEPARTMENT NAME OF THE EMPLOYEE WHOSE NAME
IS OF JONES
SELECT DEPT.DNAME FROM EMP,DEPT
WHERE EMP.DEPTNO=DEPT.DEPTNO AND ENAME LIKE 'JONES%';
LIST THE DEPARTMENT OF THE EMPLOYEES

65
SOL:
171:
SOL:
SOL: SELECT * FROM EMP
WHERE DEPTNO =ANY(SELECT DEPTNO FROM DEPT);
167: FIND OUT THE EMPLOYEES WITH SAME JOB AS JONES
SOL: SELECT ENAME,JOB FROM EMP
INTERSECT
SELECT ENAME,JOB FROM EMP
WHERE JOB IN (SELECT JOB FROM EMP WHERE ENAME LIKE 'JONES%');
168: DISPLAY INFORMATION ABOUT EMPLOYEES WHO EARN MORE THAN ANY
EMPLOYEES IN DEPARTMENT 30
SOL:
169:
SOL:
SELECT * FROM EMP
WHERE SAL>ALL(SELECT SAL FROM EMP WHERE DEPTNO=30);
LIST ALL THE EMPLOYEES IN DEPARTMENT NUMBER 10 WITH THE
SAME JOB AS IN DEPARTMENT NUMBER 30
SELECT ENAME FROM EMP WHERE DEPTNO=10
INTERSECT
SELECT ENAME FROM EMP
WHERE JOB IN (SELECT JOB FROM EMP WHERE DEPTNO=30);
170: LIST THE EMPLOYEES WITH EITHER THE SAME JOB AS JONES
OR SALARY GREATER THAN OR SAME AS FORD
SELECT ENAME FROM EMP
INTERSECT
SELECT ENAME FROM EMP
WHERE JOB IN(SELECT JOB FROM EMP WHERE ENAME LIKE 'JONES%'
OR SAL>=(SELECT SAL FROM EMP WHERE ENAME LIKE 'FORD%'));
LIST THE EMPLOYEES IN DEPARTMENT 10 WITH THE SAME
JOB AS ANY ONE IN SALES DEPARTMENT
SELECT ENAME,JOB FROM EMP
WHERE JOB IN (SELECT JOB FROM EMP WHERE DEPTNO=10)
INTERSECT
SELECT ENAME,JOB FROM EMP
WHERE DEPTNO IN (SELECT DEPTNO FROM EMP WHERE JOB='SALESMAN');
172:
SOL:
LIST EMPLOYEES WHOSE SALARY IS SAME AS THAT OF SCOTT OR WARD
SELECT ENAME FROM EMP
173: TO LIST THE DEPARTMENT THAT HAS NO EMPLOYEES
SOL: SELECT DEPTNO FROM DEPT
MINUS
SELECT DEPTNO FROM EMP;
(OR)

66
SOL:
179:
SOL:
180:
SOL:
181:
SOL:
182:
SOL:
176:
SOL:
177:
178:
174:
SOL:
175:
SELECT DEPTNO FROM DEPT
WHERE DEPTNO NOT IN
(SELECT DEPTNO FROM EMP);
TO LIST THE DEPARTMENT AND COUNT OF JOB
IN WHICH THERE ARE MORE THAN ON SALESMANS.
SELECT DEPTNO,JOB,COUNT(*) FROM EMP
WHERE JOB='SALESMAN'
GROUP BY DEPTNO,JOB
HAVING COUNT(*)>1;
LIST THE DEPARTMENT IN WHICH THEIR ARE MORE THAN ONE
SALESMAN
SELECT DEPTNO,JOB FROM EMP WHERE JOB='SALESMAN'
AND DEPTNO IN (SELECT DEPTNO FROM EMP GROUP BY DEPTNO
HAVING COUNT(JOB)>1);
SELECT THE EVEN NUMBER OF ROWS FROM EMPLOYEE TABLE
SELECT * FROM EMP
WHERE ROWID IN
(SELECT DECODE(MOD(ROWNUM,2),0,ROWID,NULL) FROM EMP);
LIST THE ODD NUMBER OF ROWS FROM EMPLOYEE TABLE
SELECT * FROM EMP
WHERE ROWID IN
(SELECT DECODE(MOD(ROWNUM,2),1,ROWID,NULL) FROM EMP);
DELETE THE ODD NUMBER ROWS FROM EMPLOYEE TABLE
DELETE FROM EMP
WHERE ROWID IN
(SELECT DECODE (MOD(ROWNUM,2),1,ROWID,NULL) FROM EMP);
DELETE THE EVEN NUMBER ROWS FROM EMPLOYEE TABLE
DELETE FROM EMP
WHERE ROWID IN
(SELECT DECODE (MOD(ROWNUM,2),0,ROWID,NULL) FROM EMP);
LIST THE EMPLOYEES WHOSE SALARY IS GREATER THAN THE
AVERAGE SALARY OF HIS DEPARTMENT
SELECT DEPTNO,EMPNO,SAL FROM EMP X WHERE
SAL>(SELECT AVG(SAL) FROM EMP Y WHERE X.DEPTNO=Y.DEPTNO);
QUERY DEPARTMENTWISE AVERAGE/MAXIMUM/MINIMUM SALARIES
SELECT EMP.DEPTNO,DNAME,MAX(SAL),MIN(SAL),AVG(SAL)
FROM EMP,DEPT
WHERE EMP.DEPTNO=DEPT.DEPTNO
GROUP BY EMP.DEPTNO,DNAME;
COUNT THE NUMBER OF MALE AND FEMALE EMPLOYEES

67
SOL:
187:
SOL:
188:
SOL:
SOL: ALTER TABLE EMP
ADD (SEX CHAR(1));
SELECT SEX,COUNT(*)
FROM EMP
GROUP BY SEX
HAVING SEX ='M';
UNION
SELECT SEX,COUNT(*)
FROM EMP
GROUP BY SEX
HAVING SEX='F';
183: DISPLAY THE YEAR AND NUMBER OF EMPLOYEES FOR THE YEAR
IN WHICH MORE THAN ONE EMPLOYEE WAS HIRED
SOL: SELECT TO_CHAR(HIREDATE,'YYYY') YEAR,COUNT(*)
FROM EMP GROUP BY TO_CHAR(HIREDATE,'YYYY')
HAVING COUNT(*)>1;
184:
SOL:
DELETE THE DUPLICATE ROWS FROM DEPT TABLE.
DELETE FROM DEPT
WHERE DEPTNO IN
(SELECT DEPTNO
FROM DEPT
GROUP BY DEPTNO
HAVING COUNT(DEPTNO)>1);
185:
SOL:
DELETE THE DUPLICATE ROWS EXCEPT ITS MINIMUM VALUE
DELETE FROM EMP A
WHERE ROWID<>(SELECT MIN(ROWID) FROM EMP B
WHERE A.EMPNO=B.EMPNO);
186: LIST LAST FIVE RECORDS FROM EMP TABLE
SELECT ENAME,SAL FROM EMP MINUS SELECT ENAME,SAL FROM EMP
WHERE ROWNUM<(SELECT MAX(ROWNUM)-4 FROM EMP );
LIST THE THIRD HIGHEST SALARY FROM EMP TABLE
SELECT MAX(SAL) FROM EMP WHERE
SAL<(SELECT MAX(SAL) FROM EMP WHERE
SAL<(SELECT MAX(SAL) FROM EMP));
LIST FIVE EMPLOYEES IN LOWEST ORDER OF SALARY
SELECT ENAME,SAL FROM EMP
MINUS
SELECT ENAME,SAL FROM EMP WHERE
SAL>(SELECT MIN(SAL) FROM EMP WHERE
SAL>(SELECT MIN(SAL) FROM EMP WHERE

68
193:
SOL:
194:
SOL:
195:
SOL:
196:
SOL:
191:
SOL:
192:
SOL:
189:
SOL:
190:
SOL:
SAL>(SELECT MIN(SAL) FROM EMP WHERE
SAL>(SELECT MIN(SAL) FROM EMP))));
LIST THE GIVEN RANGE OF RECORDS AS PER THE STORAGE OF
ROWS IN A GIVEN DATABASE TABLE NAMED EMP
SELECT ROWID FROM EMP X WHERE NOT &N>(SELECT COUNT(ROWID)
FROM EMP Y WHERE Y.ROWID<X.ROWID)
INTERSECT
SELECT ROWID FROM EMP X WHERE &M>=(SELECT COUNT(ROWID)
FROM EMP Y WHERE Y.ROWID<X.ROWID);
LIST THE NTH HIGHEST SALARY IN THE EMPLOYEE TABLE
SELECT DISTINCT SAL FROM EMP WHERE
SAL=(SELECT DISTINCT SAL FROM EMP X WHERE &N=(SELECT
COUNT(DISTINCT SAL) FROM EMP Y WHERE Y.SAL>X.SAL));
LIST THE NTH LOWEST SALARY IN THE EMPLOYEE TABLE
SELECT DISTINCT SAL FROM EMP X WHERE
&N=(SELECT COUNT(DISTINCT SAL) FROM EMP Y
WHERE X.SAL>Y.SAL);
LIST EMPLOYEES IN THE EMPLOYEE TABLE ACCEPTING THOSE
FIRST FIVE AND LAST THREE IN THE ORDER OF DATA STORAGE
SELECT ROWID FROM EMP X WHERE 5>(SELECT COUNT(ROWID)
FROM EMP Y WHERE Y.ROWID<X.ROWID)
UNION
SELECT ROWID FROM EMP X WHERE 3 >(SELECT COUNT(ROWID)
FROM EMP Y
WHERE Y.ROWID>X.ROWID);
LIST THE TREE STRUCTURED QUERY WITH EMPLOYEE NAME STARTING
WITH KING
SELECT LPAD(' ',6*(LEVEL-1))||ENAME NAME FROM EMP
START WITH ENAME='KING'
CONNECT BY MGR=PRIOR EMPNO;
LIST THE EMPLOYEES WHOSE SALARY GREATER THAN OR EQUAL TO
AVERAGE SALARY OF DEPARTMENT NUMBER 10
SELECT SAL,ENAME FROM EMP
WHERE SAL>=(SELECT AVG(SAL) FROM EMP
GROUP BY DEPTNO HAVING DEPTNO=10);
SELECT ALL THE ENAMES WITH THE OCCURANCES OF THE LETTER 'S'
SELECT INSTR(ENAME,'A') FROM EMP;
LIST THE DIFFERENT DESIGNATIONS IN DEPARTMENT 20 AND 30
SELECT DISTINCT JOB FROM EMP
WHERE DEPTNO=20

69
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SOL:
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SOL:
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SOL:
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SOL:
UNION
SELECT DISTINCT JOB FROM EMP
WHERE DEPTNO=30;
LIST THE JOBS COMMON IN DEPARTMENT 20 AND 30
SELECT JOB FROM EMP
WHERE DEPTNO=20
INTERSECT
SELECT JOB FROM EMP
WHERE DEPTNO=30;
LIST THE JOBS UNIQUE TO DEPARTMENT 20
SELECT JOB FROM EMP
WHERE DEPTNO=20
MINUS
SELECT JOB FROM EMP
WHERE DEPTNO=10
MINUS
SELECT JOB FROM EMP
WHERE DEPTNO=30;
LIST THE EMPLOYEES IF AND ONLY IF MORE THAN 10 EMPLOYEES ARE
PRESENT IN DEPARTMENT NUMBER 10
SELECT * FROM EMP
WHERE EXISTS (SELECT DEPTNO,COUNT(*) FROM EMP
WHERE DEPTNO=10
GROUP BY DEPTNO
HAVING COUNT(*)>=3);
LIST THE EMPLOYEE NAMES WHOSE SALARY IS GREATER THAN THE
LOWEST SALARY OF AN EMPLOYEE BELONGING TO DEPARTMENT 20
SELECT ENAME FROM EMP
WHERE SAL>ANY(SELECT SAL FROM EMP WHERE DEPTNO=20);
LIST THE EMPLOYEE NAMES WHOSE SALARY IS GREATER THAN THE
HIGHEST SALARY OF AN EMPLOYEE BELONGING TO DEPARTMENT NUMBER 20
SELECT ENAME FROM EMP
WHERE SAL>ALL(SELECT SAL FROM EMP WHERE DEPTNO=20);
CREATE A VIEW WITH COLUMNS EMPNO AND A 10% HIKE SALARY COLUMN
AND TRY TO INSERT A ROW IN THIS VIEW AND VERIFY IT
CREATE VIEW EMPSAL AS SELECT EMPNO,SAL*.1 TOT_SAL FROM EMP;
HINT: THE FOLLOWING VIEWS ARE READ - ONLY VIEWS i.e NO INSERT OR UPDATE THROUGH THESE VIEWS IS POSSIBLE
THIS IS A READ - ONLY VIEW BECAUSE OF THE PRESENCE
OF AN AGGREGATE FUNCTION
CREATE A VIEW WITH THE COLUMNS EMPNO,ENAME,DEPTNO SELECTED

70
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SOL:
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SOl:
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SOL:
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SOL:
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SOL:
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SOL:
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SOL:
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SOL:
FROM THE TABLE EMP AND CORRESPONDING DEPARTMENT NUMBER 30
INSERT ROWS INTO THIS VIEW AND VERIFY THE RESULT
CREATE VIEW EMPDEPT AS
SELECT EMPNO,ENAME,DEPTNO FROM EMP WHERE DEPTNO=30;
HINT: THIS IS NOT A READ - ONLY VIEW. ROWS CAN BE INSERTED
INTO THE EMP TABLE USING THIS VIEW , BUT CANNOT BE VIEWED
BY THE EMPDEPT VIEW AS THE VIEW CAN ONLY RETRIEVE ROWS
BELONGING TO DEPARTMENT 30
CREATE A VIEW WITH COLUMNS EMPNO,ENAME,DEPTNO AND DEPTNO=30
WITH A CHECK OPTION AND INSERT A ROW INTO THE VIEW WITH
DEPARTMENT NUMBER 20 AND VERIFY THE RESULT
CREATE VIEW EMPDEPT1 AS
SELECT EMPNO,ENAME,DEPTNO FROM EMP
WHERE DEPTNO=30
WITH CHECK OPTION;
DERIVE A VIEW FROM ANOTHER VIEW HAVING CHECK OPTION
CREATE VIEW EMPDEPT2 AS
SELECT EMPNO,ENAME,DEPTNO FROM EMPDEPT1;
LIST ALL THE VIEW NAMES CREATED IN YOUR LOGIN
SELECT * FROM USER_VIEWS;
CREATE A SIMPLE SEQUENCE
CREATE SEQUENCE S1 INCREMENT BY 1 START WITH 1000;
INSERT THE SEQUENCE NUMBER INTO THE EMPNO COLUMN
OF EMP TABLE
INSERT INTO EMP(EMPNO) VALUES(S1.NEXTVAL);
CREATE A SEQUENCE WITH STEP VALUE=1;
START VALUE=2;MINIMUM VALUE=1;MAXIMUM VALUE=22
AND THE SEQUENCE TO RESET AUTOMATICALLY WHEN IT COMES
TO START VALUE
CREATE SEQUENCE S2
INCREMENT BY 1
START WITH 2
MINVALUE 1
MAXVALUE 22
CYCLE;
DROP THE SEQUENCE
DROP SEQUENCE S2;
LIST ALL THE SEQUNCES CREATED IN YOUR LOGIN
SELECT * FROM USER_SEQUENCES;

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SOL:
218:
SOL:
219:
SOL:
220:
SOL:
SOL:
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SOL:
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SOL:
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SOL:
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SOL:
215:
CREATE AN INDEX ON COLUMN ENAME OF EMP TABLE
CREATE INDEX ID1 ON EMP(ENAME);
CREATE INDEX ON TWO COLUMNS EMPNO,ENAME
CREATE INDEX ID2 ON EMP (EMPNO,ENAME);
DROP THE INDEX YOU HAVE CREATED
DROP INDEX ID1;
LIST THE INDEXES CREATED ON THE TABLE EMP
SELECT * FROM USER_INDEXES WHERE TABLE_NAME='EMP';
CREATE A CLUSTER BASED ON THE DEPT AND EMP TABLE FOR
THE FIELD DEPTNO
CREATE CLUSTER C1 (DEPTNO NUMBER(2));
CREATE INDEX ID3 ON CLUSTER C1;
CREATE TABLE DEPT1
(DNO NUMBER(2) PRIMARY KEY,
DNAME CHAR(15),
LOC CHAR(15))
CLUSTER C1(DNO);
CREATE TABLE EMP1
(EMPNO NUMBER(4) PRIMARY KEY,
ENAME CHAR(15),
HIREDATE DATE,
SALARY NUMBER(9,2),
DEPTARTMENTNO NUMBER(2) REFERENCES DEPT1(DNO))
CLUSTER C1(DEPTARTMENTNO);
INSERT INTO TABLES DEPT1 AND EMP1 EACH THREE ROWS AND
CHECK THE ROWID OF THE TWO CLUSTER TABLES;
INSERT INTO DEPT1 VALUES(&DNO,'&DNAME','&LOC');
INSERT INTO EMP1 VALUES(&EMPNO,'&ENAME','&HIREDATE',&SALARY,
&DEPARTMENTNO);
SELECT DEPT1.ROWID,EMP1.ROWID FROM DEPT1,EMP1;
LIST ALL THE CLUSTERS CREATED IN YOUR LOGIN
SELECT * FROM USER_CLUSTERS;
CREATE A SYNONYM FOR TABLE EMP
CREATE SYNONYM SY1 FOR EMP;
LIST INFORMATION OF SYNONYM
SELECT * FROM SY1;

72
221:
SOL:
222:
SOL:
LIST ALL THE SYNONYM CREATED IN YOUR LOGIN
SELECT * FROM USER_SYNONYMS;
DROP THE SYNONYM CREATED
DROP SYNONYM SY1;
EMPNO ENAME JOB MGR HIREDATE SAL
COMM DEPTNO
223: CREATE THE EMPLOYEE REPORT OF THE COLUMNS EMPNO,ENAME,JOB
MGR,HIREDATE,SAL,COMM,DEPTNO IN THE FORMAT BELOW:
HEADER: BRAINWARE INFOTECH(P) LTD
EMPLOYEES REPORT
COLUMN:
NAMES EMPLOYEE EMPLOYEE DESIGNATION MANAGER DATE OF CURRENT
NUMBER NAME NUMBER JOINING SALARY
COMMISION DEPARTMENT
NUMBER
FOOTER: HAVE A NICE DAY !
SOL:
REPORT'
TTITLE LEFT'BRAINWARE INFOTECH(P) LTD| CENTER 'EMPLOYEES
BTITLE 'HAVE A NICE DAY!'
COLUMN EMPNO HEADING 'EMPLOYEE | NUMBER'
COLUMN ENAME HEADING 'NAME OF | EMPLOYEE'
COLUMN JOB HEADING ' DESIGNATION'
COLUMN MGR HEADING 'MANAGER | NUMBER'
COLUMN HIREDATE HEADING ' DATE OF | JOINING '
COLUMN SAL HEADING ' CURRENT | SALARY '
COLUMN COMM HEADING 'COMMISION '
COLUMN DEPTNO HEADING 'DEPARTMENT | NUMBER'
Package Specification
The package specification contains public declarations. The scope of these declarations is local to your database schema and global to the package. So, the declared objects are accessible from your application and from anywhere in the package.

73
#****************#
PACKAGES
#****************#
#****************##****************##****************##****************
#
1.
ALL
WRITE A FUNCTION TO RETURN MAX(EMPNO)+1 .
WRITE A PROCEDURE TO FETCH THE DETAILS WHEN EMPNO=RESULT OF
FUNCTION.
WRITE A FUNCTION TO PASS EMPLOYEE NUMBER AND GET THE JOB
WRITE A PROCEDURE TO ACCEPT DEPTNO AND DISPLAY THE DETAILS OF
EMPLOYEES OF THAT PARTICULAR DEPARTMENT.(HINT : CURSOR)
WRITE A PACKAGE WHICH INCLUDES ALL THESE PROCEDURES AND FUNCTIONS
_________________________________________________________________-
CREATE OR REPLACE PACKAGE EMP_PACK IS
FUNCTION NEXTEMP RETURN NUMBER;
PROCEDURE P1;
FUNCTION F2(ENO NUMBER) RETURN VARCHAR;
PROCEDURE P2(DNO NUMBER);
CURSOR C1 IS SELECT * FROM EMP;
END emp_pack;
CREATE OR REPLACE PACKAGE BODY EMP_PACK IS
FUNCTION NEXTEMP RETURN NUMBER IS
CURR_MAX NUMBER:=0;
BEGIN
SELECT MAX(EMPNO) INTO CURR_MAX FROM EMP;
CURR_MAX:=CURR_MAX+1;
RETURN CURR_MAX;
END NEXTEMP;
PROCEDURE P1 IS
ENO NUMBER;
NAME VARCHAR2(10);
DEPNO NUMBER;
SALARY EMP.SAL%TYPE;
BEGIN
ENO:=EMP_PACK.NEXTEMP;
PRINT('NEW EMPLOYEE NUMBER IS'||ENO);
SELECT ENAME,SAL,DEPTNO INTO NAME,SALARY,DEPNO FROM EMP WHERE
EMPNO=ENO;
PRINT(ENO||' '||NAME||' '||DEPNO||' '||SALARY);
EXCEPTION
WHEN NO_DATA_FOUND THEN
PRINT('NO DATA FOUND');
END P1;

74
PROCEDURE P2(DNO NUMBER) IS
CURSOR C1 IS SELECT * FROM EMP WHERE DEPTNO=DNO;
BEGIN
FOR I IN C1 LOOP
DBMS_OUTPUT.PUT_lINE(I.ENAME||' '||I.JOB||' '||I.DEPTNO);
END LOOP;
EXCEPTION
WHEN NO_dATA_FOUND THEN
PRINT('NO DATA FOUND');
END P2;
FUNCTION F2(ENO NUMBER) RETURN VARCHAR IS
DESIG EMP.JOB%TYPE;
BEGIN
SELECT JOB INTO DESIG FROM EMP WHERE EMPNO=ENO;
RETURN DESIG;
END F2;
END EMP_PACK;
DECLARE
NEXTEMP NUMBER;
F2 EMP.JOB%TYPE;
BEGIN
NEXTEMP:=EMP_PACK.NEXTEMP;
PRINT('NEXTEMP IS '||NEXTEMP);
EMP_PACK.P1;
F2:=EMP_PACK.F2(&EMPNO);
PRINT('PRINTING JOB FROM F2 '||F2);
EMP_PACK.P2(&DEPTNO);
END;
#****************##****************##****************##****************
#
1. Create a package that contains the following sub programs
(a) Procedure NEW_EMP to add a new employee to the emp table.
(b) Procedure UPDATE_EMP to update the employee details
(display error message if i.e error)
(c) Function CHECK_EMP to check if an employee is existing in the table
_______________________________________________________________________
CREATE OR REPLACE PACKAGE GEEPACK IS
PROCEDURE NEW_EMP(eno number,dno number,mg number,name varchar2);
PROCEDURE UPDATE_EMP(N NUMBER);
FUNCTION CHECK_eMP(N NUMBER) RETURN NUMBER;
END GEEPACK;
CREATE OR REPLACE PACKAGE BODY GEEPACK IS

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PROCEDURE NEW_EMP(ENO NUMBER, DNO NUMBER,MG NUMBER,NAME VARCHAR2) IS
BEGIN
INSERT INTO EMP(EMPNO,DEPTNO,MGR,ENAME) VALUES(ENO,DNO,MG,NAME);
END NEW_EMP;
PROCEDURE UPDATE_EMP (N NUMBER) IS
DESIG VARCHAR2(10);
BEGIN
SELECT JOB INTO DESIG FROM EMP WHERE EMPNO=N;
DBMS_OUTPUT.PUT_LINE('EMPNO = '||N||' JOB = '||DESIG);
IF DESIG='CLERK' THEN
UPDATE EMP SET JOB='FDC' WHERE EMPNO=N; print('job updated to fdc');
ELSIF DESIG='MANAGER' THEN
UPDATE EMP SET JOB='DGM' WHERE EMPNO=N; print('job updated to dgm');
END IF;
END UPDATE_EMP;
FUNCTION CHECK_eMP (N NUMBER) RETURN NUMBER
IS
N1 NUMBER;
BEGIN
SELECT COUNT(*) INTO N1 FROM EMP WHERE EMPNO=N;
IF n1=0 then
PRINT('EMPLOYEE '||n||' does not EXISTS ');
ELSE
PRINT('EMPLOYEE '||n||' EXISTs');
END IF; return n1;
END CHECK_EMP;
END GEEPACK; declare eno number:=&empno; dno number:=&deptno; mg number:=&mgr; name varchar2(10):='&name'; res number; begin print('new_emp is called and values will be inserted'); geepack.new_emp(eno,dno,mg,name); geepack.update_emp(&updateno); res:=geepack.CHECK_eMP(&checkno); print(res); end;
#****************##****************##****************##****************
#
WRITE A FUNCTION TO RETURN MAX(EMPNO)+1 .
WRITE A PROCEDURE TO FETCH THE DETAILS WHEN EMPNO=RESULT OF FUNCTION.

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END;
ALL
WRITE A PROCEDURE TO ACCEPT DEPTNO AND DISPLAY THE DETAILS OF
EMPLOYEES OF THAT PARTICULAR DEPARTMENT.(HINT : CURSOR)
WRITE A PACKAGE WHICH INCLUDES ALL THESE PROCEDURES AND FUNCTIONS
CREATE OR REPLACE PACKAGE PACK IS
FUNCTION F1 RETURN NUMBER ;
PROCEDURE P1(N NUMBER);
PROCEDURE P2(DNO NUMBER);
END;
CREATE OR REPLACE PACKAGE BODY PACK IS
FUNCTION F1 RETURN NUMBER IS
Z NUMBER;
BEGIN
SELECT MAX(EMPNO)+1 INTO Z FROM EMP;
RETURN Z;
END;
PROCEDURE P1(N NUMBER) IS
A NUMBER;
NAME VARCHAR2(10);
BEGIN
A:=F1;
SELECT ENAME INTO NAME FROM EMP WHERE EMPNO=A;
PRINT('THE NAME IS '||A);
EXCEPTION
WHEN NO_DATA_FOUND THEN
PRINT('NO DATA');
END;
PROCEDURE P2(DNO NUMBEr) IS
CURSOR C2 IS SELECT * FROM EMP WHERE DEPTNO=DNO;
BEGIN
FOR I IN C2 LOOP
PRINT(I.ENAME||' '||I.DEPTNO);
END LOOP;
END ;
DECLARE
F1RES NUMBER;

77
BEGIN
F1RES:=PACK.F1;
PRINT('THE RESULT OF FUNCTION IS '||F1RES);
PACK.P1(F1RES);
PACK.P2(&DEPTNO);
END; create table OrdTab
(
OrdId Number,
Customer_Name varchar2(10),
OrdDate Date,
Total Number
)
Partition By Range(OrdId)
(
Partition P1 VAlues Less Than (100),
Partition P2 Values Less Than (200), partition p3 values less than(300)
);
For the column ordid of the ordtab table i have inserted the below specified values
99
98
100
150
199
200
250
290 when i was above to insert 300 this is what happened insert into ordtab(ordid) values(300)
*
ERROR at line 1:
ORA-14400: inserted partition key is beyond highest legal partition key
So,to overcome this create table OrdTab
(
OrdId Number,
Customer_Name varchar2(10),
OrdDate Date,
Total Number
)
Partition By Range(OrdId)
(
Partition P1 VAlues Less Than (100),
Partition P2 Values Less Than (200),
Partition P3 Values Less Than (MaxValue)

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);
NOW I INSERTED THE VALUES
90
1000
250
350
450
200
SELECT * FROM ORDTAB PARTITION (P1);
ORDID CUSTOMER_N ORDDATE TOTAL
--------- ---------- --------- ---------
90
TRY THE SAME THING WITH P2 AND P3.
SQL> SELECT PARTITION_NAME FROM USER_TAB_PARTITIONS;
PARTITION_NAME
------------------------------
P1
P2
P3
SQL> ALTER TABLE ORDTAB SPLIT PARTITION P1 AT (50);
Table altered.
SQL> SELECT PARTITION_NAME FROM USER_TAB_PARTITIONS;
PARTITION_NAME
------------------------------
P2
P3
SYS_P61
SYS_P62
SQL> SELECT * FROM ORDTAB PARTITION(SYS_P61);
ORDID CUSTOMER_N ORDDATE TOTAL
--------- ---------- --------- ---------
45
SQL> SELECT * FROM ORDTAB PARTITION(SYS_P62);
ORDID CUSTOMER_N ORDDATE TOTAL
--------- ---------- --------- ---------
90
65
ALTER TABLE ORDTAB SPLIT PARTITION P2 AT
(150) INTO (PARTITION P5,PARTITION P6);

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Table altered.
SQL> SELECT PARTITION_NAME FROM USER_TAB_PARTITIONS;
(ALSO GIVE THE COMMAND
SELECT PARTITION_NAME,TABLE_NAME FROM USER_tAB_PARTITIONS)
SELECT TABLE_NAME,PARTITION_NAME,HIGH_VALUE FROM
USER_tAB_PARTITIONS;
PARTITION_NAME
------------------------------
P5
P3
SYS_P61
SYS_P62
P6
ADD PARTITION
~~~~~~~~~~~~~
CREATE TABLE GG
( ACNO NUMBER(3),
actype varchar2(3),
acbal number(4))
partition by range(acbal)
(partition p1 values less than(5000),
partition p2 values less than(6000));
Table created.
SQL> alter table gg add partition maxp values less than(maxvalue);
Table altered.
DROP PARTITION
~~~~~~~~~~~~~~~~~
ALTER TABLE GG DROP PARTITION P1;
ALTER TABLE <TABLENAME> DROP PARTITION <PARTITION NAME>
RENAME PARTITION
~~~~~~~~~~~~~~~~~~
ALTER TABLE EMP RENAME PARTITION P5 TO P6; create table ordtab
( ordid number(4),
prdid number(4),
ordname varchar2(10)
) partition by range(ordid,prdid)
( partition p1 values less than(25,50),
partition p2 values less than(50,75),
partition p3 values less than(75,100)
);

80
***********************************************************************
*
TO CREATE AN INDEXED PARTITION create table OrdTab
(
OrdId Number,
Customer_Name varchar2(10),
OrdDate Date,
Total Number
)
Partition By Range(OrdId)
(
Partition P1 VAlues Less Than (100),
Partition P2 Values Less Than (200), partition p3 values less than(MAXVALUE)
);
CREATE INDEX ORDID ON ORDTAB(ORDID)
LOCAL
(PARTITION P1,PARTITION P2,PARTITION P3);
CREATE INDEX ORDID ON ORDTAB(ORDID)
GLOBAL PARTITION BY RANGE(ORDID)
(PARTITION P1 VALUES LESS THAN(10),
PARTITION P2 VALUES LESS THAN(20),
PARTITION P3 VALUES LESS THAN(MAXVALUE));
LIST THE TREE STRUCTURED QUERY WITH EMPLOYEE NAME STARTING
WITH KING
SOL: SELECT LPAD(' ',6*(LEVEL-1))||ENAME NAME FROM EMP
START WITH ENAME='KING'
CONNECT BY MGR=PRIOR EMPNO;
~~~~~~~~~~~~~~~~~~~~
SIMPLE PL/SQL BLOCKS
~~~~~~~~~~~~~~~~~~~~ declare a number; b number; begin
A:=25;
B:=50; dbms_output.put_line('THE CONTENT OF A IS'||A);

81 dbms_output.put_line('THE CONTENT OF B IS'||B); end; declare a number:=&A; b numbeR:=&B; begin dbms_output.put_line('THE CONTENT OF A IS '||A); dbms_output.put_line('THE CONTENT OF B IS '||B); end; declare a number:=&A; b numbeR:=&B;
PROD NUMBER; begin
PROD:=A*B; dbms_output.put_line('THE CONTENT OF A IS '||A); dbms_output.put_line('THE CONTENT OF B IS '||B); dbms_output.put_line('THE PRODUCT IS '||PROD); end; declare a number:=10; b number:=20; res number; begin res:=a+b; dbms_output.put_line(a|| ' '||b); dbms_output.put_line('The sum is '||res); end; declare a number:=&a; b number:=&b; res number; begin res:=a+b; dbms_output.put_line(a|| ' '||b); dbms_output.put_line('The sum is '||res); end; declare a number:=&a; b number:=&b; begin if (a>b) then dbms_output.put_line('Biggest number is'||' '||a); else dbms_output.put_line('Biggest number is'||' '||b); end if; end;

82 declare a number:=&a; begin if mod(a,5)=0 then dbms_output.put_line('It is divisible by 5'); else dbms_output.put_line('It is not divisible by 5'); end if; end; declare n char(10):='&n'; begin
SELECT UPPER(N) INTO N FROM DUAL; if n='F' then dbms_output.put_line('FIRST CLASS');
ELSIF N='S' THEN dbms_output.put_line('SECOND CLASS');
ELSIF N='T' THEN dbms_output.put_line('THIRD CLASS'); else dbms_output.put_line('FAILED');
END IF;
END; declare n number:=1; begin loop dbms_output.put_line(n); n:=n+1; exit when n=11; end loop; end; declare a number:=1; begin while (a<=10) loop dbms_output.put_line(a); a:=a+1; end loop; end; declare begin for a in 1..10 loop dbms_output.put_line(a); end loop; end; declare

83 begin for a in reverse 1..10 loop dbms_output.put_line(a); end loop; end; declare n number:=&n; i number:=1; begin while i<=n loop dbms_output.put_line(i); i:=i+2; end loop; end; declare n number:=&n; i number:=1; begin while i<=n loop dbms_output.put(i); i:=i+2; end loop; dbms_output.new_line; end;
DECLARE
BEGIN
FOR I IN 1..10 LOOP
DBMS_OUTPUT.PUT_LINE(I);
IF I=5 THEN
EXIT;
END IF;
END LOOP;
END;
declare
n number:=&n;
begin
dbms_output.put_line('even numbers are');
for i in 1..n loop
if mod(i,2)=0 then
dbms_output.put_line(i);
end if;
end loop;
end; to display numbers from 1 to n in same line. declare n number:=&n; begin for i in 1..n loop dbms_output.put(i);

84
DECLARE
N NUMBER:=&N;
RES NUMBER; end loop; dbms_output.new_line; end; to display the sum of n numbers declare
n number:=&n; sum1 number:=0; begin dbms_output.put_line('the numbers are'); for i in 1..n loop dbms_output.put_line(i); sum1:=sum1+i; end loop; dbms_output.put_line('SUM IS '||SUM1);
END;

85
BEGIN
FOR I IN 1..10 LOOP
RES:=N*I;
DBMS_OUTPUT.PUT_LINE(N || ' * '|| I || ' = '|| RES );
END LOOP;
END;
GENERAL PROBLEMS
1 . Write a PL/SQL Program to display all the EVEN Number from 1 to
100.
2. Write a PL/SQL Program to list all the EVEN & ODD Number from 1 to
100 as Follows
Even Numbers
-------------------
Odd Numbers
----------------
-
0
2
4
.
.
1
3
5
.
.
3. Write a PL/SQL Program to Find the sum of numbers between 1 and 100 that are divisible by 5 but not
divisible by 7
4. Write a PL/SQL Script to find all the PRIME NUMBERS from 1 to 100
5. Write a PL/SQL program to find ARMSTRONG NUMBERS from 100 to 999.
6. Write a PL/SQL program to List to FIBBNOCI SERIES FROM 0 TO 100
7. Write a PL/SQL Program to Display the Multiplication Table for the given input.
8. Write a PL/SQL Program to Display the given input string is
PALINDROME OR NOT.
9. Write a PL/SQL Program to REVERSE the given input string.
10. Write a PL/SQL Program to Find out the Given Input data is LEAP
YEAR OR NOT.
11. Write a PL/SQL Program to display First, Second,Third Greatest number From give three numbers
12. Write a PL/SQL Program to find out the RAMAN NUMBER between
1000 and 9999 ex : 1233 , 12*12+33*33 = 1233
13. Write a PL/SQL Program to display the vowels from the input string
14. Write a PL/SQL Program to display the vowels, No.of vowels,position of each vowels and occurrences of each vowels.

86
15. Write a PL/SQL Program to find out a given sub string from the given Main string.(Without using
INSTR FUNCTION).
16. Write a PL/SQL Program to find out No.of characters, No.of digits, No.of special Characters from the given input.
***********************************************************************
******
CURSOR PROBLEMS
1. Write a PL/SQL Program to Copy the data from One table to another which has the same structure with the RECORD NUMBER.
2. Assume the following table for the given problem :
ID
NAME
MARK1
MARK2
MARK3
MARK4
1000
AYYAPPAN
100
99
90
95
1002
BASKER
30
20
25
70
1001
N.B.SING
90
60
50
35
Write a PL/SQL Program to display all the student information
with the TOTAL, AVERAGE,
GRADE. The GRADE is base on the following condition.
1 . between 100 and 90 A GRADE
2. between 89 and 80 B GRADE
3. between 79 and 70 C GRADE

87
4. otherwise WASTE.
3. Write a PL/SQL Program to display the following output
base on the department :
Department No.
10
Department Name Loc computer Bangalore
Empno
Hiredate
1000
12-MAR-98
Ename john
Sal
5000
Comm
100
1001
30-JAN-98
.......
.........
SMITH
.........
...........
6000 NULL
.......
4. Write a PL/SQL Program to display the following output : job : MANAGER
No. of Managers
3
John,smith,miller job : CLERK
-------
-------------
Sum of Salary
--------
54000
Names
5. Write a PL/SQL Program to Display the First 5 Maximum Salary by using Parameter to The cursor
6. Write a PL/SQL Program to display all the salary in the descending order without using the order by clause in the CURSOR SELECT statement
***********************************************************************
******
EXCEPTION
Assume the following table for the problems given below:
Table Name : BANK
Acc_no
Acc_name
Curr_balance number(6) varchar(40) number(20,4)
1. Write a PL/SQL Program to WITHDRAW money from a particular account.
The Acc_no and
Curr_balace should be entered from keyboard. The exceptions raised are a) Acc_no not found b) Over Drawn c) too many rows returned
2. Write a PL/SQL Program to CREDIT money to a particular account and return the current balance. The account number and amount should be entered through keyboard. The exceptions are :

88 a) account number not found b)
3. Write a PL/SQL Program to add a NEW account holder by getting the input from the user using the
exception a) duplicate account number b) too many rows c) invalid number and value error
4. Write a PL/SQL Program to DELETE account holder by entering the account number. The exception a)no data found b)Before delete display the current balance
***********************************************************************
******
SUBPROGRAM
1. Write a PL/SQL Program to SWAP the two input number without using the temporary variable, by using the PROCEDURE.
2. Write a PL/SQL Program to find out the factorial of a given input number using recursive function.
***********************************************************************
******
DATABASE TRIGGERS
1. Write a database trigger to implement the PRIMARY KEY CONSTRAINT.
2. Write a database trigger to implement the FOREIGN KEY CONSTRAINT.
3. Write a database trigger to implement the ON DELETE CASCADE.
4. Write a database trigger to disallow the DELETE operation from others User except Owner.
5. Write a database trigger to automatically convert the lower case employee name to UPPER CASE
employee name while entering.
6. Write a database trigger to disallow any operation on SUNDAY and any day BEFORE 9 AM AND
AFTER 6 PM
7. Write a database trigger to copy the record which has been deleted with USER,DATE,TIME
8. Write a database trigger to generate the serial number for the particular table.

89
9. Write a database trigger to validate the empno as a 4 digit number.
10. Write a database trigger to validate the comm may be NULL or less then 1/4 of the salary and must not be negative
***********************************************************************
******
PACKAGES
1. Create a package that contains the following sub programs
(a) Procedure NEW_EMP to add a new employee to the emp table. proper
(b) Procedure UPDATE_EMP to update any empoyees details with error message
(c) Function CHECK_EMP to check if an employee is existing the table by any
(d) Procedure DELETE_EMP to delete an employee `s record.
(e) Procedure ERROR_MESSAGE to display error message generated of the above
procedure or functions.
2. Create a package to conduct bank transactions involving the following procedures and functions.
(a) Debit
(b) Credit
(c) New account
(d) Journal entry recording all transaction(Acct_id,
Trans_type, sysdate)
(e) Enter the transactions with status pending
BLOCKS CREATED ON
1. GOTO
2. EXIT
3. EXIT WHEN
4. GENERATE EVEN/ODD SERIES
5. GENERATE MULTIPLICATION TABLES
6. REVERSE OF NUMBER
7. REVERSE OF STRING
8. PRIME OR NOT
9. SQUARE
10. M TO POWER N
11. ODD AND EVEN SERIES TOGETHER
12. ACCEPT SYMBOL FROM USER AND DEPENDING ON THAT
ADD,SUBTRACT,MULTIPLY
OR DIVIDE 2 NUMBERS.
13. GENERATE NUMBERS IN FIBONACCI SERIES.

90
14. FACTORIAL OF NUMBER
1.---------GOTO STATEMENT
~~~~~~~~~~~~~~
DECLARE
BEGIN
FOR I IN 1..10 LOOP
DBMS_OUTPUT.PUT_lINE(I);
IF I=5 THEN
GOTO AA;
END IF;
END LOOP;
<<AA>>
DBMS_OUTPUT.PUT_lINE('OUTSIDE THE LOOP');
END;
OUTPUT IS
1
2
3
4
5
HELLO
DECLARE
A NUMBER:=&A;
B NUMBER:=&B;
BEGIN a:=a+b+100; if a>1000 then goto zz; else dbms_output.put_line('out put not greater than 1000'); end if;
END ;
<<zz>> dbms_output.put_line(a);
2.-----------------EXIT STATEMENT
~~~~~~~~~~~~~~
DECLARE
BEGIN
FOR I IN 1..10 LOOP
DBMS_OUTPUT.PUT_lINE(I);
IF I=5 THEN
EXIT;
END IF;
END LOOP;
END;
OUTPUT IS
1
2
3
4

91
5
3.----------------EXIT WHEN STATEMENT
~~~~~~~~~~~~~~~~~~~
DECLARE
BEGIN
FOR I IN 1..10 LOOP
DBMS_OUTPUT.PUT_lINE(I);
EXIT WHEN I=5;
END LOOP;
END;
OUTPUT IS
1
2
3
4
5
4.-----------------------WHILE LOOP
~~~~~~~~~~
GENERATE ODD/EVEN NUMBERS
DECLARE
N NUMBER:=&N;
I NUMBER:=1;
BEGIN
WHILE(I<N) LOOP
DBMS_OUTPUT.PUT_lINE(I);
I:=I+2;
END LOOP;
END;
(FOR EVEN SERIES REPLACE 1 WITH 0);
DECLARE
N NUMBER:=&N;
BEGIN
FOR I IN 1..N LOOP
IF MOD(I,2)=0 THEN
DBMS_OUTPUT.PUT_lINE(I);
END IF;
END LOOP;
END;
5.--------------------MULTIPLICATION TABLES
~~~~~~~~~~~~~~~~~~~~~
DECLARE
N NUMBER:=&N;
RES NUMBER;
BEGIN
DBMS_OUTPUT.PUT_lINE('THE MULTIPLICATION TABLE IS');

92
FOR I IN 1..10 LOOP
RES:=N*I;
DBMS_OUTPUT.PUT_LINE(N ||' * '||I ||' = '||RES);
END LOOP;
END;
~~~~~~~~~~~~~~~~~~~~~
6.----------------REVERSE OF A NUMBER
~~~~~~~~~~~~~~~~~~~
DECLARE
N NUMBER:=&N;
R NUMBER:=0;
L NUMBER;
BEGIN
L:=LENGTH(N);
FOR I IN 1..L LOOP
R:=R*10+MOD(N,10);
N:=FLOOR(N/10);
END LOOP;
--DBMS_OUTPUT.PUT_LINE(N);
DBMS_OUTPUT.PUT_LINE(R);
END;
DECLARE
N NUMBER:=&N;
R NUMBER;
L NUMBER;
BEGIN
DBMS_OUTPUT.PUT_LINE('THE NUMBER IS '||N);
L:=LENGTH(N);
FOR I IN 1..L LOOP
R:=R||MOD(N,10);
N:=FLOOR(N/10);
END LOOP;
DBMS_OUTPUT.PUT_LINE('THE REVERSE OF THE NUMBER IS '||R);
END;
7. ------------------REVERSE OF A STRING
DECLARE
N VARCHAR2(12):='&N';
REV VARCHAR2(12);
LEN NUMBER;
BEGIN
DBMS_OUTPUT.PUT_LINE('STRING IS '||N);
LEN:=LENGTH(N);
FOR I IN REVERSE 1..LEN LOOP
REV:=REV||SUBSTR(N,I,1) ;
END LOOP;
DBMS_OUTPUT.PUT_LINE('REVERSED STRING IS '||rEV);

93
END;
8---------------------PRIME OR NOT
~~~~~~~~~~~~
DECLARE
N NUMBER:=&N;
FLAG NUMBER:=1;
BEGIN
FOR I IN 2..N-1 LOOP
IF MOD(N,I)=0 THEN
FLAG:=0;
EXIT;
END IF;
END LOOP;
IF FLAG=0 THEN
DBMS_OUTPUT.PUT_LINE('NUMBER IS NOT PRIME');
ELSE
DBMS_OUTPUT.PUT_lINE('NUMBER IS PRIME');
END IF;
END;
9.------------------DRAW A SQUARE
DECLARE
BEGIN
FOR I IN 1..10 LOOP
DBMS_OUTPUT.PUT('?');
DBMS_OUTPUT.PUT(' ');
END LOOP;
DBMS_OUTPUT.NEW_LINE;
FOR I IN 1..10 LOOP
DBMS_OUTPUT.PUT_LINE('? ?');
END LOOP;
FOR I IN 1..10 LOOP
DBMS_OUTPUT.PUT('?');
DBMS_OUTPUT.PUT(' ');
END LOOP;
DBMS_OUTPUT.NEW_LINE;
END;
10.-----------------M RAISED TO NTH POWER
DECLARE
M NUMBER:=&M;
N NUMBER:=&N;
RES NUMBER;
BEGIN
RES:=POWER(M,N);
DBMS_OUTPUT.PUT_lINE('M TO POWER OF N IS '||RES);
END;

94
11.----------------DISPLAY ODD AND EVEN SERIES
DECLARE
BEGIN
DBMS_OUTPUT.PUT_LINE('ODD-----------EVEN');
DBMS_OUTPUT.PUT_lINE('__________________');
FOR I IN 1..20
LOOP
IF MOD(I,2) = 0 THEN
DBMS_OUTPUT.PUT_LINE(' '||I);
ELSE
DBMS_OUTPUT.PUT(I);
END IF;
END LOOP;
END;
12.---------------------------
ACCEPT SYMBOL FROM USER AND DEPENDING ON THAT ADD,SUBTRACT,MULTIPLY
OR DIVIDE 2 NUMBERS.
DECLARE
NUM1 NUMBER:=&NUMBER1;
SYB CHAR:='&SYMBOL';
NUM2 NUMBER:=&NUMBER2;
RESULT NUMBER;
BEGIN
IF SYB='+' THEN
RESULT:=NUM1+NUM2;
ELSE
IF SYB='-' THEN
RESULT:=NUM1-NUM2;
ELSE
IF SYB='*' THEN
RESULT:=NUM1*NUM2;
ELSE
IF SYB='/' THEN
RESULT:=NUM1/NUM2;
END IF;
END IF;
END IF;
END IF;
DBMS_OUTPUT.PUT_LINE(RESULT);
END;

95

96
PL/SQL Tables
Objects of type TABLE are called "PL/SQL tables," which are modelled on (but not the same as) database tables. PL/SQL tables use a primary key to give you array-like access to rows. The size of a PL/SQL table is unconstrained. That is, the number of rows in a PL/SQL table can increase dynamically.
PL/SQL tables can have one column and a primary key, neither of which can be named. The column can belong to any scalar type, but the primary key must belong to type BINARY_INTEGER.
Declaring PL/SQL Tables
PL/SQL tables must be declared in two steps. First, you define a TABLE type, then declare PL/SQL tables of that type. You can declare TABLE types in the declarative part of any block, subprogram, or package using the syntax
TYPE type_name IS TABLE OF
{ column_type | variable%TYPE | table.column%TYPE 'D [NOT NULL]
INDEX BY BINARY_INTEGER; where "type_name" is a type specifier used in subsequent declarations of PL/SQL tables and "column_type" is any scalar datatype such as CHAR,
DATE, or NUMBER. You can use the %TYPE attribute to specify a column datatype.
In this example, you declare a TABLE type called "EnameTabTyp":
DECLARE
TYPE EnameTabTyp IS TABLE OF CHAR(10)
INDEX BY BINARY_INTEGER;
You could have used %TYPE to provide the column datatype, as follows:
DECLARE
TYPE EnameTabTyp IS TABLE OF emp.ename%TYPE

97
INDEX BY BINARY_INTEGER;
Once you define type "EnameTabTyp," you can declare PL/SQL tables of that type, as follows:
ename_tab EnameTabTyp;
The identifier "ename_tab" represents an entire PL/SQL table.
Like scalar variables, PL/SQL tables can be declared as the formal parameters of procedures and functions. Some packaged examples follow:
PACKAGE emp_actions IS
TYPE EnameTabTyp IS TABLE OF emp.ename%TYPE
INDEX BY BINARY_INTEGER;
TYPE SalTabTyp IS TABLE OF emp.sal%TYPE
INDEX BY BINARY_INTEGER;
ename_tab EnameTabTyp;
sal_tab SalTabTyp;
...
PROCEDURE hire_batch
(ename_tab EnameTabTyp,
sal_tab SalTabTyp,
...);
PROCEDURE log_names
(ename_tab EnameTabTyp,
num BINARY_INTEGER);
...
END emp_actions;
Referencing PL/SQL Tables
To reference rows in a PL/SQL table, you specify a primary key value using the array-like syntax
plsql_table_name(primary_key_value) where "primary_key_value" belongs to type BINARY_INTEGER. For example, you reference the third row in PL/SQL table "ename_tab" as follows:
ename_tab(3) ...
You can assign the value of a PL/SQL expression to a specific row using the following syntax:
plsql_table_name(primary_key_value) := plsql_expression;
In the next example, you assign the sum of variables "salary" and
"increase" to the fifth row in PL/SQL table "sal_tab":
sal_tab(5) := salary + increase;

98
Until a row is assigned a value, it does not exist. If you try to reference an uninitialized row, PL/SQL raises the predefined exception
NO_DATA_FOUND. Consider the following example:
DECLARE
TYPE JobTabTyp IS TABLE OF CHAR(14)
INDEX BY BINARY_INTEGER;
job_tab JobTabTyp;
BEGIN
job_tab(1) := 'CLERK';
IF job_tab(2) = 'CLERK' THEN -- raises NO_DATA_FOUND
...
END IF;
...
EXCEPTION
WHEN NO_DATA_FOUND THEN
-- here because job_tab(2) does not exist
...
END;
Inserting/Fetching Rows
You must use a loop to INSERT values from a PL/SQL table into a database column. Likewise, you must use a loop to FETCH values from a database column into a PL/SQL table. For example, given the declarations
DECLARE
TYPE EmpnoTabTyp IS TABLE OF NUMBER(4)
INDEX BY BINARY_INTEGER;
TYPE EnameTabTyp IS TABLE OF CHAR(10)
INDEX BY BINARY_INTEGER;
...
empno_tab EmpnoTabTyp;
ename_tab EnameTabTyp;
... you might use the following procedure to INSERT values from the PL/SQL tables into the "emp" database table:
PROCEDURE insert_emp_data
(rows BINARY_INTEGER,
empno_tab EmpnoTabTyp,
ename_tab EnameTabTyp,
...) IS
BEGIN
FOR i IN 1..rows LOOP
INSERT INTO emp (empno, ename, ...)
VALUES (empno_tab(i), ename_tab(i), ...);
END LOOP;
END;
Conversely, you might use the next procedure to FETCH all rows from the

99 database table into PL/SQL tables "empno_tab" and "ename_tab":
PROCEDURE fetch_emp_data
(rows OUT BINARY_INTEGER,
empno_tab OUT EmpnoTabTyp,
ename_tab OUT EnameTabTyp,
...) IS
BEGIN
rows := 0;
FOR emprec IN (SELECT * FROM emp) LOOP
rows := rows + 1;
empno_tab(rows) := emprec.empno;
ename_tab(rows) := emprec.ename;
...
END LOOP;
END;
However, you cannot reference PL/SQL tables in the INTO clause. For example, the following SELECT statement is illegal:
PROCEDURE fetch_emp_data
(rows OUT BINARY_INTEGER,
empno_tab OUT EmpnoTabTyp,
ename_tab OUT EnameTabTyp,
...) IS
BEGIN
SELECT empno, ename
INTO empno_tab, ename_tab -- illegal
FROM emp;
...
END;
Deleting Rows
You cannot delete individual rows from a PL/SQL table because the
DELETE statement cannot specify PL/SQL tables. However, you can use a simple workaround to delete entire PL/SQL tables. When you want to delete a PL/SQL table, simply assign a null to it, as shown in the following example:
DECLARE
TYPE NumTabTyp IS TABLE OF NUMBER
INDEX BY BINARY_INTEGER;
sal_tab NumTabTyp;
...
BEGIN
/* Load salary table. */
FOR i IN 1..50 LOOP
sal_tab(i) := i;
END LOOP;
...
/* Delete salary table. */

100
sal_tab := NULL; -- releases all PL/SQL table resources
...
END;
See also: Datatypes, Variables and Constants, Records,
FETCH Statement, INSERT, DELETE
1. pl/sql block to print details of employees when number=7788;
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ declare num number(5); name varchar(10); sal number(7,2); begin select empno,ename,sal into num,name,sal from emp where empno=7902; dbms_output.put_Line(num||' '||name||' '||sal); end;
2. pl/sql block to print details of employees when number=n
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ declare num number(5); name varchar(10); sal number(7,2); begin select empno,ename,sal into num,name,sal from emp where empno=&n; insert into areas values(100,4000); dbms_output.put_Line(num||' '||name||' '||sal); end;
DECLARE
NAME VARCHAR2(10):='&NAME';
DESIG VARCHAR2(12);
SALARY NUMBER(7,2);
NETSAL NUMBER(7,2);
BEGIN
SELECT JOB,SAL INTO DESIG,SALARY FROM EMP WHERE ENAME=NAME;
DBMS_OUTPUT.PUT_LINE(NAME||' '||DESIG||' '||SALARY);
IF DESIG='CLERK' THEN
UPDATE EMP SET SAL=SALARY*0.1 +SALARY WHERE ENAME=NAME;
NETSAL:=SALARY*0.1+SALARY;
DBMS_OUTPUT.PUT_LINE('THE NET SALARY IS '||NETSAL);
ELSE
UPDATE EMP SET SAL=SALARY*0.2 +SALARY WHERE ENAME=NAME;
NETSAL:=SALARY*0.1+SALARY;
DBMS_OUTPUT.PUT_LINE('THE NET SALARY IS '||NETSAL);
END IF;
END;
3. update statement in pl/sql

101 block
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ declare num number(5):=&EMPNO; name varchar(10); salary number(7,2); desig varchar2(10); begin select empno,ename,sal,job into num,name,salary,desig
from emp where empno=NUM; dbms_output.put_Line(num||' '||name||' '||salARY||' '||DESIG); if desig='CLERK' THEN
UPDATE EMP SET SAL=SAL+200 WHERE EMPNO=NUM;
ELSIF DESIG='MANAGER' THEN
UPDATE EMP SET SAL=SAL+300 WHERE EMPNO=NUM;
END IF;
COMMIT; end;
4. DELETE STATEMENT IN PL/SQL BLOCK
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ declare num number(5); name varchar(10); salary number(7,2); desig varchar2(10); begin select empno,ename,sal,job into num,name,salary,desig
from emp where empno=&n; if desig='CLERK' THEN
DBMS_OUTPUT.PUT_LINE('RECORD DELETED');
DELETE FROM EMP WHERE EMPNO=NUM;
ELSE
DBMS_OUTPUT.PUT_LINE('RECORD NOT DELETED');
END IF; dbms_output.put_Line(num||' '||name||' '||salARY||' '||DESIG); end;
5. INSERT STATEMENT IN PL/SQL BLOCK
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
DECLARE
ENO NUMBER(4);
MGR NUMBER(4);
DEPNO NUMBER(3);
BEGIN
INSERT INTO EMP(EMPNO,MGR,DEPTNO)VALUES(&ENO,&MGR,&DEPNO);
DBMS_OUTPUT.PUT_LINE(ENO||' '||MGR||' '||DEPNO);
COMMIT;
END;

102
6. SELECTING THE VALUES FROM EMP & INSERTING TO TEMP TABLE
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ declare num number(5); name varchar(10); salary number(7,2); desig varchar2(10); begin select empno,ename,sal,job into num,name,salary,desig
from emp where empno=&n; if desig='CLERK' THEN
DBMS_OUTPUT.PUT_LINE('RECORD INSERTED');
INSERT INTO TEMP VALUES(NUM,NAME,SALARY,DESIG);
END IF; dbms_output.put_Line(num||' '||name||' '||salARY||' '||DESIG);
COMMIT; end;
7. DISPLAY NAME AND DESIGNATION OF MANAGERS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
(THE BLOCK GIVES ERRORS.
IT IS JUST TO ILLUSTRATE THAT
exact fetch returns more than requested number of rows )
DECLARE
N NUMBER;
NAME EMP.ENAME%TYPE;
DESIG EMP.JOB%TYPE;
BEGIN
SELECT COUNT(*) INTO N FROM EMP WHERE JOB='MANAGER';
FOR I IN 1..N LOOP
SELECT ENAME,JOB INTO NAME,DESIG FROM EMP WHERE JOB='MANAGER';
DBMS_OUTPUT.PUT_LINE(NAME||' '||DESIG);
END LOOP;
END;
EXAMPLE FOR SELECT,INSERT,UPDATE,DELETE STATEMENTS IN PL/SQL
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
CREATE TABLE TEMP
( ENAME VARCHAR2(10),
DESIG VARCHAR2(10),
SAL NUMBER(7,2));
DECLARE
NAME VARCHAR2(10);
DESIG VARCHAR2(10);
SALARY NUMBER(7,2);
ENO NUMBER(4):=&EMPNO;
BEGIN

103
SELECT ENAME,JOB,SAL INTO NAME,DESIG,SALARY FROM EMP WHERE EMPNO=ENO;
DBMS_OUTPUT.PUT_LINE(ENO||' '||NAME||' '||SALARY||' '||DESIG);
IF DESIG='CLERK' THEN
DELETE FROM EMP WHERE EMPNO=ENO;
INSERT INTO TEMP VALUES(NAME,DESIG,SALARY);
DBMS_OUTPUT.PUT_LINE('DELETED FROM EMP AND INSERTED TO TEMP');
COMMIT;
ELSIF DESIG='MANAGER' THEN
UPDATE EMP SET SAL=SALARY+200 WHERE EMPNO=ENO;
DBMS_OUTPUT.PUT_LINE('INCREMENTED SALARY IS '||TO_CHAR(SALARY+200));
END IF;
END;
8.SELECT MAX(DEPTNO) FROM DEPT TABLE AND INSERT TO TEMP TABLE
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
DECLARE
MDEPNO NUMBER(3);
BEGIN
FOR I IN 1..4 LOOP
SELECT MAX(DEPTNO) INTO MDEPNO FROM DEPT5;
INSERT INTO TEMP VALUES(MDEPNO);
DBMS_OUTPUT.PUT_LINE(MDEPNO);
DELETE FROM DEPT5 WHERE DEPTNO=MDEPNO;
COMMIT;
END LOOP;
END;
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~
9. 2 tables are created. In one table the quantiy and the product name is stored and the other table is dummy table. If we give product name the details will be displayed.If the number of products is below 5 then insert into temp table out of stock and sysdate
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~ inventory table (inv)
~~~~~~~~~~~~~~~ quantity prodname
9
8
5
1
Racket
Book
Pencil
Marker create table inv(quantity number(3),prodname varchar(10));
temp
~~~~ prodname comment date1 create table temp( prodname varchar2(10), comm varchar2(16),
date1 date); declare qty NUMBER(5);

104 pname VARCHAR2(10); begin select quantity,prodname into qty,pname from inv where prodname='&productname'; if qty>5 then
DBMS_OUTPUT.PUT_LINE('THANK U FOR THE PURCHASES MADE VISIT AGAIN'); update inv set quantity=quantity-1 where prodname=pname; commit; else
DBMS_OUTPUT.PUT_LINE('STOCK LEVEL IS BELOW ORDER LEVEL'); insert into temp values(pname,'out of stock',sysdate); commit; end if; end;
10. example for constant
~~~~~~~~~~~~~~~~~~~~~~~~
declare
a constant number:=5;
begin
dbms_output.put_Line(a);
end;
(If we make a as an constant we cannot use a as a assignment target.
We can just print a+2,a+3 etc.....)
declare
a constant number:=5;
begin
dbms_output.put_Line(a);
dbms_output.put_Line(a+2);
end;
11.example for default
***********************
declare
a number default 3;
begin
dbms_output.put_Line(a);
end;
(hERE A CAN BE USED AS ASSIGNMENT TARGET).
12. Write a pl/sql block to fetch the details of all the employees whose
number is 7902. Now if his sal is less than 4000 then fetch salary
mgr and name of the employees whose empno should be equal to
MGR.
13. WAP TO CHECK THE BANK DETAILS. IN BANK TABLE ACCNO AND BALANCE
IS STORED. USER HAS TO ENTER THE ACCOUNT NUMBER AND WITHDRAW
AMOUNT.
IF WITHDRAWL AMOUNT < BALANCE THEN UPDATE BALANCE OF BANK TABLE
AND SUBTRACT THE WITHDRAWL AMOUNT FROM BALANCE ELSE INSERT A

105
MESSAGE LIKE INSUFFICIENT FUNDS TO TEMP TABLE create table bank
( accno number(3),
bal number(6));
ACCNO BAL
-------- ---------
10 5000
20 6000
30 20 create table temp
( accno number(3),
bal number(6),
rem varchar2(20)); declare awith number(3):=&awith; ac_no number(3):=&accno; abal number(6); begin select bal into abal from bank where accno=ac_no; if abal>awith then update bank set bal=bal-awith where accno=ac_no; commit; else insert into temp values(ac_no,abal,'insuffunds'); commit; end if; end;
14. ILLUSTRATE %TYPE
********************* declare a emp.deptno%type; begin select deptno into a from emp where empno=&A; dbms_output.put_line(a); end;
15.ILLUSTRATE %ROWTYPE
*********************** declare a emp%ROWtype; begin select * into a from emp where empno=&N; dbms_output.put_line(A.ENAME||' '||A.SAL||' '||A.COMM); end;
16 write a pl/sql block to calculate the sum and average salaries of
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

106 all the employees of a particular department.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
DECLARE
NO NUMBER:=&DEPTNO;
SUM1 NUMBER(7,2);
AVG1 NUMBER(7,2);
BEGIN
SELECT SUM(SAL),AVG(SAL) INTO SUM1,AVG1
FROM EMP
WHERE DEPTNO=NO;
DBMS_OUTPUT.PUT_line('Sum of salary is'||SUM1);
DBMS_OUTPUT.PUT_Line('Average salary is'||AVG1);
END;
NESTED TABLE
CREATE OR REPLACE TYPE EMPLOYEE AS OBJECT
_ CREATE TYPE EMPLOYEE AS OBJECT
(NO NUMBER(4),
NAME VARCHAR2(20),
JOB VARCHAR2(10),

107
SAL NUMBER(7,2));
-------------------------------------------
CREATE TYPE EMPTAB AS TABLE OF EMPLOYEE;
-------------------------------------------
CREATE TABLE DEPTNEST
(DNO NUMBER(2),
DNAME VARCHAR2(20),
EMPL EMPTAB) NESTED TABLE EMPL STORE AS EMPNEST;
---------------------------------------------
INSERT INTO DEPTNEST VALUES (10,'ACCOUNTS',EMPTAB(
EMPLOYEE(1,'RAJ','CLERK',1000),
EMPLOYEE(2,'SARAV','SALES',2000)));
-------------------------------------------------------------
INSERT INTO THE(SELECT EMPL FROM DEPTNEST WHERE
DEPTNO=10) VALUES (EMPTAB(3,'SHIV','SUPERV',2300));
SELECT X.EMPL.NAME FROM DEPTNEST X WHERE X.DNO=10;
-----------------------------------------------------
SELECT TYPE_CODE,ATTRIBUTES FROM USER_TYPES WHERE TYPE_NAME='DEPTNEST';
SELECT COLL_TYPES,ELEM_TYPE FROM USER_COL_TYPES WHERE TYPE_NAME='
';
-----------------------------------------------------------------------
--------------------------
VARRAY:
-------------
CREATE TYPE PHONE AS OBJECT
(NO NUMBER(6));
----------
CREATE TYPE PHONETYPE AS VARRAY(5) OF PHONE;
----------
CREATE TABLE CUST
(NAME VARCHAR2(20),
PHONENO PHONETYPE);
-----------
INSERT INTO CUST VALUES ('XXXX',
PHONETYPE(PHONE(232322),PHONE(345345));
-----------
SELECT COLumn_NAME,DATA_TYPE_NAME FROM USER_TAB_COLUMNS
WHERE TABLE_NAME=' ';

108
SELECT TYPE_CODE,ATTRIBUTES FROM USER_TYPES WHERE
TYPE_NAME=' ';
-----------------------------------------------------------------------
-----------------------
---------------------------------------------------------------
#**************#
PROCEDURES
#**************#
#**************##**************##**************##**************##******
********#
1.
2.
3.
4.
WRITE A PROCEDURE TO DRAW A LINE
WRITE A PROCEDURE WHICH ACTS JUST LIKE DBMS_OUTPUT.PUT_LINE
WRITE A PROCEDURE TO FETCH THE NAME AND JOB WHEN NO IS PASSED
(this is to illustrate both in and out parameters)
WRITE A PROCEDURE TO PASS THE EMPLOYEE NUMBER AND THE AMOUNT TO
BE INCREMENTED. example to illustrate in out parameter.
EXAMPLE TO ILLUSTRATE LOCAL PROCEDURE
I.E DYNAMIC CREATION OF PROCEDURES.(PROCEDURE WITHIN A BLOCK)
5.
#**************##**************##**************##**************##******
********#
1.---------- WRITE A PROCEDURE TO DRAW A LINE
CREATE OR REPLACE PROCEDURE LINE IS
BEGIN
FOR I IN 1..40 LOOP
DBMS_OUTPUT.PUT('_');
END LOOP;
DBMS_OUTPUT.NEW_LINE;
END;
EXEC LINE

109
DECLARE
OR
CURSOR C1 IS SELECT * FROM EMP WHERE JOB='CLERK';
CURSOR C2 IS SELECT * FROM EMP WHERE JOB='MANAGER';
BEGIN
LINE;
LINE;
FOR I IN C1 LOOP
DBMS_OUTPUT.PUT_LINE(I.ENAME||' '||I.JOB);
END LOOP;
LINE;
LINE;
FOR I IN C2 LOOP
DBMS_OUTPUT.PUT_LINE(I.ENAME||' '||I.JOB);
END LOOP;
LINE;
LINE;
END;
_______________________________________________________________________
___
2---------------WRITE A PROCEDURE WHICH ACTS JUST LIKE
DBMS_OUTPUT.PUT_LINE
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
CREATE OR REPLACE PROCEDURE PRINT( N VARCHAR2) is begin dbms_output.put_line(n); end; declare
A NUMBER:=25; begin
PRINT(A); print('BRAINWARE'); end;
_______________________________________________________________________
_
3------------WRITE A PROCEDURE TO FETCH THE NAME AND JOB WHEN NO IS
PASSED
-------(this is to illustrate both in and out parameters)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
CREATE OR REPLACE PROCEDURE DISP(N NUMBER)
IS
NAME EMP.ENAME%TYPE;
DESIG EMP.JOB%TYPE;
BEGIN
SELECT ENAME,JOB INTO NAME,DESIG FROM EMP WHERE EMPNO=N;
DBMS_OUTPUT.PUT_LINE(NAME||' '||DESIG);
END;
EXEC DISP(7499)

110
DECLARE
BEGIN
DISP(&N);
END;
OR
CREATE OR REPLACE PROCEDURE DISP1(ENO NUMBER,
NAME OUT VARCHAR,DESIG OUT VARCHAR)
IS
BEGIN
SELECT ENAME,JOB INTO NAME,DESIG FROM EMP WHERE EMPNO=ENO;
END;
DECLARE
NAME1 VARCHAR2(30);
DESIG1 VARCHAR2(10);
N NUMBER:=&EMPNO;
BEGIN
DISP1(N,NAME1,DESIG1);
DBMS_OUTPUT.PUT_LINE(NAME1||' '||DESIG1||' '||N);
END;
_______________________________________________________________________
___
4---------------WRITE A PROCEDURE TO PASS THE EMPLOYEE NUMBER AND THE
AMOUNT TO
BE INCREMENTED. example to illustrate in out parameter. create or replace procedure hike_sal(a in out number,incre number) is begin update emp set sal=sal+incre where empno=a; if sql%found then a:=1; else a:=0; end if; end; declare n number:=&empno; incre number:=&increment; begin dbms_output.put_line('n = '|| n||' '||' increment='||incre); hike_sal(n,incre); dbms_output.put_line('n = '|| n||' '||' increment='||incre); if n=1 then dbms_output.put_line('salary incremented'); else dbms_output.put_line('salary is not incremented');

111 end if; end;
______________________________________________________________________
5-----------EXAMPLE TO ILLUSTRATE LOCAL PROCEDURE
------------I.E DYNAMIC CREATION OF PROCEDURES.(PROCEDURE WITHIN A
BLOCK)
DECLARE
A NUMBER:=10;
J VARCHAR2(10);
ENO NUMBER;
PROCEDURE DISPJOB(N NUMBER,J OUT VARCHAR2) IS
BEGIN
SELECT JOB INTO J FROM EMP WHERE EMPNO=N;
END;
BEGIN
ENO:=&EMPNO;
DBMS_OUTPUT.PUT_LINE('EMPLOYEE NUMBER IS'||ENO);
DISPJOB(ENO,J);
DBMS_OUTPUT.PUT_lINE('EMPNO='||ENO||' JOB='||J);
EXCEPTION
WHEN NO_DATA_FOUND THEN
END;
DBMS_OUTPUT.PUT_LINE('MESSAGE');
PRINT('SORRRY NO EMPLOYEE EXISTS WITH THAT NUMBER');
_________________________________
______________________________________
CURSORS
-------
DECLARE
CURSOR C1 IS SELECT ENAME,COMM FROM EMP WHERE EMPNO=7900;
NAME EMP.ENAME%TYPE;
COMMISSION EMP.COMM%TYPE;
BEGIN
OPEN C1;
FETCH C1 INTO NAME,COMMISSION;
DBMS_OUTPUT.PUT_LINE('THE VALUES ARE'||' '||NAME||' '||COMMISSION);
CLOSE C1;
END;
DECLARE
CURSOR C1 IS SELECT EMPNO,ENAME ,DEPTNO FROM EMP;
EMPNUM EMP.EMPNO%TYPE;
EMPNAME EMP.ENAME%TYPE;
DEPTNUM EMP.DEPTNO%TYPE;
BEGIN
OPEN C1;
LOOP
FETCH C1 INTO EMPNUM,EMPNAME,DEPTNUM; if c1%notfound then

112 exit; else dbms_output.put_line(EMPNUM||' '||EMPNAME||' '||DEPTNUM); end if;
END LOOP; end;
DECLARE
CURSOR C1 IS SELECT EMPNO,ENAME ,SAL FROM EMP WHERE DEPTNO=10;
EMPNUM EMP.EMPNO%TYPE;
NAME EMP.ENAME%TYPE;
SALARY EMP.SAL%TYPE;
BEGIN
OPEN C1;
LOOP
FETCH C1 INTO EMPNUM,NAME,SALARY;
IF C1%NOTFOUND THEN EXIT;
END IF;
INSERT INTO TEMP VALUES(EMPNUM,NAME,SALARY);
END LOOP;
--CLOSE C1;
END;
//CURSOR ALREADY OPEN
DECLARE
CURSOR C1 IS SELECT EMPNO,ENAME,DEPTNO FROM EMP;
EMPNUM EMP.EMPNO%TYPE;
EMPNAME EMP.ENAME%TYPE;
DEPTNUM EMP.DEPTNO%TYPE;
BEGIN
OPEN C1;
OPEN C1;
FOR I IN 1..5
LOOP
FETCH C1 INTO EMPNUM,EMPNAME,DEPTNUM;
IF C1% NOTFOUND THEN
EXIT;
END IF;
--INSERT INTO TEMP VALUES(EMPNUM,EMPNAME,DEPTNUM);
END LOOP;
CLOSE C1;
END;
DECLARE
CURSOR C1 IS SELECT EMPNO,SAL,COMM FROM EMP;
EMPCODE EMP.EMPNO%TYPE;
SALARY EMP.SAL%TYPE;
COM EMP.COMM%TYPE;
BEGIN
OPEN C1;
LOOP
FETCH C1 INTO EMPCODE,SALARY,COM;
EXIT WHEN C1%NOTFOUND;
INSERT INTO TEMP VALUES(EMPCODE,SALARY,COM);

113
END LOOP;
CLOSE C1;
END;
////////(ISOPEN WITH CLOSE)
DECLARE
CURSOR C1 IS SELECT EMPNO,SAL,COMM FROM EMP;
EMPCODE EMP.EMPNO%TYPE;
SALARY EMP.SAL%TYPE;
COM EMP.COMM%TYPE;
BEGIN
LOOP
IF C1%ISOPEN THEN
DBMS_OUTPUT.PUT_LINE('CURSOR IS OPEN');
EXIT;
ELSE
OPEN C1;
FETCH C1 INTO EMPCODE,SALARY,COM;
EXIT WHEN C1%NOTFOUND;
INSERT INTO TEMP VALUES(EMPCODE,SALARY,COM);
END IF;
END LOOP;
CLOSE C1;
END;
DECLARE
CURSOR C1 IS SELECT EMPNO,ENAME,COMM FROM EMP;
BEGIN
--OPEN C1;
FOR I IN C1
LOOP
DBMS_OUTPUT.PUT_LINE(I.EMPNO||' '||I.ENAME||' '||I.COMM);
INSERT INTO TEMP VALUES(I.EMPNO,I.ENAME,I.COMM);
END LOOP;
--CLOSE C1;
END;
%ROWTYPE
--------
DECLARE
CURSOR C1 IS SELECT * FROM EMP;
TEMPROW EMP%ROWTYPE;
BEGIN
OPEN C1;
LOOP
FETCH C1 INTO TEMPROW;
EXIT WHEN C1%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(TEMPROW.EMPNO||' '||TEMPROW.SAL);
END LOOP;
CLOSE C1;
DECLARE
CURSOR C1 IS SELECT EMPNO,ENAME,SAL FROM EMP;
TEMPROW C1%ROWTYPE;
BEGIN
OPEN C1;

114
LOOP
FETCH C1 INTO TEMPROW;
EXIT WHEN C1%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(TEMPROW.EMPNO||' '||TEMPROW.SAL);
END LOOP;
CLOSE C1;
END;
END;
IMPLICIT CURSOR
----------------
BEGIN
UPDATE EMP SET HIREDATE='01-SEP-98' WHERE DEPTNO=20;
DBMS_OUTPUT.PUT_LINE(SQL%ROWCOUNT||'ROW UPDATED');
END;
ROWCOUNT
--------
DECLARE CURSOR C1 IS SELECT * FROM EMP;
A C1%ROWTYPE;
BEGIN
IF NOT C1%ISOPEN THEN
OPEN C1;
END IF;
LOOP
FETCH C1 INTO A;
IF C1%FOUND THEN
IF C1%ROWCOUNT<5 THEN
DBMS_OUTPUT.PUT_LINE(A.EMPNO||' '||A.ENAME||' '||A.DEPTNO);
ELSE
EXIT;
END IF;
ELSE
EXIT;
END IF;
END LOOP;
CLOSE C1;
END;
EXCEPTION;
----------
(ZERO_DIVIDE)
------------
DECLARE
A NUMBER:=&A;
B NUMBER:=&B;
C NUMBER;
BEGIN
C:=A/B;
DBMS_OUTPUT.PUT_LINE(C);
EXCEPTION
WHEN ZERO_DIVIDE THEN
DBMS_OUTPUT.PUT_LINE('THE DENOMINATOR IS ZERO');

115
B:=A;
C:=A/B;
DBMS_OUTPUT.PUT_LINE(C);
END;
VALUE error;
---------------
DECLARE
EMPNUM NUMBER(3);
NAME VARCHAR2(10);
NO NUMBER:=&NO;
BEGIN
SELECT EMPNO,ENAME INTO EMPNUM,NAME FROM EMP WHERE EMPNO=NO;
DBMS_OUTPUT.PUT_LINE(EMPNUM||' '||NAME);
EXCEPTION
WHEN VALUE_ERROR THEN
DBMS_OUTPUT.PUT_LINE('WIDTH IS NOT SUFFICIENT');
DECLARE
ENUM EMP.EMPNO%TYPE;
BEGIN
SELECT EMPNO,ENAME INTO ENUM,NAME FROM EMP WHERE EMPNO=NO ;
DBMS_OUTPUT.PUT_LINE(ENUM||' '||NAME);
END;
END;
INVALID NUMBER;
---------------
DECLARE
NAME VARCHAR2(10):='&NAME';
NUM NUMBER(3);
BEGIN
SELECT TO_NUMBER(NAME) INTO NUM FROM DUAL;
DBMS_OUTPUT.PUT_LINE(NUM);
EXCEPTION
WHEN INVALID_NUMBER THEN
DBMS_OUTPUT.PUT_LINE('INVALID NUMBER IS RAISED');
END;
TOO MANY ROWS:
--------------
DECLARE
NAME emp.ENAME%type;
EJOB EMP.JOB%TYPE:='&JOB';
BEGIN select ENAME into NAME from emp WHERE JOB=EJOB; dbms_output.put_line(NAME); exception when too_many_rows then dbms_output.put_line('too many rows are found');
DECLARE
CURSOR C1 IS SELECT ENAME,JOB,SAL FROM EMP WHERE JOB=EJOB;
BEGIN

116
IF C1%ISOPEN THEN
DBMS_OUTPUT.PUT_LINE('CURSOR IS OPEN');
END IF;
FOR I IN C1 LOOP
END;
DBMS_OUTPUT.PUT_LINE(I.ENAME||' '||I.JOB||' '||I.SAL);
END LOOP;
END;
NO_DATA_FOUND
-------------
DECLARE
NO EMP.EMPNO%TYPE;
NAME EMP.ENAME%TYPE;
SALARY EMP.SAL%TYPE;
DESIG EMP.JOB%TYPE;
BEGIN
SELECT EMPNO,ENAME,SAL,JOB INTO NO,NAME,SALARY,DESIG
FROM EMP WHERE EMPNO=&EMPNO;
IF SQL%FOUND THEN
DBMS_OUTPUT.PUT_LINE(NO||' '||NAME||' '||SALARY||' '||DESIG);
END IF;
EXCEPTION
WHEN NO_DATA_FOUND THEN
DBMS_OUTPUT.PUT_LINE('NO DATA FOUND');
DECLARE
NEWNO EMP.EMPNO%TYPE;
NAME EMP.ENAME%TYPE;
DESIG EMP.JOB%TYPE;
BEGIN
SELECT ENAME,JOB INTO NAME,DESIG FROM EMP WHERE EMPNO=&NEWNO;
DBMS_OUTPUT.PUT_LINE(NAME||' '||dESIG);
END;
END;
INVALID CURSOR(OPENING IN LOOP)
--------------
DECLARE
CURSOR C1 IS SELECT * FROM EMP;
A EMP%ROWTYPE;
BEGIN
LOOP
FETCH C1 INTO A;
OPEN C1;
EXIT WHEN C1%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(A.ENAME||' '||A.JOB||' '||A.SAL);
END LOOP;
CLOSE C1;
EXCEPTION
WHEN INVALID_CURSOR THEN
DBMS_OUTPUT.PUT_LINE('INVALID CURSOR');
END;

117
CURSOR_ALREADY_OPEN
--------------------
DECLARE
CURSOR C1 IS SELECT * FROM EMP ;
A C1%ROWTYPE;
BEGIN open c1;
LOOP
OPEN C1;
FETCH C1 INTO A;
EXIT WHEN C1%NOtFOUND;
DBMS_OUTPUT.PUT_LINE(a.sal||' '||a.ename);
END LOOP;
CLOSE C1; exception when cursor_already_open then dbms_output.put_line('cursor already openED');
END;
WHEN OTHERS
------------
DESC TEMP
A VARCHAR2(10)
B VARCHAR2(25)
C VARCHAR2(25)
DECLARE
ENO NUMBER(4);
NAME VARCHAR2(10);
DEPNO NUMBER(3);
ACODE NUMBER(4);
BMSG VARCHAR2(40);
EMPNO NUMBER(4);
BEGIN
SELECT EMPNO,ENAME,DEPTNO INTO ENO,NAME,DEPNO FROM EMP
WHERE empno=&empno;
DBMS_OUTPUT.PUT_LINE(ENO||' '||NAME||' '||DEPNO);
EXCEPTION
WHEN OTHERS THEN
ACODE:=SQLCODE;
BMSG:=SQLERRM;
DBMS_OUTPUT.PUT_LINE('ACODE:'||' '||ACODE||' '||BMSG);
--INSERT INTO temp VALUES(ACODE,BMSG ,'asds');
END;
DUP_VAL_ON_INDEX
----------------- create table temp(a number(3) primary key, b varchar2(10),c varchar2(10)); declare dno dept.deptno%type; dname dept.dname%type; loc dept.loc%type;

118 begin insert into DEPT values(&deptno,'&dname','&loc'); exception when dup_val_on_index then dbms_output.put_line('DUP_VALUES_ON_INDEX'); end;
USER_DEFINED_EXCEPTION
----------------------
DECLARE
SALARY EMP.SAL%TYPE;
COM EMP.COMM %TYPE;
MIS_COMM EXCEPTION;
NETSAL NUMBER(7);
BEGIN
SELECT SAL,COMM INTO SALARY,COM FROM EMP WHERE EMPNO=&N;
DBMS_OUTPUT.PUT_LINE(SALARY||' '||COM);
IF COM IS NULL THEN
RAISE MIS_COMM;
ELSE
NETSAL:=SALARY+COM;
DBMS_OUTPUT.PUT_LINE(SALARY||' '||COM||' '||NETSAL);
END IF;
EXCEPTION
WHEN MIS_COMM THEN
DBMS_OUTPUT.PUT_lINE('ORA421'||' '||'MISS_COMM EXCEPTION');
END;
PARAMETER(ERROR)
----------
DECLARE
I EMP%ROWTYPE;
CURSOR C1(TEMPENO NUMBER) IS

119
SELECT * FROM EMP WHERE EMPNO=TEMPENO;
BEGIN
OPEN C1(7499);
FETCH C1 INTO I ;
INSERT INTO EMP(EMPNO,ENAME,DEPTNO) VALUES(I.EMPNO,I.ENAME,I.DEPTNO);
--EXIT WHEN C1%NOT FOUND;
--END LOOP;
END;
WEAK CURSOR(NO RETURN TYPE DECLARATION)
---------------------------------------
DECLARE
TYPE T1 IS REF CURSOR;
T2 T1;
A EMP%ROWTYPE;
BEGIN
OPEN T2 FOR SELECT * FROM EMP;
LOOP
FETCH T2 INTO A;
EXIT WHEN T2%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(A.EMPNO);
END LOOP;
CLOSE T2;
END;
DATA BASE TRIGGER:
------------------
BEFORE/AFTER INSERT OR UPDATE OR DELETE ON TABLENAME FOR EACH ROW
(ERROR)
CREATE OR REPLACE TRIGGER T1 BEFORE INSERT ON EMP
DECLARE
A VARCHAR2(10);
BEGIN
SELECT TO_CHAR(SYSDATE,'DAY') INTO A FROM DUAL;
IF A ='TUESDAY' THEN
RAISE_APPLICATION_ERROR(-20909,'INSERTION NOT POSSIBLE');
END IF;
END;
ERROR NO: -20000 TO -20999
(FIND T1 OR T2 )(OK)
CREATE OR REPLACE TRIGGER T2 BEFORE INSERT ON EMP FOR EACH ROW
DECLARE
A NUMBER;
BEGIN
SELECT COUNT(*) INTO A FROM EMP WHERE DEPTNO=:NEW.DEPTNO;
IF A>=1 THEN
RAISE_APPLICATION_ERROR(-20101,'PRIMARY KEY VIOLATION');
END IF;
END;

120
CREATE OR REPLACE TRIGGER DELDEPT
AFTER DELETE ON DEPT
FOR EACH ROW
BEGIN
DELETE EMP WHERE DEPTNO=:OLD.DEPTNO;
DBMS_OUTPUT.PUT_LINE('PARENT CHILD DELETED');
END;
CREATE OR REPLACE TRIGGER CHECK_SAL
BEFORE update ON emp
FOR EACH ROW
BEGIN
IF :NEW.SAL<1000 OR :NEW.SAL>5000 THEN
RAISE_APPLICATION_ERROR(-20001,'CHECK SAL ');
END IF;
END;
CREATE OR REPLACE TRIGGER T1 BEFORE INSERT ON DEPT FOR EACH ROW
DECLARE
A DEPT.DEPTNO%TYPE;
BEGIN
SELECT COUNT(DEPTNO) INTO A FROM DEPT
WHERE DEPTNO=:NEW.DEPTNO;
IF A>=1 THEN
RAISE_APPLICATION_ERROR(-20001,'MASTER EXIST');
END IF;
EXCEPTION
WHEN NO_DATA_FOUND THEN
DBMS_OUTPUT.PUT_LINE('-20001 NO MASTER RECORD');
END;
(MUTATING ERROR)
CREATE OR REPLACE TRIGGER T3 AFTER UPDATE ON EMP FOR EACH ROW
DECLARE
A NUMBER(1);
BEGIN
SELECT COUNT(*) INTO A FROM EMP WHERE DEPTNO=:old.DEPTNO;
dbms_output.put_line('new.depttno'||' '||:old.deptno);
IF A>1 THEN
RAISE_APPLICATION_ERROR(-20001,'UPDATED');
END IF;
END ;
VARRAY SELECT STATEMENT
-----------------------
/*DECLARE
CURSOR C1 IS SELECT * FROM TABLENAME;
A CI%ROWTYPE;
BEGIN
FOR I IN C1
LOOP
DBMS_OUTPUT.PUT_LINE('SDFS :'|| );
FOR I IN C1.COUNT
LOOP

121
DBMS_OUTPUT.PUT_LINE(SDA);
END LOOP;
END LOOP
END;
NESTED TABLES:
--------------
*/
SELECT X.NAME FROM THE (SELECT EMPL FROM DEPTNEST WHERE DNO=10) X
WHERE X.NAME='YYYY';
SUBPROGRAMS
1. PROCEDURE Syntax:
CREATE OR REPLACE PROCEDURE <PROCNAME> (PARAMETERLIST) IS
<DECLARATION>
BEGIN
EXECUTABLE STATEMENTS
EXCEPTION HANDLERS
END;
Eg.:
CREATE OR REPLACE PROCEDURE P1 (A NUMBER,B NUMBER) IS
COMMISSION NUMBER;
NULL_COMM EXCEPTION;
BEGIN
SELECT COMM INTO COMMISSION FROM EMP WHERE EMPNO=A;
IF COMMISSION IS NULL THEN
RAISE NULL_COMM;
ELSE
UPDATE EMP SET COMM=SAL+B WHERE EMPNO=A;
END IF;
EXCEPTION WHEN NULL_COMM THEN
DBMS_OUTPUT.PUT_LINE('THE VALUE COMM IS NULL');
END;
EXEC P1(7499,1000);
1.1 IN PARAMETER
CREATE OR REPLACE PROCEDURE P2 (NO IN NUMBER) IS PRICE NUMBER;
BEGIN
SELECT ACTUALPRICE INTO PRICE FROM ITEM WHERE ITEMID=NO;
DBMS_OUTPUT.PUT_LINE('ORIGINAL PRICE IS'||'
'||TO_CHAR(PRICE));
IF PRICE IS NULL THEN
DBMS_OUTPUT.PUT_LINE('PRICE IS NULL');
END IF;
END;
EXEC P2(10);

122
1.2 IN OUT PARAMETER
CREATE OR REPLACE PROCEDURE P3 (INNER IN NUMBER, A OUT NUMBER)
IS ID NUMBER;
BEGIN
SELECT DEPTNO INTO ID FROM EMP WHERE EMPNO=INNER;
IF ID<40 THEN
A:=50;
END IF;
END;
DECLARE
INNER NUMBER;
A NUMBER;
BEGIN
P3 (7499,A);
DBMS_OUTPUT.PUT_LINE('THE OUT VALUE IS '||' '||TO_CHAR(A));
END;
CREATE OR REPLACE PROCEDURE SAMPLE (A IN NUMBER,B IN OUT
NUMBER)
IS ID NUMBER;
BEGIN
SELECT ORDID,PRODID INTO ID ,B FROM ITEM WHERE ITEMID=A;
IF B<500 THEN
B:=B+100;
END IF;
END;
DECLARE
A NUMBER;
B NUMBER;
BEGIN
SAMPLE(10,B);
DBMS_OUTPUT.PUT_LINE('B VALUE IS'||' '||B);
END;
FUNCTIONS
---------
<CREATE OR REPLACE FUNCTION NAME> {(ARGUMENT) - IN ,OUT ,IN OUT}
RETURN DATATYPE IS >
DECLARATION
BEGIN
EXECUTABLE STATEMENTS
EXCEPTION
EXCEPTION HANDLERS
END; create or replace function f1 return number is

123 a emp.sal%type; begin
SELECT SAL INTO A FROM EMP WHERE ENAME='ALLEN';
RETURN A;
END;
DECLARE
B NUMBER;
BEGIN
B:=F1;
DBMS_OUTPUT.PUT_LINE(B);
END;
CREATE OR REPLACE FUNCTION FUN(ID NUMBER,AMOUNT NUMBER)
RETURN BOOLEAN IS
MINI NUMBER;
MAXI NUMBER;
BEGIN
SELECT MINPRICE,STDPRICE INTO MINI,MAXI FROM PRICE WHERE PRODID=ID;
RETURN (MINI>=AMOUNT) OR (MAXI>=AMOUNT);
END;
TO EXECUTE IT:
DECLARE
ID NUMBER;
AMOUNT NUMBER;
REMARK BOOLEAN;
BEGIN
ID:=&A;
AMOUNT:=&B;
REMARK:=FUN(ID,AMOUNT);
IF REMARK=TRUE THEN
DBMS_OUTPUT.PUT_LINE('TRUE');
ELSE
DBMS_OUTPUT.PUT_LINE('FALSE');
END IF;
END;
CREATE OR REPLACE FUNCTION FUN(N VARCHAR2)
RETURN VARCHAR2 IS
J VARCHAR2(10);
BEGIN
SELECT JOB INTO J FROM EMP WHERE ENAME=N;
RETURN J;
END;
SELECT FUN('BLAKE') FROM DUAL;
IN PARAMETER
-------------
CREATE OR REPLACE FUNCTION F1(NAME IN VARCHAR2) RETURN NUMBER IS
A EMP.SAL%TYPE;
BEGIN

124
SELECT SAL INTO A FROM EMP WHERE ENAME=NAME;
RETURN A;
END;
DECLARE
B NUMBER;
BEGIN
B:=F1('&A');
DBMS_OUTPUT.PUT_LINE(B);
END;
IN AND OUT
----------
CREATE OR REPLACE FUNCTION F1(NAME IN VARCHAR2,B OUT VARCHAR2) RETURN
NUMBER IS
A EMP.SAL%TYPE;
BEGIN
SELECT SAL,JOB INTO A,B FROM EMP WHERE ENAME=NAME;
RETURN A;
END;
DECLARE
A NUMBER;
JOB VARCHAR2(20);
BEGIN
A:=F1('&c',JOB);
DBMS_OUTPUT.PUT_LINE(A||' '||JOB);
END;
IN OUT
------
CREATE OR REPLACE function F1(A IN number,c OUT NUMBER) RETURN NUMBER
IS
B EMP.COMM%TYPE;
BEGIN
SELECT SAL,COMM INTO sal1,comm1 FROM EMP WHERE EMPNO=A;
RETURN sal1;
END;
/* ERROR */
DECLARE
M2 NUMBER(5);
M3 NUMBER;
M1 NUMBER;
SALARY NUMBER;
BEGIN
M1:=F1(&M2,M3);
DBMS_OUTPUT.PUT_LINE(M2||' '||SALARY);
END;
PACKAGE SPECIATION
-------------------
CREATE OR REPLACE PACKAGE PACK1 IS
PROCEDURE P1;
FUNCTION F1 RETURN NUMBER;

125
A NUMBER;
END PACK1;
CREATE OR REPLACE PACKAGE BODY PACK1 IS
PROCEDURE P1 IS
BEGIN
DBMS_OUTPUT.PUT_LINE('P1 PACKAGE');
END P1;
FUNCTION F1 RETURN NUMBER IS
BEGIN
A:=1000;
RETURN A;
END F1;
END PACK1;
DECLARE
N NUMBER;
BEGIN
N:=PACK1.F1;
DBMS_OUTPUT.PUT_LINE(N);
PACK1.P1;
END;
/*
CREATE OR REPLACE PACKAGE PACK2 IS
PROCEDURE DDEP;
FUNCTION BALANCE RETURN NUMBER;
NAME VARCHAR2(15);
END PACK2;
CREATE PACKAGE BODY PACK2 IS
FUNCTION BALANCE (NAME IN VARCHAR2)
RETURN NUMBER AS
BALANCE NUMBER(10,2);
BEGIN
SELECT SAL INTO BALANCE FROM EMP WHERE ENAME=NAME;
RETURN(BALANCE);
EXCEPTIONS
WHEN NO_DATA_FOUND THEN
RAISE_APPLICATION_ERROR(-20101,'NO WORKER ON THAT NAME');
END PACK2;
PROCEDURE DDEP(NAME IN VARCHAR2) IS
BEGIN
INSERT INTO DEPT(DEPTNO,DNAME,LOC) VALUES(10,NAME,NULL);
END DDEP;
END PACK2; */
PL/SQL COMPOSITE DATA TYPE
--------------------------
DECLARE
TYPE T1 IS TABLE OF EMP.sal %TYPE
INDEX BY BINARY_INTEGER;

126
M BINARY_INTEGER :=1;
T2 T1;
BEGIN
FOR I IN 1..20
LOOP
T2(M) :=I*10;
DBMS_OUTPUT.PUT_LINE(T2(M)||' '||m);
M:=M+1;
END LOOP;
END;
DECLARE
TYPE T1 IS TABLE OF EMP.ENAME%TYPE
INDEX BY BINARY_INTEGER;
M BINARY_INTEGER:=0;
T2 T1;
BEGIN
FOR I IN (SELECT ENAME FROM EMP )
LOOP
T2(M):=I.ENAME;
--INSERT INTO DEPT1(DNAME) VALUES(T2(M)); dbms_output.put_line(t2(m)||' '||m);
M:=M+1;
END LOOP;
END;
DECLARE
TYPE T1 IS TABLE OF EMP.ENAME%TYPE
INDEX BY BINARY_INTEGER;
M BINARY_INTEGER :=1;
T2 T1;
T3 T1;
BEGIN
FOR I IN(SELECT ENAME FROM EMP)
LOOP
T2(M) :=I.ENAME;
T3(M):=T2;
DELETE FROM EMP WHERE ENAME=T2(M);
DBMS_OUTPUT.PUT_LINE(T3(M));
M:=M+1;
END LOOP;
END;
DECLARE
TYPE T1 IS TABLE OF DEPT%ROWTYPE
INDEX BY BINARY_INTEGER;
T2 T1;
M BINARY_INTEGER :=1;
BEGIN
FOR I IN (SELECT * FROM DEPT)
LOOP
T2(M).DEPTNO :=I.DEPTNO;
T2(M).DNAME :=I.DNAME;
T2(M).LOC :=I.LOC;
DBMS_OUTPUT.PUT_LINE(T2(M).DEPTNO||' '||T2(M).DNAME||' '||T2(M).LOC);
M :=M+1;
END LOOP;

127
END;
--RECORD(ONE ROW)
DECLARE
TYPE T1 IS RECORD
(A NUMBER(3),B VARCHAR2(30),C VARCHAR2(30));
T2 T1;
BEGIN
SELECT * INTO T2 FROM DEPT WHERE DEPTNO=10;
DBMS_OUTPUT.PUT_LINE(T2.A||T2.B||T2.C);
END;
BEGIN
END;
SELECT * FROM EMP;
-----------------------------------------
BEGIN
UPDATE EMP SET SAL=SAL+2000;
END;
-----------------------------------------
DECLARE
I NUMBER :=7788;
J NUMBER :=10000;
BEGIN
UPDATE EMP SET SAL=J WHERE EMPNO=I;
END;
-----------------------------------------
DECLARE
I NUMBER:=&I;
J NUMBER:=&J;
BEGIN
UPDATE EMP SET SAL=J WHERE EMPNO=I;
------------------------------------------
DECLARE
I NUMBER;
J NUMBER;
BEGIN
UPDATE EMP SET SAL=&J WHERE EMPNO=&I;
END;
------------------------------------------
FOR LOOP
--------
FOR <VAR> IN <MIN>..<MAXVALUE>
LOOP

128
-
-
-
END LOOP;
------------------------------------------- declare begin
FOR I IN 1..5
LOOP
INSERT INTO TEMP VALUES (I);
END LOOP; end;
-------------------------------------------
WHILE LOOP
----------
WHILE <CONDITION>
LOOP
-
-
-
END LOOP;
-------------------------------------------
DECLARE
A NUMBER(2);
BEGIN
A:=&A;
FOR COUNT IN 1..A
LOOP
INSERT INTO TEMP VALUES (COUNT);
END LOOP;
END;
-------------------------------------------
DECLARE
I NUMBER:=10;
BEGIN
WHILE I <=15
LOOP
INSERT INTO TEMP VALUES (I);
I:=I+1;
END LOOP;
END;
-------------------------------------------
DECLARE
I NUMBER:=1;
BEGIN
WHILE I<=10
LOOP
INSERT INTO TEMP VALUES(I,'XXXX');

129
IF I>5 THEN
EXIT;
END IF;
I:=I+1;
END LOOP;
INSERT INTO TEMP VALUES(I,'YYYY');
END;
-------------------------------------------
GO TO STATEMENT
---------------
DECLARE
I NUMBER:=1;
BEGIN
WHILE I<=10
LOOP
INSERT INTO TEMP VALUES(I,'XXXX');
IF I=5 THEN
GOTO PROC;
END IF;
I:=I+1;
END LOOP;
<<PROC>>
INSERT INTO TEMP VALUES(I,'PROC');
END;
------------------------------------------------------------
USING INTO CLASS
----
DECLARE
TEMP NUMBER: = &TEMPNO;
TEMPSAL NUMBER;
BEGIN
END;
SELECT SAL INTO TEMPSAL FROM EMP WHERE EMPNO=TEMP;
DBMS_OUTPUT.PUT_LINE(TEMPSAL);
SET SERVEROUT ON;
------------------------------------------------------------
////////////////(UPDATE ERROR)
DECLARE
TNO NUMBER:=&TEMPNO;
TEMPSAL NUMBER;
TEMPCOMM NUMBER;
BEGIN
SELECT SAL,COMM INTO TEMPSAL,TEMPCOMM FROM EMP WHERE
EMPNO=TNO;
IF TEMPCOMM >1000 AND TEMPSAL <=5000 THEN
UPDATE EMP SET SAL=SAL+2000 WHERE EMPNO=TNO;
ELSIF TEMPSAL >2000 THEN
UPDATE EMP SET SAL=SAL+1000 WHERE EMPNO=TNO;
END IF;
END;

130
-------------------------------------------------------------------
DECLARE
TEMPEMPNO NUMBER:=&TEMPEMPNO;
TEMPHIREDATE DATE;
TEMPNAME VARCHAR2(20);
BEGIN
THEN
SELECT HIREDATE,ENAME INTO TEMPHIREDATE,TEMPNAME FROM EMP
WHERE EMPNO=TEMPEMPNO;
IF TEMPHIREDATE >='01-JAN-80' AND TEMPHIREDATE <='30-JAN-85'
UPDATE EMP SET COMM=COMM+COMM*0.1 WHERE EMPNO=TEMPEMPNO;
END IF;
END;
-------------------------------------------------------------------
DECLARE
TEMPEMPNO NUMBER:=&TEMPEMPNO;
TEMPDEPTNO NUMBER;
BEGIN
SELECT DEPTNO INTO TEMPDEPTNO WHERE EMPNO=TEMPEMPNO;
IF TEMPDEPTNO=10 THEN
UPDATE EMP SET SAL=SAL+1000 WHERE EMPNO=TEMPEMPNO;
ELSIF TEMPDEPTNO=20 THEN
UPDATE EMP SET SAL=SAL+2000 WHERE EMPNO=TEMPEMPNO;
ELSIF TEMPDEPTNO=30 THEN
UPDATE EMP SET SAL=SAL+3000 WHERE EMPNO=TEMPEMPNO;
ELSE
UPDATE EMP SET SAL=SAL+4000 WHERE EMPNO=TEMPEMPNO;
END IF;
END;
-------------------------------------------------------------------
DECLARE
A NUMBER;
B NUMBER;
C NUMBER;
BEGIN
A:=&A;
B:=&B;
C:=A+B;
DBMS_OUTPUT.PUT_LINE(C);
END;
-----------------------------------------------------------------------
--
%TYPE
--------
DECLARE
SALARY EMP.SAL%TYPE;
DOJ EMP.HIREDATE%TYPE;
BEGIN
SELECT SAL,HIREDATE INTO SALARY,DOJ FROM EMP WHERE EMPNO=7900;

131
END;
DBMS_OUTPUT.PUT_LINE(SALARY||' '||DOJ);
-----------------------------------------------------------------------
-