4-5 4-5 Exponential and Logarithmic Exponential and Logarithmic Equations and Inequalities Equations and Inequalities Warm Up Lesson Presentation Lesson Quiz HoltMcDougal Algebra 2Algebra 2 Holt 4-5 Exponential and Logarithmic Equations and Inequalities Warm Up Solve. 1. log16x = 3 2 64 2. logx1.331 = 3 1.1 3. log10,000 = x 4 Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Objectives Solve exponential and logarithmic equations and equalities. Solve problems involving exponential and logarithmic equations. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Vocabulary exponential equation logarithmic equation Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities An exponential equation is an equation containing one or more expressions that have a variable as an exponent. To solve exponential equations: • Try writing them so that the bases are all the same. • Take the logarithm of both sides. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Helpful Hint When you use a rounded number in a check, the result will not be exact, but it should be reasonable. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Example 1A: Solving Exponential Equations Solve and check. 98 – x = 27x – 3 (32)8 – x = (33)x – 3 Rewrite each side with the same base; 9 and 27 are powers of 3. To raise a power to a power, 316 – 2x = 33x – 9 multiply exponents. 16 – 2x = 3x – 9 Bases are the same, so the exponents must be equal. x=5 Holt McDougal Algebra 2 Solve for x. 4-5 Exponential and Logarithmic Equations and Inequalities Example 1A Continued Check 98 – x = 27x – 3 98 – 5 275 – 3 93 272 729 729 The solution is x = 5. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Example 1B: Solving Exponential Equations Solve and check. 4x – 1 = 5 5 is not a power of 4, so take the log 4x – 1 = log 5 log of both sides. Apply the Power Property of (x – 1)log 4 = log 5 Logarithms. log5 x –1 = log4 Divide both sides by log 4. log5 x = 1 + log4 ≈ 2.161 Check Use a calculator. The solution is x ≈ 2.161. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 1a Solve and check. 32x = 27 (3)2x = (3)3 Rewrite each side with the same base; 3 and 27 are powers of 3. 32x = 33 To raise a power to a power, multiply exponents. 2x = 3 Bases are the same, so the exponents must be equal. x = 1.5 Holt McDougal Algebra 2 Solve for x. 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 1a Continued Check 32x = 27 32(1.5) 27 33 27 27 27 The solution is x = 1.5. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 1b Solve and check. 7–x = 21 log 7–x = log 21 (–x)log 7 = log 21 log21 –x = log7 log21 21 is not a power of 7, so take the log of both sides. Apply the Power Property of Logarithms. Divide both sides by log 7. x = – log7 ≈ –1.565 Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 1b Continued Check Use a calculator. The solution is x ≈ –1.565. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 1c Solve and check. 23x = 15 log23x = log15 (3x)log 2 = log15 log15 3x = log2 x ≈ 1.302 Holt McDougal Algebra 2 15 is not a power of 2, so take the log of both sides. Apply the Power Property of Logarithms. Divide both sides by log 2, then divide both sides by 3. 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 1c Continued Check Use a calculator. The solution is x ≈ 1.302. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Example 2: Biology Application Suppose a bacteria culture doubles in size every hour. How many hours will it take for the number of bacteria to exceed 1,000,000? At hour 0, there is one bacterium, or 20 bacteria. At hour one, there are two bacteria, or 21 bacteria, and so on. So, at hour n there will be 2n bacteria. Solve 2n > 106 Write 1,000,000 in scientific annotation. log 2n > log 106 Take the log of both sides. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Example 2 Continued nlog 2 > log 106 Use the Power of Logarithms. nlog 2 > 6 log 106 is 6. 6 n > log 2 Divide both sides by log 2. 6 n > 0.301 Evaluate by using a calculator. n > ≈ 19.94 Round up to the next whole number. It will take about 20 hours for the number of bacteria to exceed 1,000,000. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Example 2 Continued Check In 20 hours, there will be 220 bacteria. 220 = 1,048,576 bacteria. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 2 You receive one penny on the first day, and then triple that (3 cents) on the second day, and so on for a month. On what day would you receive a least a million dollars. $1,000,000 is 100,000,000 cents. On day 1, you would receive 1 cent or 30 cents. On day 2, you would receive 3 cents or 31 cents, and so on. So, on day n you would receive 3n–1 cents. Solve 3n – 1 > 1 x 108 Write 100,000,000 in scientific annotation. log 3n – 1 > log 108 Take the log of both sides. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 2 Continued (n – 1) log 3 > log 108 Use the Power of Logarithms. (n – 1)log 3 > 8 8 n – 1 > log 3 8 log 108 is 8. Divide both sides by log 3. n > log3 + 1 Evaluate by using a calculator. n > ≈ 17.8 Round up to the next whole number. Beginning on day 18, you would receive more than a million dollars. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 2 Check On day 18, you would receive 318 – 1 or over a million dollars. 317 = 129,140,163 cents or 1.29 million dollars. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities A logarithmic equation is an equation with a logarithmic expression that contains a variable. You can solve logarithmic equations by using the properties of logarithms. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Remember! Review the properties of logarithms from Lesson 7-4. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Example 3A: Solving Logarithmic Equations Solve. log6(2x – 1) = –1 6 log (2x –1) 6 = 6–1 2x – 1 = 1 6 7 x = 12 Holt McDougal Algebra 2 Use 6 as the base for both sides. Use inverse properties to remove 6 to the log base 6. Simplify. Exponential and Logarithmic Equations and Inequalities 4-5 Example 3B: Solving Logarithmic Equations Solve. log4100 – log4(x + 1) = 1 100 log4(x + 1 ) = 1 log4( x + 1 ) 100 4 = 41 100 =4 x+1 x = 24 Holt McDougal Algebra 2 Write as a quotient. Use 4 as the base for both sides. Use inverse properties on the left side. 4-5 Exponential and Logarithmic Equations and Inequalities Example 3C: Solving Logarithmic Equations Solve. log5x 4 = 8 4log5x = 8 log5x = 2 x = 52 x = 25 Holt McDougal Algebra 2 Power Property of Logarithms. Divide both sides by 4 to isolate log5x. Definition of a logarithm. 4-5 Exponential and Logarithmic Equations and Inequalities Example 3D: Solving Logarithmic Equations Solve. log12x + log12(x + 1) = 1 log12 x(x + 1) = 1 12 log x(x +1) 12 = 121 x(x + 1) = 12 Holt McDougal Algebra 2 Product Property of Logarithms. Exponential form. Use the inverse properties. 4-5 Exponential and Logarithmic Equations and Inequalities Example 3 Continued x2 + x – 12 = 0 (x – 3)(x + 4) = 0 Multiply and collect terms. Factor. x – 3 = 0 or x + 4 = 0 Set each of the factors equal to zero. x = 3 or x = –4 Solve. Check Check both solutions in the original equation. log12x + log12(x +1) = 1 log12x + log12(x +1) = 1 log123 + log12(3 + 1) log123 + log124 log1212 1 1 1 1 1 log12( –4) + log12(–4 +1) 1 x log12( –4) is undefined. The solution is x = 3. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 3a Solve. 3 = log 8 + 3log x 3 = log 8 + 3log x 3 = log 8 + log x3 3 = log (8x3) 103 = 10log (8x3) 1000 = 8x3 125 = x3 5=x Holt McDougal Algebra 2 Power Property of Logarithms. Product Property of Logarithms. Use 10 as the base for both sides. Use inverse properties on the right side. 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 3b Solve. 2log x – log 4 = 0 x 2log( 4 log 2(10 )=0 Write as a quotient. x 4 Use 10 as the base for both sides. ) = 100 2( x ) = 1 4 x=2 Holt McDougal Algebra 2 Use inverse properties on the left side. 4-5 Exponential and Logarithmic Equations and Inequalities Caution Watch out for calculated solutions that are not solutions of the original equation. Holt McDougal Algebra 2 Exponential and Logarithmic 4-5 Equations and Inequalities Example 4A: Using Tables and Graphs to Solve Exponential and Logarithmic Equations and Inequalities Use a table and graph to solve 2x + 1 > 8192x. Use a graphing calculator. Enter 2^(x + 1) as Y1 and 8192x as Y2. In the table, find the x-values where Y1 is greater than Y2. In the graph, find the x-value at the point of intersection. The solution set is {x | x > 16}. Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Example 4B log(x + 70) = 2log( x ) 3 Use a graphing calculator. Enter log(x + 70) as Y1 and 2log( x ) as Y2. 3 In the table, find the x-values where Y1 equals Y2. The solution is x = 30. Holt McDougal Algebra 2 In the graph, find the x-value at the point of intersection. 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 4a Use a table and graph to solve 2x = 4x – 1. Use a graphing calculator. Enter 2x as Y1 and 4(x – 1) as Y2. In the table, find the x-values where Y1 is equal to Y2. The solution is x = 2. Holt McDougal Algebra 2 In the graph, find the x-value at the point of intersection. 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 4b Use a table and graph to solve 2x > 4x – 1. Use a graphing calculator. Enter 2x as Y1 and 4(x – 1) as Y2. In the table, find the x-values where Y1 is greater than Y2. The solution is x < 2. Holt McDougal Algebra 2 In the graph, find the x-value at the point of intersection. 4-5 Exponential and Logarithmic Equations and Inequalities Check It Out! Example 4c Use a table and graph to solve log x2 = 6. Use a graphing calculator. Enter log(x2) as Y1 and 6 as Y2. In the table, find the x-values where Y1 is equal to Y2. The solution is x = 1000. Holt McDougal Algebra 2 In the graph, find the x-value at the point of intersection. 4-5 Exponential and Logarithmic Equations and Inequalities Lesson Quiz: Part I Solve. 1. 43x–1 = 8x+1 x= 5 3 2. 32x–1 = 20 x ≈ 1.86 3. log7(5x + 3) = 3 x = 68 4. log(3x + 1) – log 4 = 2 x = 133 5. log4(x – 1) + log4(3x – 1) = 2 x=3 Holt McDougal Algebra 2 4-5 Exponential and Logarithmic Equations and Inequalities Lesson Quiz: Part II 6. A single cell divides every 5 minutes. How long will it take for one cell to become more than 10,000 cells? 70 min 7. Use a table and graph to solve the equation 23x = 33x–1. x ≈ 0.903 Holt McDougal Algebra 2