Jeopardy Simple Compound Absolute Review Inequalities Value Word Problems Random Review Q $100 Q $100 Q $100 Q $100 Q $100 Q $200 Q $200 Q $200 Q $200 Q $200 Q $300 Q $300 Q $300 Q $300 Q $300 Q $400 Q $400 Q $400 Q $400 Q $400 Q $500 Q $500 Q $500 Q $500 Q $500 Final Jeopardy $100 Simple Review Solve, graph, describe: 10 > -5y $100 Answer Simple Review y > -2 $200 Simple Review Simplify: $200 Answer Simple Review 11 7 x y 6 4 $300 Simple Review Solve, graph, describe: 1 + 2x < 2(x – 1) $300 Answer Simple Review No Solution $400 Simple Review Evaluate: 2a 2bc 2 c 5 3 if a=2, b= -4, and c=3 $400 Answer Simple Review -2 $500 Simple Review Solve, graph, describe: y ≥ -1 and y ≥ 3 $500 Answer Simple Review y≥3 $100 Compound Inequalities Solve, graph, describe: w < 0 and w ≥ 4 $100 Answer Compound Inequalities No Solution $200 Compound Inequalities Solve, graph, describe: 7x – 1 > x + 11 or –11x > -33 $200 Answer Compound Inequalities All real numbers $300 Compound Inequalities Solve, graph, describe: 0 < 1 – x ≤ 3 or -1 ≤ 2x – 3 ≤ 5 $300 Answer Compound Inequalities -2 ≤ x ≤ 4 $400 Compound Inequalities Solve, graph, describe: -2y < -6 and y + 3 ≤ 1 $400 Compound Inequalities Answer No Solution $500 Compound Inequalities Solve, graph, describe: 3 – t < 2 or -7 ≤ t + 4 $500 Compound Inequalities Answer t ≥ -11 $100 Absolute Value Solve: │3x – 2│= 8 $100 Answer Absolute Value { -2, 10/3} $200 Absolute Value Solve, graph, describe: x 2 1 3 3 $200 Answer Absolute Value x ≤ 1 or x ≥ 5 $300 Absolute Value Solve, graph, describe: 1 d 5 2 d 13 2 $300 Answer Absolute Value -12 ≤ d ≤ 12 $400 Absolute Value Solve, graph, describe: 7 3 4d 7 4 or 4 3d 1 2 $400 Answer Absolute Value d < -1 or d > 1/3 $500 Absolute Value Solve, graph, describe: t 2t 6 $500 Answer Absolute Value 2<t<6 $100 Word Problems Define a variable, write an equation/inequality, and solve. The length of a rectangle is 5 cm more than twice its width. Find the length and width if the perimeter is 82 cm. $100 Answer Word Problems Length- 29 cm Width- 12 cm $200 Word Problems Define a variable, write an equation/inequality, and solve. Find all sets of three consecutive odd integers whose sum is between 36 and 50. $200 Answer Word Problems { 11, 13, 15 } { 13, 15, 17 } $300 Word Problems Define a variable, write an equation/inequality, and solve. The base angles of an isosceles triangle each measure fifteen degrees less than half the measure of the vertex angle. Find the measures of the angles of the triangle. $300 Answer Word Problems 37.5º, 37.5º, 105º $400 Word Problems Define a variable, write an equation/inequality, and solve. A women drove part of a 185 mile trip at 50 mi/h and the rest at 55 mi/h. Find the distance she traveled at 50 mi/h if her total driving time was 3 h and 30 minutes. $400 Answer Word Problems 75 miles $500 Word Problems Define a variable, write an equation/inequality, and solve. A grocer wants to mix peanuts and cashews to produce 20 lbs of mixed nuts worth $6.20/lb. How many pounds of each kind of nut should she use if peanuts cost $4.80/lb and cashews cost $8/lb? $500 Answer Word Problems Peanuts: 11.25 lb Cashews: 8.75 lb $100 Random Review Name all the sets the following belong: A) 6 B) ½ C) -1.2356… D) -6 $100 Answer Random Review A) RQZWN B) RQ C) RI D) RQZ $200 Random Review Solve for y: 6xy + 2a + 5yz = c $200 Answer Random Review c 2a y 6 x 5z $300 Random Review If I have n nickels and three more nickels than dimes, write an expression to represent the value in cents of my coins. $300 Answer Random Review 0.05(n) + 0.1( n – 3) $400 Random Review Evaluate: 1 2 2(3 4) 3 10 $400 Answer Random Review 1/2 $500 Random Review Define a variable, write an equation/inequality, and solve. A purse contains $2.05 in nickels, dimes, and quarters. There are twice as many nickels as dimes and three fewer quarters than nickels. Determine the number of each coin. $500 Answer Random Review Nickels: 8 Dimes: 4 Quarters: 5 Final Jeopardy Define a variable, write an equation/inequality, and solve. A bus is to be chartered for the senior class trip. The basic fare is $9.50 per passenger. If more than 20 people go, everyone’s are is reduced by $0.30 for each passenger over this number (20). At least how many people must go to make the fare less than $7.50 per passenger? Final Jeopardy Answer At least 27 people must go.