Transformation-Griffith’s Expt 1928 DNA Mediates Transformation Convert IIR to IIIS By DNA? Avery MacLeod and McCarty Experiment Circa 1943 Transforming Principle DNAse activity + means that activity is present All RNA gets degraded during enzyme preparation A-DNA, B-DNA and Z-DNA The Z-DNA helix is left-handed and has a structure that repeats every 2 base pairs. The major and minor grooves, unlike A- and B-DNA, show little difference in width Non-B DNA in disease Chapter 10 Replication of DNA and Chromosomes DNA Replication is Semiconservative Each strand serves as a template Complementary base pairing determines the sequence of the new strand Each strand of the parental helix is conserved Possible Modes of DNA Replication The Meselson-Stahl Experiment: DNA Replication in E. coli is Semiconservative Visualization of Replication in E. coli Replication in E. coli Note: OriC is 245bp The Origin of Replication in E. coli The Core Origin of Replication in SV 40 Prepriming at oriC in E. coli DNA Polymerases and DNA Synthesis In Vitro Requirements of DNA Polymerases Primer DNA with free 3'-OH Template DNA to specify the sequence of the new strand Substrates: dNTPs Mg2+ (where?) Nucleophilic attack of alpha phosphate which releases pyrophosphate Mg2+ (where?) DNA Polymerase I: 5'3' Polymerase Activity Often called: Kornberg Polymerase DNA Polymerase I: 5'3' Exonuclease Activity Cleaves ahead of itself DNA Polymerase I: 3'5' Exonuclease Activity Proofreading Klenow fragment…..is? DNA Polymerases Polymerases in E. coli – DNA Replication: DNA Polymerases III and I – DNA Repair: DNA Polymerases II, IV, and V Polymerases in Eukaryotes – Replication of Nuclear DNA: Polymerase and/or – Replication of Mitochondrial DNA: Polymerase – DNA Repair: Polymerases and All of these enzymes synthesize DNA 5' to 3' and require a free 3'-OH at the end of a primer DNA Polymerase III is the True DNA Replicase of E. coli DNA replication is a complex process, requiring the concerted action of a large number of proteins. E. coli DNA Polymerase III Holoenzyme Replication in E. coli Note: OriC is 245bp The Origin of Replication in E. coli Prepriming at oriC in E. coli DNA Replication Synthesis of the leading strand is continuous. Synthesis of the lagging strand is discontinuous. The new DNA is synthesized in short segments (Okazaki fragment) that are later joined together. What’s wrong with this picture? RNA Primers are Used to Initiate DNA Synthesis DNA Helicase Unwinds the Parental Double Helix DNA Ligase Covalently Closes Nicks in DNA DNA ligase forms a high energy intermediate that Aside: Calf Intestinal Phosphotase? Cut with EcoR1 GAATTC CTTAAG G-OH p-AATTC CTTAA-p HO-G Calf Intestinal Phosphotase? Cut with EcoR1 G-OH CTTAA-p G-OH CTTAA-OH p-AATTC HO-G HO-AATTC HO-G Calf Intestinal Phosphotase? Cut with EcoR1 p-AATTCgatacagagagactcatgacgG-OH HO-GctatgtctctctgagtactgcCTTAA-p G-OH CTTAA-OH HO-AATTC Vector won’t religate, But will take in insert HO-G Single-Strand DNA Binding (SSB) Protein Supercoiling of Unwound DNA DNA Topoisomerase I Produces SingleStrand Breaks in DNA DNA Topoisomerase II Produces Double-Strand Breaks in DNA The Replication Apparatus in E. coli The E. coli Replisome DNA Replication in Eukaryotes Shorter RNA primers and Okazaki fragments DNA replication only during S phase Multiple origins of replication Telomeres Bidirectional Replication from Multiple Origins in Eukaryotes The Eukaryotic Replisome Eukaryotic Replication Proteins DNA polymerase -DNA PCNA (proliferating cell primase—initiation; nuclear antigen)—sliding priming of Okazaki clamp fragments Replication factor-C Rf DNA polymerase — C)—loading of PCNA processive DNA Ribonuclease H1 and synthesis Ribonuclease FEN-1— DNA polymerase — removal of RNA primers DNA replication and repair in vivo The E. coli Replisome The Telomere Problem Telomerase Telomere Length and Aging Most human somatic cells lack telomerase activity. Shorter telomeres are associated with cellular senescence and death. Diseases causing premature aging are associated with short telomeres. BACs Geometric Doubling Progression 1 2 4 8 16 32 64 128 256 512 1024=103=210 ….10 more doublings is another 210 So 20 doublings is 220=103+3=106 So 30 doublings is 230=103+3+3=109 So 40 doublings is 240=103+3+3+3=1012 Molecular Weight of Nucleosides s Base plus ribose Single phosphate 330 Da= 330g/mol/nt (nucleotide) 660 Da= 660g/mol/bp (base pair) Molecular Weight of Plasmid DNA 330 Da= 330g/mol/nt (nucleotide) 660 Da= 660g/mol/bp (base pair) For 3000bp of DNA (a starting plasmid vector) 3000 bp x 660 g/mol/bp= 1000 x 3 x 660 = 1x 103 x 2 x 103 = 2 x 106 g/mol for a 3kb plasmid 2 x 106 g/mol is how many grams per molecule 6 x 1023 molecules/mol Thus 2 x 106 / 6 x 1023 = g/molecules 1g/ 3 x 1017 molecules for a given 3kb plasmid 2 x 106 g/mol is how many grams per molecule 6 x 1023 molecules/mol Thus 2 x 106 / 6 x 1023 = g/molecules 1g/ 3 x 1017 molecules for a given 3kb plasmid 1g/ 3 x 1017 molecules is the same as 1mg/ 3 x 1014 molecules 1ug/ 3 x 1011 molecules 1ng/ 3 x 108 molecules 1pg/ 3x 105 molecules 1fg/ 3 x 102 (300) molecules If each bacterium can hold 3000 molecules, then each Bacterium makes 10fg of plasmid DNA If one makes 1mg of plasmid DNA, then this is 1012 fg as well If each bacterium can hold 3000 molecules, then each Bacterium makes 10fg of plasmid DNA If one makes 1mg of plasmid DNA, then this is 1012 fg as well Since each bacterium has 10fg DNA, then only 1011 Are needed to produce 1mg DNA. …..So 40 doublings is 240=103+3+3+3=1012 236=~1011 36 doublings for 1011 bacteria 3 cell divisions per hour or about 12 hours What are the factors that affect DNA replication? Geometric Doubling Progression 1 2 4 8 16 32 64 128 256 512 1024=103=210 ….10 more doublings is another 210 So 20 doublings is 220=103+3=106 So 30 doublings is 230=103+3+3=109 So 40 doublings is 240=103+3+3+3=1012