ECE 875: Electronic Devices Prof. Virginia Ayres Electrical & Computer Engineering Michigan State University ayresv@msu.edu Lecture 20, 24 Feb 14 Chp. 02: pn junction: Info: Linearly graded junction Multiple charge layers Example Chp. 03: metal-semiconductor junction: Schottky barrier Review Examples New VM Ayres, ECE875, S14 Linearly graded junction: Why: Why: get a more uniform E (x) over a bigger x region VM Ayres, ECE875, S14 Linearly graded junction: How: Q and r E (x) yi(x) VM Ayres, ECE875, S14 Linearly graded junction: How: Q and r ~ a x E (x) ~ ax2 + B yi(x) ~ ax2 + Bx +C Linearly graded junction: How: VM Ayres, ECE875, S14 VM Ayres, ECE875, S14 Practical: 1/ The curvature of the initial C-V curve is different from that for an abrupt junction The slope gives the grading constant a The intercept gives the equilibrium built in potential ybi VM Ayres, ECE875, S14 Lecture 20, 24 Feb 14 Chp. 02: pn junction: Info: Linearly graded junction Multiple charge layers Example Chp. 03: metal-semiconductor junction: Schottky barrier Review Examples New VM Ayres, ECE875, S14 Example: Set up the answer: (a) Find ybi at equilibrium fro the following doping profile in si at 300 K (b) Draw the energy band-bending diagram p n p 1017 cm-3 1016 cm-3 1015 cm-3 VM Ayres, ECE875, S14 VM Ayres, ECE875, S14 1st 2nd 3rd VM Ayres, ECE875, S14 q q VM Ayres, ECE875, S14 Lecture 20, 24 Feb 14 Chp. 02: pn junction: Info: Linearly graded junction Multiple charge layers Example Chp. 03: metal-semiconductor junction: Schottky barrier Review Examples New VM Ayres, ECE875, S14 @ Interconnects: • Use energy band diagrams to describe what is happening • One question to answer: is it an Ohmic contact or a Schottky barrier contact? • Interconnect contacts are key for nanotechnology: – MOSFET: Ohmic contact = good – NanoFET: SB contact = good Individual energy band diagrams: Different nature of a metal Lots of e- and NO Egap EC = at EF Need 2 descriptions: Electron affinity qcs = where is EC relative to Evac Need 1 description: Work Function of the metal qFm: where is EF = EC relative to Evac Work Function qFs = where is EF relative to Evac When in physical contact EFm and EFs align: Four cases = the same approach: 1. metal with small work function/n-type semiconductor: Ohmic (barrier) 2. metal with big work function/n-type semiconductor: Schottky barrier 3. metal with small work function/p-type semiconductor: Schottky barrier 4. metal with big work function/p-type semiconductor: Ohmic (barrier) In every case, use logic: do I need to make the metal more n-type (add e- from semiconductor) or less n-type (e- move into semiconductor) Four cases = the same approach: 1. metal with small work function/n-type semiconductor: Ohmic (barrier) 2. metal with big work function/n-type semiconductor: Schottky barrier 3. metal with small work function/p-type semiconductor: Schottky barrier 4. metal with big work function/p-type semiconductor: Ohmic (barrier) In every case, use logic: do I need to make the metal more n-type (add e- from semiconductor) or less n-type (e- move into semiconductor) 2. metal with big work function/n-type semiconductor • electrons move to metal side leaving Nd+ behind • Size of n-side strip is set by doping concentration and can be large --N + N + n --N + N + To bring the Fermi energy level of the metal up: make the metal more n-type d d d d Schottky Barrier: ND+ on n-side --N + N + n --N + N + d d d d Schottky Barrier: Very narrow region with high concentration of e- similar to ionized NA = large --N + N + n --N + N + d d d d 3. metal with small work function/p-type semiconductor • electrons move to p-side and recombine with its large hole population. This leaves Na- strip • Size of p-side strip is set by doping concentration and can be large ++ Na- Na- ++ Na- Na- To bring the Fermi energy level of the metal down: make the metal less n-type p Schottky Barrier: NA- on p-side ++ Na- Na- ++ Na- Na- p Schottky Barrier: Very narrow region = high concentration exposed + nuclei similar to ionized ND = large NA- on p-side ++ Na- Na- ++ Na- Na- p Lecture 20, 24 Feb 14 Chp. 02: pn junction: Info: Linearly graded junction Multiple charge layers Example Chp. 03: metal-semiconductor junction: Schottky barrier Review Examples New VM Ayres, ECE875, S14 Example from Exam: Answer: Ei EC – EF = Egap/2 – (EF – Ei) = EF – Ei = kT ln(ND/ni) Streetman ni EC – EF = --N + N + n --N + N + d d d d Made the metal more ntype to bring EFm up to EFs Electrons left the semiconductor and went into the metal. The semiconductor is ntype: Nd+ left behind. • Size WD of n-side depletion region is set by doping concentration and can be large Example: (a) Evaluate the energy barrier qV0 = q ybi for previous problem (b) Draw the band-bending diagram Answer: (a) qV0 = --N + N + n --N + N + d d d d q ybi =qV0 = 0.057 eV (a) Band-bending diagram: Find W: Junction Equilibrium: metal contact to n-type Si when work functions qFm > qFs metal n0= 1017 cm-3 Although the charges are balanced, the layer on the metal side is very thin, similar to ionized NA = large EF qV0 -- P+ P+ P P P P P P P EF Ei E (x) Neutral region n-side Depletion region W = 1.14 x 10-5 cm = 0.14 mm Answer: (a) qV0 = --N + N + n --N + N + Also: qFB = 4.0 -3.8 eV = 0.2 eV (a) Band-bending diagram: W = 0.14 mm d d d d q ybi =qV0 = 0.057 eV