Inventory Management : MODEL PERSEDIAAN TUJUAN Mengetahui model-model pengelolaan persediaan MODEL PERSEDIAAN Tujuan Ukuran persediaan berhubungan dengan ukuran pesanan, frekuensi pesan 1. 2. menentukan ukuran persediaan Item dengan permintaan atau kebutuhan yang relatif stabil dalam jangka panjang, ukuran pesanan berdampak pada frekuensi pesan rata-rata persediaan. TRADE OFF Menentukan ukuran pesanan Makin besar ukuran pesanan : frekuensi pesan lebih kecil rata-rata persediaan besar biaya pesan kecil biaya simpan besar Sebaliknya untuk ukuran pesan kecil. Model Pengelolaan Persediaan Item dengan pasokan relatif stabil : dapat menggunakan model EOQ untuk menentukan ukuran pesanan yang ekonomis. Ketidakpastian diakomodasi dengan menentukan reorder point dan safety stock Model Persediaan Item bersifat musiman : Penting mempertimbangkan trade off antara biaya kelebihan dan kekurangan persediaan. Resiko kelebihan dapat dikurangi dengan (1) mengurangi harga jual di musim jual, (2) mengurangi lead time sehingga responsif terhadap pasar VENDOR MANAGED INVENTORY Vendor Managed Inventory (VMI) Model pengelolaan persediaan dimana keputusan waktu dan ukuran pengiriman ditentukan supplier. Pembeli memberikan informasi yang up to date tentang kondisi persediaan dan kebutuhan •Biaya pesan dan simpan •Demand is known and constant D units per time. •No stock-outs! •Leadtime=0! Costs: K: order cost c: Unit variable cost h: inventory holding cost Q : order size (decision var.) Inventory Q -D Time T Deriving EOQ Total cost at every cycle: C(Q)=K+cQ Average inventory holding cost in a cycle: Q/2 Cycle time T =Q/D G(Q)=(K+cQ)/T + hQ/2 = KD/Q + Dc + hQ/2 Q* 2 KD h EOQ: Costs G(Q) Ordering Cost Holding cost Total cost G(Q) hQ 2 KD Q Q Q* Stochastic Demand Usually the demand has a variable component D=Dconstant+Dvariable Inventory Policy C ontinuous P eriodic T ype A (s,S) (R ,s,S) T yp e B (s,Q ) (R ,S) Continuous review, reorder policy m – demand rate L – replenishment lead time S: inventory reorder level; Q: reorder size inventory +Q +Q S dL=mL Safety stock: S-dL L place order order arrives time Periodic Review, Orderup-to Policy Define: Inventory Position = Quantity on hand + Quantity on order S - Base stock level/Order-up-to Point R- Review period L- Replenishment lead time m - Demand per unit time Q - Order quantity ss - Safety stock Ordering Rule: Place an order every R periods so as to bring your inventory position to the Base Stock Level, S. Periodic review with no demand variability Inventory position Inventory Level On-hand inventory m(R+L) mR mL 0 R L 2R R+L 3R 2R+L 4R 3R+L time Periodic review with no demand variability Order Quantity, Q = mR Average Cycle stock = Q/2 = mR / 2 Pipeline stock = m L Order-up-to point, S = m (R+L) Periodic review with variable demand Order-up-to point (S) = m (R+L) + Safety Stock (ss) Average Order Quantity (Q) = mR Average Pipeline stock = m L Average Cycle stock = Q/2 = mR / 2 Average Safety Stock = ss = ? Determination of the Safety Stock Inventory Level Inventory position On-hand inventory mR+mL+ss mR+ss mL+ss ss 0 R L 2R R+L 3R 2R+L 4R 3R+L time Inventory Level Freq Inventory On-hand X Place order Lead Time Receive order Time Inventory Level Freq Inventory On-hand X m ( R L ) + SS z R L =S Safety Stock (SS) Place order Lead Time Receive order Time Given R, L, m, and : Safety Stock (ss) = z R L Expected standard loss (shortage) Demand variability over R + L units time Choose z such that: Fill Rate (p) = 1 L( z) RL mR Average demand filled per period So: L ( z ) 1 p where L(z) is the standard loss function Base Stock Level (S) =m R m L z RL mR RL Example #1 Given: Solve: L z 1 R = 2 weeks L= 1 week m = 150 units per week = 10 units per week Target fill rate, p=99% p mR R L Safety stock = ss z . 01 150 2 10 2 1 0 . 173 so from table, z = 0.58 R L 0 . 58 10 3 10 Base stock level = S m R m L z R L 150 2 150 1 10 460 Example #2 Given: R = 2 weeks L= 1 week m = 150 units per week = 10 units per week Target fill rate, p=95% Solve: L z 1 p mR R L Safety stock = ss z Base stock level = . 05 150 2 10 2 1 0 . 866 so from table, z = -0.73 R L 0 . 73 10 3 12 S m L m R z R L 150 2 150 1 12 438