Lecture 10 Ch6. Friction, Drag, and Centripetal Force University Physics: Mechanics Dr.-Ing. Erwin Sitompul http://zitompul.wordpress.com 2012 Homework 8: Coin On A Book The figure below shows a coin of mass m at rest on a book that has been tilted at an angle θ with the horizontal. By experimenting, you find that when θ is increased to 13°, the coin is on the verge of sliding down the book, which means that even a slight increase beyond 13° produces sliding. What is the coefficient of static friction μs between the coin and the book? Hint: Draw the free-body diagram of the coin first. Erwin Sitompul University Physics: Mechanics 10/2 Solution of Homework 8: Coin On A Book Forces along the y axis: Fnet,y may FN Fg cos 0• Why zero? FN Fg cos FN mg cos Forces along the x axis: Fnet,x m ax Fg sin fs 0• Why zero? Fg sin s FN 0 mg sin s mg cos 0 sin h tan s cos d So, the coefficient of static friction is: s tan13 0.231 Erwin Sitompul University Physics: Mechanics 10/3 Virtual Experiment: Determining μk θ An object is kept in rest on an inclined surface. The angle θ is 26°, which is greater than the critical angle θc (μs = tanθc). Upon release, the object directly move and slide down to the bottom. It requires 4.29 s to reach the bottom, which is 18 m away from the initial point. Determine the coefficient of kinetic friction μk between the object and the surface. Erwin Sitompul University Physics: Mechanics 10/4 Example: Blue Block → A block of mass m = 3 kg slides along a floor while a force F of magnitude 12 N is applied to it at an upward angle θ. The coefficient of kinetic friction between the block and the floor is μk = 0.4. We can vary θ from 0 to 90° (with the block remains on the floor. What θ gives the maximum value of the block’s acceleration magnitude a? Erwin Sitompul University Physics: Mechanics 10/5 Example: Blue Block Forces along the y axis: Fnet,y may FN Fy Fg 0 FN mg F sin Forces along the x axis: Fnet,x m ax Fx fk ma F cos k FN ma F F a cos k g sin m m Erwin Sitompul • What θ gives the maximum value of a? • da/dθ = 0 University Physics: Mechanics 10/6 Example: Blue Block If a is given by F F a cos k g sin m m then, the derivative of a with respect to θ is da F F sin k cos 0 d m m tan k tan 1 k tan 1 (0.4) 21.80 Erwin Sitompul University Physics: Mechanics 10/7 Example: Two Blocks Block B in the figure below weighs 711 N. The coefficient of static friction between block and table is 0.25; angle θ is 30°. Assume that the cord between B and the knot is horizontal. Find the maximum weight of block A for which the system will be stationary. Erwin Sitompul University Physics: Mechanics 10/8 Example: Two Blocks → TW → TB Block B → TB → FgB Knot → TW → TA → TA → FNB → fs,max Wall Block A → FgA → TW → fs,max Knot → FgA Erwin Sitompul University Physics: Mechanics 10/9 Example: Two Blocks Forces along the y axis: Fnet,y 0 TWy FgA 0 TW sin mA g → TW TWy θ → fs,max Knot TWx Forces along the x axis: Fnet,x 0 TWx fs,max 0 TW cos s FNB TW cos s mB g mA g s mB g sin cos sWB WA sin cos → FgA WA sWB tan (0.25)(711) tan 30 102.624 N Erwin Sitompul University Physics: Mechanics 10/10 Example: Multiple Objects A block of mass m1 on a rough, horizontal surface is connected to a ball of mass m2 by a lightweight cord over a lightweight, frictionless pulley as shown in the figure below. A force of magnitude F at an angle θ with the horizontal is applied to the block as shown and the block slides to the right. The coefficient of kinetic friction between the block and surface is μk. Find the magnitude of acceleration of the two objects. Erwin Sitompul University Physics: Mechanics 10/11 Example: Multiple Objects → FN Fy T Forces in m2 m2 → Fg2 → fk m1 → Fg1 → Fnet,y m2 a2 y T Fg2 m2a T m2 ( g a) F θ → T → Fx Forces in m1 Fnet,x m1a1x Fx T f k m1a F cos T k FN m1a T F cos m1a k FN Fnet,y 0 Fy FN Fg1 0 FN Fg1 Fy FN m1g F sin Erwin Sitompul University Physics: Mechanics 10/12 Example: Multiple Objects T m2 ( g a) T F cos m1a k FN FN m1g F sin m2 ( g a) F cos m1a k (m1g F sin ) m1a m2a F cos k F sin k m1g m2 g (m1 m2 )a F (cos k sin ) (k m1 m2 ) g F (cos k sin ) ( k m1 m2 ) g a m1 m2 Erwin Sitompul University Physics: Mechanics 10/13 Example: Trio Blocks When the three blocks in the figure below are released from rest, they accelerate with a magnitude of 0.5 m/s2. Block 1 has mass M, block 2 has 2M, and block 3 has 2M. What is the coefficient of kinetic friction between block 2 and the table? Erwin Sitompul University Physics: Mechanics 10/14 Example: Trio Blocks a Forces in m1 Fnet,y m1a1 y a T1 Fg1 Ma T1 M ( g a) a → FN → T1 → T1 m1 → fk → Fg1 Erwin Sitompul → T2 → T2 m2 → Fg2 m3 → Fg3 Forces in m2 Fnet,x m2 a2 x T2 T1 fk 2Ma T2 T1 k FN 2Ma Fnet,y m2 a2 y FN Fg2 0 FN 2Mg Forces in m3 Fnet,y m3a3 y T2 Fg3 2M (a) T2 2M ( g a) University Physics: Mechanics 10/15 Example: Trio Blocks T1 M ( g a) T2 T1 k FN 2Ma FN 2Mg T2 2M ( g a) 2M ( g a) M ( g a) k 2Mg 2Ma k 2Mg 2M ( g a) M ( g a) 2Ma 2M ( g a) M ( g a) 2Ma k Mg 5Ma k 2 Mg g 5a 2g (9.8) 5(0.5) 2(9.8) 0.372 m s 2 Erwin Sitompul 2Mg University Physics: Mechanics 10/16 The Drag Force and Terminal Speed A fluid is anything that can flow – generally a gas or a liquid. When there is a relative velocity between a fluid and a body (either because the body moves through the fluid or because the fluid → moves past the body), the body experiences a drag force D that opposes the relative motion. Here we examine only cases in which air is the fluid, the body is blunt rather than slender, and the relative motion is fast enough so that the air becomes turbulent (breaks up into swirls) behind the body. In such cases, the magnitude of the drag force is related to the relative speed by an experimentally determined drag coefficient C according to D 12 C Av2 Erwin Sitompul ρ : air specific density A : effective cross-sectional area of the body C : drag coefficient University Physics: Mechanics 10/17 The Drag Force and Terminal Speed Erwin Sitompul University Physics: Mechanics 10/18 The Drag Force and Terminal Speed When a blunt body falls from rest through air, the drag force D → is directed upward. This upward → force D opposes the downward gravitational force Fg on the body. D Fg ma If the body falls long enough, D eventually equals Fg. This means that a = 0, and so the body’s speed no longer increases. The body then falls at a constant speed, called the terminal speed vt. 1 2 C Avt2 Fg 0 vt Erwin Sitompul 2 Fg C A University Physics: Mechanics 10/19 The Drag Force and Terminal Speed • Cyclists and downhill speed skiers try to maximize terminal speeds by reducing effective crosssectional area Erwin Sitompul University Physics: Mechanics 10/20 Example: Falling Cat If a falling cat reaches a first terminal speed of 97 km/h while it is wrapped up and then stretches out, doubling A, how fast is it falling when it reaches a new terminal speed vt ,1 2 Fg C A 95km h 2 Fg 95 67.18 km h vt ,2 C 2A 2 Erwin Sitompul University Physics: Mechanics 10/21 Example: Raindrop A raindrop with radius R=1.5 mm falls from a cloud that is at height h=1200 m above the ground. The drag coefficient C for the drop is 0.6. Assume that the drop is spherical throughout its fall. The density of water ρw is 1000 kg/m3, and the density of air ρa is 1.2 kg/m3. (a) What is the terminal speed of the drop? (b) What would be the drop’s speed just before impact if there were no drag force? (a) vt 2 Fg C A 2( mw g ) C a Aw 8 w rg 2( w 43 r 3 g ) 2( wvw g ) 3 C a C a ( r 2 ) C a Aw 8 (1000)(1.5 103 )(9.8) 7.38 m s 26.56 km h 3 (0.6)(1.2) (b) vy2 v0,2 y 2g ( y y0 ) vy 2(9.8)(0 1200) 153.36 m s 552.10 km h Erwin Sitompul University Physics: Mechanics 10/22 Homework 9A In the next figure, blocks A and B have weights of 44 N and 22 N, respectively. (a) Determine the minimum weight of block C to keep A from sliding if μs, between A and the table is 0.20. (b) Block C suddenly is lifted off A. What is the acceleration of block A if μk between A and the table is 0.15? Erwin Sitompul University Physics: Mechanics 10/23 Homework 9B 1. The figure shows a 1.0-kg University Physics book connected to a 500-g tea mug. The book is pushed up the slope and reach a speed of 3.0 m/s before being released. The coefficients of friction are μs = 0.50 and μk = 0.20. (a) How far will the book slide upwards? (b) After the book reaches the highest point, will the book stick to the surface, or will it slide back down? 2. In downhill speed skiing, a skier is retarded by both the air drag force on the body and the kinetic frictional force on the skis. Suppose the slope angle is θ = 40.0°, the snow is dry with a coefficient of kinetic friction μk = 0.04, the mass of the skier and equipment is m = 85.0 kg, the cross-sectional area of the (tucked) skier is A = 1.30 m2, the drag D coefficient is C = 0.150, and the air density is 1.20 kg/m3. fk (a) What is the terminal speed? (b) If a skier can vary C by a slight amount dC by adjusting, say, the hand positions, what is the corresponding variation in the terminal speed? Erwin Sitompul University Physics: Mechanics 10/24