Products of Functions, Graphs, Games & Problems Irit Dinur Weizmann Products Why would anyone want to multiply two functions ? graphs ? problems ? • For fun: to “see what happens” • For “Hardness Amplification” (holy grail = prove that things are hard) Given f that is a little hard construct f’ that is very hard Circuit complexity, average case complexity, communication complexity, Hardness of approximation Products Why would anyone want to multiply two functions ? graphs ? problems ? • For fun: to “see what happens” • For “Hardness Amplification” (holy grail = prove that things are hard) Given f that is a little hard construct f’ that is very hard Circuit complexity, average case complexity, communication complexity, Hardness of approximation By taking f’ = f x f x … x f P1 x P2 We can multiply many different objects Numbers Strings Functions Graphs Games Computational Problems Direct Products of Strings / Functions For example, here is how to multiply two strings: 1 1 0 1 1 0 1 11 11 10 11 11 10 1 11 11 10 11 11 10 0 01 01 00 01 01 00 1 11 11 10 11 11 10 1 11 11 10 11 11 10 0 01 01 00 01 01 00 In the k-fold product of a string π , for each (π1 , π2 , … , ππ ) we have a π-bit substring corresponding to the restriction of π to π1 , π2 , … , ππ : π π1 , π2 , … , ππ = π π1 π π2 …π ππ Direct Products of Strings / Functions For example, here is how to multiply two strings: 1 1 0 1 1 0 1 11 11 10 11 11 10 1 11 11 10 11 11 10 0 01 01 00 01 01 00 1 11 11 10 11 11 10 1 11 11 10 11 11 10 0 01 01 00 01 01 00 sum In the k-fold product of a string π , for each (π1 , π2 , … , ππ ) we have a π-bit substring corresponding to the restriction of π to π1 , π2 , … , ππ : π π1 , π2 , … , ππ = π π1 π π2 …π ππ π π1 + π π2 + … + π ππ (the alphabet stays the same, but harder to analyze) Testing Direct Products Given a table of π-substrings, π: π test that distinguishes between • π is a direct product • π is far from a direct product π → 0,1 π , is there a local In [GGR] terms: is the property of being a direct product locally testable ? (answer: yes, with 2 queries) Local to Global Given: a very large and difficult problem (e.g. 3sat) We will solve it together, by splitting the work into many small sub-problems, each of (constant) size π On average, the local value is > π£ππ On average, consistent with > ππππ fraction of neighbors Question: is there a consistent global solution with value > gπ£ππ π-sub-problem Testing Direct Products [Goldreich-Safra,D.-Reingold, D.-Goldenberg, Impagliazzo-Kabanets-Wigderson] Theorem [D.-Steurer 2013] Any collection of local solutions with pairwise consistency 1 − π must be 1 − π π consistent with a global solution. i.e. the property of being a direct product is testable with 2 queries. Theorem [David-D.-Goldenberg-Kindler-Shinkar 2013] The property of being a direct sum is testable with 3 queries. k-substring Multiplying Graphs There are several natural graph products In the “strong direct product”: V(G1 x G2) = V(G1) x V(G2) u1u2 ~ v1v2 iff u1~v1 and u2 ~ v2 ( u ~ v means u=v or u is adjacent to v ) 1 2 3 1 11 12 13 2 21 22 23 3 31 32 33 Multiplying Graphs Basic question: how do natural graph properties (such as: chromatic number, max-clique, expansion, …) Behave wrt the product operation If clique ( G1 ) = m1 and clique ( G2 ) = m2 then clique ( G1 x G2 ) = m1m2 If independent-set ( G1 ) = m1 and independent-set ( G2 ) = m2 then independent-set ( G1 x G2 ) = ? Generally, the answer is easy if the maximizing solution is itself a product, but often this is not true. Then, the analysis is challenging Definition : The Shannon capacity of G is the limit of ( a(Gk) )1/k as k ο infty [Shannon 1956] a(G) – stands for maximum independent set Consider a transmission scheme of one symbol at a time, and draw a graph with an edge between each pair of symbols that might be confusable in transmission. a(G) = number of symbols transmittable with zero error a(Gk) = set of such words of length k (a(Gk))1/k = effective alphabet size Lovasz 1979 computed the Shannon capacity of several graphs, e.g. C5, by introducing the theta function C7 is still open – (one of the most notorious problems in extremal combinatorics) Multiplying Games Games (2-player 1-round) U Alice V Bob u π΅ βΆ πο Σ … … π΄ βΆπο Σ v Referee: random u ο v v u Alice Bob A(u) B(v) Games (2-player 1-round) U Alice Bob u … … π΄ βΆπο Σ V π΅ βΆ πο Σ v Value ( G ) = maximal success probability, over all possible strategies Games (2-player 1-round) U Alice V Bob u … … U = set of variables The 3SAT game V = set of 3sat clauses v FGLSS Value ( G ) = maximal success probability, over all possible strategies Label-Cover Problem : Given a game G, find value ( G ) Strong PCP Theorem: Label Cover is NP-hard to approximate [AS, ALMSS 1991] + [Raz 1995] The PCP Theorem [AS, ALMSS] PCP theorem: “gap-3SAT is NP-hard” Proof: By reduction from small gap to large gap, aka amplification Start with πΊ and end up with πΊ’, s.t. If π£ππ(πΊ) = 1 then π£ππ(πΊ’) = 1 If π£ππ(πΊ) < 1 then π£ππ(πΊ’) < ½ How? • by algebraic encoding [AS, ALMSS 1991]; or • by “multiplying” πΊ with itself, πΊ’ = πΊ ⊗ β― ⊗ πΊ repeatedly [D. 2007] Multiplying Games A game is specified by its constraint-graph, so a product of two games can be defined by a product of two constraint graphs πΊ1 X = πΊ2 πΊ1 ⊗ πΊ2 U1 V1 U2 X u1 = u2 … … … … v1 V2 v2 πΊ1 ⊗ πΊ2 U2 V1 U1 X u1 = u2 … … … … v2 v1 U1 x U2 Alice Bob Σ1 x Σ2 … ο V1 x V2 u1 u2 … A : U1 x U2 V2 v1 v2 B : V1 x V2 ο Σ1 x Σ2 k-fold product of a game Ux … x U Vx … x V Alice Bob u1u2…uk … … A : Uk ο Σk B : Vk ο Σk v1v2…vk Also called: the k-fold parallel repetition of a game Q1: If π£πππ’π ( πΊ1 ) = πΌ1 and π£πππ’π ( πΊ2 ) = πΌ2 then what is π£πππ’π ( πΊ1 ⊗ πΊ2 ) ? Q2: If π£πππ’π ( πΊ ) = πΌ, then what is π£πππ’π ( πΊ ⊗π ) for π > 1 ? One obvious candidate is the direct product strategy. But it is not, in general, the best strategy. Theorem [D.-Steurer 2013]: Let πΊ be a projection game. If π£ππ πΊ < π, then π£ππ πΊ ⊗π 2√π ≤ 1+π If π£ππ πΊ < π (close to 0), then π£ππ π/2 πΊ ⊗π ≤ (4π)π/4 (new; implies new hardness results for label-cover & optimal NP-hardness results for set-cover) If π£ππ πΊ < 1 − π (close to 1), then π£ππ πΊ ⊗π ≤ 1 π2 − 16 BGLR “sliding scale”conjecture π (known; we just improve the constants of [ Rao, Holenstein, Raz ]) Also: short proof for “strong PCP theorem” or “hardness of label-cover” Ideas extend to give a parallel repetition theorem for entangled games, i.e. when the two players share a quantum state [with Vidick & Steurer] One slide about the new proof 1. View a game as a linear operator acting on (Bob)-assignments The game value ≈ a natural norm of this operator 2. Define: val+ G β sup π» | πΊ⊗π» | π» ( πΊ is the collision value of πΊ, closely related to π£ππ(πΊ) ) Think of val+ as an “environmental value” of πΊ: how much harder is it to play πΊ in parallel with environment π», compared to playing π» alone 3. Show: Multiplicativity: π£ππ+ πΊ ⊗ π» = π£ππ+ πΊ ⋅ π£ππ+ π» Approximation: π£ππ+ πΊ ≈ π£ππ(πΊ) So: π£ππ πΊ ⊗π ≈ π£ππ+ πΊ ⊗π = π£ππ+ πΊ π ≈ π£ππ πΊ π Approximation is proven by expressing π£ππ+ as an “eigenvalue”, enabled by factoring out H; easy for expanders Summary • Direct product of strings & functions and a related local-to-global lifting theorem • Direct product of games and new parallel repetition theorem • Direct products of computational problems ?? e.g. for graph problems (max-cut, vertex-cover, ... )