Chapter 6 Rational Expressions, Functions, and Equations § 6.1 Rational Expressions and Functions: Multiplying and Dividing Rational Expressions A rational expression consists of a polynomial divided by a nonzero polynomial (denominator cannot be equal to 0). A rational function is a function defined by a formula that is a rational expression. For example, the following is a rational function: 130 x f x 100 x Blitzer, Intermediate Algebra, 5e – Slide #3 Section 6.1 Rational Expressions EXAMPLE The rational function 130 x f x 100 x models the cost, f (x) in millions of dollars, to inoculate x% of the population against a particular strain of flu. The graph of the rational function is shown. Use the function’s equation to solve the following problem. Find and interpret f (60). Identify your solution as a point on the graph. p 393 Blitzer, Intermediate Algebra, 5e – Slide #4 Section 6.1 Rational Expressions CONTINUED 1000 900 800 700 600 500 400 300 200 100 0 0 20 40 60 Blitzer, Intermediate Algebra, 5e – Slide #5 Section 6.1 80 100 Rational Expressions CONTINUED SOLUTION We use substitution to evaluate a rational function, just as we did to evaluate other functions in Chapter 2. f x 130 x 100 x 130 60 f 60 100 60 7800 195 40 This is the given rational function. Replace each occurrence of x with 60. Perform the indicated operations. Blitzer, Intermediate Algebra, 5e – Slide #6 Section 6.1 Rational Expressions CONTINUED Thus, f (60) = 195. This means that the cost to inoculate 60% of the population against a particular strain of the flu is $195 million. The figure below illustrates the solution by the point (60,195) on the graph of the rational function. 1000 900 800 700 600 (60,195) 500 400 300 200 100 0 0 20 40 60 80 Blitzer, Intermediate Algebra, 5e – Slide #7 Section 6.1 100 Rational Expressions - Domain EXAMPLE Find the domain of f if f x 3x . 2 x 13 x 36 SOLUTION The domain of f is the set of all real numbers except those for which the denominator is zero. We can identify such numbers by setting the denominator equal to zero and solving for x. x 2 13x 36 0 Set the denominator equal to 0. x 4x 9 0 Factor. p 393 Blitzer, Intermediate Algebra, 5e – Slide #8 Section 6.1 Rational Expressions - Domain CONTINUED x40 x4 or x9 0 x9 Set each factor equal to 0. Solve the resulting equations. Because 4 and 9 make the denominator zero, these are the values to exclude. Thus, Domainof f x | x is a real number and x 4 and x 9 or Domainof f - ,4 4,9 9, . Blitzer, Intermediate Algebra, 5e – Slide #9 Section 6.1 Rational Expressions - Domain CONTINUED Domainof f - ,4 4,9 9, . 3x f x . ( x 4)(x 9) In this example, we excluded 4 and 9 from the domain. Unlike the graph of a polynomial which is continuous, this graph has two breaks in it – one at each of the excluded values. Since x cannot be 4 or 9, there is not a function value corresponding to either of those x values. At 4 and at 9, there will be dashed vertical lines called vertical asymptotes. The graph of the function will approach these vertical lines on each side as the x values draw closer and closer to each of them, but will not touch (cross) the vertical lines. The lines x = 4 and x = 9 each represent vertical asymptotes for this particular function. p 395 Blitzer, Intermediate Algebra, 5e – Slide #10 Section 6.1 Rational Expressions Asymptotes Vertical Asymptotes A vertical line that the graph of a function approaches, but does not touch. Horizontal Asymptotes A horizontal line that the graph of a function approaches as x gets very large or very small. The graph of a function may touch/cross its horizontal asymptote. Simplifying Rational Expressions 1) Factor the numerator and the denominator completely. 2) Divide both the numerator and the denominator by any common factors. p 395 Blitzer, Intermediate Algebra, 5e – Slide #11 Section 6.1 Rational Expressions - Domain Check Point 2 Find the domain of f if x 5 f x 2 . 2 x 5x 3 SOLUTION 2 x 2 5x 3 0 Set the denominator equal to 0. 2x 1x 3 0 Factor. 2x 1 0 1 x 2 or or x3 0 x 3 Set each factor equal to 0. Solve the resulting equations. 1 Domainof f x | x is a real number and x 3 and x 2 1 1 Domainof f - ,-3 3, , . 2 2 p 394 Blitzer, Intermediate Algebra, 5e – Slide #12 Section 6.1 Simplifying Rational Expressions EXAMPLE Simplify: x 1 . 2 x 2x 3 SOLUTION x 1 1 x 1 x 2 2 x 3 x 3x 1 1 x 1 x 3x 1 1 x3 Factor the numerator and denominator. Divide out the common factor, x + 1. Simplify. Blitzer, Intermediate Algebra, 5e – Slide #13 Section 6.1 Simplifying Rational Expressions Check Point 3 2 x 7 x 10 Simplify: . x2 SOLUTION x 2 7 x 10 x 5x 2 x2 1x 2 x 5x 2 1x 2 x5 Factor the numerator and denominator. Divide out the common factor, x + 1. Simplify. p 397 Blitzer, Intermediate Algebra, 5e – Slide #14 Section 6.1 Simplifying Rational Expressions EXAMPLE 2 x 7 x 12 Simplify: . 2 9 x SOLUTION x 2 7 x 12 x 3x 4 2 3 x 3 x 9 x Factor the numerator and denominator. x 3x 4 3 x 1 3 x Rewrite 3 – x as (-1)(-3 + x). x 3x 4 3 x 1x 3 Rewrite -3 + x as x – 3. Blitzer, Intermediate Algebra, 5e – Slide #15 Section 6.1 Simplifying Rational Expressions CONTINUED x 3x 4 3 x 1x 3 x 4 3 x 1 Divide out the common factor, x – 3. Simplify. Do Check 4a and 4b on page 397 Blitzer, Intermediate Algebra, 5e – Slide #16 Section 6.1 Multiplying Rational Expressions Multiplying Rational Expressions 1) Factor all numerators and denominators completely. 2) Divide numerators and denominators by common factors. 3) Multiply the remaining factors in the numerators and multiply the remaining factors in the denominators. p 398 Blitzer, Intermediate Algebra, 5e – Slide #17 Section 6.1 Multiplying Rational Expressions EXAMPLE 2 x 2 3xy 2 y 2 3x 2 2 xy y 2 Multiply: 2 . 2 2 2 3x 4 xy y x xy 6 y SOLUTION 2 x 2 3xy 2 y 2 3x 2 2 xy y 2 2 2 2 3x 4 xy y x xy 6 y 2 2 x y x 2 y 3x y x y 3x y x y x 2 y x 3 y 2 x y x 2 y 3x y x y 3x y x y x 2 y x 3 y This is the original expression. Factor the numerators and denominators completely. Divide numerators and denominators by common factors. Blitzer, Intermediate Algebra, 5e – Slide #18 Section 6.1 Multiplying Rational Expressions CONTINUED 2 x y 3x y 3x y x 3 y Multiply the remaining factors in the numerators and in the denominators. Note that when simplifying rational expressions or multiplying rational expressions, we just used factoring. With one additional step that is provided in the following Definition for Division, division of rational expressions promises to be just as straightforward. Blitzer, Intermediate Algebra, 5e – Slide #19 Section 6.1 Multiplying Rational Expressions EXAMPLE 8y 2 3 y 2 . Multiply: 2 y 9 4y y SOLUTION 8y 2 3 y 2 2 y 9 4y y 24 y 1 3 y y 3 y 3 y4 y 1 24 y 1 1( y 3) y 3 y 3 y4 y 1 This is the original expression. Factor the numerators and denominators completely. Divide numerators and denominators by common factors. Because 3 – y and y -3 are opposites, their quotient is -1. Blitzer, Intermediate Algebra, 5e – Slide #20 Section 6.1 Multiplying Rational Expressions CONTINUED 2 y 3 y or 2 y 3 y Now you may multiply the remaining factors in the numerators and in the denominators. Blitzer, Intermediate Algebra, 5e – Slide #21 Section 6.1 Multiplying Rational Expressions Check Point 5 Multiply: x 4 x 2 4 x 21 . 2 x7 x 16 x 3 x 4 pages 398-399 Blitzer, Intermediate Algebra, 5e – Slide #22 Section 6.1 Multiplying Rational Expressions Check Point 6 Multiply: 4 x 8 3x 2 4 x 4 . 2 2 6 x 3x 9x 4 4 x 2 3 x3 x 2 4 x 2 3 x3 x 2 pages 398-399 Blitzer, Intermediate Algebra, 5e – Slide #23 Section 6.1 Dividing Rational Expressions Simplifying Rational Expressions with Opposite Factors in the Numerator and Denominator The quotient of two polynomials that have opposite signs and are additive inverses is -1. Dividing Rational Expressions If P, Q, R, and S are polynomials, where Q 0, R 0, and S 0, then P R P S PS . Q S Q R QR R Change division to multiplication. Replace S with its reciprocal by interchanging its numerator and denominator. Blitzer, Intermediate Algebra, 5e – Slide #24 Section 6.1 Dividing Rational Expressions EXAMPLE xy y 2 2 x 2 xy 3 y 2 Divide: 2 2 . 2 x 2 x 1 2 x 5xy 3 y SOLUTION xy y 2 2 x 2 xy 3 y 2 2 2 x 2 x 1 2 x 5xy 3 y 2 This is the original expression. xy y 2 2 x 2 5 xy 3 y 2 2 x 2 x 1 2 x 2 xy 3 y 2 Invert the divisor and multiply. yx y 2 x 3 y x y 2 x 1 2 x 3 y x y Factor. Blitzer, Intermediate Algebra, 5e – Slide #25 Section 6.1 Dividing Rational Expressions CONTINUED yx y 2 x 3 y x y 2 x 1 2 x 3 y x y y x y x 12 Divide numerators and denominators by common factors. Multiply the remaining factors in the numerators and in the denominators. Blitzer, Intermediate Algebra, 5e – Slide #26 Section 6.1 Multiplying Rational Expressions Check Point 7a Divide: 9 x 2 49 3x 7 . 9 93x 7 Blitzer, Intermediate Algebra, 5e – Slide #27 Section 6.1 Multiplying Rational Expressions Check Point 7b Divide: x 2 x 12 x 2 10x 24 . 2 5x x 6x x 3 5 Blitzer, Intermediate Algebra, 5e – Slide #28 Section 6.1 DONE