Yr 11 MCAT Algebra Practice 2 6. Write an expression for the area of the following shape… 6a 1. Expand and Simplify… a2 + 8a – 20 = a + 10 3a (3a + 8)(a – 1) = 10. Simplify fully… 2. (2a2 x 3a3)2 = 36ak What is the value of k? 3. Rearrange to make x the subject of… y = 3x – 6 4. Simplify fully… a) 8ab – 3ab + 5c3 + b) 24a10b6 = 30a4b8 c) 8a2 x 2a3 x 3a = c3 = 7. If the above area is 450cm2 what is the value of a? 8. Factorise fully… a) a2 + 22a + 40 = b) 15ab + 20a = c) a2 – 100 = 9. Solve the following… 5. Simultaneously solve for a & b. 6a + 5b = 108 3a + 5b = 84 a) 13a – 16 = 10a + 2 b) 5a4 = 80 c) (a – 4)(a + 9) = 0 d) a2 + 14a + 40 = 0 11. Three consecutive numbers beginning with a are added together. Write a simplified expression for the sum of these three numbers. 12. If these three numbers total up to 171. What is the value of the first number (a). 13. Simplify fully… a + a = 3 5 3a2 ÷ 9a = 4b 20b3 Yr 11 MCAT Algebra Practice 2 6. Write an expression for the area of the following shape… 6a 1. Expand and Simplify… (3a + 8)(a – 1) = (2a2 x 3a3)2 = 36ak k = 10 7. If the above area is 450cm2 what is the value of a? 3. Rearrange to make x the subject of… 3x – 6 = y y = 3x – 6 3x = y + 6 4. x= y+6 3 Simplify fully… a) 8ab – 3ab + 5c3 + 4 a6 5 b2 c3 450 = 18a2 18a2 = 450 a2 = 25 a = √25 a = 5 . 8. Factorise fully… = 5ab + 6c3 b) 24a10b6 = 30a4b8 c) 8a2 x 2a3 x 3a = 48a6 . 6a + 5b = 108 3a + 5b = 84 3a = 24 a=8 eqn 1 eqn 2 subtract eqn 2 off eqn 1 1st + 2nd + 3rd = a + a + 1+ a + 2 = 3a + 3 12. If these three numbers total up to 171. What is the value of the first number (a). a2 + 22a + 40 = (a + 2 )(a + 20) b) 15ab + 20a = 5a ( 3b + 4) c) a2 – 100 = (a + 10)(a - 10 ) a) 13a – 16 = 10a + 2 3a = 18 b) 13a – 10a = 2 + 16 a=6 a = 4√16 5a4 = 80 a = 2 and -2 a4 = 16 c) (a – 4)(a + 9) = 0 d) a2 + 14a + 40 = 0 substitute a back into eqn 1 6(8) + 5b = 108 5b = 60 b = 12 11. Three consecutive numbers beginning with a are added together. Write a simplified expression for the sum of these three numbers. a) 9. Solve the following… 5. Simultaneously solve for a & b. . =a–2 Area (rectangle) = base x height Area = 6a x 3a Area = 18a2 What is the value of k? (6a5)2 = 36a10 a2 + 8a – 20 = (a + 10)(a – 2) a + 10 a + 10 3a - 3a + 8a - 8 = 3a2 + 5a - 8 2. 3a2 10. Simplify fully… 3a + 3 = 171 3a = 168 a = 56 13. Simplify fully… a + a = 5a + 3a = 8a 15 15 15 3 5 4 or ___ -9 a is ___ -10 or ___ -4 (a + 10)(a + 4) = 0 a is ___ . 3a2 ÷ 9a = 3a2 x 20b3 4b 9a 4b 20b3 = 60a2b3 36ab 2 = 1 /3ab2