Intermediate Algebra 098A Review of Exponents & Factoring 1.1 – Integer Exponents • For any real number b and any natural number n, the nth power of b is found by multiplying b as a factor n times. b bbb n b Exponential Expression – an expression that involves exponents • Base – the number being multiplied • Exponent – the number of factors of the base. Product Rule a a a n n mn Quotient Rule m a mn a n a Integer Exponent a n 1 n a Zero as an exponent a 1 a 0 R 0 Calculator Key • Exponent Key ^ Sample problem 3 0 8x y 2 5 24 x y 5 y 5 3x more exponents • Power to a Power a n m a mn Product to a Power ab r a b r r Polynomials - Review •Addition •and • Subtraction Objective: • Determine the coefficient and degree of a monomial Def: Monomial • An expression that is a constant or a product of a constant and variables that are raised to whole –number powers. • Ex: 4x 1.6 2xyz Definitions: • Coefficient: The numerical factor in a monomial • Degree of a Monomial: The sum of the exponents of all variables in the monomial. Examples – identify the degree 8x 4 0.5x y 4 5 4 5 Def: Polynomial: • A monomial or an expression that can be written as a sum or monomials. Def: Polynomial in one variable: • A polynomial in which every variable term has the same variable. Definitions: • Binomial: A polynomial containing two terms. • Trinomial: A polynomial containing three terms. Degree of a Polynomial • The greatest degree of any of the terms in the polynomial. Examples: 5 x x 10 x 9 x 1 6 3 2 3x 4 x 5 2 x 16 2 x 3x y 2 xy y 6 5 3 4 3 2 Objective •Add •and •Subtract • Polynomials To add or subtract Polynomials • Combine Like Terms • May be done with columns or horizontally • When subtracting- change the sign and add Evaluate Polynomial Functions • Use functional notation to give a polynomial a name such as p or q and use functional notation such as p(x) • Can use Calculator Calculator Methods • • • • • • 1. 2. 3. 4. 5. 6. Plug In Use [Table] Use program EVALUATE Use [STO->] Use [VARS] [Y=] Use graph- [CAL][Value] Objective: • Apply evaluation of polynomials to real-life applications. Intermediate Algebra 5.4 •Multiplication •and •Special Products Objective • Multiply •a • polynomial • by a • monomial Procedure: Multiply a polynomial by a monomial • Use the distributive property to multiply each term in the polynomial by the monomial. • Helpful to multiply the coefficients first, then the variables in alphabetical order. Law of Exponents r s b b b r s Objectives: • Multiply Polynomials • Multiply Binomials. • Multiply Special Products. Procedure: Multiplying Polynomials • 1. Multiply every term in the first polynomial by every term in the second polynomial. • 2. Combine like terms. • 3. Can be done horizontally or vertically. Multiplying Binomials • FOIL • First • Outer • Inner • Last Product of the sum and difference of the same two terms Also called multiplying conjugates a b a b a 2 b 2 (a b) a 2 ab b 2 Squaring a Binomial a b a 2ab b 2 2 2 a b a 2ab b 2 2 2 Objective: • Simplify Expressions • Use techniques as part of a larger simplification problem. Albert EinsteinPhysicist • “In the middle of difficulty lies opportunity.” Intermediate Algebra –098A •Common Factors •and • Grouping Def: Factored Form • A number or expression written as a product of factors. Greatest Common Factor (GCF) • Of two numbers a and b is the largest integer that is a factor of both a and b. Calculator and gcd • [MATH][NUM]gcd( • Can do two numbers – input with commas and ). • Example: gcd(36,48)=12 Greatest Common Factor (GCF) of a set of terms •Always do this FIRST! Procedure: Determine greatest common factor GCF of 2 or more monomials • 1. Determine GCF of numerical coefficients. • 2. Determine the smallest exponent of each exponential factor whose base is common to the monomials. Write base with that exponent. • 3. Product of 1 and 2 is GCF Factoring Common Factor Find the GCF of the terms • 2. Factor each term with the GCF as one factor. • 3. Apply distributive property to factor the polynomial • 1. Example of Common Factor 16 x y 40 x 3 2 8 x (2 xy 5) 2 Factoring when first terms is negative • Prefer the first term inside parentheses to be positive. Factor out the negative of the GCF. 20 xy 36 y 3 4 y (5 xy 9) 2 Factoring when GCF is a polynomial a(c 5) b(c 5) (c 5)(a b) Factoring by Grouping – 4 terms • 1. Check for a common factor • 2. Group the terms so each group has a common factor. • 3. Factor out the GCF in each group. • 4. Factor out the common binomial factor – if none , rearrange polynomial • 5. Check Example – factor by grouping 32 xy 48 xy 20 y 30 y 2 2 2 y 16 xy 24 x 10 y 15 2 y 2 y 38 x 5 Ralph Waldo Emerson – U.S. essayist, poet, philosopher •“We live in succession , in division, in parts, in particles.” Intermediate Algebra 098A •Special Factoring Objectives:Factor • a difference of squares • a perfect square trinomial • a sum of cubes • a difference of cubes Factor the Difference of two squares a b a b a b 2 2 Special Note • The sum of two squares is prime and cannot be factored. a b 2 2 is prime Factoring Perfect Square Trinomials a 2ab b a b 2 2 a 2ab b a b 2 2 2 2 Factor: Sum and Difference of cubes a b (a b) a ab b 2 a b (a b) a ab b 2 3 3 3 3 2 2 Note • The following is not factorable a ab b 2 2 Factoring sum of Cubes informal • (first + second) • (first squared minus first times second plus second squared) Intermediate Algebra 098A • Factoring Trinomials • of • General Quadratic ax bx c 2 50 y 15 y Objectives: • Factor trinomials of the form x bx c 2 ax bx c 2 Factoring x bx c 2 • 1. Find two numbers with a product equal to c and a sum equal to b. • The factored trinomial will have the form(x + ___ ) (x + ___ ) • Where the second terms are the numbers found in step 1. • Factors could be combinations of positive or negative Factoring Trial and Error ax bx c 2 • 1. Look for a common factor • 2. Determine a pair of coefficients of first terms whose product is a • 3. Determine a pair of last terms whose product is c • 4. Verify that the sum of factors yields b • 5. Check with FOIL Redo Factoring ac method ax bx c 2 • 1. Determine common factor if any • 2. Find two factors of ac whose sum is b • 3. Write a 4-term polynomial in which by is written as the sum of two like terms whose coefficients are two factors determined. • 4. Factor by grouping. Example of ac method 6x 11x 4 2 6x 3x 8x 4 2 3x(2x 1) 4(2x 1) (2x 1)(3x 4) Example of ac method 5 y (8 y 10 y 3) 2 2 5 y 8 y 2 y 12 y 3 2 2 5 y 2 y 4 y 1 3 4 y 1 2 5 y 4 y 1 2 y 3 2 Factoring - overview • • • • • • • 1. Common Factor 2. 4 terms – factor by grouping 3. 3 terms – possible perfect square 4. 2 terms –difference of squares Sum of cubes Difference of cubes Check each term to see if completely factored Isiah Thomas: • “I’ve always believed no matter how many shots I miss, I’m going to make the next one.” Intermediate Algebra 098A •Solving Equations •by •Factoring Zero-Factor Theorem •If a and b are real numbers •and ab =0 •Then a = 0 or b = 0 Example of zero factor property x 5 x 2 0 x 5 0 or x 2 0 x 5 or x 2 5, 2 or 2, 5 Solving a polynomial equation by factoring. 1. Factor the polynomial completely. 2. Set each factor equal to 0 3. Solve each of resulting equations 4. Check solutions in original equation. 5. Write the equation in standard form. Example – solve by factoring 3x 11x 4 2 3x 11x 4 0 2 3x 1 x 4 0 3x 1 0 or x4 0 1 x or x 4 3 Example: solve by factoring x 4 x 12 x 3 2 x 4 x 12 x 0 3 2 x x 4 x 12 0 2 x x 6 x 2 0 0, 6, 2 Example: solve by factoring • A right triangle has a hypotenuse 9 ft longer than the base and another side 1 foot longer than the base. How long are the sides? • Hint: Draw a picture • Use the Pythagorean theorem Solution x x 1 x 9 2 2 2 x 20 or x 4 • Answer: 20 ft, 21 ft, and 29 ft Example – solve by factoring 3x 2 x 7 12 • Answer: {-1/2,4} Example: solve by factoring 1 2 1 1 2 x 3 x x 2 2 12 3 • Answer: {-5/2,2} Example: solve by factoring 9 y y 1 4 y 6 y 1 3 y 2 • Answer: {0,4/3} Example: solve by factoring t 3t 13 7t 3t 1 3 2 • Answer: {-3,-2,2} Sugar Ray Robinson • “I’ve always believed that you can think positive just as well as you can think negative.” Maya Angelou - poet • “Since time is the one immaterial object which we cannot influence – neither speed up nor slow down, add to nor diminish – it is an imponderably valuable gift.”