Celestial Coordinates Junior Navigation Chapter 5 Light List for the Sky Junior Navigation Chapter 6 1 Selecting DIP Correction HE 14.1ft corr -3.6’ 14.4 If an entry falls on an exact number in these tables, use the upper correction (“upper” means the correction that is physically higher on the page). HE 14.4 ft corr -3.7’ HE 14.9ft corr -3.7’ 2 Learning Objectives Define declination, hour circle, GHA, and LHA Understand how the GP of a body is located by celestial coordinates, and relationships among hour angles Obtain GHA and declination of the sun from the Nautical Almanac Calculate LHA and declination from Nautical Almanac data 3 Defining Positions To obtain a celestial LOP you need: Ho, altitude of celestial body you observed Hc, altitude you calculated from your DR To calculate Hc, you need to know LHA & Dec 4 Terrestrial Positions Coordinates? GP Latitude – measured from equator along a meridian of longitude, N or S, to maximum of 90º Longitude – measured from prime meridian along a parallel of latitude, E or W, to a maximum of 180º 5 GHA GP LHA Circles Points Starting Coordinates Great Celestial Positions Celestial Equator Greenwich Celestial Meridian Hour Circle (longitude) measured Parallel of Declination along the celestial (latitude) measured equator West toAngle Greenwich Hour along hour circle from maximum of 360º equator, N or S, to Declination maximum of 90º Local Hour Angle 6 Computing LHA LHA - need to compute local hour angle of body (cos LHA x cos Lat x cos Dec) + (sin Lat x sin Dec) = sin Hc Relationship between LHA and GHA is defined as: LHA = GHA – West Longitude or LHA = GHA + East Longitude 7 LHA = GHA – West Longitude M 30º 45º LHA GHA 15º G 45º 120º 60º 75º LHA = GHA 120º – Lo 45º W LHA = 75º g m 8 LHA = GHA + East Longitude M 30º G 45º 15º 45º 315º 60º 300º 75º 90º 285º LHA = GHA 270º + Lo 45º E LHA = 315º 105º LHA 270º 255º 240º 120º GHA 225º 135º 270º g 150º 210º 165º 180º 195º m 9 LHA = GHA – West Longitude M LHA = GHA 90º – Lo 150º W + 360º GHA 450º – Lo 150º W g LHA = 300º GHA LHA ? 90º G m 10 Meridian Transit When sun directly over Observer’s Meridian: Details in Chapter 9 Sun reaches its maximum altitude M Body is g due North or South Lo = GHA LHA = 000º G m 11 Sun Overhead An observer sees the sun directly overhead, Ho 90º 00.0’ Nautical Almanac lists Sun GHA as 298° and Sun’s Dec is 20° N What is your latitude and longitude? Since Dec = 20°N, then Lat = 20°N GHA of the sun > 180°, so GP of sun is East Lo GHA of the sun 360° – 298° = 62° E 12 The Almanac Published annually by the Nautical Almanac Office of the U.S. Naval Observatory. 13 The Daily Pages 2013 JANUARY 10, 11, 12 2013 JANUARY 10, 11, 12 (THU., FRI., SAT.) LEFT PAGE RIGHT PAGE GHA for Aries, and the GHA & GHAor & moon Dec for Sun and Moon Sun symbols: Dec plus Magnitude, SHA, & Mer. plus times for nautical and civil continuous above horizon Pass. for the four Navigational twilight, sunrise, moonrise, continuous below horizon Planets, sunset, moonset, and time of twilight lasts all night and the SHA & Dec for the 57for sun and meridian passage Navigational Stars moon. T H U R S D A Y T H U R S D A Y F R I D A Y F R I D A Y 14 (TH Increments and Corrections Two minutes per page Used to interpolate between whole-hour values of GHA & Dec Tables for each minute of the hour ‘v’ (variable motion) & ‘d’ (declination) corrections ‘v’ correction for sun included in hourly values of GHA; other ‘v’ corrections in ‘d’ correction needed for sun Navigation 15 Other Almanac Pages Calendars – Public holidays by country; religious holidays for United States; moon phase calendar, Julian calendar Eclipses Standard times through-out the world Star charts Polaris tables Sight reduction procedures Sight reduction tables (NASR method) Conversions of arc to time Altitude correction tables for the moon 16 Sight Reduction Form 17 Find UT and LHA and Dec 10 May 2012 17 – 34 – 37 On 10 May you make an observation of the sun from St. Paul, at 17 – 34 – 37 WT and your WE is 8 sec slow 00 – 08 + 17 – 34 – 45 + 5 22 – 34 – 45 10 May 2012 18 Find UT and LHA and Dec UT is 22 – 34 – 45 and longitude is 92ºARIES 14.5’MOON W SUN m 34 22 34 155 8 441 150 45 0 3 SECOND FIRST CALCULATE PAGE PAGE 42 8 40 5 8 41 9 8 16 8 41 8 40.3 8 41.7 . 22 ?– 159 ?36 3 92 14 5 67 ?21 8 PLANETS + ? 8 16.5 . . 43 8 40.8 8 42.3 8 17.0 44 8 41.0 8 42.4 8 17.3 3 17 45 8 8 249 8 42 7 8 17 5 41.3 0 46 68 41.5 . 5 8 17.7 49 8 42.3 8 43.7 8 18.5 + 47 8 42.9 . 8 41.8 8 043.23 8 18.0 48 817 42.0 ? 8 43.41 8 18.2 50 19 Find UT and LHA and Dec M g G UT 2235 zm m 20 Extract LHA & Dec Data 10 38 ? ?9 328 12 ?– 03 0 33 0 10 337 ? 36 0 34 33 3 303 02 7 ? Your DR Lo is 34°33.3´W when you take a sight on the sun at UT 10–38–12 on 19 March. ?– 1?0 – ?0 ?0 26 0 ? 0 6 25 4 21 Extract LHA & Dec Data 12 38 ? ?9 358 10 ?– 07 8 32 5 12 367 ? 40 3 34 33 3 333 07 0 ? Your DR Lo is 34°33.3´W when you take a sight on the sun at UT 12–38–10 on 20 March. ?– 1?0 – ?0 ?0 00 3 ? 0 6 00 3 22 LHA, Dec & Ho 20 18 16FOR 14 YOUR 12 10 ANSWERS? 8 6 4 2 READY On 17 August, from the point at Bayport Marina, you observe the LL of the sun at WT 08-57-12 DST; WE is 1min 08sec slow; recording a sextant height of 27°35.2’; IE reading is 53.4’ off the arc; HE is 22.0ft and distance to far shore is 0.5nm GPS reads N45°00.170' W092°46.534' Complete the upper part of the SR96 (USPS Sight Reduction Form), calculating LHA, Dec, Ho, and draw time diagram. 23 USPS SR96 1 Sun LL 45 00 2 92 46 5 17 August 08-57-12 1-08 + 08-58-20 5 + 22 0 27 35 2 66 25 1 NEXT (0.4156 x d)WEEK + [0.5658 x (h/d)] Ds = (0.4156 x 0.5) + [0.5658 x (22/0.5)] bring Ds = 0.2078 + (0.5658 x 44) Ds = 0.2078 + 24.8952 Ds calculator = 25.103 6 6 25 1 13-58-20 Ds = 17 August 18 5 27 16 7 g 13Hc Ho G 14 2 14 00 5 27 31.3’ 27 30.9’ 58 20 14 35 0 zm 13 28 35 5 - 92 46 5 295 49 0 - 13 17 4 14 2 0 0 + 14 2 0 8 16 6 27 30 9 0 8 13 24 Quiz 1. The coordinates of the GP of the sun are: Lat 7° 09.5' S, Lo 150° 04.2' E. a. What are the GHA and declination of the sun at this time? GHA = 209° 55.8' [GHA = 360° - Lo E] Dec = 7° 09.5'S b. If the LHA of the sun at the same time is 48°32.1' what is the observer's Lo? Lo = 161°23.7' W [Lo W = GHA - LHA] 25 Quiz 2. You have determined your position by GPS to be Lat 23° 01.8' N, Lo 76° 56.3'. You look up and see the sun directly overhead. What are the Declination, GHA, and LHA of the sun at this time? Declination of the sun: 23° 01.8'N GHA of the sun: 76°56.3' LHA of the sun: 000° 26 Quiz 3. All meridians of longitude and parallels of latitude are great circles. a. True b. False 27 Quiz 4. Fill in the blanks in the following statements about celestial coordinates: Declination a. __________is the angular distance of the GP of a body north or south of the equator. Greenwich Hour Angle b. ___________________is the angular distance from the Greenwich meridian westward to the hour circle of a body. Local Hour Angle is the angular distance from c. ______________ an observer's local meridian westward to the hour circle of a body. 28 Quiz 5. When finding declination of the sun from the Nautical Almanac, a d correction must be determined. a. True b. False. 29 Quiz 6. Using the Excerpts from the Nautical Almanac for August 24, will the d value be entered on the Sight Reduction form as positive or negative? a. positive b. negative 30 Quiz 7. Using the Excerpts from the Nautical Almanac, what is the declination of the sun for 1400 UT on March 30? 57.0' N Declination of the sun = 3° _________ 31 Quiz 8. Declination of the Sun is equal to the Hour Declination _____________ plus or minus the d correction. a. plus b. minus c. plus or minus 32 Quiz 9. The local hour angle (LHA) is found by subtracting __________ DR Lo(W) from the GHA of the Sun. a. adding b. subtracting 33 Celestial Coordinates End of Junior Navigation Chapters 5 & 6 34