Lot by lot acceptance sampling

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IENG 486 - Lecture 18

Introduction to Acceptance Sampling,

Mil Std 105E

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Assignment

 Reading:

Chapter 9

 Sections 9.1

– 9.1.5: pp. 399 - 410

 Sections 9.2

– 9.2.4: pp. 419 - 425

 Sections 9.3: pp. 428 - 430

 Homework:

Due 03 DEC

CH 9 Textbook Problems:

 1a, 17, 26 Hint: Use Excel!

 Last Assignment:

Download and complete Last Assign: Acceptance Sampling

 Requires MS Word for Nomograph

 Requires MS Excel for AOQ

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Acceptance Sampling

Company receives shipment from vendor

Sample taken from lot,

Quality characteristic inspected

NO Lot Sentencing:

Accept lot?

YES

Use lot in production

Return lot to vendor

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Three Important Aspects of

Acceptance Sampling

1.

Purpose is to sentence lots, not to estimate lot quality

2.

Acceptance sampling does not provide any direct form of quality control. It simply rejects or accepts lots. Process controls are used to control and systematically improve quality, but acceptance sampling is not.

3.

Most effective use of acceptance sampling is not to “inspect quality into the product,” but rather as audit tool to insure that output of process conforms to requirements.

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Three Approaches to Lot

Sentencing

1.

Accept with no inspection

2.

100% inspection – inspect every item in the lot, remove all defectives

Defectives

– returned to vendor, reworked, replaced or discarded

3.

Acceptance sampling

– sample is taken from lot, a quality characteristic is inspected; then on the basis of information in sample, a decision is made regarding lot disposition.

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Acceptance Sampling

Used When:

 Testing is destructive

100% inspection is not technologically feasible

 100% inspection error rate results in higher percentage of defectives being passed than is inherent to product

Cost of 100% inspection extremely high

 Vender has excellent quality history so reduction from 100% is desired but not high enough to eliminate inspection altogether

Potential for serious product liability risks; program for continuously monitoring product required

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Advantages of Acceptance

Sampling over 100% Inspection

 Less expensive because there is less sampling

 Less handling of product hence reduced damage

 Applicable to destructive testing

 Fewer personnel are involved in inspection activities

Greatly reduces amount of inspection error

Rejection of entire lots as opposed to return of defectives provides stronger motivation to vendor for quality improvements

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Disadvantages of Acceptance

Sampling (vs 100% Inspection)

 Always a risk of accepting “bad” lots and rejecting “good” lots

Producer’s Risk: chance of rejecting a “good” lot –

Consumer’s Risk: chance of accepting a “bad” lot –

 Less information is generated about the product or the process that manufactured the product

 Requires planning and documentation of the procedure – 100% inspection does not

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Lot Formation

 Lots should be homogeneous

Units in a lot should be produced by the same:

 machines, operators,

 from common raw materials,

 approximately same time

If lots are not homogeneous

– acceptance-sampling scheme may not function effectively and make it difficult to eliminate the source of defective products.

 Larger lots preferred to smaller ones – more economically efficient

 Lots should conform to the materials-handling systems in both the vendor and consumer facilities

Lots should be packaged to minimize shipping risks and make selection of sample units easy

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Random Sampling

 IMPORTANT:

Units selected for inspection from lot must be chosen at random

Should be representative of all units in a lot

 Watch for Salting:

Vendor may put “good” units on top layer of lot knowing a lax inspector might only sample from the top layer

 Suggested technique:

1.

2.

3.

4.

Assign a number to each unit, or use location of unit in lot

Generate / pick a random number for each unit / location in lot

Sort on the random number – reordering the lot / location pairs

Select first (or last) n items to make sample

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Single Sampling Plans for

Attributes

 Quality characteristic is an attribute, i.e., conforming or nonconforming

N - Lot size n - sample size c - acceptance number

Ex. Consider N = 10,000 with sampling plan n = 89 and c = 2

From lot of size N = 10,000

Draw sample of size n = 89

If # of defectives

 c = 2

 Accept lot

If # of defectives > c = 2

 Reject lot

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How to Compute the OC

Curve Probabilities

 Assume that the lot size N is large (infinite)

d - # defectives ~ Binomial(p,n) where

 p - fraction defective items in lot n - sample size

 Probability of acceptance:

P a

P

 d

 c

 i c 

0 p i

1

 p

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Example

 Lot fraction defective is p = 0.01,

n = 89 and c = 2. Find probability of accepting lot.

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OC Curve

 Performance measure of acceptance-sampling plan

 displays discriminatory power of sampling plan

Plot of: P a

P a vs. p

= P[Accepting Lot]

 p = lot fraction defective

p = fraction defective in lot P a

= P[Accepting Lot]

0.005

0.010

0.015

0.020

0.025

0.030

0.035

0.9897

0.9397

0.8502

0.7366

0.6153

0.4985

0.3936

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OC Curve

Probability of Acceptance, Pa

Pa

1.0

0.8

0.6

0.4

0.2

0.0

0.00

0.02

n=89 c=2

0.04

0.06

0.08

0.10

Lot fraction defective, p

 OC curve displays the probability that a lot submitted with a certain fraction defective will be either accepted or rejected given the current sampling plan

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Ideal OC Curve

 Suppose the lot quality is considered bad if p = 0.01 or more

 A sampling plan that discriminated perfectly between good and bad lots would have an OC curve like:

Probability of Acceptance, Pa

1.00

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0.01

0.02

0.03

Lot fraction defective, p

0.04

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Ideal OC Curve

 In theory it is obtainable by 100% inspection IF inspection were error free.

Obviously, ideal OC curve is unobtainable in practice

 But, ideal OC curve can be approached by increasing sample size, n.

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Effect of

n

on OC Curve

Probability of Acceptance, Pa

1.00

0.80

Pa

0.60

0.40

0.20

0.00

0.00

n=50, c=1 n=100, c=2 n=200, c=4 n=1000, c=20

0.02

0.04

0.06

0.08

Lot fraction defective, p

0.10

 Precision with which a sampling plan differentiates between good and bad lots increases as the sample size increases

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Effect of

c

on OC Curve

Probability of Acceptance, Pa

1.0

0.8

Pa

0.6

0.4

0.2

0.0

0.00

n=89, c=2 n=89, c=1 n=89, c=0

0.02

0.04

0.06

0.08

Lot fraction defective, p

0.10

 Changing acceptance number, c, does not dramatically change slope of OC curve.

 Plans with smaller values of c provide discrimination at lower levels of lot fraction defective

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Producer and Consumer Risks in

Acceptance Sampling

 Because we take only a sub-sample from a lot, there is a risk that:

 a good lot will be rejected

(Producer’s Risk –

) and

 a bad lot will be accepted

(Consumer’s Risk –

)

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Producer’s Risk -

 Producer wants as many lots accepted by consumer as possible so

Producer “makes sure” the process produces a level of fraction defective equal to or less than: p

1

= AQL = Acceptable Quality Level

 is the probability that a good lot will be rejected by the consumer even though the lot really has a fraction defective

 p

1

 That is,

 

P

Lot is rejected given that process has an acceptable quality level

 

P Lot is rejected p

AQL

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Consumer’s Risk -

 Consumer wants to make sure that no bad lots are accepted

Consumer says, “I will not accept a lot if percent defective is greater than or equal to p

2

” p

2

= LTPD = Lot Tolerance Percent Defective

 is the probability a bad lot is accepted by the consumer when the lot really has a fraction defective

 p

2

 That is,

P

Lot accepted given that lot has unacceptable quality level

P Lot accepted p

LTPD

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Designing a Single-Sampling Plan with a Specified OC Curve

 Use a chart called a Binomial Nomograph to design plan

 Specify:

 p

1

= AQL (Acceptable Quality Level)

 p

2

= LTPD (Lot Tolerance Percent Defective)

1 – 

= P[Lot is accepted | p = AQL]

β = P[Lot is accepted | p = LTPD]

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Use a Binomial Nomograph to Find

Sampling Plan

(Figure 15-9, p. 643)

 Draw two lines on nomograph

Line 1 connects p

1

Line 2 connects p

2

= AQL to ( 1-

)

= LTPD to

Pick n and c from the intersection of the lines

 Example: Suppose

 p

1

= 0.01,

α = 0.05, p

2

= 0.06,

β = 0.10.

Find the acceptance sampling plan.

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p

1

= AQL = .01

p - Axis p

2

= LTPD = .06

n = 120

Greek - Axis

= .10

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1 – 

= 1 – .05 = .95

c = 3

Take a sample of size 120.

Accept lot if defectives ≤ 3.

Otherwise, reject entire lot!

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Rectifying Inspection

Programs

 Acceptance sampling programs usually require corrective action when lots are rejected, that is,

Screening rejected lots

 Screening means doing 100% inspection on lot

 In screening, defective items are

Removed or

Reworked or

Returned to vendor or

Replaced with known good items

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Rectifying Inspection

Programs

Incoming Lots:

Fraction Defective p

0

Inspection

Activity

Rejected Lots:

100%

Inspected

Fraction

Defective = 0

Accepted

Lots

Fraction

Defective p

0

Outgoing Lots:

Fraction Defective p

1

 p

0

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Where to Use Rectifying

Inspection

 Used when manufacturer wishes to know average level of quality that is likely to result at given stage of manufacturing

 Example stages:

Receiving inspection

In-process inspection of semi-finished goods

Final inspection of finished goods

 Objective: give assurance regarding average quality of material used in next stage of manufacturing operations

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Average Outgoing Quality:

AOQ

 Quality that results from application of rectifying inspection

Average value obtained over long sequence of lots from process with fraction defective p a

  n

AOQ

N

N - Lot size, n = # units in sample

 Assumes all known defective units replaced with good ones, that is,

If lot rejected, replace all bad units in lot

If lot accepted, just replace the bad units in sample

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Development of AOQ

 If lot accepted:

Number defective units in lot:

  

N

 n

 fraction defective

# units remaining in lot

 Expected number of defective units:

P a

 

N

 n

 

Prob

Lot

 

 

# defective accepted

  units in lot

 Average fraction defective,

Average Outgoing Quality, AOQ:

AOQ

P p

N

 n

N

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Example for AOQ

 Suppose N = 10,000, n = 89, c = 2, and incoming lot quality is

p = 0.01. Find the average outgoing lot quality.

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Questions & Issues

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