講者: 許永昌 老師 1 Contents Contour Integral Representation of the Hankel Functions Steepest descents Asymptotic series Modified Bessel function 2 Contour Integral Representation of the Hankel Functions (請預讀P707~P710) Since x g x , t exp 2 1 t t Jn xt , n n g(x,t) will have essential singularities at t=0, . Residue theorem? It is worked for n is an integer number case; otherwise, it will have a branch point at t=0. Derived by yourself: B essel equation: x 2 2x x x x 2 If x 2 2x x x x 2 w e get f x, t 2 g x, t t 1 2 J x 0, t g x , t f x , t , x 1 t 2 t . t 2 2 2 T herefore, x x x x x 2 a b g x, t t 1 dt gf b a . 3 Contour Integral Representation of the Hankel Functions (continue) You will find both t=0+ and t=- will let fg=0 Re{x}>0. Bessel J : J z 1 2 i Check: z 1 J z 2 2 i z 1 2 2 i s0 z 2 2s e i 2 e e i i exp y 2 z 1 2 y y e 1 z exp t t 2 dt 1 t i 2 exp y y 1 , s ! s ! s 1 s0 1 z 2 e C 2s z dy 1 y z s s dy s! 2 i dz 2 i 1 sin 4 Contour Integral Representation of the Hankel Functions (continue) Hankel function: H 1 z 2 H z 1 i 1 i e i 0 0 e i 1 z exp t t 2 dt 1 t 1 z exp t t 2 dt 1 t 1 1 2 J z H z H z , 2 N z 1 H 1 z H 2 z 2i 5 Contour Integral Representation of the Hankel Functions (continue) Prove that N z 1 H 1 z H 2 z 2i Prove that H 1 x e i H 1 x 2 2 i H x e H x at first. Use these equations to find out J-(x). Finally, we get the formula of N shown in Ch11.3. 6 Asymptotic series of the Hankel Functions (請預讀P719~P723,此page只大略講) When z and Re{t-1/t}<0, Exp(z/2[t-1/t])0 i.e. (|t|-1/|t|)cos(ang(t)) <0 0 The main contribution is at the saddle point i. Steepest descent: z 2 t 1 t z zi 2 iz y 1 H z 1 i 2 z e i 0 iz i t e e 2 t z if y i 2 1 1 1 2 z exp 2 i zO t 1 dt t t i 1 i 2 2 2 * H z, z i 1 2 . e 3 g 0 t i , dy i z e iz i 1 y 2 i z 2 2 1 2 dt dy 1 2 7 Modified Bessel Functions, I & K (請預讀P713~P716,另一本無) Helmholtz eq. : [2+k2]y=0 Bessel eq. : x2y’’+xy’+[x2-n2]y=0 Modified Helmholtz eq. : [2k2]y=0 Modified Bessel eq. : x2y’’+xy’-[x2+n2]y=0 ----(1) ----(2) Eq. (2) can be transformed from Eq. (1) by the transformation x ix. I(x)iJ(ix)=ei/2J(xei/2). [i is used to make sure I(x) if x ]. K(x)/2 i1H(1)(ix). [i1 is used to make sure K(x) if x . Besides, it will tend to zero when x.] 8 Homework 11.6.3(a~c) (12.3.2e) 11.6.5 (12.3.3e) 11.4.7 9