Math 90A Test 2

```Solving Equations
Solving Equations
Equations contain an equal sign (or
inequality) and at least one variable.
Find what value(s)
make the equation true.
How do you
accomplish it?
Isolate the variable.
Get rid of the furthest
number that is “with” the
variable first.
Solve:Isolate the variable.
then
If multiplied,
then multiply by the reciprocal
How do you know
you are correct?
original equation to see if both
side have the same value.
Questions to focus on
Who is the variable?
Where is the variable?
Is the variable on the right side or left side
of the equal sign?
Combine like terms on the same side of the equation
What numbers are with the variable?
(on the same side of the equal sign)
Which number is “furthest away” according to the
Order of Operations? (P, E, M D, A S)
Questions to focus on
How is that number with the variable
How do you get rid of that number?
(Add opposite or Multiply by reciprocal)
Add the opposite or Multiply by the reciprocal
to both sides of the equal sign!
Start over with the first question
until the variable has been isolated.
2 w 3
2 w 3
Check:
23 w 33
5w
2  5  3
22
y
5
 10
y
(5)
 10
5
Check:
y
 50 
 ( 5 )10
5
y  50
5
 10
Your turn to try a few problems
(2 operations)
3x + 5 = 20
(2 operations)
3x + 5 = 20
3x + 5 – 5 = 20 – 5
3x = 15
3x = 15
-3
-3
x = 5
Check:
3(5) + 5 = 20
20 = 20
(2 operations)
7 = 4 – 6x
(2 operations)
7 = 4 – 6x
7 – 4 = 4 – 4 – 6x
3 = -6x
3 = -6x
-6
-6
-1/2 = x
Check:
7 = 4 – 6( )
7 = 4 – 6( -1/2 )
7 = 4 – -3
7=4+3
7=7
Your turn to try a few problems
(variables on the same side of equation)
5x + 2 – 4x = 6
(variables on the same side of equation)
5x + 2 – 4x = 6
5x – 4x + 2 = 6
Check:
5(4) + 2 – 4(4) = 6
1x + 2 = 6
x+2–2=6–2
x = 4
20 + 2 – 16 = 6
22 – 16 = 6
6 = 6
(variables on both sides of the equation)
4x – 7 = 6x + 2
(variables on both sides of the equation)
4x – 7 = 6x + 2
4x + -4x + -7 = 6x + -4x + 2
-7 = 2x + 2
Check:
-7 + -2 = 2x + 2 + -2
4(-9/2) – 7 = 6(-9/2) + 2
-9 = 2x
-18 – 7 = -27 + 2
-9 = 2x
-18 + -7 = -27 + 2
2 2
-25 = -25
-9/2 = x
(variables on 1 sides of the equation)
2x + 3(x – 4) = 13
(variables on 1 sides of the equation)
2x + 3(x – 4) = 13
2x + 3(1x + -4) = 13
2x + 3x + -12 = 13
5x + -12 = 13
5x + -12 + 12 = 13 + 12
5x = 25
5x = 25
5
5
x=5
Check:
2(5) + 3((5) – 4) = 13
10 + 3(1) = 13
10 + 3 = 13
Your turn to try a few problems
Types of solutions:
 No solution, there is no value for the variable
that will make the equation true.
5=2
 A unique answer, there is at least one value
that makes the equation true.
x = number
 Infinite number of solutions, all real
numbers makes the equation true.
3 = 3
Solve for x.
x+2=x–4
x–x+2=x–x–4
2 = -4
No Solution
Solve for x.
2x – 1 = x + 5
2x – x – 1 = x – x + 5
x–1=5
x–1+1=5+1
x = 6 unique solution
Solve for x.
x+4=4+x
x–x+4=4+x–x
4 = 4
Infinite number of solutions
```
Related flashcards
Special functions

14 Cards