Chapter 34: Thin Lenses Now consider refraction through this piece of glass: focal point optic axis converging light This is called a “Double Convex Lens” 1 Chapter 34: Thin Lenses Converging Lenses (convex) Diverging Lenses (concave) 2 Chapter 34: Thin Lenses Diverging Lens Where is the focal point for these 4 incoming rays? Don’t confuse these reflections for something meaningful. Converging Lens The focal point is visible because real rays go through it. 3 Chapter 34: Thin Lenses Optical Ray Diagram: a line drawing depicting a small number of key light rays. For a lens, an optical ray diagram should include: 1. Parallel Ray. A ray parallel to the optic axis which passes through the object & the focal point. 2. Focal Ray. A ray that passes through both the focal point and the object. 3. Chief Ray. A ray that passes through both the center of the lens and the object. These three rays intersect at the image. Note: we don’t use reflected rays in lens analysis. 4 Chapter 34: Thin Lenses The Diverging Lens parallel ray f f Virtual part: where the refracted ray appears to come from. 5 Chapter 34: Thin Lenses The Diverging Lens real part virtual part Virtual part: where the refracted ray appears to come from. 6 Chapter 34: Thin Lenses The Diverging Lens The chief ray has no virtual part. 7 Chapter 34: Thin Lenses Put all three rays together: The three refracted rays have no intersection. 8 Chapter 34: Thin Lenses Put all three rays together: object focal point upright image There is an intersection of the virtual parts. Need virtual parts to find the image? Virtual image. 9 Chapter 34: Thin Lenses The Thin Lens Equation Parallel ray a converging lens f so si 10 Chapter 34: Thin Lenses The Thin Lens Equation Parallel ray a converging lens Positive side for object distance Positive side for Negative side for image distance image distance focal length focal length (e.g. diverging lens) Opposite for mirrors 11 Chapter 34: Thin Lenses The Thin Lens Equation 1 1 P so si 1 1 1 so si f “Strength” or “Power” of lens Note: our book uses “P”. Other books use “S”. 1 P f f, so and di all must have the same length units. Units of P usually in [m-1] or rather [Diopters]. 12 Chapter 34: Thin Lenses Why is 1/f called the “lens power”? (or sometimes “strength”) focal point at 1 if f or ratherP 0 f then thelens has NO EFFECT on thelight 13 Chapter 34: Thin Lenses Why is 1/f called the “lens power”? (or sometimes “strength”) focal point very close to the lens 1 if f 0 or ratherP f then thelens has A HUGE EFFECT on thelight 14 Chapter 34: Thin Lenses Example 1: A lens focuses light from an object 2.75m away as an image 0.483m on the other side of the lens. What are the focal length, lens type and image type? 1 1 1 1 1 f so si 2.75m 0.483m f 0.411meters The lens is converging because: f>0 Converging lens: f>0 Diverging lens: f<0 What is the image type? 15 Chapter 34: Thin Lenses The image is real (si>0). Is it inverted or upright? 2.75 m 0.483m 6 cm = 1m 0.411m Ray diagram shows the image is: Real Inverted True whenever the object is outside the focal point of a converging lens. 16 Chapter 34: Thin Lenses The ray diagram also shows the image is small. positive side for di and f negative side for di and f ho hi Magnification: hi di m ho do Minus sign indicates that real images are always inverted. 17 Chapter 34: Thin Lenses How to do lens problems graphically Use a full sheet – Landscape. Sketch the lens on the optic axis. Sketch the objects – correctly positioned. Show a scale. You might wish to show a different scale for vertical and horizontal lengths 5. Sketch two principle rays per object and find the image. 6. Refraction occurs on the vertical center-line. 1. 2. 3. 4. 18 Chapter 34: Thin Lenses Example 2: How far from a converging lens with a focal length of 25 cm should an object be placed to produce a real image which is the same size as the object? si >0 si We want m 1 so si so (Minus because all real images are inverted.) 1 1 1 f so si 1 1 1 2 25 cm s o s o s o s o 50 cm 19 Chapter 34: Thin Lenses How to make a magnifying glass What kind of lens has an upright image with m>1? si m 1 so si negative |si| > |so| image is farther from the lens than the object si <0 f Place the object within the focal length of a converging lens. 20