Alge-Tiles
Making the Connection between the
Concrete ↔ Symbolic
(Alge-tiles)
↔
(Algebraic)
What are Alge-Tiles?
Alge-Tiles are rectangular and square
shapes (tiles) used to represent integers and
polynomials.
Examples: 1→
1x →
1x2 →
Objectives for this lesson
Using Alge-Tiles for the following:
- Combining like terms
- Multiplying polynomials
- Factoring
- Solving equations
Allow students to work in small groups when
doing this lesson.
Construction of Alge-Tiles
1 (let the side = one unit)
For one unit tile:
(it is a square tile)
1
Area = (1)(1) = 1
x
For a 1x tile
(it is a rectangular tile)
(unknown length therefore let it = x)
1
Side of unit tile = side of x tile
Area = (1)(x) = 1x
x
Side of x2 tile = side of x tile
For x2 tile:
(It is a square tile)
Other side of x2 tile = side of x tile
Area = (x)(x) = x2
x
Part I: Combining Like Terms
Prerequisites: prior to this lesson students would have been taught the
Zero Property
Outcomes: Grade 7 - B11, B12, B13
Grade 8 – B14, B15
Grade 9 – B8
Grade 10 – B1, B3
Use the Alge Tiles to represent the following:
3x
3
2x2
Part I: Combining Like Terms
For negative numbers use the other side of each
tile (the white side)
Use the Alge Tiles to represent the following:
-2x →
-4 →
-3x - 4 →
Part I: Combining Like Terms
Represent “2x” with tiles
Represent “3” with tiles
Can 2x tiles be combined with the tiles for 3 to make
one of our three shapes? Why or why not?
Therefore: simplify 2x + 3 =
2x + 3 can’t be simplified any further (can’t touch this)
Part I: Combining Like Terms
Combine like terms (use the tiles):
+
2x + 2x →
1 +1x +2 →
+
-2x + 3x +1→
Using the zero property
= 4x
= 1x+3 (ctt)
+
+
+
= 1x +1(ctt)
Part I: Combining Like Terms
After mastering several questions where students
were combing terms you could then pose the
question to the class working in groups:
“Is there a pattern or some kind of rule you
can come up with that you can use in all
situations when combining polynomials.”
In conclusion, when combining like terms you can
only combine terms that have the same tile shape
(concrete) → Algebraic: Can combine like terms if
they have the same variable and exponent.
Part II: Multiplying Polynomials
Prerequisites: Students were taught the distributive
property and finding the area of a rectangle.
Area(rectangle) = length x width
When multiplying polynomials the terms in each
bracket represents the width or length of a rectangle.
Find the area of a rectangle with sides 2 and 3. Two
can be the width and 3 would be the length.
The area of the rectangle would = (2)•(3) = 6
Part II: Multiplying Polynomials
We will use tiles to find the answer. The same premise will be
used as finding the area of a rectangle.
Make the length = 3 tiles
The width = 2 tiles
The tiles form a rectangle, use other tiles to fill in the rectangle
Once the rectangle is filled in remove the sides and what is left
is your answer in this case it is 6 or 6 unit tiles
Part II: Multiplying Polynomials
Try: (2x)(3x)→
Side: 3x
Side: 2x
Remove the sides
Therefore: (2x)(3x) = 6x2
Part II: Multiplying Polynomials
Try (1x + 2)(3)
Side: 1x + 2)
Side: 3
Therefore: (1x + 2)(3) = 3x + 6 (ctt)
Make rectangle, fill rectangle
Remove sides
Part II: Multiplying Polynomials
Try (1x +2)(1x -1)
Side: 1x - 1
Side: 1x + 2
Tiles remaining:
Simplify to get:
x2 + 2x – 1x – 2
x2 + 1x – 2 (ctt)
Part II: Multiplying Polynomials
Pattern: After mastering several questions where
students were combing terms you could then pose
the question to the class working in groups:
“Is there a pattern or some kind of rule you
can come up with that you can use in all
situations when multiplying polynomials.”
This can lead to a larger discussion where students
can put forth their ideas.
Part III: Factoring
Outcomes: Grade 9 – B9, B10, Grade 10 – B1, B3, C16
Take an expression like 2x + 4 and use the rectangle to factor.
You will go in reverse when being compared to multiplying
polynomials. (make the rectangle to help find the sides)
The factors will be the sides of the rectangle
i. Construct a rectangle using 2 ‘x’ tiles and 4 unit one tiles. This
can be tricky until you get the hang of it.
Part III: Factoring
Now make the sides; width and length of the
rectangle using the alge-tiles.
Side 1 : (1x + 2)
Side 2 : (2)
2x + 4 = (2)(1x +2)
Remove the rectangle and what is left are the factors of 2x +4
Part III: Factoring
Try factoring 3x + 6 with your tiles.
1x + 2
First make a rectangle
Make the sides
Remove the rectangle
3
The sides are the factors
Factors → (1x + 2)(3)
3x + 6 = (3)(1x + 2)
Part III: Factoring
Try factoring x2 + 5x + 6 (make rectangle)
(1x + 3)
**Hint: when the expression has x2,
start with the x2 tile.
Next, place the 6 unit tiles at the
bottom right hand corner of the x2 tile.
You will make a small rectangle(1x
with+ 2)
the unit tiles.
Then add the x tiles where needed to
complete the rectangle
3
2
When the rectangle is finished examine
to see
if+the
tiles
combine
to give
you
2it +
x
5x
6
=
(1x
+
3)
(1x
+
2
the original expression → x + 5x + 6
Next make the sides for the rectangle
Remove the rectangle and you have the factors. (1x + 3) (1x + 2)
2)
Part III: Factoring
What if someone tried the following:
Factor: x2 + 5x + 6 (make rectangle)
Start with the x2 tile, now make a rectangle
with the 6 unit tiles.
Now complete the rectangle using the x
tiles.
1
When the rectangle is finished examine it to
see if the tiles combine to give you the
original expression → x2 + 5x + 6
6
When the tiles are combined, the result is
x2 + 7x + 6, where is the mistake?
The unit tiles must be arranged in a rectangle so when the x tiles are used
to complete the rectangle they will combine to equal the middle term, in
this case 5x.
Factoring
Have students try to factor more trinomials
(refer to Alge-tile binder – Factoring section: F – 3b for additional
questions)
After mastering several questions where students were
factoring trinomials you could then pose the question to the
class :
“Is there a pattern or some kind of rule
you can come up with that you can use when
factoring trinomials?”
Part III: Factoring (negatives)
Try factoring:
x2 - 1x – 6
Start with x2 tile, then fill in the unit tiles in
this case -6 which is 6 white unit tiles.
1x - 3
Remember to make a rectangle at the
bottom corner of the x2 tiles where the sides
have to add to equal the coefficient of the
1x + 2
middle term, -1.
-3
Next fill in the x tiles to make the
rectangle.
2
Now the rectangle is complete check
to see if the tiles combine to equal
x2 - 1x – 6.
Therefore x2 - 1x – 6 = (x – 3) (x + 2)
Fill in the sides and remove the rectangle
to give you the factors.
Part IV: Solving for X
Outcomes: Grade 7 check, Grade 8 - C6, Grade 9 – C6, Grade 10-C 27
Solve 2x + 1 = 5 using alge-tiles
Set up 2x + 1= 5 using tiles
=
1x = 2
Using the zero property to remove the 1 tile you add a -1 tile to both sides
On the left side -1 tile and +1 tile give us zero and you are left with 2 ‘x’ tiles
On the right side adding -1 tile gives you +4 tiles
Now 2 ‘x’ tiles = 4 unit tiles, (how many groups of 2 are in 4)
Therefore 1 ‘x’ tile = 2 unit tiles
Part IV: Solving for X
Solve 3x + 1 = 7
=
1x = 2
Add a -1 tile to both sides
Zero Property takes place
What’s left? 3 ‘x’ tiles = 6 unit tiles (how many groups of 3 are in 6)
Therefore 1x tile = 2 unit tiles
Part IV: Solving for X
Solve for x:
2x – 1 = 1x + 3
=
1x = 4
Now add +1 tile to both sides… zero property
You are left with 2x = 1x + 4
Add -1x tile to each side… zero property
Leaving 1x = 4
Alge-Tile Conclusion
Assessment: While students are working on
question sheet handout, go around to each group
and ask students to do some questions for you to
demonstrate what they have learned.
For practice refer to handout of questions for all four
sections:
Part I: Combining Like Terms
Part II: Multiplying Polynomials
Part III: Factoring
Part IV: Solving for an unknown
(P.S. the answers are at the end)