MAT 1234 Calculus I Section 1.6 Part II Using the Limit Laws http://myhome.spu.edu/lauw Homework WebAssign 1.6 Part II Turn in the one problem at the end of your handout (the last page) tomorrow. Recall: Limit of a Function lim f ( x) L xa if and only if lim f ( x) L xa Independent of f(a) and lim f ( x) L xa Preview Limits with Absolute Values The Squeeze Theorem Pay extra attention to the presentation expectations (especially those who have photographic memory!) Recall (absolute value function) x if x 0 x x if x 0 Example 8(a) (Limits with Absolute Values) lim x x0 This is not a polynomial or an rational function Absolute function is not in one of the 11 limit laws Find the limit by using the definition of limits Example 8(a) (Limits with Absolute Values) lim x x0 This is not a polynomial or an rational function Absolute function is not in one of the 11 limit laws Find the limit by using the definition of limits Example 8(a) (Limits with Absolute Values) lim x x0 This is not a polynomial or an rational function Absolute function is not in one of the 11 limit laws Find the limit by using the definition of limits Example 8(a) (Limits with Absolute Values) lim x x0 This is not a polynomial or an rational function Absolute function is not in one of the 11 limit laws Find the limit by using the definition of limits Example 8(a) (Limits with Absolute Values) lim x x0 We are going to look at left and right hand limits: 1. As x 0 , x 0 lim x x 0 2. As x 0 , x 0 lim x x 0 lim x x 0 x if x 0 x x if x 0 Example 8(a) (Limits with Absolute Values) Note that solutions steps are very important here. You need to pay attention and understand the correct way of presenting your solutions. WebAssign do not check your solutions steps. Advise: Write out full solutions in your notebook even WebAssign does not ask for it. Example 8(b) x2 lim x 2 x 2 Example 8(b) x2 lim x 2 x 2 Again, no direct substitution!! x if x 0 x x if x 0 if x 2 0 x2 x2 ( x 2) if x 2 0 Example 8(b) 1. As x 2 , x 2 lim x 2 2. x2 x2 As x 2 , x 2 lim x 2 x2 x2 x2 lim x 2 x 2 if x 2 x2 x2 ( x 2) if x 2 Example 9 (Limits with Absolute Values) 1 1 lim 5 x 0 x x Example 9 (Limits with Absolute Values) 1 1 lim 5 x 0 x x As x 0 , x 0 1 1 lim 5 x 0 x x x if x 0 x x if x 0 Squeeze Theorem If f ( x) g ( x) h( x) when x is near a and lim f ( x) lim h( x) L x a then x a lim g ( x) L x a Squeeze Theorem y f ( x) g ( x) h( x) h(x) g (x) f (x) a x Squeeze Theorem y f ( x) g ( x) h( x) h(x) lim f ( x) lim h( x) L xa L f (x) a x xa Squeeze Theorem y f ( x) g ( x) h( x) h(x) lim f ( x) lim h( x) L xa g (x) L xa lim g ( x ) L xa f (x) a x Squeeze Theorem y h(x) g (x) L f (x) a x You will see this type of idea over and over again. Example 10 1 2 lim x sin lim x x0 x x0 2 1 lim sin x 0 x We cannot apply the limit laws since 1 lim sin x 0 x DNE (Lab 2, 4(c)) Example 10 1 2 lim x sin lim x x0 x x0 2 1 lim sin x 0 x We cannot apply the limit laws since 1 lim sin x 0 x DNE (Lab 2, 4(c)) Example 10 1 2 lim x sin lim x x0 x x0 2 1 lim sin x 0 x We cannot apply the limit laws since 1 lim sin x 0 x DNE (Lab 2) Example 10 1 y sin x 1 lim x sin x 0 x 2 Example 10 1 sin x f ( x) g ( x) h( x) lim f ( x) lim h( x) L xa 1 x sin x 2 xa lim g ( x ) L xa Expectations 1 sin x 1 x 2 sin x lim x0 and lim x0 Example 10 1 y x sin x 2 Review: We learned… How to find limits involving absolute values. The idea of the squeeze theorem. Pay attention to the expectations of the solutions details. Note that in the exam, you will be ask to state the theorems you learned in this class. Quiz Please use pencils and erasers. Please make sure your handwriting is easy to understand. You have 20 min. Do not look at your neighbor’s paper. If you need to relax your neck, … Double check your work. Once you turn in your paper, you can go. Quiz Evaluate lim h 0 lim h0 2h 2 h 2h 2 h