13.3 Completing the Square • Objective: To complete a square for a quadratic equation and solve by completing the square Steps to complete the square • 1.) You will get an expression that looks like this: AX²+ BX • 2.) Our goal is to make a square such that we have (a + b)² = a² +2ab + b² • 3.) We take ½ of the X coefficient (Divide the number in front of the X by 2) • 4.) Then square that number To Complete the Square x2 + 6x • Take half of the coefficient of ‘x’ 3 • Square it and add it 9 x2 + 6x + 9 = (x + 3)2 Complete the square, and show what the perfect square is: x 12x x 12x 36 2 2 y 14 y y 14 y 49 y 10 y y 10y 25 2 2 x 5x 2 2 2 25 x 5x 4 2 x 6 2 y 7 2 y 5 2 5 x 2 2 To solve by completing the square • If a quadratic equation does not factor we can solve it by two different methods • 1.) Completing the Square (today’s lesson) • 2.) Quadratic Formula (Next week’s lesson) Steps to solve by completing the square 1.) If the quadratic does not factor, move the constant to the other side of the equation Ex: x²-4x -7 =0 x²-4x=7 2.) Work with the x²+ x side of the equation and complete the square by taking ½ of the coefficient of x and squaring Ex. x² -4x 4/2= 2²=4 3.) Add the number you got to complete the square to both sides of the equation Ex: x² -4x +4 = 7 +4 4.)Simplify your trinomial square Ex: (x-2)² =11 5.)Take the square root of both sides of the equation Ex: x-2 =±√11 6.) Solve for x Ex: x=2±√11 Solve by Completing the Square x 6 x 16 0 2 x 6 x 16 2 +9 +9 x 6 x 9 25 2 x 3 25 x 3 5 x 3 5 x 8 x 2 2 Solve by Completing the Square x 22 x 21 0 2 x 22 x 21 2 +121 +121 x 22 x 121 100 2 x 11 100 x 11 10 x 11 10 x 21 x 1 2 Solve by Completing the Square x 2x 5 0 2 x 2x 5 2 +1 +1 x 2x 1 6 2 x 1 6 x 1 6 2 x 1 6 Solve by Completing the Square x 10 x 4 0 2 x 10 x 4 2 +25 +25 x 10 x 25 29 2 x 5 29 2 x 5 29 x 5 29 Solve by Completing the Square x 8 x 11 0 2 x 8 x 11 2 +16 +16 x 8 x 16 5 2 x 4 5 x 4 5 2 x 4 5 Solve by Completing the Square x 6x 4 0 2 x 6 x 4 2 +9 +9 x 6x 9 5 2 x 3 5 x 3 5 2 x 3 5 The coefficient of 2 x 3x 3 0 2 2 2 2 2 3 3 x x 0 2 2 2 x must be “1” 2 3 33 x 4 16 2 3 33 x 4 16 3 3 3 2 3 2 x x 4 33 3 33 2 2 2 x 3 33 x 4 4 16 3 9 3 9 2 x 2 x 16 2 16 4 The coefficient of 3x 12 x 1 0 1 2 x 4x 3 2 x must be “1” 2 1 x 4 x 4 4 3 2 x 2 2 11 3 11 x2 3 11 x 2 3 33 x 2 3 3 3 6 x 32 33 3 6 33 x 3