HOMEWORK PROBLEMS
HW.11
BRYCE CASSELL
Chapter 11 Solutions
11.1 Use Table 11.2 "Solubilities of Some Ionic Compounds" to decide if a solution containing the
following is unsaturated, saturated, or supersaturated.
(a) 45.0 g of NaCl per 100 g of H2O → Supersaturated
(b) 0.000092 g of AgCl per 100 g of H2O → Unsaturated
11.2 (a) Which solvent is Br2 more likely soluble in—CH3OH or C6H6?
C6H6
(c) Which solvent is NaOH more likely soluble in—CH3OH or C6H6?
CH6OH
11.3 What is the molarity of the solution when 32 g of C6H12O6 is dissolved in 4.66 L of solution?
0.0381 M C6H16O6
11.4 How many moles of solute are present in 0.0331 L of a 2.55 M solution?
0.0844 MOL OF SOLUTE
11.5 What volume of 0.333 M Al(NO3)3 is needed to obtain 26.7 g of Al(NO3)3?
0.376 L OR 376mL
11.6 What is the mass of solute in 24.5 mL of 0.755 M CoCl2?
2.40g of CoCl2
11.7 What are the individual ion concentrations and the total ion concentration in 1.04 M Al2(SO4)3?
Al3+ = 2.08M
SO42- = 3.12M
Total ion concentration = 5.20M
11.8 Using concentration as a conversion factor, how many liters are needed to provide 0.822 mol of
NaBr from a 0.665 M solution?
1.24L
11.9 What volume of solution is needed to provide 9.04 g of NiF2 from a 0.332 M solution?
0.282L or 282mL
11.10 What is the mass percentage of H2O2 in a solution with 1.67 g of H2O2 in a 55.5 g sample?
3.01% H2O2
11.11 If there is 0.551 mg of As in 348 g of solution, what is the As concentration in ppm?
1.58 ppm
11.12 If 665 mL of a 0.875 M KBr solution is boiled gently to concentrate the solute to 1.45 M, what will
be its final volume?
Final Volume = 401mL
11.13 How much water must be added to 75.0 mL of 0.332 M FeCl3(aq) to reduce its concentration to
0.250 M?
24.6mL of water
11.14 What volume of 1.000 M Na2CO3 will react with 342 mL of 0.733 M H3PO4?
3Na2CO3 + 2H3PO4 → 2Na3PO4 + 3H2O + 3CO2
386mL
11.15 It takes 23.77 mL of 0.1505 M HCl to titrate with 15.00 mL of Ca(OH)2. What is the concentration
of Ca(OH)2? You will need to write the balanced chemical equation first.
Balanced Equation = 2HCl + Ca(OH)2 → CaCl2 + 2H2O | 0.1192M Ca(OH)2
11.16 It takes 4.667 mL of 0.0997 M HNO3 to dissolve some solid Cu. What mass of Cu can be dissolved?
Cu + 4HNO3(aq) → Cu(NO3)2(aq) + 2NO2 + 2H2O
0.00739 g or 7.39mg of Cu
11.17 If 25.0 g of C6H12O6 are dissolved in 100.0 g of H2O, what is the boiling point and the freezing
point of this solution?
Boiling point = 100.71 degrees C
Freezing point = -2.58 degrees C
11.18 NaCl is often used in winter to melt ice on roads and sidewalks, but calcium chloride (CaCl2) is
also used. Which would be better (on a mole-by-mole basis), and why?
CaCl2 is better because it lowers the freezing point of ice more than NaCl by breaking into 3 ions,
Ca2+ and 2Cl-.
11.19 Calculate the boiling point and the freezing point of an aqueous solution of NaNO3 made by
mixing 15.6 g of NaNO3 with 100.0 g of H2O. Assume an ideal van’t Hoff factor.
Boiling point = 101.88 degrees C
Freezing point = -6.83 degrees C
11.20 What does it mean when we say that 0.15 M NaCl solution is isotonic with blood, whereas
distilled water is hypotonic?
Isotonic means that the NaCL solution has the same concentration as blood. When NaCl enters
the bloodstream, blood cells don’t swell or shrink because both NaCl and blood are similar in
concentration. Distilled water has a lower solute concentration than blood, meaning when it enters
the bloodstream, red blood cells absorb the water and burst due to the increased internal pressure.