VIETNAMESE - GERMAN UNIVERSITY
MECHANICS 1 STATICS FORMULA SHEET
Authors:
Hoang Minh Khoi, MEN2021
Khuong Khanh Phuong, MEN2021
Supervisor:
Dr. Tran Tuan Minh
This document is allowed in the exam room
NO modification of this document is allowed
1
Equilibrium Conditions
1.1
Vector Appendix:
βπ β
βπ β
1
βπβ
• Unit vector: π = βπβ → Unit vector: π = √
β β
2
2
2
π + π + π ββπ ββ
βπ β
π
π
|π| = |π||π| sin π
π
π
• Vector product:
| ππ₯ ππ¦ ππ§ |
|
| |π π |
|π π |
|π π |
– π = π × π = ||ππ₯ ππ¦ ππ§ || = || π¦ π§ || ππ₯ − || π₯ π§ || ππ¦ + || π₯ π¦ || ππ§
| π π π | | ππ¦ ππ§ |
| ππ₯ ππ§ |
| ππ₯ ππ¦ |
| π₯ π¦ π§|
– π =π×
{π = |π| |π| sin π ππ
ππ βΆ the unit vector perpendicular to vector π and π
where
π βΆ the angle between vector π and π
π
π
• Dot product:
π
π cos π
βπ1 β βπ1 β
– π ⋅ π = βπ2 β ⋅ βπ2 β = π1 π1 + π2 π2 + π3 π3
β β β β
βπ3 β βπ3 β
– π ⋅ π = |π||π| cos π
1.2
Specified formulas:
• Force: π = ππ₯ + ππ¦ + ππ§ = πΉπ₯ ππ₯ + πΉπ¦ ππ¦ + πΉπ§ ππ§
where ππ is the unit vector of ππ (π = π₯, π¦, π§)
• Moment:
1. π = β.πΉ
{
β βΆ perpendicular distance from the point of application to the line of force
where
πΉ βΆ magnitude of applied force
| ππ ππ ππ |
|
|
2. π΄ = π × π = || π1 π2 π3 || = ππ₯ ππ₯ + ππ¦ ππ¦ + ππ§ ππ§
|πΉ πΉ πΉ |
| 1 2 3|
{
π βΆ the position vector pointing from point O to an arbitrary point on the action line of π
where
π βΆ the applied force
1
2
Center of Gravity, Center of Mass, Centroids
2.1
Centroid:
• Line
– Non-linear:π₯ =
∫ π₯ ππ
π¦=
,
∫ π¦ ππ
∫ ππ
∫ ππ
∑
∑
π₯π
π¦π
– Linear: π₯ = ∑ π π , π¦ = ∑ π π
ππ
ππ
• Area
– Non-linear:π₯ =
∫ π₯ ππ΄
π¦=
,
∫ π¦ ππ΄
∫ ππ΄
∫ ππ΄
∑
∑
π₯π΄
π¦π΄
– Linear: π₯ = ∑ π π , π¦ = ∑ π π
π΄π
π΄π
• Volume
– Non-linear: π₯ =
∫ π₯ ππ
,
π¦=
∫ π¦ ππ
,
π§=
∫ π§ ππ
∫ ππ
∫ ππ
∫ ππ
∑
∑
∑
π₯π
π¦π
π§π
– Linear: π₯ = ∑ π π , π¦ = ∑ π π , π§ = ∑ π π
ππ
ππ
ππ
2.2
Center of mass:
• Non-linear: π₯ =
∫ π₯π ππ
∫ πππ
∑
π₯ππ
• Linear: π₯ = ∑ π π π ,
ππ ππ
2.3
,
π¦=
∫ π¦π ππ
∫ πππ
∑
π¦ππ
π¦ = ∑ π π π,
ππ ππ
,
π§=
∫ π§π ππ
∫ πππ
∑
π§ππ
π§= ∑π π π
ππ ππ
Possible Centroids
2
3
Support Reactions
4
Trusses
Zero-force members cases:
3
π1 = 0 , π2 = 0
5
Beams
5.1
Quantities relationships
π1 = πΉ , π2 = 0
ππ
=π
ππ₯
ππ
= −π,
ππ₯
5.2
π1 = π2 , π 3 = 0
Relationships of V, M and loads
Types of loads
V diagram
M diagram
π=0
const
linear
π = const
linear
parabola
π = linear
parabola
cubic
concentrated
force
jump
kink
moment couple
continuous
4
jump
5.3
Relationships of lines:
π ′′
π′
π
(+)
(+)
(−)
(+)
(+)
(−)
(−)
(+)
(+)
(−)
(−)
(+)
(−)
(−)
6
Static friction
6.1
Basic formula:
|π»| < π»0 ,
π»0 = π0 π
β§π» βΆ static friction force
βͺ
βͺπ»0 βΆ limiting friction force
β¨
βͺπ0 βΆ coefficient of static friction
βͺπ βΆ normal force
β©
6.2
Problem types:
1. Static friction (stays at rest): π» < π0 π
2. Limiting friction (at rest an on the verge of moving): π» = π0 π
3. Kinetic friction (the body slips): π
= ππ
5
6.3
Belt friction
π1 ≤ π2 ππ0 π
The system is in equilibrium if
π1 π−π0 π ≤ π2 ≤ π1 ππ0 π
7
Virtual Work and Stability
7.1
Principle of Virtual Work
∑
∑
πΏπ =
πΉπ πΏππ +
ππ πΏππ = 0
{
πΏππ βΆ virtual linear displacement
where
πΏππ βΆ virtual angular displacement
7.2
Stability of Equilibrium States
• Equation of Stability State: πΏπ = −πΏπ =
ππ
=0
ππ₯
• Types of potential energy:
– Gravitational: π = ππβ
– Linear Spring: π = 12 π (Δπ₯)2
– Torsion Spring: π = 12 ππ (ΔπΌ)2
• Stability criterion:
1. 1st derivative:
– π′ =0
– π′ >0
– π′ <0
→
→
→
neutral
stable
unstable
2. 2nd derivative:
– π ′′ (π₯0 ) = 0
– π ′′ (π₯0 ) > 0
– π ′′ (π₯0 ) < 0
→
→
→
required further investigations
minimum → stable
maximum → unstable
6