Feedback Amplifiers
Feedback Amplifier: The feedback amplifier can be defined as an amplifier which has
a feedback path that exists between output and input. In this type of amplifier, the output
signal is sampled, then fed back to the input where it is mixed with the original source
signal to give the input signal, which is then amplified and turned into the output signal.
This is how the feedback process takes place in a feedback amplifier.
Two Types of Feedback Amplifier:
1. Positive Feedback Amplifier- Positive feedback can be defined as when the feedback
current, otherwise voltage, is applied with the purpose of increasing the input voltage.
Direct feedback is another name for this positive feedback. Because positive feedback
generates unnecessary distortion, it is often not used in amplifiers. But since it amplifies
the original signal power, it can be used in oscillator circuits.
2. Negative Feedback Amplifier- Negative feedback can be defined as when the feedback
current, otherwise voltage, is applied with the purpose of reducing the amplifier input.
Inverse feedback is another name for this negative feedback. This kind of feedback is
commonly used in amplifier circuits.
Here,
π₯
π΄ = π = Gain of Basic Amplifier
π½=
π₯π
π₯π
= Feedback Factor
π₯π
π₯π
π΄π =
π₯π
= Gain with Feedback
π₯π = π₯π − π₯π
= π₯π − π½π₯π
= π₯π − π½π΄π₯π
⇒ π₯π (1 + π΄π½) = π₯π
∴ π΄π =
π₯π
π₯π
π΄
=
=
<π΄
π₯π π₯π (1 + π΄π½) 1 + π΄π½
π΄ > π΄π
Gain with Feedback is always smaller than Gain of Basic Amplifier.
(1 + π΄π½) → Amount of Feedback
If, π΄π½ >> 1
∴ π΄π =
π₯π
π΄
π΄
1
=
≅
=
π₯π 1 + π΄π½ π΄π½ π½
Now, Gain of Feedback Amplifier is independent of Gain of Basic Amplifier; Gain of
Feedback Amplifier depends only on feedback factor.
Feedback factor (π½) is not affected much by temperature, as π½ is the ratio of resistors.
Moreover, they will cancel each other out at higher temperatures. So, ultimately π΄π (Gain
with Feedback) does not change, and instead gets more stable.
Advantages of Negative Feedback Amplifier:
β Stabilizes Gain
β Widens Bandwidth
β Reduces Noise
β Reduces Non-Linear Distortion
β Adjusts Input/Output Resistance
Feedback Topologies:
1. Sampling voltage at output; Mixing voltage at input; Voltage Sampling & Voltage
Mixing.
π₯π = ππ , π₯π = ππ , π₯π = ππ ;
π
π΄ = π → Voltage Amplifier
ππ
2. Sampling voltage at output; Mixing current at input; Voltage Sampling & Current
Mixing.
π₯π = πΌπ , π₯π = πΌπ , π₯π = ππ ;
π
π΄ = π → Transresistance Amplifier
πΌπ
3. Sampling current at output; Mixing current at input; Current Sampling & Current
Mixing.
π₯π = πΌπ , π₯π = πΌπ , π₯π = πΌπ ;
πΌ
π΄ = π → Current Amplifier
πΌπ
4. Sampling current at output; Mixing voltage at input; Current Sampling & Voltage
Mixing.
π₯π = ππ , π₯π = ππ , π₯π = πΌπ ;
πΌ
π΄ = π → Transconductance Amplifier
ππ
1. Voltage Sampling, Voltage Mixing (Series-Shunt Feedback Amplifier)
Block Diagram:
Input: Series Connection
Output: Shunt Connection
π
π΄π = π = Gain with Feedback
ππ
π
ππ = Input Resistance of Feedback Amplifier
π
ππ = Output Resistance of Feedback Amplifier
π΄=
ππ
ππ
ππ = ππ + ππ
= ππ + π½ππ
= ππ + π½π΄ππ
= ππ (1 + π΄π½)
π
ππ
ππ
ππ (1+π΄π½)
∴ π΄π = π =
π
ππ =
=
π΄
1+π΄π½
π
[Gain, π΄ = π]
ππ
ππ (1 + π΄π½)
πΌπ
= π
π (1 + π΄π½)
# In order to find the output resistance, we apply a test voltage ππ₯ . We will also set ππ to
be zero, otherwise π
ππ =
ππ₯
πΌπ₯
will not be valid as there will be current from ππ as well.
# The current to the feedback network is zero because of high input resistance considering
the ideal case.
ππ₯ = πΌπ₯ π
π + π΄ππ
= πΌπ₯ π
π − π΄ππ
= πΌπ₯ π
π − π΄π½ππ₯
∴ πΌπ₯ π
π = ππ₯ (1 + π΄π½)
∴ π
ππ =
ππ = ππ + ππ
⇒ ππ = −ππ [ππ → 0]
ππ₯
π
π
=
πΌπ₯ 1 + π΄π½
# In series connection, resistance increases by factor of (1 + π΄π½) whether at input or
output.
# In parallel/shunt connection, resistance decreases by factor of (1 + π΄π½).
2. Voltage Sampling, Current Mixing (Shunt-Shunt Feedback Amplifier)
Block Diagram:
Here,
π
π΄π = π = Gain of Feedback Amplifier
πΌπ
π
π΄ = π = Gain of Basic Amplifier = Transresistance Gain
πΌπ
π
ππ = Input Resistance of Feedback Amplifier
π
ππ = Output Resistance of Feedback Amplifier
πΌπ = πΌπ + πΌπ
= πΌπ + π½ππ
= πΌπ + π½π΄πΌπ
= πΌπ (1 + π΄π½)
∴ π΄π =
π
ππ =
ππ
ππ
π΄
=
=
πΌπ πΌπ (1 + π΄π½) 1 + π΄π½
ππ
ππ
π
π
=
=
πΌπ πΌπ (1 + π΄π½) 1 + π΄π½
# Here, the connection is shunt, so resistance decreases by factor of (1 + π΄π½).
# In order to find π
ππ , we apply a test voltage ππ₯ once again, and set πΌπ to zero, under the
assumption that current flowing to the feedback network is zero due to ideal conditions.
ππ₯ → Active; πΌπ = 0
πΌπ = πΌπ + πΌπ
πΌπ = −πΌπ
∴ ππ₯ = πΌπ₯ π
π + π΄πΌπ
= πΌπ₯ π
π − π΄πΌπ
= πΌπ₯ π
π − π΄π½ππ₯
∴ πΌπ₯ π
π = ππ₯ (1 + π΄π½)
∴ π
ππ =
ππ₯
π
π
=
πΌπ₯ 1 + π΄π½
3. Current Sampling, Current Mixing (Shunt-Series Feedback Amplifier)
Block Diagram:
Here,
πΌ
π΄
πΌπ
πΌπ
1+π΄π½
π΄π = π =
π΄=
πΌπ
π
ππ =
= Current Gain
π
π
1+π΄π½
π
ππ = π
π (1 + π΄π½)
4. Current Sampling, Voltage Mixing (Series-Series Feedback Amplifier)
Block Diagram:
Here,
πΌ
π΄
ππ
1+π΄π½
π΄π = π =
πΌ
π΄ = π = Transconductance Gain
ππ
π
ππ = π
π (1 + π΄π½)
π
ππ = π
π (1 + π΄π½)
Basic Amplifier
Applying Voltage Divider Rule:
π
ππ =
π½=
π
+π
π
ππ
ππ
π΄π =
=
ππ ;
π
π
+π
π
π
π
1
=1+
π½
π
π
ππ = π
ππ (1 + π΄π½)
π
ππ =
π
π
1 + π΄ππΏ π½
π
π΄ππΏ
ππ
1+π΄ππΏ π½
π΄π = π =
=
π΄ππΏ
π΄ππΏ π½
=
1
π½
[π΄ππΏ π½ >> 1]