© Copyright 2024 M. M. Afshar. All rights reserved.
Physics 101
Final Exam Formula Sheet
Conversions:
§ 1 mile = 5280 feet = 1609.344 meters
§ 1 meter = 3.281 feet = 39.37 inches
§ 360 degrees = 2π radians
"
§ Fahrenheit to Celsius: π! = # (π$ − 32)
§ Kelvin to Celsius: π! = π% − 273.15
§ 1 atmosphere = 101325 pascals
Physics:
§ Uniform mass density: π = ππ
§ Non-uniform mass density: π = ∫ π ππ
§ Velocity and acceleration:
56β
;6β
<β
59
§ Kinematic equations in π₯:
?
π₯= = π₯> + π£2> π‘ + &π2 π‘ &
?
Constants:
§ Grav. acceleration on Earth: π = 9.8 π/π &
§ Earth’s mass: π' = 5.974 × 10&( ππ
§ Earth’s radius: π
' = 6.378 × 10) π
§ Density of liquid water: π = 1000 ππ/π*
Mathematics:
§ Circle – Circumference: πΆ = 2ππ
§ Circle – Area: π΄ = ππ
&
§ Sphere – Surface Area: π = 4ππ
&
(
§ Sphere – Volume: π = * ππ
*
§ Cylinder – Surface Area: π = 2ππ
& + 2ππ
πΏ
§ Cylinder – Volume: π = ππ
& πΏ
§ sin π = π/π» , cos π = π΄/π» , tan π = π/π΄
+
§ sin L& ± πN = cos(π)
+
§ cos L & ± πN = β sin(π)
§ sin& π + cos & π = 1
§ Quadratic formula: π₯ =
,-±√- ! ,(01
&0
Tβ = π΄π΅ cos π = π΄2 π΅2 + π΄3 π΅3
§ π΄β ⋅ π΅
Tβ = Uπ΄3 π΅4 − π΄4 π΅3 Vπ€Μ + (π΄4 π΅2 − π΄2 π΅4 )π₯Μ
§ π΄β × π΅
+Uπ΄2 π΅3 − π΄3 π΅2 VπZ
<β
;9
π£β = 58 , π£β09: = ;8 , πβ = 58 , πβ09: = ;8
π₯= = π₯> + &Uπ£2> + π£2= Vπ‘
π£2= = π£2> + π2 π‘
&
&
π£2=
= π£2>
+ 2π2 Uπ₯= − π₯> V
§ π605 = −π£ & /π
§ π€ = ππ
§ π@ ≤ π@ π
§ πA = πA π
§ π
9>@ = ππ£
?
§ π
560: = πΌπ£ & where πΌ = & π·π΄π
§ πΉβ@ = −ππ₯ π€Μ
§ ∑ πΉβ = ππβ
§ πΉβ?BC& = −πΉβ&BC?
6β
§ π = ∫6β ! πΉβ ⋅ ππ β
"
§ π = πΉ π cos π
§ πCD8 = ΔπΎ
§ π1 = −Δπ
§ π: = πππ¦
?
§ π@ = & ππ₯ &
?
§ πΎ = & ππ£ &
§ ΔπΎ + Δπ = πC1
EF
EF
§ πΉ2 = − E2 , πΉ3 = − E3
§ π = ππΈ/ππ‘ , π09: = π/Δπ‘
© Copyright 2024 M. M. Afshar. All rights reserved.
Moments of Inertia of Homogeneous Rigid Objects
§ πβ = ππ£β
5Gβ
§ ∑πΉβD28 =
58
§ πΌβ ≡ ∫ ∑πΉβD28 ππ‘
§ Elastic collision: πΎ> = πΎ=
§ Perf. inelastic collision: π£β?= = π£β&=
§ Elastic, head-on collision:
H ,H
&H
!
π£?= = H" IH! π£?> + H IH
π£&>
"
&H"
!
"
!
H! ,H"
π£&= = H IH π£?> + H IH π£&>
?
"
!
§ πβ1H ≡ J ∑> π> πβ>
?
"
!
?
§ πβ1H = J ∫ πβ ππ = J ∫ πβ π ππ
&
§ πΌ = ∑> π> π>K
§ πΌ = ∫ πK& ππ = ∫ πK& π ππ
§ πΌ = πΌ1H + ππ·&
5L
;L
§ π = 58 , π09: = ;8
5!L
5M
;M
§ πΌ = 58 = 58 ! , πΌ09: = ;8
§ Angular kinematic equations:
?
π= = π> + π> π‘ + &πΌπ‘ &
?
π= = π> + &Uπ> + π= Vπ‘
π= = π> + πΌπ‘
π= & = π> & + 2πΌUπ= − π> V
§ π = ππ
§ π£ = ππ
§ |π80C | = ππΌ
§ |π605 | = ππ&
?
?
&
§ πΎ = πΎN>C + πΎ0C: = & ππ£1H
+ & πΌ1H π&
§ πΏTβ = πβ × πβ
§ πΏTβ = πΌπ
Tβ
<β
5O
§ ∑πβD28 = 58
§ πβ = πβ × πΉβ βΉ π = ππΉ sin π = πK πΉ
§ ∑πD28 = πΌπΌ