IAP Exercises Chapter 3 – Answers
3.1 Water tank
(a) β(π‘) =
Μ
π΄π
π΄0 π
[1 − cos(ππ‘)] + β0
3.2 Leaking water tank 1
β(π‘) = β0 −
π΄π0
π‘
π΄0
3.3 Leaking water tank 2
2
β(π‘) = [√β0 −
π΄
π΄0
ππ‘
√ π‘]
2
3.6 Order of a differential equation
(a) First order
(b) Second order
(c) Second order
(d) Fourth order
(e) Two coupled first order differential equations gives a second-order
differential equation →
π2π₯
ππ‘ 2
+π₯ =0
(f) Three coupled first order differential equations gives a third-order
differential equation →
3.7 Linear versus non-linear
(a) Linear
(b) Non-linear
(c) Non-linear
(d) Linear
(e) Linear
(f) Non-linear
π3π₯
ππ‘ 3
+2
ππ₯
ππ‘
+ 2π₯ = 0
(g) Non-linear
(h) Non-linear
(i) Non-linear
1
1
2
2
(j) Linear → π₯(π‘) = π πΆ exp (− π‘ 2 ) = π₯0 expβ‘(− π‘ 2 )
(k) Linear
(l) Non-linear → πΜ + sin(π) = 0
(m) Non-linear → π₯Μ + π₯ + (π₯ 2 − 1)π₯Μ = 0
3.8 Separation of variables
πΌ
− π‘
(a) πΜ
(π‘) = π0 π πΆπ€
(b) π₯(π‘) = π π‘
(c) π(π‘) = π0 π πΌπ‘
(d) π£(π‘) = β‘ −
1
1+π½π‘
3.9 Drag
(a)
ππ
ππ‘
π·
= − π2
π
(b) πβ‘~β‘
π
π·π0
π
(c) π(π‘) = π·π00
π
π‘+1
3.10 Decelerating bike
(a) π
ππ
ππ‘
1
= β‘ −ππ 2
1
3
(b) πβ‘β‘ [ππβ‘π2 β‘π −2 ]
(c) π(π‘) = (√π0 −
π
2π
3.11 Railway turntable
(a) π βΆ β‘ [ππβ‘π−1 β‘π −2 ]
(c) πΜ = π
2
π‘)
3.12 Kirchhoff 1
(a) πΌ1 = 2.0β‘A
(b) πΌ2 = −3.0β‘A
3.13 Kirchhoff 3
(a) πΌ1 = 1.38β‘A
(b) π = πΆβ‘βππππ = 66.0β‘πC
3.14 Kirchhoff 3
(a) π − πΌ1 π
1 − πΌ2 π
2 = 0
(b) πΌ1 =
π
π
1
(c) πΌ1 = πΌπ£ + πΌ2 + πΌ3
π
2 π
3 +π
π£ π
3 +π
π£ π
2
(d) πΌ1 = π (
π
π£ π
2 π
3 +π
1 π
2 π
3 +β‘π
1 π
π£ π
3 +β‘π
1 π
2 π
π£
)
(e) π
π£ = π
1 = π
2 = π
3
3.15 Charging a capacitor
(a)
ππ
ππ‘
=−
1
π
πΆ
(π − πΆπ)
π‘
(b) π(π‘) = πΆπ (1 − π −π
πΆ )
(d) For example: after π‘ = 3π
πΆ → π(π‘ = 3π
πΆ) ≅ 0.95β‘πΆπ
3.16 Langmuir model
(a) πβ‘[π−2 ]β‘, πβ‘[−]β‘, π€β‘[π−2 π −1 ]β‘
1
(b) π(π‘ + βπ‘) − π(π‘) = π€(1 − π)βπ‘
π
(c)
ππ
ππ‘
π€
= (1 − π)β‘
π
π€
(d) π(π‘) = 1 − π −ππ‘
(e)
ππ
ππ‘
π€
= (1 − π) − ππβ‘β‘
π
3.17 Solar sail
(b) π(π‘ + βπ‘) − π(π‘) = β‘πππ · π€π΄π₯π‘β‘
(c) πΉπ = β‘
ππ
ππ‘
(d) πΉπ = β‘π
= πππ π€π΄β‘
π2π₯
ππ‘ 2
= πππ π€π΄
(e) π₯(π‘) = π₯0 +
πππ π€π΄ 2
π‘
2π
3.18 Characteristic timescales
πΆ
(a) π = π€
πΌ
(b) πβ‘~β‘π
πΆ
π
(c) πβ‘~ β‘
πΌ
(d)
ππ
ππ‘
= πΆπ with πΆ > 0.
π‘ = β‘π ln(2)