ISSN 1541-308X, Physics of Wave Phenomena, 2020, Vol. 28, No. 3, pp. 299–304. © Allerton Press, Inc., 2020. PHYSICS OF 1D AND 2D MEDIA Optical Solitons with Kudryashov’s Equation by Lie Symmetry Analysis1 S. Kumara, S. Malika, A. Biswasb, c, d, e, *, Q. Zhouf, L. Morarug, A. K. Alzahranic, and M. R. Belich aDepartment of Mathematics and Statistics Central University of Punjab, Punjab, Bathinda-151001 India bDepartment of Physics, Chemistry and Mathematics, Alabama A&M University, Normal, AL 35762-7500 USA c Department of Mathematics, King Abdulaziz University, Jeddah, 21589 Saudi Arabia dDepartment of Applied Mathematics, National Research Nuclear University, Moscow, 115409 Russia e Department of Mathematics and Statistics, Tshwane University of Technology, Pretoria, 0008 South Africa School of Electronics and Information Engineering, Wuhan Donghu University, Wuhan, 430212 People’s Republic of China g Faculty of Sciences and Environment, Department of Chemistry, Physics and Environment, “Dunarea de Jos” University of Galati, Galati, 800008 Romania hScience Program, Texas A&M University at Qatar, Doha, PO Box 23874 Qatar *e-mail: biswas.anjan@gmail.com f Received December 25, 2019; revised January 21, 2020; accepted January 21, 2020 Abstract—In this work, Kudryashov’s equation is studied with Lie symmetry analysis, which is implemented to describe the propagation pulses in an optical fiber. The equation is converted into system of ordinary differential equations with similarity transformations. These gave way to bright, dark and singular optical soliton solutions to the model. DOI: 10.3103/S1541308X20030127 1. INTRODUCTION Optical solitons are aggressively pursued with several models that have existed since the past few decades [1–17]. There are several equations that have been lately proposed to address the dynamics of soliton propagation through a variety of waveguides such as optical fibers, crystals, metamaterials, PCF and magneto-optic waveguides. The most familiar model is the nonlinear Schrödinger’s equation [2, 7, 11, 15]. A few other models, governing soliton dynamics, are Biswas–Arshed equation [8, 16], Triki–Biswas equation [1, 10], and the Radhakrishan–Kundu–Laksmanan equation [13] that come with different forms of nonlinear refractive index. Recently, N. Kudryashov proposed a law of refractive index that led to Kudryashov’s equation (KE) [9]. KE is used to describe the propagation pulses in an optical fiber. The solutions to KE have been recovered with extended trial function [4], F-expansion [5] and undetermined coefficients [6]. The current paper handles KE by Lie symmetry analysis. Here, first we generate infinitesimals and Lie symmetries of KE. Then two vector fields are obtained. With the help of these vector fields, the governing equation is reduced into system of ordinary differential equations (ODEs). Then exact optical soliton solu1 The text was submitted by the authors in English. tions of system of ODEs are recovered. Finally, the corresponding bright, dark and singular optical soliton solutions of governing equation are presented. 1.1. Governing Model The dimensionless form of KE is given by [4–6, 9] ( iqt + aq xx + b q 2n +cq +g q n −n +hq −2 n ) q = 0. (1) In Eq. (1), the first term indicates the linear temporal evolution and a indicates the coefficients of chromatic dispersion. The remaining terms are nonlinear and stem from the law of refractive index of an optical fiber and gives self-phase modulation effect to the model. At n = 1; by taking g = h = 0 and c = g = h = 0, the model referred as parabolic law and Kerr law respectively, which has been extensively studied. Other special cases are power law and dual-power laws of nonlinearity that has also been extensively studied. The goal of the current paper will address Eq. (1), as it stands, extensively and exhaustively by Lie symmetry analysis. 2. LIE SYMMETRY ANALYSIS In this section, we will employ Lie classical method [18–20] on Eq. (1) in order to obtain the infinitesimals. To achieve this goal, let us consider 299 300 KUMAR et al. q( x, t ) = u( x, t ) exp [i v ( x, t )] , (2) where u and v are real-valued functions. Equation (2) transforms Eq. (1) into imaginary and real portions as ut + 2aux v x + auv x, x = 0, aux, x − uvt − auv x2 + (bu2n + cu n + gu −n + hu −2n )u = 0. (3) For the system of equations (3), let us consider one-parameter (ε) transformations as x* = x + εξ ( x, t, u, v ) + O(ε2 ), t* = t + ετ ( x, t, u, v ) + O(ε ), 2 (4) u* = u + εη ( x, t, u, v ) + O(ε2 ), v * = v + εφ ( x, t, u, v ) + O(ε2 ), 0 = aη − 2auv x φ − uφ − xx x t ( where ξ, τ, η, and φ are infinitesimals, depending upon x, t, u, v, have to be determined. The vector field associated with these transformations is (5) V = ξ∂ x + τ∂t + η∂u + φ∂ v . For system of equations (3), the second prolongations formula [19, 20] are pr (2)V = V + ηx ∂ + φ x ∂ + ηt ∂ + φ xx ∂ , ∂u x ∂v x ∂ut ∂v xx (6) pr (2)V = V + φ x ∂ + φt ∂ + ηxx ∂ , ∂v x ∂v t ∂uxx x t x t xx xx where η , η , φ , φ , φ , and η are extended infinitesimals. From the invariance conditions pr(2)V(Δ) = 0 whenever Δ = 0 in(3), we have ( ) 0 = aηv xx + auφ xx + 2a ηx v x + φ x ux + ηt , av x2 + vt (7) ) η + (2n + 1) bu + ( n + 1) cu − ( n − 1) gu − (2n − 1) hu η. 2n Substituting the values of infinitesimals ηx, ηt, φx, t, φxx, and ηxx, and by equating the coefficient of var- −n n −2 n 3.1. Case (i): V4 φ ious derivative terms equal to zero, we get the system of PDEs. By solving this system, we get By solving characteristic Eq. (11), we have following similarity variables: ξ = C2 + tC1, τ = C1, η = 0, φ = C3 + x C4, (8) 2a where C1, C2, C3, and C4 are arbitrary constants. Hence Lie algebra of system (3) is spanned by the infinitesimal generators as (12) s = t, u( x, t ) = P (s), v ( x, t ) = x + Q(s), 4at where P and Q are new dependent variables, which depends upon s. Using (12) in (3), we have V1 = ∂ , V2 = ∂ , V3 = ∂ , V4 = t ∂ + x ∂ . (9) ∂t ∂x ∂v ∂x 2a ∂v The commutation relations determined of V1, V2, V3, and V4 are given by [V1,V2 ] = 0, [V1,V3 ] = 0, [V1,V4 ] = V2, [V2,V3 ] = 0, [V2,V4 ] = V3 , [V1,V4 ] = 0. 2a (10) 2 P ' + 1 P = 0, 2s ( (13) ) Q ' − bP 2n + cP n + gP −n + hP −2n = 0, (14) where prime represents derivative w.r.t. s. From (13), we have P ( s ) = k1 (15) s, 3. SYMMETRY REDUCTION AND INVARIANT SOLUTIONS To derive invariant solutions of system (3), we have to solve the corresponding characteristic equation given as where k1 is arbitrary constant. By substituting (15) into (14) and solving, we have following cases: (a) When n = –2 dx = dt = du = dv , (11) ξ τ η φ where ξ, τ, η, and φ are presented by (8). To solve characteristic Eq. (11), we will consider two cases of vector fields: (i) V4 and (ii) V3 + βV2 + μV1, where β and μ are arbitrary non-zero real numbers. (16) 4 3 2 hk Q ( s ) = 1 bs4 + 1 cs2 + gk12 ln s − 1 + k2. 3 k1 2 k1 s (b) When n = –1 3 2 2 Q ( s ) = 1 bs2 + 2 cs + 2 gk1 s + hk12 ln s + k3. (17) 2 k1 3 k1 PHYSICS OF WAVE PHENOMENA Vol. 28 No. 3 2020 OPTICAL SOLITONS WITH KUDRYASHOV’S EQUATION (a) When n = –2, Eq. (26) can be written as (c) When n = 1 Q (s) 2 = bk1 ln s + 2ck1 3 2 2 4aμ − β2 1 k7 M −3 + M" = 1 M 4 a2μ4 4 a2β2μ4 − 1 2 bM −3 + cM −1 + gM 3 + hM 5 . aμ Integrating (27), we have 2 gs s+2 + 1 hs2 + k4. (18) 3 k1 2 k1 ( (d) When n = 2 Q (s) = − − 2 3 bk14 gs 2 + ck1 ln s + 1 2 + 1 hs4 + k5. (19) s 2 k1 3 k1 (e) When n ≠ –2, –1, 1, and 2 bk12n 1− n 2ck1n 1− n /2 s − s n −1 n−2 (20) 2 gk1−n 1+ n /2 hk1−2n 1+ n s s + k6, + + n+2 n +1 where k2, k3, k4, k5, and k6, are arbitrary constants. Hence, corresponding solution of (1) is given by Q (s) = − q ( x, t ) = 2 ( aμ aμ 2 k + k9 A − 2 72 4 − 4b2 . a β μ aμ Equation (29) can be written as 4aμ − β 2g α1 = − 4h 2 , α2 = − 2 , α3 = , 3aμ aμ a2μ4 k2 α4 = k9, α5 = − 2 72 4 − 4b2 . a β μ aμ (b) When n = –1, Eq. (26) can be written as 2 Substituting (22) in (3), we have 2 4aμ − β2 1 k7 M −3 M" = 1 M + 4 a2μ4 4 a2β2μ4 2 3 −1 − 1 2 bM + c + gM + hM , aμ Integrating (32), we have (2aμ − β + 2aβμ N ') M ' + aβμ MN " = 0, (23) aβ μ M " + (β − 2aμβ) N ' − a − aβ μ N ' M (24) + β ( bM + cM + gM + hM ) M = 0, 2n n 2 −n ( 2 −2 n N = k7 β − 2aμ 1 dρ + k , ρ+ 8 2 2 2 2aβμ 2aβμ M 2 4aμ − β2 1 k7 M −3 + M" = 1 M 4 a2μ4 4 a2β2μ4 1+ 2n 1+ n 1− n 1− 2n . − 1 2 bM + cM + gM + hM aμ ) Vol. 28 ) k72 −2 M 2 4 2 2 4 2 8 aμ 8a β μ k g − 1 2 b ln M + c + M 3 + h M 4 + 10 , 3 4 2 aμ ( ) (33) where k10 is arbitrary constant. Assuming M(ρ) = A(ρ), k7 = 0 and b = 0; Eq. (33) transform into Eq. (30), where Substituting (25) into (24), we have PHYSICS OF WAVE PHENOMENA (32) 2 (25) where k7 and k8 are arbitrary constants. ( (31) ( M ') = 1 4aμ − β2 M 2 − 1 where prime represents derivative w.r.t. ρ. Double integral of (23) gives 2 (30) where where M and N are new dependent variables, which depends upon ρ. 2 (29) ( A ')2 = α1 A 4 + α2 A3 + α3 A 2 + α4 A + α5, ρ = μx − β t, u( x, t ) = M (ρ), v ( x, t ) = x + N (ρ), (22) β 2 2 2 2 (21) By solving characteristic Eq. (11), we have following similarity variables: 3 ) ( A') = − 4h2 A4 − 2 g2 A3 + 4aμ2 −4β A2 3.2. Case (ii): V3 + βV2 + μV1 2 2 ) 3aμ k1 2 exp i x + Q , t 4at 2 (27) (M ') k2 4aμ − β2 2 −2 = 1 2 4 M − 1 2 72 4 M 2 8 aμ 8a β μ (28) k9 g 4 h 6 −2 b 1 − 2 − M + c ln M + M + M + , 2 4 6 8 aμ where k9 is arbitrary constant. Assuming M2(ρ) = A(ρ) and c = 0; Eq. (28) transform into where Q is given by (16)–(20) and s is given by (12). 2 301 4aμ − β 2g , α3 = α1 = − h 2 , α2 = − , 2 2aμ 3aμ 4a2μ4 α4 = − 2c2 , α5 = k10. aμ 2 (26) No. 3 2020 (34) 302 KUMAR et al. Let us assume M(ρ) = A1/n(ρ), we have (c) When n = 1, Eq. (26) can be written as 2 4aμ − β2 1 k7 M −3 + M" = 1 M 4 a2μ4 4 a2β2μ4 −1 3 2 − 1 2 bM + cM + g + hM . aμ Integrating (35), we have ( (35) ) ( M ') = 1 4aμ − β2 M 2 − 1 2 2 k7 −2 M 2 4 2 2 4 2 8 aμ 8a β μ (36) k11 3 4 b c 1 − 2 ln M + M + gM + hM + , 3 2 aμ 4 where k11 is arbitrary constant. Assuming M(ρ) = A(ρ), k7 = 0 and h = 0; Eq. (36) transform into Eq. (30),where ( ) 4aμ − β α1 = − b 2 , α2 = − 2c 2 , α3 = , 2aμ 3aμ 4a2μ4 2g α4 = − 2 , α5 = k11. aμ (d) When n = 2, Eq. (26) can be written as 2 2 4aμ − β2 1 k7 M −3 + M" = 1 M 4 a2μ4 4 a2β2μ4 − 1 2 bM 5 + cM 3 + gM −1 + hM −3 . aμ Integrating (38), we have ( (38) ) ( M ') = 1 4aμ − β2 M 2 − 1 2 (37) 2 k7 −2 M 2 8 a2μ4 8 a2β2μ4 (39) k12 6 4 −2 1 b c h − 2 M + M + g ln M − M + , 4 2 8 aμ 6 where k12 is arbitrary constant. Assuming M2(ρ) = A(ρ) and g = 0; Eq. (39) transform into Eq. (30), where ( ) 4aμ − β α1 = − 4b 2 , α2 = − 2c2 , α3 = , aμ a2μ4 3aμ (40) k72 h 4 α4 = k12, α5 = 2 − 2 2 4 . aμ a β μ (e) In the case of n ≠ –2, –1, 1, 2, by integrating Eq. (26), we have 2 b M ( aμ 2n + 2 ( M ')2 = 1 4aμ − β2 M 2 − 1 2 8 aμ 2 4 2n + 2 2 c M n + 2 + g M 2 − n + h M 2 − 2n n+2 2−n 2 − 2n 2 k k − 1 2 72 4 M −2 + 13 , 8a β μ 2 where k13 is arbitrary constant. + ) (41) ( 2 1 A 2/ n A ' 2 = 1 4aμ − β A 2/ n − 1 b A 2/ n+ 2 ( ) 2 2 4 2 8 aμ 2n aμ 2n + 2 g / 2/ 2/ n − 2 2 n n + − 1 1 (42) + c A + A + h A n+2 2−n 2 − 2n k k2 − 1 2 72 4 A −2/ n + 13 . 8a β μ 2 ) Multiplying Eq. (42) by n2A2 – 2/n and taking k7 = 0 and k13 = 0, we have 2 bn2 A 4 − 22cn A3 aμ (n + 1) aμ (n + 2) (43) 2 2 2 2 (4aμ − β )n 2 2 gn hn . + A + 2 A+ 2 4a2μ4 aμ (n − 2) aμ (n − 1) Equation (43) is similar to Eq. (30), where ( A')2 = − 2 2 2 bn , α2 = − 22cn , aμ (n + 1) aμ (n + 2) 2 2 (4aμ − β )n (44) , α3 = 4a2μ4 2 2 gn2 , α5 = 2hn . α4 = 2 aμ (n − 2) aμ (n − 1) Relation between parameters a, b, c, g, h, and n of (1) and parameters α1, α2, α3, α4, and α5 of (30) in order to derive the solutions M(ρ) of (26) is given by following Table 1. α1 = − 2 3.3. Soliton Solutions to Equation (30) To derive the general solution of the equation (45) ( A′)2 = α1 A 4 + α2 A3 + α3 A 2 + α4 A + α5, one can use substituting methods [11, 12, 16, 17]. In [9], the author expressed the general solution of Eq. (45) in the form of Weierstrass and Jacobi elliptic function. Here we obtained the bright, dark and singular soliton solutions of Eq. (45). 3.3.1. Bright solitons. Let us assume α2(4α3α1 − α22 ) , α12 α2(16α3α1 − 5α22 ) α5 = 1 2 . 256 α13 Then the solution of Eq. (45) is given by α4 = 1 8 α A (ρ) = − 1 2 ± 1 6α22 − 16α3α1 4 α1 4α1 2(8α3α1 − 3α22 ) × sech 1 ρ ± k14 , α1 4 PHYSICS OF WAVE PHENOMENA Vol. 28 No. 3 (46) 2020 OPTICAL SOLITONS WITH KUDRYASHOV’S EQUATION 303 Table 1. Relation between parameters of Eqs. (1) and (30) in order to derive the solutions M(ρ) of (26) α1 Parameters α2 α3 α4 α5 M(ρ) 2g 2 aμ 4aμ − β 2 4 aμ k9 k2 − 2 72 4 − 4b2 aμ a β μ A(ρ) 2 n = –2, c=0 − 4h 2 3aμ − n = –1, k7 = b = 0 − h2 2aμ − 2g 2 3aμ 4aμ − β 2 4 4a μ − 2c2 aμ k10 A(ρ) n = 1, k7 = h = 0 − b2 2aμ − 2c 2 3aμ 4aμ − β 2 4 4a μ − 2g 2 aμ k11 A(ρ) n = 2, g=0 − 4b 2 3aμ − 2c2 aμ 4aμ − β 2 4 aμ k12 4h − k7 2 2 2 4 aμ aβμ A(ρ) 2cn2 2 aμ (n + 2) (4aμ − β )n 2 4 4a μ hn2 2 aμ (n − 1) A1/n(ρ) n ≠ –2, –1, 1, 2, k7 = k13 = 0 − bn2 2 aμ (n + 1) − 2 2 2 2 2 where k14 is arbitrary constant. Hence corresponding bright soliton solution of Eq. (1) is given by q ( x, t ) 2 β − 2aμ 1 = M (ρ) exp i x + d ρ + k8 , 2 2 M β 2αβμ (47) where ρ = μx – βt and the values of M depending upon various parameters and the function A as discussed in Table 1 and A is given by (46). 3.3.2. Dark solitons. Let us assume 2 2 2 gn 2 aμ (n − 2) Then the solution of Eq. (45) is given by α A (ρ) = − 1 2 ± 1 16α3α1 − 6α22 4 α1 4α1 (50) 2 8α3α1 − 3α22 × csch 1 ρ ± k16 , 4 α1 where k16 is arbitrary constant. Hence corresponding bright soliton solution of Eq. (1) is given by ( ) q ( x, t ) = M (ρ) k7 β − 2aμ 1 d ρ + k , (51) × exp i x + ρ+ 8 2 2 2αβμ M 2 β 2αβμ where ρ = μx – βt and the values of M depending upon various parameters and the function A as discussed in Table 1 and A is given by (50). The constraint conditions or existence criteria for these solitons are given as 2 α (4α α − α2 ) α (4α α − α2 ) α4 = 1 2 3 21 , α5 = 1 2 3 31 . 8 64 α1 α1 2 2 2 Then the solution of Eq. (45) is given by α A (ρ) = − 1 2 ± 1 3α22 − 8α3α1 4 α1 4α1 1 3α22 − 8α3α1 × tanh ρ ± k15 , α1 4 (48) ( k7 β2 − 2aμ 1 d ρ + k , (49) × exp i x + ρ+ 8 2 2 2 2αβμ M β 2αβμ where ρ = μx – βt and the values of M depending upon various parameters and the function A as discussed in Table 1 and A is given by (48). 3.3.3. Singular solitons. Let us assume 2 2 α2(4α3α1 − α22 ) 1 α2(16α3α1 − 5α2 ) . , α = 5 256 α12 α13 Vol. 28 No. 3 (52) for bright and singular solitons, while for dark solitons one needs to have ( ) α1 8α3α1 − 3α22 < 0. q ( x, t ) = M (ρ) PHYSICS OF WAVE PHENOMENA ) α1 8α3α1 − 3α22 > 0, where k15 is arbitrary constant. Hence corresponding bright soliton solution of Eq. (1) is given by α4 = 1 8 (53) 4. CONCLUSIONS This paper studied KE to secure bright, dark and singular soliton solutions to the model. The existence criteria for such solitons are also enumerated. These constraints guarantee the formation of such solitons. The results are thus strongly encouraging to pursue this avenue of research, further along. Later on, the model will be extended to study soliton dynamics with KE in birefringent fibers and DWDM topology. Additional optoelectronic devices are also going to be 2020 304 KUMAR et al. touched base upon. These would be magneto-optic waveguides, optical metamaterials, optical couplers and several such. Those results are currently awaited and they would be reported with time. FUNDING Support of CSIR Research Grant 09/1051(0028)/2018EMR-I to one of the authors (S. Malik) for carrying out the research work is fully acknowledged. The research work of fourth author (QZ) was supported by the National Natural Science Foundation of China (Grant nos. 11705130 and 1157149); this author was also sponsored by the Chutian Scholar Program of Hubei Government in China. The research work of the seventh author (MRB) was supported by the grant NPRP 11S-1126-170033 from QNRF and he is thankful for it. 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