2025 Fall
Solid Mechanics II
MEN23101
#00 Review of Statics
and Solid Mechanics I
Prof. KIM Sung Youb
(sykim@unist.ac.kr)
Computational
Advanced
Nanomechanics Lab
Review of Solid Mechanics I
2
(Statics)
(normal stress)
F
= lim
A → 0 A
(shear stress)
P
ave =
A
P
ave =
A
Computational
Advanced
Nanomechanics Lab
Review of Solid Mechanics I
3
(State of Stress)
• Only six components of stress are required
to define the complete state of stress in 3D.
• Only three components of stress are required
to define the complete state of stress in 2D.
→ Stress is symmetric. Otherwise, the system rotates.
Computational
Advanced
Nanomechanics Lab
Review of Solid Mechanics I
4
(Stress-strain diagram(curve))
(Fatigue)
(Elastic vs. Plastic)
B: elastic limit
(yield stress)
Beyond B: Plastic
Endurance limit
of steel
Repeated loading
makes a material
weaker → fatigue
Computational
Advanced
Nanomechanics Lab
Review of Solid Mechanics I
5
(axial loading)
• From Hooke’s Law:
P
= E
= =
E
AE
• From the definition of strain:
=
(Poisson’s ratio)
L
• Equating and solving for the
deformation,
* E = Young’s Modulus or
PL
Modulus of Elasticity
=
(for steel, E ~ 200 GPa)
AE
=−
lateral strain
=− y =− z
axial strain
x
x
Computational
Advanced
Nanomechanics Lab
Review of Solid Mechanics I
6
(Hooke’s law)
(Shearing strain)
x y z
x = +
E
y = −
z = −
Shear stress
Shear strain
−
x
E
+
E
−
y z
E
x y
E
−
E
−
E
+ z
E
E
xy = G xy yz = G yz zx = G zx
xy = G xy yz = G yz zx = G zx
* k = Bulk Modulus or
Modulus of Compression
Computational
Advanced
Nanomechanics Lab
Review of Solid Mechanics I (Torsion)
7
(Terminology)
Shaft
Torque (twisting couple) T [N‧m]
Polar moment of inertia J [m4]
Angle of twist
(Important relations)
Tc
T
and =
J
J
Tc
max = max =
G
JG
max =
=
TL
JG
Computational
Advanced
Nanomechanics Lab