CONSTRUCTION COST ENGINEERING — EXAM
SOLUTIONS
Part B: Problem-Solving (Short Computations)
B1. Convert ■5,500 / m³ to ■ / L. 1 m³ = 1,000 L.
■5,500 ÷ 1,000 = ■5.50/L
Answer: ■5.50 per L
B2. Rebar crew output = 1,000 kg/day. Time to finish 2,700 kg:
2,700 ÷ 1,000 = 2.7 days
Answer: 2.7 days
B3. Labor rate = ■2,400/worker-day. 6 workers × 6.67 days.
Daily = ■2,400×6 = ■14,400; Total = ■14,400×6.67 = ■96,048
Answer: ■96,048
B4. Steel: 2,700 kg × ■65/kg = ■175,500
Answer: ■175,500
B5. Formwork: 200 m² × ■220/m² = ■44,000
Answer: ■44,000
B6. Concrete: 30 m³ × ■5,500/m³ = ■165,000
Answer: ■165,000
B7. Direct cost ■250,000. Add 15% O/H = ■37,500 → ■287,500.
Add 10% contingency = ■28,750 → ■316,250 total.
Answer: ■316,250
B8. 0.1 labor-hr/ft² × 120 ft² = 12 labor-hr
Answer: 12 labor-hours
B9. ■9,000 ÷ 3 days = ■3,000/day
Answer: ■3,000 per day
B10. Project O/H ■40,000 + (5% of ■400,000 = ■20,000) = ■60,000
Answer: ■60,000