Science Olympiad — Hawk/Hornet 2023 Division C
Team name:______________________________________________________________________ Team number:____________________
Student names:____________________________________________________________________________________________________
Scoring: Time to solve first problem: ________________________________ (use to calculate Bonus below)
Question
Value
Timed
550
1★
210
2
604
3
242
4
684
5
633
6★
159
7
211
8
373
9
331
10
208
11
594
12
417
13
475
14★
241
15
255
16
522
17
476
18
364
Bonuses
Final Score
Timed:
Incorrect letters
Deduction
Score
★
★
★
Special Bonus: ★ = 150; ★★ = 400; ★★★ = 750
The following tables might be useful during the event.
A
B
C
D
E
F
G
H
I
J
K
L
M
AAAAA
A
ABBAA
N
A,B N
O
P
Q
R
S
T
U
V
W
X
Y
Z
AAAAB
B
ABBAB
O
C,D O
P
Q
R
S
T
U
V
W
X
Y
Z
N
AAABA
C
ABBBA
P
E,F P
Q
R
S
T
U
V
W
X
Y
Z
N
O
AAABB
D
ABBBB
Q
G,H Q
R
S
T
U
V
W
X
Y
Z
N
O
P
AABAA
E
BAAAA
R
I,J R
S
T
U
V
W
X
Y
Z
N
O
P
Q
AABAB
F
BAAAB
S
K,L S
T
U
V
W
X
Y
Z
N
O
P
Q
R
AABBA
G
BAABA
T
M,N T
U
V
W
X
Y
Z
N
O
P
Q
R
S
AABBB
H
BAABB
U/V
O,P U
V
W
X
Y
Z
N
O
P
Q
R
S
T
ABAAA
I/J
BABAA
W
Q,R V
W
X
Y
Z
N
O
P
Q
R
S
T
U
ABAAB
K
BABAB
X
S,T W
X
Y
Z
N
O
P
Q
R
S
T
U
V
ABABA
L
BABBA
Y
U,V X
Y
Z
N
O
P
Q
R
S
T
U
V
W
ABABB
M
BABBB
Z
W,X Y
Z
N
O
P
Q
R
S
T
U
V
W
X
Y,Z Z
N
O
P
Q
R
S
T
U
V
W
X
Y
A
B
C
D
E
F
G
H
I
J
K
L
M
N
0
1
2
3
4
5
6
7
8
9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
A
B
C
D
E
F
G
H
I
J
K
L
M
N
O
P
Q
R
S
T
U
V
W
X
Y
Z
Z
Y
X
W
V
U
T
S
R
Q
P
O
N
M
L
K
J
I
H
G
F
E
D
C
B
A
1
3
5
7
9 11 15 17 19 21 23 25
1
9 21 15 3 19 7 23 11 5 17 25
O
P
Q
R
S
T
U
V
W
X
Y
Z
Frequency Table of English letters:
E -
12.51%
S -
6.54%
C -
3.06%
G -
1.96%
K -
0.67%
T A O I N -
9.25%
8.04%
7.60%
7.26%
7.09%
R H L D -
6.12%
5.49%
4.14%
3.99%
U M F P -
2.71%
2.53%
2.30%
2.00%
W Y B V -
1.92%
1.73%
1.54%
0.99%
X J Q Z -
0.19%
0.16%
0.11%
0.09%
Frequency Table of Spanish letters:
E -
14.08%
I -
5.98%
M -
3.08%
Y -
1.09%
Z -
0.47%
A O S N R -
12.16%
9.20%
7.20%
6.83%
6.41%
L D T U C -
5.24%
4.67%
4.60%
4.69%
3.87%
P B H Q -
2.89%
1.49%
1.18%
1.11%
V G F J -
1.05%
1.00%
0.69%
0.52%
Ñ X K W -
0.17%
0.14%
0.11%
0.04%
For the purposes of cryptograms it is customary to treat n and ñ as distinct letters, but a and á are the same letter. Likewise for e and é, and i
and í. In other words, all the accent marks get amputated when working with cryptograms. Also, while some older Spanish dictionaries consider
ch, ll, and rr, to be their own letters—this has fallen out of modern usage. Accordingly, “burro” is considered as five letters: “b-u-r-r-o” and not as
four letters “b-u-rr-o.”
Hawk/Hornet 2023 Division C
School:__________
Timed Question [550 points] Solve this Aristocrat which is a quote by Meg Medina. When you have solved it, raise your hand so that the time
can be recorded and the solution checked.
BIZT UIOT JLB BL QMGBTJ BL IJWLJT RKL BTQQG WLY RKIB
WLY UIJ IJS UIJ’B VT MJ QMAT.
Frequency
A
B
1
8
C
D
E
F
G
2
H
I
J
K
L
M
7
8
2
7
3
Replacement
Page 1
N
O
1
P
Q
R
S
T
U
V
W
4
2
1
7
3
1
3
X
Y
Z
2
1
Hawk/Hornet 2023 Division C
★(Special Bonus Question) 1) [210 points] Decode this Hill cipher, the key is FONT.
(
F
N
L
O
5 14
)≡(
)
T
13 19
Q
I
T
M
E
Z
J
K
O
A
X
F
T
Y
G
M
Y
R
S
T
1
6
2) [604 points] Solve this Xenocrypt.
ZC HTQC FW ENSGC. HTHF CMCWTNJCQCLFJGF O WTFJGF ZC
KFZTETQCQ.
A
Frequency
B
C
9
D
E
F
G
H
2
7
3
3
I
J
K
L
M
N
3
1
1
1
2
Replacement
Page 2
Ñ
O
1
P
Q
4
U
V
W
3
X
Y
Z
3
Hawk/Hornet 2023 Division C
School:__________
3) [242 points] Solve this Baconian cipher, which is a quote by Guy Kawasaki, co-founder Alltop
373333337733733333337333733333733333373333733
333337333773773373333737737773373733373337377
337333773373373333337337337333377373773337333
7333733777333337333333377
4) [684 points] Solve this K1 Aristocrat, a quote by Yasmin Mogahed. The keyword is BRAIN.
IOZKUKOLMO VOJLZ FWB OEXOIKOLMO, FWB POOU, FWB PJKU,
FWB RBIA. FWB PJUU. HBA, FWB TOOX QWKLQ.
K1
A
B
Frequency
2
8
C
D
E
F
1
6
G
H
I
J
K
L
M
1
3
3
5
4
2
Replacement
Page 3
N
O
P
Q
R
12
3
2
1
S
T
U
V
W
X
1
5
1
7
2
Y
Z
2
Hawk/Hornet 2023 Division C
5) [633 points] Solve this K1 Patristocrat a quote by Mark Zuckerberg, Facebook. The keyword is LEARN, and the first two letters are IF.
TQGXC PXBSJ BSTMR ABSKB KLJJK ATJLQ TLABB SJMGX
COKMK OBCKI IGWKV JKIXB XQYLX RLJAA
K1
A
B
C
Frequency
5
8
3
D
E
F
G
3
H
I
J
K
L
M
3
7
8
5
3
N
O
P
Q
R
S
T
2
1
3
2
4
4
U
V
W
X
Y
1
1
6
1
Z
Replacement
★(Special Bonus Question) 6) [159 points] The following quote by LeBron James needs to be encoded with the Porta Cipher with a keyword
of TRIES.
D O N T B E
A F R A I D
W A Y T O S
U C C E E D
O F F A I L
U R E T H I
Page 4
S I S T H E
Hawk/Hornet 2023 Division C
School:__________
7) [211 points] Solve this Baconian cipher, a quote by Tom Kelley, founder Ideo.
132143131312313143213421431234213
413123134213413123421423421342142
314231341313131243123134213421314
313123134131321313142431321423412
432142313143123131
8) [373 points] Solve this K2 Aristocrat, which is a quote by Judy Garland. The keyword is SING.
FUBFDI HL F MQSIN-SFNL ALSIQXW XM DXGSILUM, QWINLFK
XM F ILJXWK-SFNL ALSIQXW XM IXVLXWL LUIL.
Replacement
K2
A
B
Frequency
2
1
C
D
2
E
F
G
H
I
J
K
L
M
N
7
1
1
9
1
2
12
5
4
Page 5
O
P
Q
4
R
S
6
T
U
V
W
X
3
1
5
9
Y
Z
Hawk/Hornet 2023 Division C
9) [331 points] Solve this Aristocrat which is a quote by Adam Osborne.
MTO SABM YPVQPEVO MTDCX HAQ UPC SPJO DB P SDBMPJO –
HAQ UPC’M VOPKC PCHMTDCX WKAS EODCX IOKWOUM.
Frequency
A
B
C
D
E
4
3
7
5
2
F
G
H
I
J
K
3
1
2
3
L
M
N
7
O
P
Q
8
9
3
R
S
T
U
V
W
X
Y
4
3
3
3
2
3
1
Z
Replacement
10) [208 points] The following quote by Krystle Ng-A-Mann needs to be decoded with the Porta Cipher with a keyword of BOXES.
F M Y J O B W J
D N Q U C S A B
T U N V L Q M I
S K P T
K V W W E X C M
Page 6
K U P C V R A S
Hawk/Hornet 2023 Division C
School:__________
11) [594 points] Solve this Patristocrat, a quote by Napoleon Hill.
OCXBW YMUBK MCKHM QUJMU BBUAZ MFBQM AYWYM UBMXB
XRLLM XXDRX BCZMX BMKGM TCZFB QMAYW YMUBM XBPUA HRYM
Frequency
A
B
C
D
4
12
4
1
E
F
G
H
2
1
2
I
J
K
L
M
1
3
2
16
N
O
P
Q
R
1
1
3
3
S
T
U
1
7
V
W
X
Y
Z
3
8
6
3
Replacement
12) [417 points] The following quote by Bill Gates needs to be decoded with the Nihilist Substitution Cipher with a keyword of HAWK and
polybius key of HORNET
1
2
3
4
5
1
2
3
4
5
44 36 67
85 26 35
64 55 23
36 67
73 46 23
56 74 59
33 76 64
65 42 55
Page 7
66 75 65
43 104 49
25 43 85
49 55 36
Hawk/Hornet 2023 Division C
13) [475 points] Alexa severely misheard a phrase from me, and this is how it was encoded using an Aristocrat K1 alphabet. What did it come
out as? It is a quote by Nelson Mandela. The keyword is HELPFUL.
JGJ KTVJ MAJXRB EIY IODJ TXRJLJXRJXC WTXRB PJQONBJ
CIJG CJXR CEY WOVJ JEJ BJJ LAYPKJWB MAYW OKK OXSJKB.
K1
A
B
C
D
E
Frequency
3
6
4
1
3
F
G
2
H
I
J
K
L
M
N
O
P
Q
R
S
T
3
19
5
2
2
1
5
2
1
5
1
3
Replacement
Page 8
U
V
W
X
Y
2
4
7
4
Z
Hawk/Hornet 2023 Division C
School:__________
★(Special Bonus Question) 14) [241 points] Solve this Cryptarithm and use the values to decode what 97118860454 stands for.
Values to decode for solution
9 7 1 1 8 8 6 0 4 5 4
Cryptarithm formula
0
T A L K
+
A
B
B O O K S
C
L I S T E N
D
E
I
K
L
N
O
R
S
T
Page 9
1
2
3
4
5
6
7
8
9
Hawk/Hornet 2023 Division C
15) [255 points] Solve this Aristocrat, a quote by Charles Dickens.
QJ WVUZKX ZM, RXUXG VA LAQAGGAO OSWL JAB KWR VA
LAVWJ. HGAKGWMLZRWLZAR ZM LSX LSZXP AP LZQX.
Frequency
A
B
10
1
C
D
E
F
G
H
5
1
I
J
K
L
M
3
3
8
3
N
O
P
Q
R
S
2
2
3
4
3
T
U
V
W
X
2
4
6
6
Y
Z
7
Replacement
16) [522 points] Solve this K1 Aristocrat, a quote by Glenn Beck. Decode the key phrase.
Enter the Keyword here
Cipher:
LFH VTE ORSZOP VFDNCTRE TUFHS ZFJ ZTPW LFHP CRXO RQ,
FP LFH VTE POTCRMO SZTS FECL LFH TPO POQNFEQRUCO XFP
RS.
K1
Frequency
A
B
C
D
E
F
5
1
5
11
G
H
5
I
J
1
K
L
M
N
O
P
Q
R
S
T
U
V
W
X
5
1
2
8
8
3
7
5
8
2
3
1
2
Replacement
Page 10
Y
Z
4
Hawk/Hornet 2023 Division C
School:__________
17) [476 points] Solve this K3 Aristocrat, a quote by Ryan Allis, co-founder and CEO iContact. The keyword is FIRST.
OHIM GOM MWL CW VCWL HWL MIMDT LHT VHQM EFDM TXF’DM
RXDQCWN GXRHDLE CG.”
K3
Frequency
A
B
C
D
E
F
G
H
I
4
5
2
2
3
5
2
J
K
L
M
N
O
5
8
1
2
P
Q
R
2
2
S
T
3
U
V
W
X
2
5
3
Y
Z
Replacement
18) [364 points] A quote by J. K. Rowling has been encoded using the Complete Columnar Encoder. You are told that 4 rails were used to
encode it.
IETSI RIHES ACTAY ILULA NTTCI BTSUS UTLOE ESIOT
REROE GRSTL RFEFE FARSS HIEAO ATTDE UX
Answer: _______________________________________________
Page 11