ME 330 – Fall 2025 Formula Sheet (2 pages)
Engineering :  =
=
Force
Area
E =
=
Engineering :  =
Length
 = E
Length

 − 1
= 2

 2 − 1
 dF 
E 

 dr  r = r 0
F
=
Ao
 = G
 = tan( )
C1 =
L − Lo
Lo
m1
 100
m1 + m2
E = 2G (1 +  )


 =− x =− y
z
z
C1 =
V =
W

+
W

nm1 =
m1
A
True :  T =
 =
L
 A
 = ln  = ln(1 +  )
 Lo 
 Ao 
F
=  (1 +  )
A
 T = KT n
% CW =
Ao − Af
Ao
 L
True :  T = ln 
 Lo 
F
A
 T = ln
 = e +  p
 =
x 100
 L − Lo 
% EL = 
 *100
L
 o 

+ p A − A 
E
% AR =  o

Ao
AL = A0 L0
nm1
 100
nm1 + nm 2
W

F
Ao
Midterm Exam 1
𝜌=
𝑚
𝑣
NA = 6.023 x 1023 atoms/mol
k = 8.62 x 10-5 eV/atom•K
R = 8.314 J/(mol•K)
 *100

=
Mass atoms
nA
=
Volume cell Vc N A
− Qv 
N v = N exp 

 kT 
R =
APF =
𝑝𝑙𝑎𝑛𝑎𝑟 𝑑𝑒𝑛𝑠𝑖𝑡𝑦 =
(
Vatoms n * R
=
Vc
a3
Presolved
P
= cos  cos  =  cos  cos 
Aslip plane A
4
3
3
)
𝐴𝑟𝑒𝑎 𝑜𝑓 𝑎𝑡𝑜𝑚𝑠 𝑜𝑛 𝑎 𝑝𝑙𝑎𝑛𝑒
𝐴𝑟𝑒𝑎 𝑜𝑓 𝑝𝑙𝑎𝑛𝑒
n
n
 xi
x = i =1
n
s=
 ( xi − x )
i =1
2
n −1


u1u2 + v1v2 + w1w2
cos  = 

2
2
2
2
2
2
 (u1 + v1 + w1 )(u2 + v2 + w2 ) 