The country of Honiglandia is always in long-run equilibrium; the πππ = 0.6 and planned investment
decreases by 30 for every one percentage point increase in the real interest rate (i.e., π in the investment
function equals 30). Assume that π = 10.
Suppose taxes and government purchase both increase by 200 (i.e., βπ = βπΊ = 200).
1. Calculate the change in the following quantities holding π constant:
a) Consumption.
πΆ = πΆΜ
+ πππ(π − π) − ππ
βπΆ = πππ(−βπ) = .6(−200) = −120
Note that without knowing what π, π, π, πΆΜ
are, we can’t calculate the specific value for
πΆ. But that’s okay, we just want to know how much πΆ changes.
b) π (national saving)
π = ππ + π − πΊ
π = (π − π) − πΆ + π − πΊ
π = (π − π) − [πΆΜ
+ πππ(π − π) − ππ] + π − πΊ
βπ = −βπ − [πππ(−βπ)] + βπ − βπΊ = −100 + .6 ∗ 100 + 100 − 100 = −80
So the π curve shifts to the left by 80. We know it’s a shift because we’re calculating the change
in π for a given π.
2. Calculate the change in the equilibrium π, π, πΌ:
We know that in equilibrium, π = πΌ(π) so βπ = βπΌ(π) (we started in equilibrium where π = πΌ and
end in equilibrium where π = πΌ, so π and πΌ must change by the same amount).
The complication now is that due to the shift in π from part 1, π will change and so we also need
to consider the effects of changes in π on π and πΌ.
βπ = βπΌ(π)
−βπ − [πππ(−βπ) − πβπ] + βπ − βπΊ = −π
βπ
−80 + 10βπ = −30βπ
ο βπ = 2
Then you can calculate the changes in the equilibrium levels for π and by just plugging in βπ = 2.
βπ = −80 + 10βπ = −80 + 20 = −60
βπΌ = −30βπ = −60
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Here is what has happened graphically.
The savings line shifts left by 80. But this induces a rise in π that increases π. So in the
end, π and πΌ only fall by 60.
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