Business analytics homework#3, 2021120213 Ryu Jongwon
1. Single mean
H0= the mean of carat=0.8
H1= the mean of carat≠ 0.8
P value=0.509>0.05(not significant)=>We do not reject the null hypothesis.
2. Single proportion
H0: the proportion of ideal in cut=0.3
H1: the proportion of ideal in cut>0.3
P value is less than 0.001<0.05(very significant)=>So, reject the null hypothesis(H0), and
adopt the H1.
Q3. Single mean
H0: the mean of HH_size=3
H1: the mean of HH_size>3
P value is less than 0.001<0.05(very significant)=>So, reject the null hypothesis(H0), and
adopt the H1.
Q4. Single proportion
H0: the proportion of 1 in HH_size=0.1
H1: the proportion of 1 in HH_size>0.1
P value=0.173>0.05(not significant)=>Do not reject the null hypothesis(H0). So, the
proportion of single is equal to 0.1.