MATH 161: Dr. ALLAN BICKLE
EXAM 1 Answer Key
Form A Answers:
1 2 3 4 5 6 7 8 9 10 11a 11b 11c 11d 11e 11f 11g 11h
E E C B D D D C E A -3,1
3
2 −∞ 1
2
0
-.5
Form B Answers:
1 2 3 4 5 6 7 8 9 10 11a 11b 11c 11d 11e 11f 11g 11h
B E A C E B D A C B -3,1
3
2 −∞ 1
2
0
-.5
Form M Answers:
1 2 3 4 5 6 7 8 9 10 11a 11b 11c 11d 11e 11f 11g 11h
C D C B A D A C E B -3,1
3
0
∞
-1
0
0
1.5
Notes:
For 1 (form A) and 5 (form B) the domain is (−∞, −6) ∪ (6, ∞).
For 7 (form A) and 1 (form B) the right-hand limit is 0 and the left-hand limit is 1, so the
(two-sided) limit does not exist.
For 8 (form A) and 2 (form B) the limit going to ∞
is -4, and the limit going to −∞ is 3.
1
For 9 (form A) and 3 (form B) the hole is at 2, 5 .
For 12 (forms A and B), see the notes from 3.1/3.2 for the full solution.
1