AIAA 2011-6623 AIAA Modeling and Simulation Technologies Conference 08 - 11 August 2011, Portland, Oregon A Non-Iterative Aeroengine Model Based on Volume Effect Xiangxing Kong 1 , Xi Wang 2 , Daoliang Tan3, Ai He4 Laboratory of Jet Informatics Department of Aviation Propulsion, Beihang University Beijing, China, 100191 Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 In traditional aeroengine modeling, the nonlinear equations of engine model are generally solved through iterative algorithm. However, due to the strong nonlinear characteristics of the equations, the iterative model often fails to converge at some points of the full envelope and has a poor real time performance. In order to solve the problems, this paper proposes a non-iterative modeling method based on volume effect. In this method, several variables and differential equations of volume dynamics in aeroengine are introduced to the nonlinear equations, as a result, the whole set of equations becomes closed-form and can be solved without iteration. The non-iterative model of a gas turbine engine is written in matlab code. Furthermore, an open-loop simulation is carried out in matlab/simulink, both under groud and altitude condition. Meanwhile, a comparison is made between the non-iterative model and a previous iterative model. The results illustrate that the non-iterative model provides better performance than iterative model both in the stability of solutions and real time performance. Nomenclature N = rotate speed (r/min) J = rotor inertia (kg•m2) R = air/gas constant (kj/kg/K) Cp = specific heat at constant pressure (kj/kg/K) Cv = specific heat at constant volume (kj/kg/K) K = adiabatic exponent π = pressure ratio v = velocity of airflow h = air/gas enthalpy (kj/kg) u = air/gas internal energy (kj/kg) V = volume cubage (m3) Wf = main fuel (kg/s) W = air/gas flow (kg/s) Wcol = cooling air (kg/s) 1 Doctor Graduate Student, Department of Aviation Propulsion, E-mail:kongxx@sjp.buaa.edu.cn. 2 Professor, Department of Aviation Propulsion, E-mail:xwang@buaa.edu.cn. 1 American Institute of Aeronautics and Astronautics Copyright © 2011 by the American Institute of Aeronautics and Astronautics, Inc. All rights reserved. T = total temperature (K) P = total pressure (Pa) or power (j/s) Ps = static pressure (Pa) BPR = Bypass Ratio FP = propulsive force (N) SFC = Specific Fuel Consumption (kg/N/h) PLA = Power Location Angle (degree) I. Introduction Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 T o establish an exact numerical aeroengine model is the most essential work for the control system design and research. Aeroengine model has been extensively applied in engine dynamic performance research, control plan constituting and control system designing. In traditional aeroengine modeling, the nonlinear equations of engine model are generally solved through iterative algorithm. But it requires much computer’s memory to achieve the solutions. Generally, the iterative steps are restricted less than 5, so that the model can execute in real time. However, the restriction of the iterative steps results in the loss of calculation accuracy. Moreover, the iterative model often fails to converge at some points of the full envelope. As a result, we have the necessity for attempting an approach to establish a non-iterative aeroengine model. In recent ten years, the non-iterative method plays an important role in aeroengine modeling domain, since many problems brought by iteration can be eliminated. During this period, an amount of research has been devoted to achieving a fast non-iterative real time model. For example, Khary I. Parker and Ten-Heui Guo 5 developed a turbofan engine in a graphical simulation environment in 2003. Dean K. Frederick 2 described a new method for constructing fast models of jet engines in Simulink. George Mink and Al Behbahani 8 accomplished a real time engine model for Air Force Research Laboratory in 2009. As reported, they all obtained good simulation results to validate their models. However, in their papers there is a lack of detailed engine equations and simulation results obtained in the full flight envelope. This paper makes an exhaustive research on non-iterative aeroengine modeling. The purpose of this paper is to establish a non-iterative model of aeroengine so as to overcome the drawbacks of the iterative model. Furthermore, different from the simulations of the non-iterative model in most papers, the engine equations are listed in detail and the simulation is operated not only under the sea-level, standard-day condition, but also over the full flight envelope. Last but not least, this paper proposes a unique and original modeling measure to realize the gas flow mix of the bypass and the core, contrast to the traditional modeling, it makes several improvements in the bypass and the mixer components. This paper is organized as follows. First, we introduce the modeling method in Section Ⅱ, including non-iterative principle, volume dynamics and component equations. Then, an open-loop simulation involving two experiments is operated in Section Ⅲ. The simulation results are analyzed in this section. Finally, according to the simulation results, three conclusions are concluded in Section Ⅳ. II. Modeling Method In this section, we begin with a general description of the non-iterative principle and follow up with a detailed description of the volume dynamics. In the end, the equations of an aeroengine are listed in detail. A. Non-Iterative Principle 2 American Institute of Aeronautics and Astronautics In the traditional modeling method, aerothermodynamic equations are utilized to represent the components of the engine. Then, the equilibrium relationships of aerothermodynamic and shaft dynamics unite the equations of components as a whole. The progress of solving the aeroengine model is to solve the equilibrium equations. However, during the calculation, several interim variables, such as N H , N L , π F , π C etc. , are unknown quantities. Consequently, a set of guess values must be given at first and then iteration is needed to solve the equilibrium equations. Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 As a simplification, this paper takes the following nonlinear equations as an example, ⎧ x1 = f1 ( x 2 , a )......(1) ⎪ ⎨ x 2 = f 2 ( x1 ).........(2) ⎪ x = f ( x ).........(3) 3 2 ⎩ 3 where a is a known quantity; x1、x 2、x3 are unknown quantities. It is not difficult to find that the equations above need to be solved by iteration. This paper introduces the volume dynamic differential equations to avoid iteration. For the equations listed above, assume a differential equation, x& 4 = f 4 ( x 4 ) , can be introduced in, and x1 in the former equation (2) can be substituted by x 4 . Ultimately, the nonlinear equations changes to the following form, ⎧ x& 4 = f 4 ( x 4 ).........(4) ⎪ x = f ( x ).........(5) ⎪ 2 2 4 ⎨ ⎪ x1 = f 1 ( x 2 , a )......(6) ⎪⎩ x3 = f 3 ( x 2 ).........(7) In substance, the principle of avoiding iteration is to change the equations (1)(2)(3) to equations (4)(5)(6)(7). To analyze the equations in the viewpoint of engine modeling, functions of f 1 and f 2 represent the aerothermodynamic functions of two adjacent components. While the volume effect3,7 is not taken into account, the inlet and outlet parameters of the volume between components are equivalent. The output of the front component acts as input of the next component, which is as equation (2) expressed; while the volume effect is considered, the inlet and outlet parameters of the volume are no longer equivalent. The volume dynamic differential equation (4) is introduced to calculate the volume outlet parameters, which act as the input of the next component, as equation (5) shown. The differential equation (4) is calculated through Euler scheme3. Then the non-linear equations changes to be closed-form. The equations can be worked out explicitly in turn so the iteration is not needed. B. Volume Dynamics As part A discussed, the volume dynamics is introduced to avoid iteration. Hence, the volume effect is necessarily described before deducing the component equations. An aeroengine consists of numerous small chambers called volumes. A volume is shown in Fig.1. The volume effect denotes the effect of the volume dynamics. The volume effect indicates that in 3 American Institute of Aeronautics and Astronautics dynamic progress each volume is capable of storing thermal energy and air/gas masses. As a result, the inlet and outlet parameters of volume are no longer equivalent. Generally, the volume dynamics involves mass equation, energy equation and momentum equation. For this case, mass equation and energy equation are considered so as to avoid iteration. ⎛ RT ⎞ ⎟ m& (Ref. 7) ⎝ V ⎠0 mass equation: P& = ( ρR ) 0 T& + ⎜ ⎛ RT ⎞ ⎛ RT2 ⎞ ⎟⎟ (minhin − mouthout) − ⎜⎜ & (Ref. 7) ⎟⎟ m ⎝ PV ⎠0 ⎝ cv PV ⎠0 Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 energy equation: T& = ⎜⎜ where P& = dP dT dm = Pin − Pout ; T& = = Tin − Tout ; m& = = min − mout 。 dt dt dt Define H& = min hin − mout hout . By equation of ideal gas state, mass equation and energy equation can be simplified as follows, dT T = (k − 1) ⋅ ⋅ ( H& − um& ) (Ref. 4) dt PV dP P dT RT = ⋅ + ⋅ m& (Ref. 4) dt T dt V where u represents the internal energy of air/gas. T and P denote the total temperature and pressure of the volume respectively. C. Component Equations The schematic of a turbofan aeroengine is shown as Fig.2. Note that the volume element(marked by ①②③④) is inserted in the engine to allow for the mass and energy storages. Then, the equations of the components are deduced in turn (The footnotes of the parameters which denote engine sections are all defined in Fig.2.). 1)Fan W2 T2 P2 = f FAN ( η F = f FAN ( N1 T2 ⎛ N1 ⎞ ⎜ ⎟ ,π F ) ⎜ T ⎟ ⎝ 2 ⎠ des N1 T2 ⎛ N1 ⎞ ⎜ ⎟ ,π F ) ⎜ T ⎟ ⎝ 2 ⎠ des f FAN denotes the 2 × 2 map function of the component characteristics. The fan inlet flow rate W2 and efficiency η F are calculated by characteristic interpolation. Fan pressure ratio, πF = P13 P2 Fan exit temperature, T13 = T2 × (1 + (π F a (k -1)/k a - 1)/η F ) 4 American Institute of Aeronautics and Astronautics 2)Compressor The compressor inlet flow rate W25 and efficiency η C are calculated by characteristic interpolation. W25 T25 P25 = f COMPRESSOR( T25 N2 η C = f COMPRESSOR ( Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 N2 T25 ⎛ N2 ⎞ ⎜ ⎟ ,π C ) ⎜ T ⎟ ⎝ 25 ⎠des ⎛ N2 ⎞ ⎜ ⎟ ,π C ) ⎜ T ⎟ ⎝ 25 ⎠ des T25 = T13 P25 = σ 25 P13 πC = P3 P25 ( k −1) / k a T3 = T25 × (1 + (π C a − 1) / η C ) The exit flow rate, W3 = W25 − W27 col 3)Combustor Chamber Calculate the inlet and exit flow rate, W31 = W3 − W3col W4 = W41 − W41col Combustor calculation demands high precision, so volume dynamic equations adopted in this component are not simplified. Rg ⋅T4 ⎡ hg hg dT4 1 ⎤ = ⎢Wf ⋅(ηb ⋅ Hu +hf − ) +W31 ⋅(ha − ) −W4 ⋅(1− )⋅ hg⎥(Ref. 7) dt P4 ⋅V⋅ DHg ⎣⎢ kg kg kg ⎦⎥ T4 = T4 + dT4 ⋅ Δt dt dP4 R g ⋅ T4 P dT = ⋅ (W f + W31 − W4 ) + 4 ⋅ 4 (Ref. 7) dt V T4 dt P4 = P4 + dP4 ⋅ Δt dt 5 American Institute of Aeronautics and Astronautics ⎡ h (T + 1) hg (T4 − 1) ⎤ where DH = 0.5 × ⎢ g 4 − ⎥; g k k g g ⎣⎢ ⎦⎥ P31 = P4 / σ CC σ CC denotes the combustor total pressure coefficient. P41 = P4 Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 T31 = T3 P3 = P31 T41 = W4 C pg T4 + W41col C pa T3 W41C pg 4)High Pressure Turbine The inlet flow rate W 41 and efficiency η HT are calculated by characteristic interpolation. W41 T41 P41 η HT = f HT ( π HT = N2 = f HT ( T41 N2 T41 , π HT ) , π HT ) P41 P43 T43 = T41 × (1 - (1 - π HT (1- kg)/kg) × η HT ) W43 = W41 5)Section 43-45 Volume The volume effect between the two turbines is taken into account. The volume dynamics is introduced to calculate the pressure and temperature of section 45. W44 = W43 + W44col T44 = W43C pg T43 + W44col C pa T44col W44 C pg H& = W44 C pg T44 − W45 C pg T45 m& = W44 − W45 6 American Institute of Aeronautics and Astronautics u 45 = Cvg T45 dT45 T = ( k g − 1) ⋅ 45 ⋅ ( H& − u 45 m& ) dt P45V45 T45 = T45 + dT45 ⋅ Δt dt Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 dP45 P45 dT45 R g T45 = ⋅ + ⋅ m& dt T45 dt V45 P45 = P45 + P45 P44 = P43 = dP45 ⋅ Δt dt σ 45 P44 σ 44 6)Low Pressure Turbine The inlet flow rate W45 and efficiency η LT are calculated by characteristic interpolation. W45 T45 P45 = f LT ( η LT = f LT ( π LT = N1 T45 ⎛ N1 ⎞ ⎜ ⎟ , π LT ) ⎜ T ⎟ ⎝ 45 ⎠ des N1 T45 ⎛ N1 ⎞ ⎜ ⎟ , π LT ) ⎜ T ⎟ ⎝ 45 ⎠ des P45 P5 T5 = T45 × (1 - (1 - π LT (1- kg)/kg ) × η LT ) W5 = W45 W51 = W5 + W5col T51 = W5 C pg T5 + W5col C pa T27 col W51C pg 7)Section 6-63 Volume Section 6-63 is a volume between the low pressure turbine and core nozzle. 7 American Institute of Aeronautics and Astronautics H& = W6 C pg T6 − W63C pg T63 m& = W6 − W63 u63 = Cvg T63 dT63 T = (k g − 1) ⋅ 63 ⋅ ( H& − u63 m& ) dt P63V63 Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 T63 = T63 + dT63 ⋅ Δt dt dP63 P63 dT63 Rg T63 = ⋅ + ⋅ m& dt T63 dt V63 P63 = P63 + P6 = P5 = dP63 ⋅ Δt dt P63 σ 63 P6 σ 51 W6 = W5 + W51col + W6 col 8)Mixer The exit total pressure, P65 = σ 65 P63 The exit total temperature, T65 = W63C pg T63 + W18C paT18 W65C pg 9)Core Nozzle The exit total pressure, P8 = σ e P65 The critical pressure ratio, kg ⎛ k + 1 ⎞ kg −1 P ⎟ π e ,cr = 8 = ⎜⎜ g Pcr ⎝ 2 ⎟⎠ Nozzle may work under three working states, 8 American Institute of Aeronautics and Astronautics if P8 P P < π e ,cr , P8 s = PH , π (λ8 ) = 8 s = H ,through π (λ8 ) work out λ8 ,then calculate PH P8 P8 Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 q ( λ8 ) ; If P8 = π e ,cr , P8 s = PH , q(λ8 ) = 1 ; PH If P8 > π e ,cr , q(λ8 ) = 1 , P8 s > PH . PH W8 = K q' P8 A8 q (λ8 ) T65 v8 = σ e λ8 a cr = σ e λ8 2k g kg +1 R g T65 10)Bypass Volume The volume effect is taken into account in bypass volume. W13 = W2 − W25 + W13col W16 = W18 H& = W13 C pa T13 − W16 C pa T16 m& = W13 − W16 u16 = CvaT16 dT16 T = ( k a − 1) ⋅ 16 ⋅ ( H& − u16 m& ) dt P16V16 T16 = T16 + dT16 ⋅ Δt dt dP16 P16 dT16 Ra T16 = ⋅ + ⋅ m& dt T65 dt V16 P16 = P16 + P13 = dP16 ⋅ Δt dt P16 σ 16 9 American Institute of Aeronautics and Astronautics P18 = P16 11)Bypass Nozzle Traditionally, in iterative modeling, the static pressures for bypass exit Ps ,16 and low pressure turbine exit Ps ,5 are assumed equivalence. But, in terms of non-iterative modeling, this can result in the bypass, low pressure turbine and mixer do not co-operate with each other. As the solution, Ps ,18 is Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 assumed the same as the atmosphere pressure PH . Then, the section 16-18 is considered as a bypass nozzle. The airflow of the bypass duct is ejected through the bypass nozzle and then is mixed together with the gas flow of the core duct. P18 = σ e P16 kg ⎛ k + 1 ⎞ kg −1 P ⎟ π e ,cr = 18 = ⎜⎜ g Pcr ⎝ 2 ⎟⎠ If P18 P P < π e ,cr , P18 s = PH , π (λ18 ) = 18 s = H ,through π (λ18 ) work out λ18 ,then calculate PH P18 P18 q(λ18 ) ; If P18 = π e ,cr , P18 s = PH , q(λ18 ) = 1 ; PH If P18 > π e ,cr , q(λ18 ) = 1 , P18 s > PH . PH W18 = K q' P18 A18 q(λ18 ) T16 v18 = σ e λ18 a cr = σ e λ18 2k g kg +1 R g T16 W63 = W8 − W18 12)Power Equations PFan = W2 C pa (T13 − T2 ) × 10 3 PC = (W3 C paT3 + W27 col C p T27 − W25 C pa T25 ) × 10 3 PHT = (W41C pg T41 − W43 C pg T43 ) × 10 3 10 American Institute of Aeronautics and Astronautics PLT = (W45 C pg T45 − W5 C pg T5 ) × 10 3 PFan , PC , PHT and PLT separately denote the power of fan, compressor, high and low pressure turbines. Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 13)Rotor Dynamic Equations dN H π = (η NH PHT − PC ) /[( ) 2 J H N L ] dt 30 dN H NH = NH + ⋅ Δt dt dN L π = (η NL PLT − PFan ) /[( ) 2 J L N L ] dt 30 dN L NL = NL + ⋅ Δt dt All these equations constitute the aeroengine model. The differential equations in this part are calculated through Euler scheme of single step, and other equations can be calculated explicitly. Finally, the non-iterative model is obtained. In addition, it should be pointed out that the algebraic loops in the model are eliminated by unit delay block in matlab/simulink. III. Simulation Result The aeroengine model is established under matlab/simulink software environment. In this paper, we are only concerned about the open-loop performance of the model. The open-loop simulation is carried on both under the sea-level, standard-day condition and over the full flight envelope. The purpose of the simulation is to validate whether the non-iterative model is of notable advantages in stability of solution and real time performance. In order to achieve the purpose, two experiments are operated, including ground experiment and altitude experiment. A. Ground Experiment The first open-loop experiment is operated under the sea-level, standard-day condition. The PLA command is given as Fig.3. Over the entire range of operation, totally eighteen static operating states of aeroengine are presented in the dynamic progress. And the simulation time in matlab/simulink is 1100 seconds. The simulation is capable of reflecting both the transient and the steady-state performance of the model. Furthermore, the data from ground test is used to evaluate the accuracy of the non–iterative model, as well as a previous iterative model is included in this simulation. Finally, a comparison between the two models is made. Fig.4 shows the performance curves of N H , P3 , P 6 and T 6 ( N H , P3 , P 6 and T 6 respectively denote the rotate speed of the high pressure rotor, total pressure of the compressor exit, total pressure and total temperature of the low pressure turbine exit). The outputs are divided by the parameters of design point so as to eliminate the dimensions. The curves show that the solutions of iterative model bear great instability at some points in the low power rating state. Meanwhile, the solutions of noniterative model are of high stability. The errors of the solutions are plot in Fig.5. As Table 1 described, on the whole, the average errors of non-iterative model are a bit higher, except N H . And none of them exceeds 5%. However, the maximum and minimum errors of the iterative model are evidently much 11 American Institute of Aeronautics and Astronautics higher(at some points, it exceeds 100%), which illuminates that the solutions of the non-iterative model are of better stability. What’s more, the calculating time of the model is sharply shortened due to noniteration, from 2473.1 seconds to 175.6 seconds. To sum up, in ground experiment, the non-iterative model has good calculating accuracy; And the non-iterative model is of better performance in terms of computational stability and efficiency. B. Altitude Experiment In this part, the second open-loop experiment is operated over the full flight envelope so as to evaluate the non-iterative model’s performance at altitude. For achieving our aim, the PLA command remains the same as the ground experiment, and the flight trajectory is shown in Fig.6. (The iterative Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 model fails to converge at some points of the full envelope. So, it is not included in this experiment.) Then, the non-iterative model is validated by the following approach. First, convert the test data from ground test to altitude using similarity theory3, then make a comparison between the test data and the calculation results. Fig.7 shows the simulation results of N H 、 P3 、 P 6 、 T 6 . The outputs are divided by the parameters of design point so as to eliminate the dimensions. The curves generated by non-iterative model appear good consistent with the test data. Fig.8 implies the errors between the calculation results and the test data. The simulation results are summarized in Table 2. As table 2 shown, the average errors of the non-iterative model calculation results are no more than 5%. And, the calculating time of the model is 182.4 seconds. It indicates that the non-iterative model is also of favorable accuracy and real time performance in the full envelope. IV. Conclusion According to the open-loop simulation results, the following conclusions can be concluded, (1) The component equations of aeroengine deduced in this paper are of high validity and applicability; (2) The non-iterative model provides better performance than iterative model both in the stability of solutions and real time performance; (3) The non-iterative model has a high accuracy in the full flight envelope. References 1 Hua Qing. A Realtime Simulation Model of a Typical Turbofan Engine in Full Flight Envelope. Aeroengine, 2002,01(12):47~52. 2 Dean K. Frederick. A New Method for Constructing Fast Models of Jet Engines in Simulink. 45th AIAA/ASME/SAE/ASEE Joint Propulsion Conference & Exhibit August 2009, AIAA 2009-5419. 3 Luo Guangqi,Sang Zengchan. Numerical Methods for Aviation Gas Turbine Engine Simulation. National Defence Industry Press. 2007.4. 4 Tang Shijian,Tong Wanjun. Gear Driving Turbofan Engine Dynamic Modeling Study based on Volume Method. Jet Propulsion Control conference. 2010.11. 5 Khary I. Parker and Ten-Heui Guo. Development of a Turbofan Engine Simulation in a Graphical Simulation Environment. NASA/TM—2003-212543. 6 Sonny Martin, Iain Wallace and Declan G. Bates. Development and Validation of an Aero-engine Simulation Model for advanced controller design. 2008 American Control Conference . June 11-13, 2008. 12 American Institute of Aeronautics and Astronautics 7 Gurevich, Gore Bigger(Russia). Turbofan Aero-Engine control Method and Transient characteristicSimulation. China Aviation Motor Control System Institute. 1998. 8 George Mink. The AFRL ICF Generic Gas Turbine Engine Model. 41st AIAA/ASME/SAE/ASEE Joint Propulsion Conference & Exhibit . 10-13 July 2005. 9 Jeffrey S. Dalton, Al Behbahani. An Integrated Approach to Conversion, Verification,Validation and Integrity of AFRL Generic Engine Model and Simulation. 42nd AIAA/ASME/SAE/ASEE Joint Propulsion Conference & Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 Exhibit . 9-12 July 2006. 13 American Institute of Aeronautics and Astronautics Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 APPENDIX: Figures and Tables Figure 1. An air/gas volume Figure 2. Schematic of a Turbofan Aeroengine Figure 3. PLA Command 14 American Institute of Aeronautics and Astronautics Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 Figure 4. Aeroenginge Simulation Results of Ground Experiment 15 American Institute of Aeronautics and Astronautics Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 Figure 5. Aeroenginge Simulation Errors of Ground Experiment Figure 6. Flight Trajectory of Altitude Experiment Figure 7. Aeroenginge Simulation Results of Altitude Experiment Figure 8. Aeroenginge Simulation Errors of Altitude Experiment 16 American Institute of Aeronautics and Astronautics Figure 9. Turbofan Engine model in Matlab/Simulink 17 American Institute of Aeronautics and Astronautics Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 Model Type Non-Iterative Model Downloaded by BEIJING INSTITUTE OF TECHNOLOGY on October 8, 2022 | http://arc.aiaa.org | DOI: 10.2514/6.2011-6623 Iterative Model Model Type Non-Iterative Model Table 1. Summary of the Ground Experiment Simulation Results Calculating NH Error P3 Error P6 Error T6 Error Time (%) (%) (%) (%) (second) Min -1.91 Min -13.61 Min -37.47 Min -22.07 175.6 Max 8.47 Max 14.11 Max 17.5 Max 4.42 Ave 0.80 Ave -3.68 Ave -1.60 Ave -4.91 Min -7.31 Min -127.1 Min -146.9 Min -40.05 2473.1 Max 7.48 Max 54.78 Max 76.89 Max 7.93 Ave 2.45 Ave 1.23 Ave 1.44 Ave -2.73 Table 2. Summary of the Altitude Experiment Simulation Results Calculating NH Error P3 Error P6 Error T6 Error Time (%) (%) (%) (%) (second) Min -1.74 Min -21.43 Min -33.63 Min -19.21 182.4 Max 7.48 Max 11.58 Max 16.54 Max 4.41 Ave 0.51 Ave -4.67 Ave -1.24 Ave -4.54 18 American Institute of Aeronautics and Astronautics
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